How to remove #define use in C++ array constant? - c++

Question

Having this code:
#define GREEN 0.0f, 1.0f, 0.0f
#define RED 1.0f, 0.0f, 0.0f
const float colors[] = {
RED, GREEN, RED, RED,
};
I can not think of a better (typed) way to create colors, without using the #define. Is it a better way? Also, having the C++11 standard in mind.
UPDATE:
Full example of code using this kind of define, https://bitbucket.org/alfonse/gltut/src/3ee6f3dd04a76a1628201d2543a85e444bae8d25/Tut%2005%20Objects%20in%20Depth/OverlapNoDepth.cpp?at=default

Answer 1

I'm not sure to understand what you're trying to do, but to create a list of colors I would do it like this :
#include <vector>
class color {
public:
color(float r, float g, float b)
: m_red(r), m_green(b), m_blue(b) { }
float m_red;
float m_green;
float m_blue;
};
const auto red = color(1.0f, 0.0f, 0.0f);
const auto green = color(0.0f, 1.0f, 0.0f);
const auto blue = color(0.0f, 0.0f, 1.0f);
int main {
auto colors = std::vector<color>();
colors.push_back(red);
colors.push_back(green);
colors.push_back(blue);
colors.push_back(red);
...
}
Edit
As juanchopanza suggested it, I initialized the floats in the constructor initialization list.

Answer 2

As Elasticboy suggested, do something like this:
struct Color {
float R;
float G;
float B;
};
And now, create constants:
const Color Red = {1.0f, 0.0f, 0.0f };
const Color Green = {0.0f, 1.0f, 0.0f };
and so on...

Answer 3

you can use enum here. e.g.
typedef enum color
{
RED, GREEN, BLUE
} color;
alternatively you can assign default values to the colors also. e.g
typedef enum color
{
RED=1, GREEN=5, BLUE=7
} color;
the only thing you have to keep in mind is that these are named integer constants. float values are not allowed here.