Fortran: output large array - exceeded length, split on two lines - fortran

In a Fortran program, I need to write an array into a file with a specific format.
I perfectly works for smaller array (e.g. alen=10 in the example below), but won't work for bigger arrays: it then splits each line into two, as if a maximum number of characters per line was exceeded.
Example (very similar to the structure in my program):
PROGRAM output_probl
IMPLICIT NONE
INTEGER, PARAMETER :: alen=110
DOUBLE PRECISION, DIMENSION(alen)::a
INTEGER :: i,j
OPEN(20,file='output.dat')
30 format(I5,1x,110(e14.6e3,1x))
DO i=1,15
DO j=1,alen
a(j)=(i*j**2)*0.0123456789
ENDDO
write(20,30)i,(a(j),j=1,alen)
ENDDO
END PROGRAM output_probl
It compiles and runs properly (with Compaq Visual Fortran). Just the output file is wrong. If I for example change the field width per array item from 14 to 8, it'll work fine (this is of course not a satisfactory solution).
I thought about an unsuitable default maximum record length, but can't find how to change it (even with RECL which doesn't seem to work - if you think it should, a concrete example with RECL is welcome).
This might be basic, but I've been stuck with it for some time... Any help is welcome, thanks a lot!

Why not stream access? With sequential there is allways some processor dependent record length limit.
PROGRAM output_probl
IMPLICIT NONE
INTEGER, PARAMETER :: alen=110
DOUBLE PRECISION, DIMENSION(alen)::a
INTEGER :: i,j
OPEN(20,file='output.dat',access='stream', form='formatted',status='replace')
30 format(I5,1x,110(e14.6e3,1x))
DO i=1,15
DO j=1,alen
a(j)=(i*j**2)*0.0123456789
ENDDO
write(20,30)i,(a(j),j=1,alen)
ENDDO
END PROGRAM output_probl
As a note, I would use a character variable for the format string, or place it directly in the write statement, instead of the FORMAT statement with a label.
Fortran 95 version:
PROGRAM output_probl
IMPLICIT NONE
INTEGER, PARAMETER :: alen=110
DOUBLE PRECISION, DIMENSION(alen)::a
INTEGER :: i,j,rl
character(2000) :: ch
inquire(iolength=rl) ch
OPEN(20,file='output.dat',access='direct', form='unformatted',status='replace',recl=rl)
30 format(I5,1x,110(e14.6e3,1x))
DO i=1,15
DO j=1,alen
a(j)=(i*j**2)*0.0123456789
ENDDO
write(ch,30)i,(a(j),j=1,alen)
ch(2000:2000) = achar(10)
write(20,rec=i) ch
ENDDO
END PROGRAM output_probl

The program below should test. With Absoft compiler it works fine for n=10000, 10 character words, that is a line 100000 characters wide (plus a couple) in all. With G95 I get a message "Not enough storage is available to process this command" for n=5000 (n=4000 works).
character*10,dimension(:),allocatable:: test
integer,dimension(:),allocatable::itest
1 write(,)'Enter n > 0'
read , n
if(n.le.0) then
write(,)'requires value n > 0'
go to 1
endif
write(,*)'n=',n
allocate(test(n),itest(n))
write(test,'((i10))')(i,i=1,n)
write(*,*)test
open(10,file='test.txt')
write(10,*)test
write(*,*)'file test.txt written'
close(10)
open(11,file='test.txt')
read(11,*)itest
write(*,*)itest
end

Related

How to send command line input to a Fortran subroutine? [duplicate]

GCC version 4.6
The Problem: To find a way to feed in parameters to the executable, say a.out, from the command line - more specifically feed in an array of double precision numbers.
Attempt: Using the READ(*,*) command, which is older in the standard:
Program test.f -
PROGRAM MAIN
REAL(8) :: A,B
READ(*,*) A,B
PRINT*, A+B, COMMAND_ARGUMENT_COUNT()
END PROGRAM MAIN
The execution -
$ gfortran test.f
$ ./a.out 3.D0 1.D0
This did not work. On a bit of soul-searching, found that
$./a.out
3.d0,1.d0
4.0000000000000000 0
does work, but the second line is an input prompt, and the objective of getting this done in one-line is not achieved. Also the COMMAND_ARGUMENT_COUNT() shows that the numbers fed into the input prompt don't really count as 'command line arguments', unlike PERL.
If you want to get the arguments fed to your program on the command line, use the (since Fortran 2003) standard intrinsic subroutine GET_COMMAND_ARGUMENT. Something like this might work
PROGRAM MAIN
REAL(8) :: A,B
integer :: num_args, ix
character(len=12), dimension(:), allocatable :: args
num_args = command_argument_count()
allocate(args(num_args)) ! I've omitted checking the return status of the allocation
do ix = 1, num_args
call get_command_argument(ix,args(ix))
! now parse the argument as you wish
end do
PRINT*, A+B, COMMAND_ARGUMENT_COUNT()
END PROGRAM MAIN
Note:
The second argument to the subroutine get_command_argument is a character variable which you'll have to parse to turn into a real (or whatever). Note also that I've allowed only 12 characters in each element of the args array, you may want to fiddle around with that.
As you've already figured out read isn't used for reading command line arguments in Fortran programs.
Since you want to read an array of real numbers, you might be better off using the approach you've already figured out, that is reading them from the terminal after the program has started, it's up to you.
The easiest way is to use a library. There is FLAP or f90getopt available. Both are open source and licensed under free licenses.
The latter is written by Mark Gates and me, just one module and can be learned in minutes but contains all what is needed to parse GNU- and POSIX-like command-line options. The first is more sophisticated and can be used even in closed-source projects. Check them out.
Furthermore libraries at https://fortranwiki.org/fortran/show/Command-line+arguments
What READ (*,*) does is that it reads from the standard input. For example, the characters entered using the keyboard.
As the question shows COMMAND_ARGUMENT_COUNT() can be used to get the number of the command line arguments.
The accepted answer by High Performance Mark show how to retrieve the individual command line arguments separated by blanks as individual character strings using GET_COMMAND_ARGUMENT(). One can also get the whole command line using GET_COMMAND(). One then has to somehow parse that character-based information into the data in your program.
I very simple cases you just need the program requires, for example, two numbers, so you read one number from arg 1 and another form arg 2. That is simple. Or you can read a triplet of numbers from a single argument if they are comma-separated like 1,2,3 using a simple read(arg,*) nums(1:3).
For general complicated command line parsing one uses libraries such as those mentioned in the answer by Hani. You have set them up so that the library knows the expected syntax of the command line arguments and the data it should fill with the values.
There is a middle ground, that is still relatively simple, but one already have multiple arguments, that correspond to Fortran variables in the program, that may or may not be present. In that case one can use the namelist for the syntax and for the parsing.
Here is an example, the man point is the namelist /cmd/ name, point, flag:
implicit none
real :: point(3)
logical :: flag
character(256) :: name
character(1024) :: command_line
call read_command_line
call parse_command_line
print *, point
print *, "'",trim(name),"'"
print *, flag
contains
subroutine read_command_line
integer :: exenamelength
integer :: io, io2
command_line = ""
call get_command(command = command_line,status = io)
if (io==0) then
call get_command_argument(0,length = exenamelength,status = io2)
if (io2==0) then
command_line = "&cmd "//adjustl(trim(command_line(exenamelength+1:)))//" /"
else
command_line = "&cmd "//adjustl(trim(command_line))//" /"
end if
else
write(*,*) io,"Error getting command line."
end if
end subroutine
subroutine parse_command_line
character(256) :: msg
namelist /cmd/ name, point, flag
integer :: io
if (len_trim(command_line)>0) then
msg = ''
read(command_line,nml = cmd,iostat = io,iomsg = msg)
if (io/=0) then
error stop "Error parsing the command line or cmd.conf " // msg
end if
end if
end subroutine
end
Usage in bash:
> ./command flag=T name=\"data.txt\" point=1.0,2.0,3.0
1.00000000 2.00000000 3.00000000
'data.txt'
T
or
> ./command flag=T name='"data.txt"' point=1.0,2.0,3.0
1.00000000 2.00000000 3.00000000
'data.txt'
T
Escaping the quotes for the string is unfortunately necessary, because bash eats the first quotes.

How do I skip lines when some conditions are met with Fortran? [duplicate]

It is my understanding that Fortran, when reading data from file, will skip lines starting with and asterisk (*) assuming that they are a comment. Well, I seem to be having a problem with achieving this behavior with a very simple program I created. This is my simple Fortran program:
1 program test
2
3 integer dat1
4
5 open(unit=1,file="file.inp")
6
7 read(1,*) dat1
8
9
10 end program test
This is "file.inp":
1 *Hello
2 1
I built my simple program with
gfortran -g -o test test.f90
When I run, I get the error:
At line 7 of file test.f90 (unit = 1, file = 'file.inp')
Fortran runtime error: Bad integer for item 1 in list input
When I run the input file with the comment line deleted, i.e.:
1 1
The code runs fine. So it seems to be a problem with Fortran correctly interpreting that comment line. It must be something exceedingly simple I'm missing here, but I can't turn up anything on google.
Fortran doesn't automatically skip comments lines in input files. You can do this easily enough by first reading the line into a string, checking the first character for your comment symbol or search the string for that symbol, then if the line is not a comment, doing an "internal read" of the string to obtain the numeric value.
Something like:
use, intrinsic :: iso_fortran_env
character (len=200) :: line
integer :: dat1, RetCode
read_loop: do
read (1, '(A)', isostat=RetCode) line
if ( RetCode == iostat_end) exit ReadLoop
if ( RetCode /= 0 ) then
... read error
exit read_loop
end if
if ( index (line, "*") /= 0 ) cycle read_loop
read (line, *) dat1
end do read_loop
Fortran does not ignore anything by default, unless you are using namelists and in that case comments start with an exclamation mark.
I found the use of the backspace statement to be a lot more intuitive than the proposed solutions. The following subroutine skips the line when a comment character, "#" is encountered at the beginning of the line.
subroutine skip_comments(fileUnit)
integer, intent(in) :: fileUnit
character(len=1) :: firstChar
firstChar = '#'
do while (firstChar .eq. '#')
read(fileUnit, '(A)') firstChar
enddo
backspace(fileUnit)
end subroutine skip_comments
This subroutine may be used in programs before the read statement like so:
open(unit=10, file=filename)
call skip_comments(10)
read(10, *) a, b, c
call skip_comments(10)
read(10, *) d, e
close(10)
Limitations for the above implementation:
It will not work if the comment is placed between the values of a variable spanning multiple lines, say an array.
It is very inefficient for large input files since the entire file is re-read from the beginning till the previous character when the backspace statement is encountered.
Can only be used for sequential access files, i.e. typical ASCII text files. Files opened with the direct or append access types will not work.
However, I find it a perfect fit for short files used for providing user-parameters.

Command line arguments in fortran (a filename, an integer, and another filename) [duplicate]

GCC version 4.6
The Problem: To find a way to feed in parameters to the executable, say a.out, from the command line - more specifically feed in an array of double precision numbers.
Attempt: Using the READ(*,*) command, which is older in the standard:
Program test.f -
PROGRAM MAIN
REAL(8) :: A,B
READ(*,*) A,B
PRINT*, A+B, COMMAND_ARGUMENT_COUNT()
END PROGRAM MAIN
The execution -
$ gfortran test.f
$ ./a.out 3.D0 1.D0
This did not work. On a bit of soul-searching, found that
$./a.out
3.d0,1.d0
4.0000000000000000 0
does work, but the second line is an input prompt, and the objective of getting this done in one-line is not achieved. Also the COMMAND_ARGUMENT_COUNT() shows that the numbers fed into the input prompt don't really count as 'command line arguments', unlike PERL.
If you want to get the arguments fed to your program on the command line, use the (since Fortran 2003) standard intrinsic subroutine GET_COMMAND_ARGUMENT. Something like this might work
PROGRAM MAIN
REAL(8) :: A,B
integer :: num_args, ix
character(len=12), dimension(:), allocatable :: args
num_args = command_argument_count()
allocate(args(num_args)) ! I've omitted checking the return status of the allocation
do ix = 1, num_args
call get_command_argument(ix,args(ix))
! now parse the argument as you wish
end do
PRINT*, A+B, COMMAND_ARGUMENT_COUNT()
END PROGRAM MAIN
Note:
The second argument to the subroutine get_command_argument is a character variable which you'll have to parse to turn into a real (or whatever). Note also that I've allowed only 12 characters in each element of the args array, you may want to fiddle around with that.
As you've already figured out read isn't used for reading command line arguments in Fortran programs.
Since you want to read an array of real numbers, you might be better off using the approach you've already figured out, that is reading them from the terminal after the program has started, it's up to you.
The easiest way is to use a library. There is FLAP or f90getopt available. Both are open source and licensed under free licenses.
The latter is written by Mark Gates and me, just one module and can be learned in minutes but contains all what is needed to parse GNU- and POSIX-like command-line options. The first is more sophisticated and can be used even in closed-source projects. Check them out.
Furthermore libraries at https://fortranwiki.org/fortran/show/Command-line+arguments
What READ (*,*) does is that it reads from the standard input. For example, the characters entered using the keyboard.
As the question shows COMMAND_ARGUMENT_COUNT() can be used to get the number of the command line arguments.
The accepted answer by High Performance Mark show how to retrieve the individual command line arguments separated by blanks as individual character strings using GET_COMMAND_ARGUMENT(). One can also get the whole command line using GET_COMMAND(). One then has to somehow parse that character-based information into the data in your program.
I very simple cases you just need the program requires, for example, two numbers, so you read one number from arg 1 and another form arg 2. That is simple. Or you can read a triplet of numbers from a single argument if they are comma-separated like 1,2,3 using a simple read(arg,*) nums(1:3).
For general complicated command line parsing one uses libraries such as those mentioned in the answer by Hani. You have set them up so that the library knows the expected syntax of the command line arguments and the data it should fill with the values.
There is a middle ground, that is still relatively simple, but one already have multiple arguments, that correspond to Fortran variables in the program, that may or may not be present. In that case one can use the namelist for the syntax and for the parsing.
Here is an example, the man point is the namelist /cmd/ name, point, flag:
implicit none
real :: point(3)
logical :: flag
character(256) :: name
character(1024) :: command_line
call read_command_line
call parse_command_line
print *, point
print *, "'",trim(name),"'"
print *, flag
contains
subroutine read_command_line
integer :: exenamelength
integer :: io, io2
command_line = ""
call get_command(command = command_line,status = io)
if (io==0) then
call get_command_argument(0,length = exenamelength,status = io2)
if (io2==0) then
command_line = "&cmd "//adjustl(trim(command_line(exenamelength+1:)))//" /"
else
command_line = "&cmd "//adjustl(trim(command_line))//" /"
end if
else
write(*,*) io,"Error getting command line."
end if
end subroutine
subroutine parse_command_line
character(256) :: msg
namelist /cmd/ name, point, flag
integer :: io
if (len_trim(command_line)>0) then
msg = ''
read(command_line,nml = cmd,iostat = io,iomsg = msg)
if (io/=0) then
error stop "Error parsing the command line or cmd.conf " // msg
end if
end if
end subroutine
end
Usage in bash:
> ./command flag=T name=\"data.txt\" point=1.0,2.0,3.0
1.00000000 2.00000000 3.00000000
'data.txt'
T
or
> ./command flag=T name='"data.txt"' point=1.0,2.0,3.0
1.00000000 2.00000000 3.00000000
'data.txt'
T
Escaping the quotes for the string is unfortunately necessary, because bash eats the first quotes.

Error in fortran, undefined reference to subroutine

I am writing a subroutine and main function to call it, but getting error as undefined reference to ___. I found one reason: When I save the main and subroutine in the same file, compile and run that file, everything runs perfectly. However, when I save them into different .f90 files and try to run the main file, I get error. Is there any way I can make subroutine into a separate file and call into main calling program?
I got confused with another place - in the main program at !------ERROR------ place. I referred to Automatic width integer descriptor in fortran 90 I can use I0 as automatic width display indicator. But when I used the same, there is run time error expected integer but got character. Any idea about this?
! saved as sub_program.f90 file
SUBROUTINE sub_program (v1,v2,ctr)
IMPLICIT NONE
INTEGER, INTENT(IN) :: ctr
INTEGER, INTENT (OUT) :: v1,v2
SELECT CASE (ctr)
CASE (1)
v1=1
v2=0
CASE (2)
v1=0
v2=1
END SELECT
RETURN
END SUBROUTINE
! main calling program, saved as caller.f90
PROGRAM caller
IMPLICIT NONE
INTEGER :: v1,v2,ctr
DO ctr = 1,2,1
CALL sub_program (v1,v2,ctr)
WRITE (*,100) 'STEP = ',ctr,'V1 = ',v1,'V2 = ',v2 !------ERROR------
100 FORMAT (I0)
END DO
END PROGRAM
Thanks!
What is your compile command? For me, this compiles and runs normally
gfortran caller.f90 foo.f90 && ./a.out
I0 is an integer indicator, but some items following your WRITE statement are character strings. You can try, for example,
100 FORMAT (3(A, I0, 1X))
where 1X refers to a space.
As a note, if formatting is not terribly important and you're only interested in seeing some quick results, you can use the free format output (WRITE(*,*) ...).
EDIT: I had incorrectly referred to FORMAT as obsolete.

mpi rank not valid in do loop

Im updating a program in fortran to run with MPI and have run into an issue with the rank not showing up properly. In the beginning of this subroutine I call MPI_COMM_RANK(MPI_COMM_WORLD,rank,ierr) and it returns the proper rank until this point:
DO IY=2,NY+1
DO IX=2,NX+1
D(IX,IY)=(h_roms(IX,IY)+zeta(IX,IY))*maskr(IX,IY)
call mpi_barrier(mpi_comm_world,ierr)
write(out,12) rank,ix,iy
12 format('disappearing?',i3,'ix:',i3,'iy',i3)
ENDDO
ENDDO
NY and NX are 124,84 respectively and the rank prints properly until iy becomes 125, and ix is 3. after that it only prints out as *** . IT still prints out everything twice (running on 2 processors) but the rank isn't valid, or giving any errors. Ive tried calling MPI_COMM_RANK after the do loop and still nothing. Any ideas would be much appreciated.
Fortran generally prints a sequence of asterisks, your ***, if a numeric output field is too small to contain the number you are trying to write into it. Try changing some of the i3s in the format statement to i6 or even i0; this last form tells the compiler to print an integer in a field wide enough for all its digits but no wider.