I can't seem to figure out why this while loop stopped looping. It was doing fine before I moved some code around. Now I got something else working and it just doesn't loop. I've also tried making quit a bool set to true and tried to have it loop while it was true until the user hit 4 to exit in which case it would turn it to false but that didn't work. I also tried adding a while loop to the function of showMenu but that also didn't work. I know it must be something simple I just can't catch it. gggrrrr.
#include "stdafx.h"
#include <iostream>
#include <iomanip>
using namespace std;
enum transType { SETUP=1, DEPOSITE, WITHDRAW, EXIT};
int showMenu(double balance);
double transaction(double amount, double balance, transType trans);
int menuSwitch;
int quit=0;
int _tmain(int argc, _TCHAR* argv[]){
int amount=0,balance=0;
while(quit!=4){
showMenu(balance);
switch (menuSwitch){
case DEPOSITE:
cout<<"Enter the amount of deposit: ";
cin>>amount;
cout<<"Your current balance is: "<<transaction(amount,balance,DEPOSITE)<<endl<<endl;
break;
case WITHDRAW:
cout<<"Enter the amount of withdraw: ";
cin>>amount;
if(amount>balance){
cout<<"*** Insufficient funds."<<"Your current balance is: "<<transaction(amount,balance,WITHDRAW)<<endl<<endl;
}
else cout<<"Your current balance is: "<<transaction(amount,balance,WITHDRAW)<<endl<<endl;
break;
case EXIT:
cout<<"Have a Nice Day."<<endl;
quit=4;
break;
}
return 0;
}
}
int showMenu(double balance){
// while(quit==true){
cout<<"Your Online Checking Account System"<<endl;
cout<<"-------------------------------------------"<<endl;
cout<<"Select an option:"<<endl<<endl;
cout<<" 1. Set up the account."<<endl;
cout<<" 2. Deposit Funds into your Account."<<endl;
cout<<" 3. Withdraw Funds out of your Account."<<endl;
cout<<" 4. Exit"<<endl;
cout<<endl<<">>";
cin>>menuSwitch;
switch (menuSwitch){
case SETUP:
cout<<"Enter the balance: ";
cin>>balance;
cout<<endl<<"Your current balance is: "<<balance<<endl<<endl;
break;
}
return balance;
// }
}
double transaction(double amount, double balance, transType trans){
double withdraw = balance-amount;
double deposite = balance+amount;
if(trans=DEPOSITE){
return deposite;
}
else
return withdraw;
}
//return balance;
You return 0 within the switch brackets, ie inside the while loop. Change it so that you return 0 outside of the while loop.
Related
A basic student database using classes, I accept
name,
roll number, and
sgpa(cgpa equivalent but out of 10).
I used while loop, and switch case,but if the code for sgpa validation, and code for displaying all students with same sgpa is removed, the program works neatly, but if not, the program goes into continuous loop, the while loop inside the main, as it accepts the options itself and keeps doing it.
The code fails when i accept the sgpa(while taking the student data) or call the displaySGPA fucntion(option 3)
int totalStudents=0;
class database{
float sgpa;
int roll;
string name;
public:
void getSGPA();
void getData(database []);
friend void displaySGPA(int,database []);
};
//Display Students with same SGPA
void displaySGPA(int temp,database students[]){
int i,sameSGPA=0;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
sameSGPA+=1;
}
}
if(sameSGPA>1){
cout<<"\nStudents with SGPA "<<temp<<"."<<endl;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
cout<<" "<<students[i].roll<<" "<<students[i].name;
}
}
}
else if(sameSGPA==1){
cout<<"Only one student with the SGPA , "<<temp<<". :"<<endl;
for(i=0;i<totalStudents;i++){
if(students[i].sgpa==temp){
cout<<" "<<students[i].roll<<" "<<students[i].name;
break;
}
}
}
else{
cout<<"No Student with given SGPA."<<endl;
}
}
void database :: getData(database students []){
cout<<"\nEnter Name : ";
cin>>name;
cout<<"Enter Roll. ";
cin>>roll;
getSGPA();
}
//SGPA validation
void database :: getSGPA(){
int x=1,temp;
while(x==1){
cout<<"Enter SGPA : ";
cin>>temp;
if(temp<=10){
sgpa=temp;
break;
}
else{
cout<<"Please enter a valid SGPA.";
}
}
}
//main Loop
int main() {
int x,temp;
database students[50];
while (x!=5){
cout<<"\n1.Enter a New Student.\n3.Display students with same SGPA.\n5.Exit.\n\nYour Choice : ";
cin>>x;
switch(x){
case 1:
students[totalStudents].getData(students);
totalStudents++;
break;
case 3:
cout<<"\nEnter the SGPA.";
cin>>temp;
displaySGPA(temp,students);
break;
case 5:
cout<<"Exiting the program.....";
break;
default:
cout<<"Please select a valid option."<<endl;
}
}
}
I found the bug, it was a type conversion bug, i was accepting a float value but passing it as a int,just worked, don't know why.But thanks for each comment and suggestion.
I am currently studying c++ but I fell behind a little bit, so I apologize if my question is obvious.
I have to create a program that asks for a student's name, GPA, Year of admission, and get a random 5 digit number generated for that person. The number of students will not exceed 42.
My program compiled (somehow) and I am able to get the error for invalid menu selection, however, whenever I give a valid selection (currently 1) nothing happens.
Maybe I am missing something, this is why I need help.
Here is my code.
#include <iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;
//print all the menu options
void print_menu()
{
cout<<"\nRCNJ Registrar Menu:"<<"\n"
<<"\n"
<<"[1] Add a student"<<"\n"
<<"[2] Display all students"<<"\n"
<<"[3] Display by year"<<"\n"
<<"[4] Display statistics"<<"\n"
<<"[5] Quit"<<"\n";
}
//get and return the student's name
void get_name(string& student_name) //call student_name after that.
{
cout<<"Please enter the sudent's name: ";
cin >> student_name;
cout<<"\n";
}
//validate and return gpa
double get_gpa()
{
double student_gpa = 0;
cout<<"Please enter the GPA: ";
cin >>student_gpa;
cout<<"\n";
while (student_gpa > 4 || student_gpa < 0)
{
cout<<"Please enter a valid GPA for the student (0.00 - 4.00): ";
cin >> student_gpa;
cout<<"\n";
}
return student_gpa;
}
//validateand return year
int get_year()
{
int student_year = 0;
cout<<"Please enter the year: ";
cin >> student_year;
cout<<"\n";
while (student_year >2016 || student_year <1972)
{
cout<<"Please enter a valid year (min 1972, max 2016): ";
cin >> student_year;
cout<<"\n";
}
return student_year;
}
//generate the student's R#
int generate_number()
{
int r_number;
srand (time(NULL));
r_number = rand() % 89999 + 10000;
return r_number;
}
//save info. Include get_name, get_gpa, get_year
void input_new_student()
{
string student_name;
double student_gpa;
int student_year;
int r_number;
int s_name, s_gpa, s_year, r_num;
get_name(student_name);
get_gpa();
get_year();
generate_number();
}
//display all students in the proper format
void print_all()
{
}
//get a year as selection and print all students that are the same year
void print_by_year()
{
}
//display statistics based on entered students
void print_statistics()
{
}
//validate and return the menu option selected by the user.
//it should call print_menu defined earlier
int get_selection(int menu_choice)
{
menu_choice = 0;
cout<<"\n"
<<"Selection: ";
cin >> menu_choice;
cout<<"\n";
while (menu_choice > 5 || menu_choice< 1)
{
cout<<" Menu choice is invalid. Please re-enter (1 - 5): ";
cin>> menu_choice;
cout<<"\n";
}
return menu_choice;
}
int main()
{
string student_name;
double student_gpa;
int student_year;
int r_number;
int menu_choice;
int s_name=0;
int s_gpa=0;
int s_year=0;
int r_num=0;
string nameArray[42];
s_name++;
double gpaArray[42];
s_gpa++;
int yearArray[42];
s_year++;
int ramapoArray[42];
r_num++;
print_menu();
get_selection(menu_choice);
switch (menu_choice)
{
case 1:
input_new_student();
nameArray[s_name] = student_name;
gpaArray[s_gpa] = student_gpa;
yearArray[s_year] = student_year;
ramapoArray[r_num] = r_number;
break;
}
return 0;
}
I dont have permission to comment, hence adding it here.
In you main(),
get_selection(menu_choice);
switch (menu_choice)
You return menu_choice, but there is none to take the value, you end you using garbage value as it is uninitialized.
So two ways you can do it, either by passing the address/reference of menu_choice or by return value. try either of these it should work, though I have not gone through the rest of your program.
As suggested by others, try a debugger e.g. gdb?
Why is the following code not giving results and how to get results?
Whenever I run the code, it first asks for the names of the players of two teams playing the match, then it shows the menu from which if we select any one of the option it again asks for the batsman name which is not according to the program designed. My research on the code and the problem is that I think buffer memory is full but I don't know how to free it, any help would be beneficial. Thank you
#include<iostream>
#include<string.h>
#include<conio.h>
using namespace std;
class scorecard{
char batname[11][20];
int runscored[11];
char situation[11][10];
char mode[11][15];
char bowlername[11][20];
float oversplayed[11];
int maiden[11];
int runsgiven[11];
int wicketstaken[11];
public:
void updatebatsman(void);
void updatebowler(void);
void displaybat(void);
void displaybowl(void);
void menu(void);
scorecard()
{for(int n=0;n<12;n++)
{
runscored[n]={0};
oversplayed[n]={0};
maiden[n]={0};
runsgiven[n]={0};
wicketstaken[n]={0};
}
}
};
int main()
{
int jb=0;
scorecard s1;
int kb;
s1.menu();
do
{
cout<< "Enter the option"<<endl;
cout<<"(1) Display batting score"<<endl<<"(2) Display Bowling score"<<endl<<"(3) Update batting score"<<endl;
cout<<"(4) Update Bowling score"<<endl;
cin >>kb;
switch(kb)
{
case 1 : s1.displaybat();
break;
case 2 :s1.displaybowl();break;
case 3:s1.updatebatsman();break;
case 4:s1.updatebowler();break;
default:cout<<"Wrong choice";
}
}while (jb<1);
}
void scorecard::updatebowler(void)
{char bowlname[20];
int str,k,option,overnumbers,maidenumb,uprun,upwicket;
cout<<"Enter Bowler name:";
cin.getline(bowlname,20);
for( k=0;k<11;k++)
{str= strcmp(bowlername[k],bowlname);
if (str== 0)
{
cout<<"Menu for Bowler information update "<<endl;
cout<<"(1) Update Number of overs"<<endl<<"(2) Update maiden overs"<<endl<<"(3) Update runs given"<<endl;
cout<<"(4) Update wickets taken"<<endl;
cin >> option;
switch(option)
{
case 1:{cout<<"Enter Numbers of overs to be updated:";
cin >>overnumbers;
cout<<endl;
oversplayed[k]+=overnumbers;
break;
}
case 2:{cout <<"Enter the number of maiden overs to be updated:";
cin>>maidenumb;
cout<<endl;
maiden[k]+=maidenumb;
break;
}
case 3:{cout <<"Enter the number of runs to be added:";
cin>>uprun;
cout<<endl;
runsgiven[k]+=uprun;
break;
}
case 4: {cout<<"Enter number of wickets to be updated:";
cin >>upwicket;
cout<<endl;
wicketstaken[k]+=upwicket;
}
default:cout<<"wroung choice";
}
break;
}
}
if (str!=0)
cout <<"You entered wrong player."<<endl;
}
void scorecard::updatebatsman(void)
{char batsmaname[20];
int str,k;
cout<<"Enter Batsman name:";
cin.getline(batsmaname,20);
for( k=0;k<11;k++)
{str= strcmp(batname[k],batsmaname);
if (str== 0)
{
cout<<"enter runs scored:";
cin>>runscored[k];
cout<<endl<<"enter weather out or not out:";
cin>>situation[k];
cout<<endl<<"enter mode(if batsman out) by which batsman was out:";
cin>>mode[k];
break;
}
}
if (str!=0)
cout <<"You entered wrong player."<<endl;
}
void scorecard::displaybat(void)
{
cout << "Batsman name"<<'t'<<"Runs scored"<<'t'<<"situation"<<'t'<<"mode"<<endl;
for(int j=0;j++;j<12)
{
cout<<batname[j]<<'t'<<runscored[j]<<'t'<<situation[j]<<'t'<<mode[j]<<endl;
}
}
void scorecard::displaybowl(void)
{
cout << "Bowler name"<<'t'<<"overs played"<<'t'<<"maiden overs"<<'t'<<"wicket taken"<<'t'<<"Runs given"<<endl;
cout<<endl;
for(int j=0;j++;j<12)
{
cout<<bowlername[j]<<'t'<<oversplayed[j]<<'t'<<maiden[j]<<'t'<<wicketstaken[j]<<'t'<<runsgiven[j]<<endl;
}
}
void scorecard::menu(void)
{
cout<<"Enter the name of players of batting team"<<endl;
for (int k=0;k<11;k++)
{
cout <<"Enter name of player "<<k+1<<":";
cin>>batname[k];
}
cout <<"Enter the name of players of bowling team"<<endl;
for (int n=0;n<11;n++)
{
cout <<"Enter name of player "<<n+1<<":";
cin>>bowlername[n];
}
}
This is very wrong:
for(int j=0;j++;j<12)
It should be:
for(int j=0; j < 11; j++)
You are also missing a break in your case 4 statement for the options:
case 4: {cout<<"Enter number of wickets to be updated:";
cin >>upwicket;
cout<<endl;
wicketstaken[k]+=upwicket;
break;
}
default:cout<<"wroung choice";
Without the break you will see also the output wrong choice when the user selects option 4.
I am trying to keep a track of total amount of bought groceries.
In my program, every time I buy apples, cheese, or bread, the program should continue with displaying the menu again.
But it keeps asking "How many apples?" after the program has already calculated the total for the apples instead of going back to the menu to choose another item.
Perhaps it has something to do with the type of loop I have used.
I am stuck on trying to figure this out. Any help would be appreciated.
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main()
{
double BUDGET;
const double apple= .60;
const double lb_cheese= 1.60;
const double loaf_bread = 2.50;
double total;
int count;
char choice;
double amount_left;
cout <<"Welcome! What is the budget for your picnic lunch?"<< endl;
cin>> BUDGET;
cout<<"Choose one of the following"<<endl;
cout<<"-------------------------------------"<<endl;
cout<<" MENU \n "<<endl;
cout<<"A-Apple B-Cheese C-Bread"<<endl;
cout<<" $0.60 $1.50 $2.50 "<<endl;
cout<<"-------------------------------------"<<endl;
cin>> choice;
while ((choice != 'Q') && (total <BUDGET)) //Q is the sentinel value to "quit" the program
{
switch(choice)
{
case 'A':
case 'a':
cout<<"How many apples?";
cin>> count;
total+= (count *apple);
break;
case 'B':
case 'b':
cout<<"How many pounds of cheese ?";
cin>> count;
total+= (count* lb_cheese);
break;
case 'C':
case 'c':
cout<<"How many loafs of bread?";
cin>> count;
total+= (count * loaf_bread);
break;
default:
cout<<"The entry you have entered is not valid, please try again."<<endl;
}
if( total > BUDGET)
{ cout<<"You have exceeded your budget please check your cart.\n\n";
break;
}
cout<<"Your total is: $"<<setprecision((2))<<fixed<<total<<endl;
amount_left= BUDGET-total;
cout<<"You have $"<<setprecision(2)<<fixed<<amount_left<<" left to spend."<<endl;
}
return 0;
}
Displaying menu is out of the loop:
display menu
read option
while (option != quit) {
do some calculations
}
and the menu is therefore displayed only once. You could change it to infinite loop:
while (true) {
display menu
read option
if (choice == 'Q' || total >= BUDGET)
break;
do some calculations
}
Also try to avoid writing functions that are longer than 50 lines, place some logic into some different function and just call this function, decompose it to smaller parts, it will be much easier to read and also much easier to understand.
Yes, get the menu in a loop to display it the number of times you desire and also please remember to initialize your variables as good practice.
Double total=0.00 // initialize.
Ok so I'm having trouble with this C++ program I am supposed to do for school and I need some help with an error I keep getting. I have the basics but I need help with classes and objects.
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
class BankAccount {
private:
double accountBalance;
string name;
public:
BankAccount();
BankAccount(string,double);
double deposit(double);
double withdraw(double);
void checkBalance();
};
BankAccount::BankAccount()
{
accountBalance=0;
name="";
}
BankAccount::BankAccount(string name,double money)
{
name=name;
accountBalance=accountBalance;
}
double BankAccount::deposit(double money)
{
accountBalance+=money;
return accountBalance;
}
double BankAccount::withdraw(double money)
{
accountBalance-=money;
return accountBalance;
};
void BankAccount::checkBalance()
{
cout<<"The balance on the account is $"<<accountBalance<<"!!"<<endl;
};
int main(int argc, char *argv[])
{
int c;
double m;
string n;
cout<<"==================Bank======="<<endl;
cout<<"[1] Open a new Bank Account |"<<endl;
cout<<"[2] Deposit money |"<<endl;
cout<<"[3] Withdraw money |"<<endl;
cout<<"[4] Check balance |"<<endl;
cout<<"============================="<<endl;
cout<<endl;
cout<<"What would you like to do :";
cin>>c;
switch (c){
case 1:
cout<<"Ok I see you want to open a new Bank Account"<<endl;
cout<<"But first answer a few questions:"<<endl;
cout<<"What is your name? ";
cin>>n;
cout<<"Next tell me the amount of money you wish to open your account with: ";
cin>>m;
BankAccount::BankAccount(n,m);
cout<<"OK all set, "<<n<<"!!"<<endl;
break;
case 2:
cout<<"How much money would you like to deposit? : ";
cin>>m;
BankAccount.deposit(m);
break;
case 3:
cout<<"How much money would you like to withdraw? : ";
cin>>m;
BankAccount.withdraw(m);
break;
case 4:
cout<<"OK I'll check your balance"<<endl;
BankAccount.checkBalance();
break;
}
system("PAUSE");
return EXIT_SUCCESS;
}
So if you could help me that would be very much appreciated.
BankAccount is a type name, not a variable name. You cannot invoke instance methods on a type.
Create a variable of type BankAccount, assign it an instance, and then call methods on the instance using the same notation that you already have:
BankAccount acct;
switch (c){
case 1:
cout<<"Ok I see you want to open a new Bank Account"<<endl;
cout<<"But first answer a few questions:"<<endl;
cout<<"What is your name? ";
cin>>n;
cout<<"Next tell me the amount of money you wish to open your account with: ";
cin>>m;
acct = BankAccount(n,m);
cout<<"OK all set, "<<n<<"!!"<<endl;
break;
case 2:
cout<<"How much money would you like to deposit? : ";
cin>>m;
acct.deposit(m);
break;
case 3:
cout<<"How much money would you like to withdraw? : ";
cin>>m;
acct.withdraw(m);
break;
case 4:
cout<<"OK I'll check your balance"<<endl;
acct.checkBalance();
break;
}
BankAccount is a class you defined, you cannot use :: operator to access non-static members of that class. In this case, you need to first create an object of BankAccount, then using dot operator to access the deposit and other member functions since those non-static member functions are associated with instance of the class.
If deposit and other relevant functions are static member function, you can do that.