I print a bool to an output stream like this:
#include <iostream>
int main()
{
std::cout << false << std::endl;
}
Does the standard require a specific result on the stream (e.g. 0 for false)?
The standard streams have a boolalpha flag that determines what gets displayed -- when it's false, they'll display as 0 and 1. When it's true, they'll display as false and true.
There's also an std::boolalpha manipulator to set the flag, so this:
#include <iostream>
#include <iomanip>
int main() {
std::cout<<false<<"\n";
std::cout << std::boolalpha;
std::cout<<false<<"\n";
return 0;
}
...produces output like:
0
false
For what it's worth, the actual word produced when boolalpha is set to true is localized--that is, <locale> has a num_put category that handles numeric conversions, so if you imbue a stream with the right locale, it can/will print out true and false as they're represented in that locale. For example,
#include <iostream>
#include <iomanip>
#include <locale>
int main() {
std::cout.imbue(std::locale("fr"));
std::cout << false << "\n";
std::cout << std::boolalpha;
std::cout << false << "\n";
return 0;
}
...and at least in theory (assuming your compiler/standard library accept "fr" as an identifier for "French") it might print out faux instead of false. I should add, however, that real support for this is uneven at best--even the Dinkumware/Microsoft library (usually quite good in this respect) prints false for every language I've checked.
The names that get used are defined in a numpunct facet though, so if you really want them to print out correctly for particular language, you can create a numpunct facet to do that. For example, one that (I believe) is at least reasonably accurate for French would look like this:
#include <array>
#include <string>
#include <locale>
#include <ios>
#include <iostream>
class my_fr : public std::numpunct< char > {
protected:
char do_decimal_point() const { return ','; }
char do_thousands_sep() const { return '.'; }
std::string do_grouping() const { return "\3"; }
std::string do_truename() const { return "vrai"; }
std::string do_falsename() const { return "faux"; }
};
int main() {
std::cout.imbue(std::locale(std::locale(), new my_fr));
std::cout << false << "\n";
std::cout << std::boolalpha;
std::cout << false << "\n";
return 0;
}
And the result is (as you'd probably expect):
0
faux
0 will get printed.
As in C++ true refers to 1 and false refers to 0.
In case, you want to print false instead of 0,then you have to sets the boolalpha format flag for the str stream.
When the boolalpha format flag is set, bool values are inserted/extracted by their textual representation: either true or false, instead of integral values.
#include <iostream>
int main()
{
std::cout << std::boolalpha << false << std::endl;
}
output:
false
IDEONE
Related
I print a bool to an output stream like this:
#include <iostream>
int main()
{
std::cout << false << std::endl;
}
Does the standard require a specific result on the stream (e.g. 0 for false)?
The standard streams have a boolalpha flag that determines what gets displayed -- when it's false, they'll display as 0 and 1. When it's true, they'll display as false and true.
There's also an std::boolalpha manipulator to set the flag, so this:
#include <iostream>
#include <iomanip>
int main() {
std::cout<<false<<"\n";
std::cout << std::boolalpha;
std::cout<<false<<"\n";
return 0;
}
...produces output like:
0
false
For what it's worth, the actual word produced when boolalpha is set to true is localized--that is, <locale> has a num_put category that handles numeric conversions, so if you imbue a stream with the right locale, it can/will print out true and false as they're represented in that locale. For example,
#include <iostream>
#include <iomanip>
#include <locale>
int main() {
std::cout.imbue(std::locale("fr"));
std::cout << false << "\n";
std::cout << std::boolalpha;
std::cout << false << "\n";
return 0;
}
...and at least in theory (assuming your compiler/standard library accept "fr" as an identifier for "French") it might print out faux instead of false. I should add, however, that real support for this is uneven at best--even the Dinkumware/Microsoft library (usually quite good in this respect) prints false for every language I've checked.
The names that get used are defined in a numpunct facet though, so if you really want them to print out correctly for particular language, you can create a numpunct facet to do that. For example, one that (I believe) is at least reasonably accurate for French would look like this:
#include <array>
#include <string>
#include <locale>
#include <ios>
#include <iostream>
class my_fr : public std::numpunct< char > {
protected:
char do_decimal_point() const { return ','; }
char do_thousands_sep() const { return '.'; }
std::string do_grouping() const { return "\3"; }
std::string do_truename() const { return "vrai"; }
std::string do_falsename() const { return "faux"; }
};
int main() {
std::cout.imbue(std::locale(std::locale(), new my_fr));
std::cout << false << "\n";
std::cout << std::boolalpha;
std::cout << false << "\n";
return 0;
}
And the result is (as you'd probably expect):
0
faux
0 will get printed.
As in C++ true refers to 1 and false refers to 0.
In case, you want to print false instead of 0,then you have to sets the boolalpha format flag for the str stream.
When the boolalpha format flag is set, bool values are inserted/extracted by their textual representation: either true or false, instead of integral values.
#include <iostream>
int main()
{
std::cout << std::boolalpha << false << std::endl;
}
output:
false
IDEONE
Before converting wstring to double - how to validate it with regex? Java no problem, but C++ raising questions.. :)
I suppose you have a string and you want to know if it is a double or not. The following code does not use regular expressions. Instead it initializes a stringstream and reads a double from it. If the string starts with something non-numeric, then ss.fail() will be set. If it starts with a number, but does not read the whole string, then there's something non-numeric at the end of the string. So if everything went well and the string is really only a number, then ss.eof() && !ss.fail() will be true.
#include <iostream>
#include <sstream>
int main()
{
std::stringstream ss("123.456");
double mydouble;
ss >> mydouble;
if (ss.eof() && !ss.fail())
std::cout << "yay, success: " << mydouble << std::endl;
else
std::cout << "that was not a double." << std::endl;
return 0;
}
There's also std::wstringstream if you need to convert wide character strings.
You might also want to have a look at the boost libraries, especially at Boost.Lexical_Cast.
With this library you could do the following:
#include <boost/lexical_cast.hpp>
#include <iostream>
int main()
{
try
{
double mydouble = boost::lexical_cast<double>("123.456");
std::cout << "yay, success: " << mydouble << std::endl;
}
catch(const boost::bad_lexical_cast &)
{
std::cout << "that was not a double." << std::endl;
}
return 0;
}
Or maybe it is simpler to do that this way:
std::wstring strKeyValue = "147.sd44";
double value = (double) _wtof(strKeyValue.c_str());
And if strKeyValue==0 then it means it's not double.
lexical_cast throws an exception in the following case. Is there a way to use lexical_cast and convert the string to integer.
#include <iostream>
#include "boost/lexical_cast.hpp"
#include <string>
int main()
{
std::string src = "124is";
int iNumber = boost::lexical_cast<int>(src);
std::cout << "After conversion " << iNumber << std::endl;
}
I understand, I can use atoi instead of boost::lexical_cast.
If I'm understanding your requirements correctly it seems as though removing the non-numeric elements from the string first before the lexical_cast will solve your problem. The approach I outline here makes use of the isdigit function which will return true if the given char is a digit from 0 to 9.
#include <iostream>
#include "boost/lexical_cast.hpp"
#include <string>
#include <algorithm>
#include <cctype> //for isdigit
struct is_not_digit{
bool operator()(char a) { return !isdigit(a); }
};
int main()
{
std::string src = "124is";
src.erase(std::remove_if(src.begin(),src.end(),is_not_digit()),src.end());
int iNumber = boost::lexical_cast<int>(src);
std::cout << "After conversion " << iNumber << std::endl;
}
The boost/lexical_cast uses stringstream to convert from string to other types,so you must make sure the string can be converted completely! or, it will throw the bad_lexical_cast exception,This is an example:
#include <boost/lexical_cast.hpp>
#include <iostream>
#include <string>
#define ERROR_LEXICAL_CAST 1
int main()
{
using boost::lexical_cast;
int a = 0;
double b = 0.0;
std::string s = "";
int e = 0;
try
{
// ----- string --> int
a = lexical_cast<int>("123");//good
b = lexical_cast<double>("123.12");//good
// -----double to string good
s = lexical_cast<std::string>("123456.7");
// ----- bad
e = lexical_cast<int>("abc");
}
catch(boost::bad_lexical_cast& e)
{
// bad lexical cast: source type value could not be interpreted as target
std::cout << e.what() << std::endl;
return ERROR_LEXICAL_CAST;
}
std::cout << a << std::endl; // cout:123
std::cout << b << std::endl; //cout:123.12
std::cout << s << std::endl; //cout:123456.7
return 0;
}
How do I print boolean values with boost::format as symbolic values?
Can this be done without boost::io::group? It seems that flags sent to the stream beforehand get retested:
#include <iomanip>
#include <iostream>
#include <boost/format.hpp>
int main()
{
std::cout
<< std::boolalpha
<< true << " "
<< boost::format("%1% %2%\n")
% true
% boost::io::group(std::boolalpha, true)
;
}
Output
true 1 true
You can archive that like this:
#include <iomanip>
#include <iostream>
#include <boost/format.hpp>
int main()
{
std::cout
<< std::boolalpha
<< true << " "
<< boost::format("%1$b %2%\n")
% true
% boost::io::group(std::boolalpha, true)
;
}
It doesn't appear to me that you can.
I looked at the Boost.Format documentation and the code, and didn't see anything.
On the other hand, the sample code shows how to write a formatter for a user-defined type. You could write one for "bool"
How do you capitalize the output generated by the cout of boolean values.
I know that if I did:
cout << boolalpha << true;
it will output
true
how do I get it to output
True
I have some feeling it has to do with do_truename and do_falsename, but I have no clue how to do it.
For a fleeting moment I thought that this could be done using std::uppercase but this doesn't seem to be the case: these only apply to things like the hexadecimal digits and the exponent. So, it seems it, indeed, requires a std::numpunct<char> override which is, however, not that bad:
#include <iostream>
#include <locale>
struct numpunct
: std::numpunct<char>
{
std::string do_truename() const { return "True"; }
std::string do_falsename() const { return "False"; }
};
int main()
{
std::locale loc(std::cout.getloc(), new numpunct);
std::cout.imbue(loc);
std::cout << std::boolalpha << true << "\n";
}