How to return multiple objects in django - django

Question

I am working on an e-commerce app and want customers to be able to order several items. Currently they can only order one and i am having a hard time figuring out how i can achieve this.
in my menu template i return all the items in their category as follows:
{% for category in categories %}
<h5> {{ category.title }} </h5>
{% for item in category.item.all %}
<li><a href="{% url item_order item.id %}">{{item.name}}<span> {{item.price}}frw</span></li><a/>
OnClick, each item redirects to a form where you can order the quantity. here is the view:
def show_item(request,id):
# need to evaluate the HTTP method
if request.method == 'POST':
a = Item.objects.get(pk=id)
form = forms.PartialOrderItemForm(request.POST,instance=a)
# check validation of posted data
if form.is_valid():
order.add_to_order(request)
# if test cookie worked, get rid of it
if request.session.test_cookie_worked():
request.session.delete_test_cookie()
url =urlresolvers.reverse('order_index')
# redirect to order page
return HttpResponseRedirect(url)
else:
# it's a GET, create the unbound from. Note request as a Kwarg
form = forms.PartialOrderItemForm(request.GET)
# set the test cookie on our first GET request
request.session.set_test_cookie()
context={
# 'categories':categories,
'form':form,
# 'menu':menu,
}
return render_to_response('item.html',context,context_instance=RequestContext(request))
At some point, the above view calls the following view, that is after validating the form order.add_to_order(request)
add an item to order
def add_to_order(request):
postdata = request.POST.copy()
# get item slug from post data, return blank if empty
# item_slug = postdata.get('item_slug','')
#get quantity added, return 0 if empty
quantity = postdata.get('quantity',0)
# fetch the item or return missing page error_message
i = get_object_or_404(Item,pk=1)
i.orderitem_set.all()
# get items in order
order_items = get_order_items(request)
item_in_orders = False
# check to see if item is already in order
for order_item in order_items:
if order_item.item.id == i.id:
#update the quantity if found
order_item.augment_quantity(quantity)
item_in_orders = True
if not item_in_orders:
# creat and save a new order item
oi = OrderItem()
oi.order_id = _order_id(request)
oi.quantity = quantity
oi.item = i
oi.save()
Once the form is validated, the order is shown in the order page. here is the view that does this
def show_order(request):
if request.method == 'POST':
postdata = request.POST.copy()
if postdata['submit'] == 'Remove':
order.remove_from_order(request)
if postdata['submit'] == 'Update':
order.update_order(request)
order_items = order.get_order_items(request)
# page_title = 'F4L order'
order_subtotal = order.order_subtotal(request)
context = {
'order_items':order_items,
'order_subtotal':order_subtotal,
}
return render_to_response('public/order.html',context,context_instance=RequestContext(request))
here is part of the template for the order page.
<tbody>
{% if order_items %}
{% for item in order_items %}
<tr>
<td>
{{ item.item.name }}
</td>
<td>{{ item.item.price }}<span> frw</span></td>
<td class="right">
<form method="post" action="." class="order">
{% csrf_token %}
<label for="quantity">Quantity:</label>
<input type="text" name="quantity" value="{{ item.quantity }}" id="quantity" size="2" class="quantity" max_length="5" />
<input type="hidden" name="item_id" value="{{ item.id }}" />
</td>
<td>
<input type="submit" name="submit" value="Update" />
</form>
Here is what is happening, when i order the first item with pk=1 it works out properly, but then when i order the second item or any other and fill in the form, instead the order page returns the first item always.
How do you think i should go about this.