The original question that gave the idea behind this particular regex is Regex to find content not in quotes.
Let's just modify the original sample a little bit:
INSERT INTO Notifify (to_email, msg, date_log, from_email, ip_from)
VALUES
(
:to_email,
'test teste nonono',
:22,
:3mail,
:ip_from
)
I know that variables starting with numerals are not allowed in any programming language, but that doesn't mean we can't have scenarios where we need to match just :to_email or :3mail and :ip_from and not :22.
How do we proceed? Me and my friend tried it(theoretically only) this way ->
Store all string in a set
Subtract the set that contains only numbers
For online testing, I am using RegExr.
i don't know which programming language do you use, but why can't you just check if the line match:
^\s*:[0-9]+,?\s*$
and just take unmatched lines?
lookaheads will work here
\b(?=\d*[a-z])\w+\b
as will
\b\d*[a-z]\w*\b
Related
I'm using the following regex to find URLs in a text file:
/http[s]?://(?:[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+/
It outputs the following:
http://rda.ucar.edu/datasets/ds117.0/.
http://rda.ucar.edu/datasets/ds111.1/.
http://www.discover-earth.org/index.html).
http://community.eosdis.nasa.gov/measures/).
Ideally they would print out this:
http://rda.ucar.edu/datasets/ds117.0/
http://rda.ucar.edu/datasets/ds111.1/
http://www.discover-earth.org/index.html
http://community.eosdis.nasa.gov/measures/
Any ideas on how I should tweak my regex?
Thank you in advance!
UPDATE - Example of the text would be:
this is a test http://rda.ucar.edu/datasets/ds117.0/. and I want this to be copied over http://rda.ucar.edu/datasets/ds111.1/. http://www.discover-earth.org/index.html). http://community.eosdis.nasa.gov/measures/).
This will trim your output containing trail characters, ) .
import re
regx= re.compile(r'(?m)[\.\)]+$')
print(regx.sub('', your_output))
And this regex seems workable to extract URL from your original sample text.
https?:[\S]*\/(?:\w+(?:\.\w+)?)?
Demo,,, ( edited from https?:[\S]*\/)
Python script may be something like this
ss=""" this is a test http://rda.ucar.edu/datasets/ds117.0/. and I want this to be copied over http://rda.ucar.edu/datasets/ds111.1/. http://www.discover-earth.org/index.html). http://community.eosdis.nasa.gov/measures/). """
regx= re.compile(r'https?:[\S]*\/(?:\w+(?:\.\w+)?)?')
for m in regx.findall(ss):
print(m)
So for the urls you have here:
https://regex101.com/r/uSlkcQ/4
Pattern explanation:
Protocols (e.g. https://)
^[A-Za-z]{3,9}:(?://)
Look for recurring .[-;:&=+\$,\w]+-class (www.sub.domain.com)
(?:[\-;:&=\+\$,\w]+\.?)+`
Look for recurring /[\-;:&=\+\$,\w\.]+ (/some.path/to/somewhere)
(?:\/[\-;:&=\+\$,\w\.]+)+
Now, for your special case: ensure that the last character is not a dot or a parenthesis, using negative lookahead
(?!\.|\)).
The full pattern is then
^[A-Za-z]{3,9}:(?://)(?:[\-;:&=\+\$,\w]+\.?)+(?:\/[\-;:&=\+\$,\w\.]+)+(?!\.|\)).
There are a few things to improve or change in your existing regex to allow this to work:
http[s]? can be changed to https?. They're identical. No use putting s in its own character class
[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),] You can shorten this entire thing and combine character classes instead of using | between them. This not only improves performance, but also allows you to combine certain ranges into existing character class tokens. Simplifying this, we get [a-zA-Z0-9$-_#.&+!*\(\),]
We can go one step further: a-zA-Z0-9_ is the same as \w. So we can replace those in the character class to get [\w$-#.&+!*\(\),]
In the original regex we have $-_. This creates a range so it actually inclues everything between $ and _ on the ASCII table. This will cause unwanted characters to be matched: $%&'()*+,-./0123456789:;<=>?#ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_. There are a few options to fix this:
[-\w$#.&+!*\(\),] Place - at the start of the character class
[\w$#.&+!*\(\),-] Place - at the end of the character class
[\w$\-#.&+!*\(\),] Escape - such that you have \- instead
You don't need to escape ( and ) in the character class: [\w$#.&+!*(),-]
[0-9a-fA-F][0-9a-fA-F] You don't need to specify [0-9a-fA-F] twice. Just use a quantifier like so: [0-9a-fA-F]{2}
(?:%[0-9a-fA-F][0-9a-fA-F]) The non-capture group isn't actually needed here, so we can drop it (it adds another step that the regex engine needs to perform, which is unnecessary)
So the result of just simplifying your existing regex is the following:
https?://(?:[$\w#.&+!*(),-]|%[0-9a-fA-F]{2})+
Now you'll notice it doesn't match / so we need to add that to the character class. Your regex was matching this originally because it has an improper range $-_.
https?://(?:[$\w#.&+!*(),/-]|%[0-9a-fA-F]{2})+
Unfortunately, even with this change, it'll still match ). at the end. That's because your regex isn't told to stop matching after /. Even implementing this will now cause it to not match file names like index.html. So a better solution is needed. If you give me a couple of days, I'm working on a fully functional RFC-compliant regex that matches URLs. I figured, in the meantime, I would at least explain why your regex isn't working as you'd expect it to.
Thanks all for the responses. A coworker ended up helping me with it. Here is the solution:
des_links = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', des)
for i in des_links:
tmps = "/".join(i.split('/')[0:-1])
print(tmps)
I need to put together a regex that matches a patter only if string does not begin with 'N'.
Here is my pattern so far [A-E]+[-+]?.
Now I want to make sure that it does not match something like:
N\A
NA
NB+
NB-
NCAB
This is for REGEXP_SUBSTR command in Oracle SQL DB
UPDATE
It looks like I should have been more specific, sorry
I want to extract from a string [A-E]+[-+]? but if the string also matches ^(N|n) then I want my regex to return nothing.
See examples below:
String Returns
N/A
F1/AAA AAA
NABC
FABC ABC
To match a character between A and E not preceded by N, you can use:
([^N]|^)[A-E]+
If you want to avoid fields that contains N[A-E] use a negation in your query using the pattern N[A-E] (in other words, use two predicates, this one to exclude NA and the first to find A)
To be more clear:
WHERE NOT REGEXP_LIKE(coln, 'N[A-E]') AND REGEXP_LIKE(coln, '[A-E]')
Ok I figured it out, I broadened the scope of the problem a little, I realized that I can also play with other parameters of REGEXP_SUBSTR in this case that I can have returned only second substring.
REGEXP_SUBSTR(field1, '^([^NA-D][^A-D]*)?([A-D]+[-+]?)',1,1,'i',2)
I still have to give you guys the credit, lot of good ideas that led me to here.
Just throw a [^N]? in front. That should do it.
OOPS...
That actually needs to include an " OR ^ "...
It should look like this:
([^N]|^)[A-E]+[-+]?
Sorry about that...It looks like the right answer already got posted anyway.
I have a payload that contains the following:
����\�p�a�t�r�i�c�k�-�t�e�s�t�-�f�i�l�e�.�t�x�t������x�SMB2
I'm looking to extract the file name of patrick-test-file.txt
I can get close by using this, but it continues to include everything (including ascii characters)
[\\\\](.*?)x�SMB2
With a result of this: �p�a�t�r�i�c�k�-�t�e�s�t�-�f�i�l�e�.�t�x�t������ for the capture group.
How would I just match the characters of the file name, which could be anything of variable length, and could contain alphanumeric characters? Is this possible with pure regex?
Any help is much appreciated.
Sometimes you just can't do a single language-agnostic Regular Expression to accomplish something. And sometimes (usually) it is more performant to do a series of string functions.
I wouldn't personally accept any solution which has hard-coded values, such as x�SMB2.
If you want to use Regular Expressions only, you can first select the File-Name portion like so: (([-\w\d.\\]+)[^-\w\d.\\]?)+, then go ahead and replace [^-\w\d.\\] with nothing "".
Honestly, given the limited detail, the best function is like so:
var fileName = "\patrick-test-file.txt";
But half-joking aside, and with that limited detail, your best bet is to do a couple string functions:
var yuckyString = #"����\�p�a�t�r�i�c�k�-�t�e�s�t�-�f�i�l�e�.�t�x�t������x�SMB2";
var fileNameArea = yuckyString.Split(new[] { "��" }, StringSplitOptions.RemoveEmptyEntries)[0];
var fileName = fileNameArea.Replace("�", "");
Granted, there was no language listed, so I'm using C#. Also, the answer would change if there were irregularities with those special characters. With the limited info, the pattern seems clear.
I'm trying to search a field in a database to extract URLs. Sometimes there will be more than 1 URL in a field and I would like to extract those in to separate variables (or an array).
I know my regex isn't going to cover all possibilities. As long as I flag on anything that starts with http and ends with a space I'm ok.
The problem I'm having is that my efforts either seem to get only 1 URL per record or they get only 1 the last letter from each URL. I've tried a couple different techniques based on solutions other have posted but I haven't found a solution that works for me.
Sample input line:
Testing http://marko.co http://tester.net Just about anything else you'd like.
Output goal
$var[0] = http://marko.co
$var[1] = http://tester.net
First try:
if ( $status =~ m/http:(\S)+/g ) {
print "$&\n";
}
Output:
http://marko.co
Second try:
#statusurls = ($status =~ m/http:(\S)+/g);
print "#statusurls\n";
Output:
o t
I'm new to regex, but since I'm using the same regex for each attempt, I don't understand why it's returning such different results.
Thanks for any help you can offer.
I've looked at these posts and either didn't find what I was looking for or didn't understand how to implement it:
This one seemed the most promising (and it's where I got the 2nd attempt from, but it didn't return the whole URL, just the letter: How can I store regex captures in an array in Perl?
This has some great stuff in it. I'm curious if I need to look at the URL as a word since it's bookended by spaces: Regex Group in Perl: how to capture elements into array from regex group that matches unknown number of/multiple/variable occurrences from a string?
This one offers similar suggestions as the first two. How can I store captures from a Perl regular expression into separate variables?
Solution:
#statusurls = ($status =~ m/(http:\S+)/g);
print "#statusurls\n";
Thanks!
I think that you need to capture more than just one character. Try this regex instead:
m/http:(\S+)/g
I need some help with writing a regex validation to check for a specific value
here is what I have but it don't work
Regex exists = new Regex(#"MyWebPage.aspx");
Match m = exists.Match(pageUrl);
if(m)
{
//perform some action
}
So I basically want to know when variable pageUrl will contains value MyWebPage.aspx
also if possible to combine this check to cover several cases for instance MyWebPage.aspx, MyWebPage2.aspx, MyWebPage3.aspx
Thanks!
try this
"MyWebPage\d*\.aspx$"
This will allow for any pages called MyWebPage#.aspx where # is 1 or more numbers.
if (Regex.Match(url, "MyWebPage[^/]*?\\.aspx")) ....
This will match any form of MyWebPageXXX.aspx (where XXX is zero or more characters). It will not match MyWebPage/test.aspx however
That RegEx should work in the case that MyWebPage.aspx is in your pageUrl, albeit by accident. You really need to replace the dot (.) with \. to escape it.
Regex exists = new Regex(#"MyWebPage\.aspx");
If you want to optionally match a single number after the MyWebPage bit, then look for the (optional) presence of \d:
Regex exists = new Regex(#"MyWebPage\d?\.aspx");
I won't post a regex, as others have good ones going, but one thing that may be an issue is character case. Regexs are, by default, case-sensitive. The Regex class does have a static overload of the Match function (as well as of Matches and IsMatch) which takes a RegexOptions parameter allowing you to specify if you want to ignore case.
For example, I don't know how you are getting your pageUrl variable but depending on how the user typed the URL in their browser, you may get different casings, which could cause your Regex to not find a match.