I have update my django to 1.5 and I have one problem: in urls.py I have
urlpatterns += patterns('django.views.generic.simple',
(r'^$','direct_to_template', {'template': 'index.html'}),)
In 1.4 it works nice, but today it wrotes
"Could not import django.views.generic.simple.direct_to_template. Parent module django.views.generic.simple does not exist."
I searched in google - I find this, but it the same I have in code. Please, help
That direct_to_template() function doesn't exist anymore.
Try this with a generic template view:
from django.conf.urls import patterns
from django.views.generic import TemplateView
urlpatterns = patterns('',
(r'^$', TemplateView.as_view(template_name="index.html")),
)
Related
I know this question has been asked and i have gone through all those answers but i didn't get the solution still. Please help me find out what is wrong .
This is the code from django website for version 1.11 of django .
mysite/urls.py
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^polls/', include('polls.urls')),
url(r'^admin/', admin.site.urls),
]
mysite/polls/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index'),
]
mysite/polls/views.py
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, world. You're at the polls index.")
I am getting the following error
Click to view the error
Your urls.py is in the wrong place, it should be mysite/mysite/urls.py (in the same directory as settings.py).
[A similar question was asked, but not marked as answered, here. I considered continuing that thread but the website told me I'm only supposed to post an answer, so it seems I have to start a new topic.] I'm trying to follow this tutorial and I'm having problems with the URL mapping. Specifically with the part described as "So best practice is to create an “url.py” per application and to include it in our main projects url.py file". The relevant, I hope, part of the folder structure, which arose by following steps of the tutorial to the letter (if possible; usage of the 'patterns' module was impossible for example) and using Django 1.10 is the following:
myproject/
myapp/
urls.py
views.py
myproject/
urls.py
The myproject/urls.py is as follows:
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include(myapp.urls)),
]
The myapp/urls.py is as follows:
from django.conf.urls import include, url
urlpatterns = [
url(r'^hello/', myapp.views.hello),
]
The myapp/views.py is as follows:
from django.shortcuts import render
def hello(request):
return render(request, "hello.html", {})
However, running 'python manage.py runserver' results in the following error:
url(r'^myapp/', include(myapp.urls)),
NameError: name 'myapp' is not defined
INSTALLED_APPS in settings.py contains 'myapp'.
I'd be greatful for any tips on how to deal with the NameError! [Or any tips whatsoever that anyone might consider to be helpful!]
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which means that the import is not required.
url(r'^myapp/', include('myapp.urls')),
Since you have move the hello URL pattern into myapp/urls.py, you can remove from myapp.views import hello from myproject/urls.py.
Once you've made that change, you will get another NameError in myapp/urls.py. In this case, a common approach is to use a relative import for the app's views.
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^hello/$', views.hello),
]
Make sure you have imported following modules to urls.py.
from django.conf.urls import url
from django.contrib import admin
in django 2.0
use these
from django.contrib import admin
from django.urls import path
from first_app import views
urlpatterns = [
path('',views.index, name="index"),
path('admin/', admin.site.urls),
]
your app URL has to be a string
so, here is how the code should look like.
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include('myapp.urls')),
]
also, note that from python 2 upward the regular expression is not needed.
change URL to path
from django.conf.URLs import include path
from Django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
path('^admin/', include(admin.site.urls)),
path('^myapp/', include('myapp.urls')),
]
In Django 2.1.7 here is the default urls .py file
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
]
so we need to add this line as well
from django.conf.urls import url
I have followed #Alasdair answers
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which
means that the import is not required.
Unfortunately, it didn't work out(I still got the name X is not defined error). Here is how I do it.
from django.contrib import admin
from django.urls import include
from django.conf.urls import url
from article import urls as article_users
from article import urls as user_urls
urlpatterns = [
path('admin/', admin.site.urls),
path('api/article/', include(article_users)),
path('api/user/', include(user_urls)),
]
Before using the URL command be sure to first import the url from the module Urls. Then try using the runserver.
from django.conf.urls import url
from django.contrib import admin
from django.urls import path
from django.conf.urls import url, patterns, include
from django.contrib import admin
from django.views.generic import TemplateView
from collection import *
#from collection.views import index,thing_detail,edit_thing
urlpatterns = [
url(r'^$', views.index, name='home'),
url(r'^about/$',TemplateView.as_view(template_name='about.html'),name='about'),
url(r'^contact/$',TemplateView.as_view(template_name='contact.html'),name='contact'),
url(r'^things/(?P<slug>[-\w]+)/$', 'views.thing_detail' ,name='thing_detail'),
url(r'^things/(?P<slug>[-\w]+)/edit/$', 'views.edit_thing',name='edit_thing'),
url(r'^admin/', include(admin.site.urls)),
]
After running the server there is an error "NameError: name 'views' is not defined"
Any help ??
You aren't importing your own views.
Try adding this to your urls.py:
from . import views
Or if you are importing them from a specific app, try replacing . with the app name
First thing I notice is the import *, realize that this will/can cause confusion for other Developers reading your scripts. Python has a methodology that insists that explicit is better than implicit. Which in this senario means you should be explicit about what you are importing.
from django.conf.urls import url, patterns, include
from django.contrib import admin
from django.views.generic import TemplateView
from collection import views as collection_views
urlpatterns = [
# Function Based Views
url(r'^$', collection_views.index, name='home'),
url(r'^things/(?P<slug>[-\w]+)/$', collection_views.thing_detail ,name='thing_detail'),
url(r'^things/(?P<slug>[-\w]+)/edit/$', collection_views.edit_thing,name='edit_thing'),
# Class Based Views
url(r'^about/$',TemplateView.as_view(template_name='about.html'),name='about'),
url(r'^contact/$',TemplateView.as_view(template_name='contact.html'),name='contact'),
# Admin
url(r'^admin/', include(admin.site.urls)),
]
Here instead of importing everything from collection I'm importing just your views and assigning them to a variable. Then using that variable in the URL definitions.
Be sure to import your views by
specifying its location and the methods inside the view to be imported on your urls.py.
from . collection import *
(line above means from current location find collection.py and import everything on it)
Happy coding!
I am trying to display contents of a static page in Django project.
urls.py :-
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'spollow.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
(r'^$', 'django.views.generic.simple.direct_to_template', {'template': 'index.html'}),
url(r'^admin/', include(admin.site.urls)),
)
index.html is in the same directory as urls.py
I am getting 500 internal server error. Any ideas where I am going wrong?
First of all, what is the stacktrace from the 500 error saying that the error may be? You may be using Django 1.6 and the call to direct_to_template is deprecated.
On Django 1.5 or newer you can use TemplateView
Here's the example from the documentation
https://docs.djangoproject.com/en/dev/topics/class-based-views/
from django.conf.urls import patterns
from django.views.generic import TemplateView
urlpatterns = patterns('',
(r'^about/', TemplateView.as_view(template_name="about.html")),
)
You can use the direct_to_template view on Django 1.4 or older
Here's the relevant documentation
https://docs.djangoproject.com/en/1.4/ref/generic-views/#django-views-generic-simple-direct-to-template
from django.views.generic.simple import direct_to_template
urlpatterns = patterns('',
(r'^foo/$', direct_to_template, {'template': 'foo_index.html'}),
(r'^foo/(?P<id>\d+)/$', direct_to_template, {'template': 'foo_detail.html'}),
)
If it is the latter, I would use a module instead of string, (look at the import on the example).
Other than that, without the 500 details it will be shooting in the dark, you may not have the right template, or an incorrect path, or a million different things.
Bonus note
If you just want to serve static pages, it might be better to serve them through the actual webserver in front of django (nginx, apache, etc), specially if you are expecting a high volume of traffic.
If Your error is due to unable to find index.html
if yours is an app(ie: created by python manage.py startapp <app>) then:
Then django will search for template files in <app>/templates directory, if you added the app to INSTALLED_APPS in settings.py.
so you need to create a folder templates inside your <app> and put index.html inside it.
if you don't have any apps, you want to add the template path manually :
open settings.py, then edit TEMPLATE_DIRS
TEMPLATE_DIRS = (
# Put the full path of the template dir here, like "/home/html/django_templates" or
# "C:/www/django/templates".
)
In Django 1.5 or newer you can use the render function instead of direct_to_template:
from django.conf.urls import patterns, include, url
urlpatterns = patterns('',
url(r'^$', 'django.shortcuts.render', {'template_name': 'index.html'}),
)
Or if you prefer the more complex way :), you can use class-based TemplateView:
from django.conf.urls import patterns, include, url
from django.views.generic import TemplateView
urlpatterns = patterns('',
url(r'^$', TemplateView.as_view(template_name="index.html")),
)
ImportError at /
No module named simple
Django Version: 1.5.dev20120710212642
I installed latest django version. I am using
from django.views.generic.simple import redirect_to
in my urls.py. What is wrong? Is it deprecated?
Use class-based views instead of redirect_to as these function-based generic views have been deprecated.
Here is simple example of class-based views usage
from django.conf.urls import patterns, url, include
from django.views.generic import TemplateView
urlpatterns = patterns('',
(r'^about/', TemplateView.as_view(template_name="about.html")),
)
Update
If someone wants to redirect to a URL, Use RedirectView.
from django.views.generic import RedirectView
urlpatterns = patterns('',
(r'^one/$', RedirectView.as_view(url='/another/')),
)
this should work
from django.conf.urls import patterns
from django.views.generic import RedirectView
urlpatterns = patterns('',
url(r'some-url', RedirectView.as_view(url='/another-url/'))
)
Yes, the old function-based generic views were deprecated in 1.4. Use the class-based views instead.
And for the record (no relevant example currently in documentation), to use RedirectView with parameters:
from django.conf.urls import patterns, url
from django.views.generic import RedirectView
urlpatterns = patterns('',
url(r'^myurl/(?P<my_id>\d+)$', RedirectView.as_view(url='/another_url/%(my_id)s/')),
)
Please note that although the regex looks for a number (\d+), the parameter is passed as a string (%(my_id)s).
What is still unclear is how to use RedirectView with template_name in urls.py.