Static libraries. Importing and exporting inline functions - c++

This question arose while I was implementing my static library.
I want to check my guess and gain information on using inline functions in static libs.
My guess is that an iplementator of a static lib can not export an inline function in his library
Due to the inline statement is
implemented by a compiler(it is up to the compiler whether to make
the function inline) by placing low level commands representing
operations in the function body to the code segment so that
operations won't be placed in the tables of export/import and
therefore can't be processed by linker and therefore can't be
included by librarian to the code of application to which static lib
is attached. Is my logic right?
I guess that importing function as inline is allowed but I wonder how it is implemented, because it is compiler`s
responsibility but on the linkage state there is only librarian, so
that means that it must undertake some actions in order to make
function inline.

Yes, inline functions are typically placed in a header, so the function body is directly visible to the compiler everywhere the function is used. This lets the compiler evaluate whether to generate inline code for the function in any particular instance.
This basically doesn't arise -- "An inline function shall be defined in every translation unit in which it is odr-used." (§3.2/3). That means if the compiler is going to generate the function inline, what goes into the library is object code that includes inline expansion of the code for that function. Since it's possible that function may not be expanded inline at every use, there will also typically be a definition of the function in the library, but that definition will be used (at least primarily) like a normal function, not expanded inline.
Linkers can also generate code though. Regardless of whether a function is or isn't an inline function by the language standard, and is defined in the same or a different translation unit from the one where it's used, the linker may be able to generate inline code for it anyway.
To make a long story short, the inline keyword has little or no effect on a typical compiler as far as whether a function's code will be generated inline or not. The main (if not sole) effect is that it changes the one-definition rule -- being inline means that multiple (identical) definitions of the same function can exist without causing a problem.

Do you understand the keyword inline - you could equally use replace.
An inline function enables the compile if so choosing to replace the function call with the actual code - nothing to export/import. It is defined in the header file. Anything that uses the object code will require that header code and thus the compiler will replace the function call with the actual code.

On Visual C++ you can use Microsoft specific behavior, and export/import inline functions with __declspec(dllexport) inline or extern inline. Note that this is Microsoft specific behavior, if you target anything but Windows and are not concerned at all with portability, you could consider it.

Related

Can a very short function become inlined even if it was not explicitly defined as inline?

I know in advance that, when writing a program in C or C++, even if I declare a function as "inline" the compiler is free to ignore this and decide not to expand it at each (or any) call.
Is the opposite true as well? That is, can a compiler automatically inline a very short function that wasn't defined as inline if the compiler believes doing so will lead to a performance gain?
Two other subquestions: is this behaviour defined somewhere in the ANSI standards? Is C different from C++ in this regard, or do they behave the same?
inline is non-binding with regards to whether or not a function will be inlined by the compiler. This was originally what it was intended to do. But since then, it's been realized that whether or not a function is worth inlining depends as much on the call site as the function itself and is best left to the compiler to decide.
From https://en.cppreference.com/w/cpp/language/inline :
Since this meaning of the keyword inline is non-binding, compilers are free to use inline substitution for any function that's not marked inline, and are free to generate function calls to any function marked inline. Those optimization choices do not change the rules regarding multiple definitions and shared statics listed above.
Edit : Since you asked for C as well, from https://en.cppreference.com/w/c/language/inline :
The intent of the inline specifier is to serve as a hint for the compiler to perform optimizations, such as function inlining, which require the definition of a function to be visible at the call site. The compilers can (and usually do) ignore presence or absence of the inline specifier for the purpose of optimization.
Regarding the relation between C and C++, the inline specifier is treated differently in each language.
In C++: inline functions (and function like entities, and variables (since C++17) ) that have not been previously declared with internal linkage will have external linkage and be visible from other compilation units. Since inline functions (usually) reside in header files, this means that the same function will have repeated definitions across different compilation units (this is would be a violation of the One definition rule but the inline makes it legal). At the end of the build process (when linking an executable or a shared lib), inline definitions of the same entity are merged together. Informally, C++ inline means: "there may be multiple identical definitions of some function across multiple source files, but I want them to end up as a unique definition".
In C: If extern is not explicitly specified, then an inline function definition is not visible from other translation units, different translation units may have different definitions with inline specifier for the same function name. Also, there may exist (at most) one definition for a function name that is both inline and extern and this qualifies that function as the one that is externally visible (ie gets selected when one applies the address of & operator to the function name). The One definition rule from C and its relation with extern and inline is somehow different from C++.
can a compiler automatically inline a very short function that wasn't defined as inline if the compiler believes doing so will lead to a performance gain?
Limitation:
When code uses a pointer to the function, then the function needs to exist non-inlined.
Limitation:
When the function is visible outside the local .c file (not static), this prevents simplistic inlined code.
Not a limitation:
The length of the function is not an absolute limitation, albeit a practical one.
I've worked with embedded processor that commonly inline static functions. (Given code does not use a pointer to them.)
The usefulness of the inline keyword does not affect the ability for a compiler to inline function.
When it comes to the standard, the keyword inline has nothing to do with inlining.
The rules (in c++) are basically:
A function which is not declared inline can by only defined in one translation union. It still needs to be delared in each translation unit where it is used.
A function which is declared inline has to be defined in each translation unit where it is odr-used (ord-use means to call the function or to take the pointer,...).
So, in a standard project setting it is almost always correct to follow the following two rules. Functions that are defined in a header file, are always to be declared inline. Functions defined in a *.cpp-file are never declared inline.
This said, I think the compiler cannot really draw any conclusions about the programmer wanted inlining from using or not using keyword inline. The name of the keyword is an unfortunate legacy from a bad naming.

C++ - how can I inline a function that resides in a .lib?

As far as I know it's impossible to have a function declared as "inline" in a lib file and have that function "magically inlined" into a caller function into another project (since linking is not the same as compiling and the latter happens before).
How could I inline a function when having multiple functions (into multiple libraries) that have the same declaration but different definition?
e.g.
obj1.lib
void function1() { printf("Hi"); }
obj2.lib
void function1() {printf("whatsup?"); }
main.cpp
void function1();
int main()
{
function1(); // I'd like to be able to inline this, I can steer the linking against obj1 or obj2, but I can't inline this one
}
To inline a function from an object (or a library) file you'll need this object file be compiled with link-time optimization (LTO). See Inlining functions from object files for more details.
Even if you inline functions, they always have to have the same definition: having different defintions for the same entity in a C++ program is a violation of the one definition rule (ODR) specified in 3.2 [basic.def.odr]. ODR violations are often not detected by compilers and linkers and tend to result in rather weird problems.
You'll need to make sure the functions are different, e.g., using one of these techniques:
Give them a different name.
Put the functions into a namespace.
Give the functions a different signature.
Make the static to have them visible only in the given translation units.
The simplest you can do is to give the functions different names.
If you want built-time selection of a function with a given name, that has 2 or more different implementations, and you want to support machine code inlining of that function, then declare it as inline, which requires also supplying the implementation in each variant's header, and use include and lib paths to select the relevant header (for compilation) and lib (for linking) – they'd better match. As with any inline function this doesn't guarantee machine code inlining. With respect to machine code inlining inline is just a hint (it's guaranteed effect is about permitting a definition in each translation unit, and requiring such a definition in each translation unit where it's used).
How to use include and lib paths depends on your toolchain.
Edited in response to Sam Cristall's comment.
If you mean "inline at compile time" then:
In order to use a library you need to include the header file(s) associated with that library. If the desired function is declared inline in that header and the function definition (the body of the function) is available, then the compiler will (at it's discretion) inline the function. Otherwise it won't.
If you mean "inline at link time" (an unfortunate overloading of the word "inline") than see the other answers

Are C++ class methods defined in the header always inlined?

Edit: I've restored the original title but really what I should have asked was this: 'How do C++ linkers handle class methods which have been defined in multiple object files'
Say I have a C++ class defined in a header along these lines:
class Klass
{
int Obnoxiously_Large_Method()
{
//many thousands of lines of code here
}
}
If I compile some C++ code which uses 'Obnoxiously_Large_Method' in several locations, will the resulting object file always inline the code for 'Obnoxiously_Large_Method' or will it optimise for size (for example, when using g++ -Os) and create a single instance of 'Obnoxiously_Large_Method' and use it like a normal function?, if so, how do linkers resolve the collisions between other object files which have instantiated the same function?. Is there some arcane C++ namespace Juju which keeps the separate object instances of method from colliding with each other?
7.1.2 Function specifiers
A function declaration (8.3.5, 9.3, 11.4) with an inline specifier
declares an inline function. The inline specifier indicates to the
implementation that inline substitution of the function body at the
point of call is to be preferred to the usual function call mechanism.
An implementation is not required to perform this inline substitution
at the point of call; however, even if this inline substitution is
omitted, the other rules for inline functions defined by 7.1.2 shall
still be respected.
So, the compiler is not required to actually 'inline' any function.
However, the standard also says,
An inline function with external linkage shall have the same address in all translation units.
Member functions normally have external linkage (one exception is when the member function belongs to a 'local' class), so inline functions must have a unique address for cases where the address of the function is taken. In this case, the compiler will arrange for the linker to throw away all but one instance of a non-inlined copy of the function and fix-up all address references to the function to be to the one that's kept.
Section [9.3], Member functions, of the C++98 Standard states:
A member function may be defined (8.4) in its class definition, in which case it is an inline member function (7.1.2).
Thus, it has always been the case that marking member functions defined in the class definition explicitly inline is unnecessary.
On the inline function specifier, the Standard states:
A function declaration (8.3.5, 9.3, 11.4) with an inline specifier declares an inline function. The inline specifier indicates to the [C++ compiler] that inline substitution of the function body at the point of call is to be preferred to the usual function call mechanism. [However, a C++ compiler] is not required to perform this inline substitution at the point of call;
So, it is up to the compiler whether it will actually inline the definition of the function rather than call it via the usual function call mechanism.
Nothing is always inlined (unless your compiler has an attribute or private keyword to force it to do so...at which point you're writing $(COMPILER)-flavored C++ rather than standard C++). Very long functions, recursive functions, and a few other things generally aren't inlined.
The compiler can choose not to inline stuff if it determines that doing so will degrade performance, unreasonably increase the object file's size, or make things work incorrectly. Or if it's optimizing for size instead of speed. Or if you ask it not to. Or if it doesn't like your shirt. Or if it's feeling lazy today, cause it compiled too much last night. Or for any other reason. Or for no reason at all.
There is no - single answer to this question. Compilers are smart beasts. You can specifically use the inline words if you want, but this doesn't mean that the compiler will actually inline the function.
Inline is there to help the developer with optmization. It hints at the compiler that something should be inlined, but these hints are generally ignored nowadays, since compilers can do better at register assignment and deciding when to inline functions (in fact, a compiler can either inline or not inline a function at different times). Code generation on modern processors is far more complicated than on the more deterministic ones common when Ritchie was inventing C.
What the word means now, in C++, is that it can have multiple identical definitions, and needs to be defined in every translation unit that uses it. (In other words, you need to make sure it can be inlined.) You can have an inline function in a header with no problems, and member functions defined in a class definition are automatically effectively inline.
That said, I used to work with a greenhills compiler, and it actually obeyed my will more than it disobeyed it :).. It's up to the compiler, really.
The inline keyword deals with c++ definition of a function. The compiler may inline object code where ever it wants.
Functions defined inline (eg they use the inline keyword), create object code for the function in every compilation unit. Those functions are marked as special so the linker knows to only use one.
See this answer for more specifics.
It doesn't have to be inlined, no; it's just like if you specified inline explicitly.
When you write inline, you promise that this method won't be called from translation units where it isn't defined, and therefore, that it can have internal linkage (so the linker won't connect one object-file's reference to it to another object-file's definition of it). [This paragraph was wrong. I'm leaving it intact, just struck-out, so that the below comments will still make sense.]

what is/are the purpose(s) of inline?

I had a discussion with Johannes Schaub regarding the keyword inline.
The code there was this:
namespace ... {
static void someFunction() {
MYCLASS::GetInstance()->someFunction();
}
};
He stated that:
Putting this as an inline function may
save code size in the executable
But according to my findings here and here it wouldn't be needed, since:
[Inline] only occurs if the compiler's cost/benefit analysis show it to be profitable
Mainstream C++ compilers like Microsoft Visual C++ and GCC support an option that lets the compilers automatically inline any suitable function, even those not marked as inline functions.
Johannes however states that there are other benefits of explicitly specifying it. Unfortunately I do not understand them. For instance, he stated that And "inline" allows you to define the function multiple times in the program., which I am having a hard time understanding (and finding references to).
So
Is inline just a recommendation for the compiler?
Should it be explicitly stated when you have a small function (I guess 1-4 instructions?)
What other benefits are there with writing inline?
is it needed to state inline in order to reduce the executable file size, even though the compiler (according to wikipedia [I know, bad reference]) should find such functions itself?
Is there anything else I am missing?
To restate what I said in those little comment boxes. In particular, I was never talking about inlin-ing:
// foo.h:
static void f() {
// code that can't be inlined
}
// TU1 calls f
// TU2 calls f
Now, both TU1 and TU2 have their own copy of f - the code of f is in the executable two times.
// foo.h:
inline void f() {
// code that can't be inlined
}
// TU1 calls f
// TU2 calls f
Both TUs will emit specially marked versions of f that are effectively merged by the linker by discarding all but one of them. The code of f only exists one time in the executable.
Thus we have saved space in the executable.
Is inline just a recommendation for the compiler?
Yes.
7.1.2 Function specifiers
2 A function declaration (8.3.5, 9.3, 11.4) with an inline specifier declares an inline function. The inline
specifier indicates to the implementation that inline substitution of the function body at the point of call
is to be preferred to the usual function call mechanism. An implementation is not required to perform this
inline substitution at the point of call; however, even if this inline substitution is omitted, the other rules
for inline functions defined by 7.1.2 shall still be respected.
For example from MSDN:
The compiler treats the inline expansion options and keywords as suggestions. There is no guarantee that functions will be inlined. You cannot force the compiler to inline a particular function, even with the __forceinline keyword. When compiling with /clr, the compiler will not inline a function if there are security attributes applied to the function.
Note though:
3.2 One definition rule
3 [...]An inline function shall be defined in every translation unit in which it is used.
4 An inline function shall be defined in every translation unit in which it is used and shall have exactly
the same definition in every case (3.2). [ Note: a call to the inline function may be encountered before its
definition appears in the translation unit. —end note ] If the definition of a function appears in a translation
unit before its first declaration as inline, the program is ill-formed. If a function with external linkage is
declared inline in one translation unit, it shall be declared inline in all translation units in which it appears;
no diagnostic is required. An inline function with external linkage shall have the same address in all
translation units. A static local variable in an extern inline function always refers to the same object.
A string literal in the body of an extern inline function is the same object in different translation units.
[ Note: A string literal appearing in a default argument expression is not in the body of an inline function
merely because the expression is used in a function call from that inline function. —end note ] A type
defined within the body of an extern inline function is the same type in every translation unit.
[Note: Emphasis mine]
A TU is basically a set of headers plus an implementation file (.cpp) which leads to an object file.
Should it be explicitly stated when you have a small function (I
guess 1-4 instructions?)
Absolutely. Why not help the compiler help you generate less code? Usually, if the prolog/epilog part incurs more cost than having it inline force the compiler to generate them? But you must, absolutely must go through this GOTW article before getting started with inlining: GotW #33: Inline
What other benefits are there with writing inline?
namespaces can be inline too. Note that member functions defined in the class body itself are inline by default. So are implicitly generated special member functions.
Function templates cannot be defined in an implementation file (see FAQ 35.12) unless of course you provide a explicit instantiations (for all types for which the template is used -- generally a PITA IMO). See the DDJ article on Moving Templates Out of Header Files (If you are feeling weird read on this other article on the export keyword which was dropped from the standard.)
Is it needed to state inline in order to reduce the executable file
size, even though the compiler
(according to wikipedia [I know, bad
reference]) should find such functions
itself?
Again, as I said, as a good programmer, you should, when you can, help the compiler. But here's what the C++ FAQ has to offer about inline. So be wary. Not all compilers do this sort of analysis so you should read the documentation on their optimization switches. E.g: GCC does something similar:
You can also direct GCC to try to integrate all “simple enough” functions into their callers with the option -finline-functions.
Most compilers allow you to override the compiler's cost/benefit ratio analysis to some extent. The MSDN and GCC documentation is worth reading.
Is inline just a recommendation for the compiler?
Yes. But the linker needs it if there are multiple definitions of the function (see below)
Should it be explicitly stated when you have a small function (I guess 1-4 instructions?)
On functions that are defined in header files it is (usually) needed. It does not hurt to add it to small functions (but I don't bother). Note class members defined within the class declaration are automatically declared inline.
What other benefits are there with writing inline?
It will stop linker errors if used correctly.
is it needed to state inline in order to reduce the executable file size, even though the compiler (according to wikipedia [I know, bad reference]) should find such functions itself?
No. The compiler makes a cost/benefit comparison of inlining each function call and makes an appropriate choice. Thus calls to a function may be inlined in curtain situations and not inlined in other (depending on how the compilers algorithm works).
Speed/Space are two competing forces and it depends what the compiler is optimizing for which will determine weather functions are inlined and weather the executable will grow or shrink.
Also note if excessively aggressive inlining is used causing the program to expand too much, then locality of reference is lost and this can actually slow the program down (as more executable pages need to be brought into memory).
Multiple definition:
File: head.h
// Without inline the linker will choke.
/*inline*/ int add(int x, int y) { return x + y; }
extern void test()
File: main.cpp
#include "head.h"
#include <iostream>
int main()
{
std::cout << add(2,3) << std::endl;
test();
}
File: test.cpp
#include "head.h"
#include <iostream>
void test()
{
std::cout << add(2,3) << std::endl;
}
Here we have two definitions of add(). One in main.o and one in test.o
Yes. It's nothing more.
No.
You hint the compiler that it's a function that gets called a lot, where the jump-to-the-function part takes a lot of the execution time.
The compiler might decide to put the function code right where it gets called instead where normal functions are. However, if a function is inlined in x places, you need x times the space of a normal function.
Always trust your compiler to be much smarter than yourself on the subject of premature micro-optimization.
Actually, inline function may increase executable size, because inline function code is duplicated in every place where this function is called. With modern C++ compilers, inline mostly allows to programmer to believe, that he writes high-performance code. Compiler decides itself whether to make function inline or not. So, writing inline just allows us to feel better...
With regards to this:
And "inline" allows you to define the function multiple times in the program.
I can think of one instance where this is useful: Making copy protection code harder to crack. If you have a program that takes user information and verifies it against a registration key, inlining the function that does the verification will make it harder for a cracker to find all duplicates of that function.
As to other points:
inline is just a recommendation to compiler, but there are #pragma directives that can force inlining of any function.
Since it's just a recommendation, it's probably safe to explicitly ask for it and let the compiler override your recommendation. But it's probably better to omit it altogether and let the compiler decide.
The obfuscation mentioned above is one possible benefit of inlining.
As others have mentioned, inline would actually increase the size of the compiled code.
Yes, it will readily ignore it when it thinks the function is too large or uses incompatible features (exception handling perhaps). Furthermore, there is usually a compiler setting to let it automatically inline functions that it deems worthy (/Ob2 in MSVC).
It should be explicitly stated if you put the definition of the function in the header file. Which is usually necessary to ensure that multiple translation units can take advantage of it. And to avoid multiple definition errors. Furthermore, inline functions are put in the COMDAT section. Which tells the linker that it can pick just one of the multiple definitions. Equivalent to __declspec(selectany) in MSVC.
Inlined functions don't usually make the executable smaller. Since the call opcode is typically smaller than the inlined machined code, except for very small property accessor style functions. It depends but bigger is not an uncommon outcome.
Another benefit of in-lining (note that actual inlining is sometimes orthogonal to use of the "inline" directive) occurs when a function uses reference parameters. Passing two variables to a non-inline function to add its first operand to the second would require pushing the value of the first operand and the address of the second and then calling a function which would have to pop the first operand and address of the second, and then add the former value indirectly to the popped address. If the function were expanded inline, the compiler could simply add one variable to the other directly.
Actually inlining leads to bigger executables, not smaller ones.
It's to reduce one level of indirection, by pasting the function code.
http://www.parashift.com/c++-faq-lite/inline-functions.html

Does defining a function inside a header always make the compiler treat it as inline?

I just learned that defining a c++ function inside a class's header file make the function inline. But I know that putting the inline keyword next to a function is only a suggestion and the compiler wont necessarily follow it. Is this the same for header defined c++ functions and is there a difference in behavior between a standalone c++ function and a c++ function that is part of a class?
"defining a c++ function inside a class's header file make the function inline"
That's not true. Defining a function (that is to say, providing the body of the function instead of just a declaration) inside a class definition makes it inline. By "makes it inline", I mean it's the same as giving it the inline keyword. But class definitions don't have to be in headers, and headers can contain other things than class definitions.
So in this example, the function foo is implicitly inline. The function bar is not implicitly inline:
struct Foo {
void foo() {}
void bar();
};
void Foo::bar() {}
"putting the inline keyword next to a function is only a suggestion and the compiler wont necessarily follow it"
inline has two effects. One of them is a hint to the compiler which it can ignore. The other is not optional, and always has its effect. The "hint" is that the compiler is advised to replace calls to that function with a copy of the code for the function itself.
The guaranteed effect is that an inline function can be defined in multiple translation units, and those be linked together, without a multiple definition error, and all but one of the copies is removed by the linker. So, if the example above appears in a header file which is shared between multiple translation units, bar needs to be explicitly marked inline. Otherwise, the linker will discover multiple definitions of bar, which is not allowed.
Despite the name, inline in C++ is mostly about the second, compulsory effect, not the first, optional one. Modern optimising compilers have their own ideas about which calls should be inlined, and don't pay a whole lot of attention to inline when making that decision. For instance I've seen it have an effect in gcc at moderate optimisation levels, but at low levels approximately nothing is inlined, and at high levels approximately everything is (if the definition is available when the call is compiled) unless it makes the function too big.
Whether a function is defined in a header or in a cpp file has absolutely no effect on anything by itself. You can safely imagine that what #include does is copy and paste the header file into the cpp file in the preprocessor, before the compiler ever sees it. If a function is defined in the same translation unit as a call to it, then the function code is available to be inlined by the compiler. If they're in different translation units, then the code is not available and the call can only be inlined by the linker, with whole-program optimisation or similar. A "translation unit" more or less means, "a cpp file, after all the headers have been copy and pasted into it".
C++ compilers are free to choose what will be inline and what won't, no matter what hints you give them. It shouldn't matter if the function is part of a class or not, or whether it is in a header file or source file; the compiler doesn't pay attention to those things while making its decision.
No, not always. The compiler treats it as a hint, just like the inline keyword, but it mostly decides on its own, because it knows better than you what the costs and benefits may be. Inlining the code avoids the function call overhead, but makes the code bigger, which has negative performance impacts on the instruction cache.
These performance hints from the programmer are generally more and more often ignored by the compiler. What it does not ignore (or rather, what the linker does not ignore) is that a function declared inline may appear in several compilation units, and should be treated as multiple copies of the same function without resulting in linker errors.
If you place the definition of a free non-template function in a header file, you will end up with a function definition in each .cpp file that includes the header (directly or indirectly). This can lead to problems when linking.
However, if you declare the function to be inline, the linker will make sure you only use a single definition even if it is included at multiple places.