How to exclude child elements in xml? - templates

Question

I have the following xml :
<?xml version="1.0" encoding="UTF-8"?>
<persons>
<person>
<phone type='home'>203-555-1212</phone>
<phone type='fax'>203-555-1212</phone>
<address type='home'>
<street>12 Main Street</street>
<city>Southbury</city>
<state>CT</state>
<zip>06488</zip>
</address>
<firstName>Charles</firstName>
<lastName>Smithington</lastName>
</person>
<person1>
<phone type='home'>58-99-44-999</phone>
<phone type='fax'>5788-9987-3365</phone>
<address type='home'>
<street>12 Main Street</street>
<city>Park Avenue</city>
<state>NY</state>
<zip>10025</zip>
</address>
<firstName>Mike</firstName>
<lastName>Shinoda</lastName>
</person1>
</persons>
Here i have to exclude the address field of the person whose state is CT whereas to include the address of the person whose state is NY.

Answer 1

<xsl:template match="persons">
<persons>
<xsl:apply-templates select="person"/>
<xsl:apply-templates select="person1"/>
</persons>
</xsl:template>
<xsl:template match="person">
<person>
<xsl:copy-of select="*[name() != 'address']"/>
<xsl:apply-templates select="address"/>
</person>
</xsl:template><xsl:template match="person1">
<person1>
<xsl:copy-of select="*[name() != 'address']"/>
<xsl:apply-templates select="address"/>
</person1>
</xsl:template>
<xsl:template match="address">
<xsl:if test="not(state='CT')">
<xsl:copy-of select="../address"/>
</xsl:if>
</xsl:template>
As you apply above transformation on provided xml then it will produce following result xml.
<person>
<phone type="home">203-555-1212</phone>
<phone type="fax">203-555-1212</phone>
<firstName>Charles</firstName>
<lastName>Smithington</lastName>
</person>
<person1>
<phone type="home">58-99-44-999</phone>
<phone type="fax">5788-9987-3365</phone>
<firstName>Mike</firstName>
<lastName>Shinoda</lastName>
<address type="home">
<street>12 Main Street</street>
<city>Park Avenue</city>
<state>NY</state>
<zip>10025</zip>
</address>
</person1>