In my program I have a CImage that gets saved to a .bmp file on the hard drive. How can I have my program automatically open that picture in Windows Photo Viewer?
If you want the default program for that file type/extension to open the file, then you will have to open a shell and tell it to open the program for that file type.
See: How can you open a file with the program associated with its file extension? for more details.
You should just run the program, and probably give path to the file you want to open through command line parameters. It really depnds on the program you want to run.
On Linux, to start a program, you should use fork / exec pair. On Windows, you use CreateProcess
This question is old but I was also looking for the same and got the answer.
Hope it will be helpful for others also.
::ShellExecute(NULL,L"open",_T("rundll32.exe"),_T("shimgvw.dll,ImageView_Fullscreen picture.bmp"),NULL,SW_SHOWNORMAL);
This will open the picture in Windows Default Photo Viewer.
at the place of picture.bmp you need to pass full path of the picture/image like D:\\picture.bmp.
Related
If this has already been answered elsewhere, I'm sorry, I couldn't find it.
I have an interesting problem whereby I have a compiled program, prog.exe, which reads a file prog.cfg which contains the config. If I open prog.exe by double-clicking on it, everything's good. However, if I open it from a command line or batch file, I first have to set the directory. For example, if I have my program in a progs folder on the desktop, and from the desktop run progs\prog.exe, it doesn't load the config because it's looking for the config on the desktop ie in the current working directory.
This is fine if you know about it, but it's just another hoop for users to jump through. Is there a way in c++ to backtrack to the command used to launch the program to deduce whether the config file will be in the current working directory or not?
Alternatively, am I asking completely the wrong question?
Many thanks!
You can use GetModuleFileName(nullptr, buf, bufsize) to get a path to the executable.
Note that the standard main function's argv[0] is not guaranteed to provide that path, and when it provides a path, is not guaranteed to provide a programmatically usable representation of the path.
if i understand you correctly, you always want your .exe read your .cfg file from the folder your .exe located? right?
try argv[0].
argv[0] is your full .exe path when you run your exe, and it is a parameter of main function.
What I'm trying to do is basically:
./myProgram < myData.txt
While I'm debugging with CLion IDE. I just can't find the option to do so.
A similar question - but product-specific to MSVS
I had the same problem and it seems that CLion is not handling standard inputs yet.
I got around this problem by changing the input stream before running my program.
As an example if you want to input a file stream inside your stdin you can write in your main:
std::ifstream in("ABSOLUTE_PATH_TO_YOUR_FILE");
std::cin.rdbuf(in.rdbuf());
Then you can find a way to toggle this stream change when you want. Note that for files you will need to provide absolute path since the application is run from a different directory than the current one.
I hope this can help until CLion provides a real solution.
Assuming your input file is myData.txt, you can reopen/reuse the stdin stream using freopen
freopen("myData.txt","r",stdin);
if you want to do the same with your output:
freopen("myOutput.txt","w",stdout);
this will work for std::cin, printf, etc...
You can find more information about this here: http://www.cplusplus.com/reference/cstdio/freopen/
By the way, there is already a feature request for this. If you are interested, you can vote here so it gets prioritized:
https://youtrack.jetbrains.com/issue/CPP-3153
As of CLion 2020.1 this feature is built in:
Input redirection
If you need to redirect input from a file to the
stdin of your application, you can now do that. Use a new field in the
configuration called Redirect input from. Enter:
A relative path (CLion will prepend with the Working directory path).
An absolute path (will be remapped for remote configurations).
Or macros (like FilePrompt).
Still Clion don't have the feature like pycharm where we can give input in terminal while debugging the code.
But it has an option to give input through a .txt file while debugging.
Image of debug setting window
Click the setting icon in the debug console (on upper left corner) to open the setting of debugging. Then check the "Redirect input from" box and select the input file path and click "OK".
Here you go!
Now you can give input from the text file while debugging the code.
For me, CLion creates the executable in a file called 'cmake-build-debug'. Check out my file structure in the pic.
Then, I just opened up my terminal and went to the directory containing the executable and used this command to pipe in the text file:
./FirstProject < ../hw1.txt
I was wondering how to open a file other than notepad... Our prof gave us an example:
s = "notepad.exe test.txt";
system(s.c_str());
That will open a file type of "notepad.exe" and the file name of "test.txt"
Main Question:
Now, I was wondering if there was a way to open other type of files, such as Microsoft Excel, Microsoft Word, Visual Studio, or 7zip.
My attempt opened something in a new cmd.exe (because of the START keyword):
fileNeededtoBeOpened = "START \"New Microsoft Office Excel Worksheet.xlsx\"";
system(fileNeededtoBeOpened.c_str());
(This code is slightly different from my original, where I'm trying to open a file from a vector...) but all I really need to know is instead of "notepad.exe" or "START" is there a different command to open different file types that aren't .txt
Also, a side note, I was reading on the internet that it wasn't safe to use system() to open files, is this correct?
I found the answer by myself... for those who are curious, here an the answers:
To open a text file: system(notepad)
To open an excel file: system(start excel)
To open a word doc file: system(start winword)
To open a 7z file: system(start 7zFM)
To open a visual studio file: system(start devenv)
I think you're confused.
System executes a command as you would on the command line (type cmd into the run prompt under start menu to get that).
So, when you type notepad.exe test.txt it's saying:
Open the program notepad.exe which is on the system path (so the
command line can find it to execute that program), and pass the
parameter test.txt to it.
Notepad itself decides what to do with test.txt, in this case it opens it.
So, you can tell it to run any command (program/executable) and pass any parameters to it in reality. If excel's on your system path, you can probably just type excel.exe to open it from your system command. Otherwise, find the location excel is installed in, and refer to it with the whole path to excel.exe and it will work fine.
For example, on my computer, executing "C:\Program Files\Microsoft Office\Office12\EXCEL.EXE" would open excel from the command line. I can pass further parameters to it by having more information (like filenames) after the Excel.exe" portion, just as you did in your notepad example. Using your system command should have equivilent behavior when that line is executed.
If you are only targeting Windows systems you can use the ShellExecuteEx function (part of the Win32 API). You can just pass a filename to it and it will launch what ever program is registered to handle that file type (just as if you opened the file from windows explorer). Documentation is available on MSDN:
http://msdn.microsoft.com/en-us/library/windows/desktop/bb762154(v=vs.85).aspx
There is some examples on Launching Applications (ShellExecute, ShellExecuteEx, SHELLEXECUTEINFO) MSDN article and lots more elsewhere around the internet.
AS the other guys mentioned , the System function only executes a cmd command, .. notepad.exe is in the system's path by default so it works directly
but for example for me if I want to open a zip file on my desktop , I'd type something like
"C:\Program Files\7-Zip\7zFM.exe" Desktop\zipfile.zip
that's when I'm currently at the my user's directory [by default] , or
"C:\Program Files\7-Zip\7zFM.exe" C:\Users\JiMMaR\Desktop\zipfile.zip
[where JiMMaR is my user name on windows 7]
note that this certain command works only on windows , if you are using another OS this won't work as it is
try doing a
fileNeededtoBeOpened = "\"C:\Program Files\7-Zip\7zFM.exe\" C:\Users\YOUR_USER_NAME\Desktop\zipfile.zip";
and see if that executes or not
edit:
if you cannot escape the space , then try this one
fileNeededtoBeOpened = "C:\Program~1\7-Zip\7zFM.exe C:\Users\YOUR_USER_NAME\Desktop\zipfile.zip";
Ok, firstly - system - is a function that starts a separate process to your program. Much the same as in a command window when you type the command. The command lines you provide will be dependent on the applications you want to launch.
Now, I was wondering if there was a way to open other type of files,
such as Microsoft Excel, Microsoft Word, Visual Studio, or 7zip.
Yes I would be pretty shocked if there wasn't a command line parameter you could specify to load a document in these apps at start up. (Ok not shocked, but it is pretty standard)
Does this have anything to do with c++ - not really - you need to look at references for the applications you mention and see what the command lines parameters are for them. Then craft a string and system(...) to your hearts content.
I have 2 questions to ask regarding opening files (any kind of files) using C++. I am currently working on a GUI program and I want to add a changelog in txt form. Also I want a menu in my program to open that changelog.txt with the default text editor every user has installed or to simply put it to open that text file. Please keep in mind that I want to open the file for display NOT in the program for input/output.I know I can do that using
system("notepad.exe filepath.txt");
or to open them with the preset program:
system("filepath.txt");
The problem is that both of those open a command line behind the notepad. I know there is another command to open files using Win32 API called CreateProccess() but my compiler doesn't recognise that command (OpenWatcom W32).
So here are my questions:
1) Is there any other command to open files or is there a way to stop the command line from opening when using system command?
2) How do you define in Windows that the text file is in the current program folder? I mean instead of giving the entire filepath which will change from user to user is there any way to "tell" the program that the file is always on the current folder that the program is in?
I am sorry for any errors, if you want any clarification please let me know.
CreateProcess would be the wrong function to use here. That would require you to decide which process to run. The user may prefer to use a text editor other than Notepad, I know I do! The right way to do this on Windows is to ask the shell to open the file with whatever program the user has associated with the file. The ShellExecute function does this.
Call it like this:
ShellExecute(
MainWindowHandle,
"open",
FullyQualifiedTextFileName,
NULL,
NULL,
SW_SHOWNORMAL
);
You will need to include the Shellapi.h header file and link to the Shell32.lib library. If your compiler does not include these files, and I would be surprised if that was the case, then you can get them from the Platform SDK. That said, if you are serious about programming on Windows you should get hold of a tool that gives you access to the Windows API.
I do recommend that you use a fully qualified path for a task like this. Since your text file is located in the same directory as the executable you should simply join that directory to your text file's name. Get hold of the full path to the executable by calling GetModuleFileName passing NULL for the hModule parameter.
I am using Borland Builder C++ 2009. I want to add a button to a form that allows the user to open a file in Excel that I specify. I can't think of how to do this. I know how to link with other code and executables -- is there a Microsoft Excel executable that I could use? How could I specify the file then? Any hints on this, or at least a place to look online, would be greatly appreciated.
Assuming that the file type is registered with Excel, you could call ShellExecute() on the file, using the "open" verb. This will cause the file to be opened as if double clicked by the user in Explorer and will invoke Excel.
If that isn't the case, and you can assume that Excel is installed, you could instead pass "excel" to ShellExecute() as the application, and the path of the file as the parameter. (Note that I didn't test this, but it worked from the Run dialog, so I think that it should work from ShellExecute() as well).
Thanks, Andy. I am using ShellExecute() as you suggested, giving Excel as the application and the path of the file as the parameter. It works to open Excel, however, it cannot seem to find the file. I have tried moving the file around, typing in the entire path, part of the path with no change. Here is the code I use:
ShellExecute(NULL, "open" ,"Excel.exe", "C:\\Documents and Settings\\Lab1\\My Documents\\Waypoint Tool.xls", NULL, SW_SHOWNORMAL);
So, I need to figure out why it isn't able to find this file.
Thank you for the suggestion to use ShellExecute though. I think I am on the right track!
Try:
print("ShellExecute(NULL, "open" ,"Waypoint Tool.xls", "C:\\Documents and Settings\\Lab1\\My Documents\\", NULL, SW_SHOWNORMAL);");
Looking at this page: http://msdn.microsoft.com/en-us/library/bb762153(VS.85).aspx
It seems like it wants the file you are wanted to execute the open on as the third parameter and the directory for the fourth.
System() command should be enough i think.
For any Windows application, we can open any file using the Location of .exe file and the File Path.
Eg.,
system("PATH C:\\Program\ Files\\Microsoft\ Office\\OFFICE11;%PATH% & excel \"C:\\Documents and Settings\\User\\Desktop\\ExcelFile.xls\"");