django ImportError at /admin/ no module named todo - django

I am following a tutorial on http://www.lightbird.net/dbe/todo_list.html to create a simple todo app. In one of the steps, I had to modify view to add an ability in 'admin' to mark tasks as done from that view. However I get the error ImportError at /admin/ no module named todo.
The error is not thrown from any particular line from the code so I do not know how to debug this. I am new to django. So I documented my error in my blog here: http://djangounchain.wordpress.com/2013/01/10/tutorial-8-todo-list-app/
Hope someone can help me!

You are registering your models to AdminSite in todo/models.py itself.
As per official django documentation, you need to create admin.py file inside your app for admin.autodiscover() to work properly.
The last step in setting up the Django admin is to hook your AdminSite
instance into your URLconf. Do this by pointing a given URL at the
AdminSite.urls method.
In this example, we register the default AdminSite instance
django.contrib.admin.site at the URL /admin/
# urls.py
from django.conf.urls import patterns, url, include
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^admin/', include(admin.site.urls)),
)
Above we used admin.autodiscover() to automatically load the
INSTALLED_APPS admin.py modules.

Related

django urls: "Django tried these URL patterns"

I am trying a tutorial on Django called blog. I have the following structure:
FirstBlog|FirstBlog
settings
urls
__init__
etc
blog
templates | index.html
migrations
views.py
manage.py
The view.py has
from django.shortcuts import render
from django.shortcuts import render_to_response
from blog.models import posts
def home(request):
return render('index.html')
The urls.py has
from django.conf.urls import url
from django.conf.urls import include
from django.contrib import admin
urlpatterns = [
url(r'^blog', 'FirstBlog.blog.views.home',name='home'),
]
and I get this error:
Using the URLconf defined in FirstBlog.urls, Django tried these URL patterns, in this order: ^blog [name='home']
The current URL, , didn't match any of these.
I can't seem to get it right..
Any help would be appreciated.
Thank you,
You are requesting for / url and you have not saved any such mapping. Current mapping is for /blog . So it will work for the same url.
i.e goto the browser and request /blog
If you need it to work for / then change the urls appropriately.
within your blog app, create a urls.py file and add the following code which calls the home view.
blog/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
#url(r'^',views.home, name='home'),
]
then in your root urls file which can be found at FirstBlog/urls.py
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^blog/',include('blog.urls')), #when you visit this url, it will go into the blog application and visit the internal urls in the app
]
PS:
your templates should be in blog/templates/blog/index.html
Read this docs on templates to understand how django locates templates.
This one is to understand how urls work Urls dispatcher
You are doing this in the wrong way! Try doing that using TemplateView from class-based views, which are the current standard from django views.
Check the django documentation: https://docs.djangoproject.com/en/1.9/topics/class-based-views/
Use this at the urls.py:
from django.conf.urls import url
from django.views.generic import TemplateView
urlpatterns = [
url(r'^blog/', TemplateView.as_view(template_name="index.html")),
]
And then, create a folder called templates in the project root ( like this: https://docs.djangoproject.com/en/1.9/intro/tutorial03/#write-views-that-actually-do-something ) named index.html
Simply go to file then select Save all your project instead of save. Or use shortcut Ctrl +k s on windows. Project should be able to sync and display the code on Django interface

How can I fix my Wagtail URL namespace and explorer when adding wagtail to a current project?

My issue is my URL is coming up mysite.com/test-news-1/ instead of mysite.com/news/test-news-1/
I've started a new project using cookiecutter-django. I then wanted to add wagtail cms to the project and followed the docs to do so.
I get the wagtail admin page up fine, at /cms/ instead of /admin/ like it says to do on this page - http://docs.wagtail.io/en/v1.3.1/getting_started/integrating_into_django.html
I added a few apps just to practice and get used to wagtail, one directly copied from the wagtail blog example. This is where my issue starts.
The wagtail admin Explorer does not list my apps like it shows on the wagtail site https://wagtail.io/features/explorer/, instead it just says "Welcome to your new Wagtail site!" When I select Add Child Page it allows me to select the app pages I have set up and seems to go by my models just fine. But when I post something and click go to live site it comes up as mysite.com/blog1/ instead of mysite.com/blog/blog1/
I believe my problem that I dont understand the final part of the doc page that I linked above. It says,
Note that there’s one small difference when not using the Wagtail
project template: Wagtail creates an initial homepage of the basic
type Page, which does not include any content fields beyond the title.
You’ll probably want to replace this with your own HomePage class -
when you do so, ensure that you set up a site record (under Settings /
Sites in the Wagtail admin) to point to the new homepage.
I tried adding the homepage model from the doc page, but this didn't seem to help at all.
I'm very inexperienced, this is my urls.py file, if you need to see other files please let me know.
urls.py
from __future__ import unicode_literals
from django.conf import settings
from django.conf.urls import include, url
from django.conf.urls.static import static
from django.contrib import admin
from django.views.generic import TemplateView
from django.views import defaults as default_views
from wagtail.wagtailadmin import urls as wagtailadmin_urls
from wagtail.wagtaildocs import urls as wagtaildocs_urls
from wagtail.wagtailcore import urls as wagtail_urls
urlpatterns = [
url(r'^$', TemplateView.as_view(template_name='pages/home.html'), name="home"),
url(r'^about/$', TemplateView.as_view(template_name='pages/about.html'), name="about"),
# Django Admin, use {% url 'admin:index' %}
url(settings.ADMIN_URL, include(admin.site.urls)),
# User management
url(r'^users/', include("contestchampion.users.urls", namespace="users")),
url(r'^accounts/', include('allauth.urls')),
# Your stuff: custom urls includes go here
# Wagtail cms
url(r'^cms/', include(wagtailadmin_urls)),
url(r'^documents/', include(wagtaildocs_urls)),
url(r'', include(wagtail_urls)),
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
if settings.DEBUG:
# This allows the error pages to be debugged during development, just visit
# these url in browser to see how these error pages look like.
urlpatterns += [
url(r'^400/$', default_views.bad_request, kwargs={'exception': Exception("Bad Request!")}),
url(r'^403/$', default_views.permission_denied, kwargs={'exception': Exception("Permission Denied")}),
url(r'^404/$', default_views.page_not_found, kwargs={'exception': Exception("Page not Found")}),
url(r'^500/$', default_views.server_error),
]
These two url confs are in conflict =
url(r'^$', TemplateView.as_view(template_name='pages/home.html'), name="home"),
url(r'', include(wagtail_urls)),
One must change, otherwise Django will always resolve the base url of `yourdomain.com/' to the first entry. One easy way to fix this is to update the second-
url(r'^content/', include(wagtail_urls)),
Now your Wagtail root page will be accessible at yourdomain.com/content.
As for mysite.com/blog/blog1/ not coming up, that Url would assume that, from your Wagtail root page, there's a page w/ slug 'blog', and then a child page of that with slug blog1. The tree structure of your Wagtail site determines the URLs by default. If you want to override that you'll have to use the RoutablePageMixin as described here.

grappelli dashboard ValueError on two admin sites

I want use two admin sites for my project. Each with grappelli dashboard. I've executed this commands:
python manage.py customdashboard dashboard.py
python manage.py customdashboard dashboard.py
twice (once in project/project and second time in project/app)
#file system
project
project
dashboard.py
urls.py
app
dashboard.py
admin.py
#settings.py
GRAPPELLI_INDEX_DASHBOARD = {
'django.contrib.admin.site': 'project.dashboard.CustomIndexDashboard',
'app.admin.operator_site': 'app.dashboard.CustomIndexDashboard',
}
#urls.py
from django.conf.urls import patterns, url, include
from django.contrib import admin
from app.admin import admin_site
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^myadmin/', include(operator_site.urls)),
url(r'^grappelli/', include('grappelli.urls')),
)
#app/admin.py
from django.contrib.admin import AdminSite
class MyAdminSite(AdminSite):
pass
admin_site = MyAdminSite()
The problem is when I go to /admin/ everything is ok, but when I go to /myadmin/ , I've got ValueError
Dashboard matching "{'app.admin.operator_site': 'app.dashboard.CustomIndexDashboard', 'django.contrib.admin.site': 'project.dashboard.CustomIndexDashboard'}" not found
full error trace: http://pastebin.com/w8W2eRPd
Where is the problem?
Ok, i've found it out. When making a subclass of a AdminSite on make an instance
admin_site = MyAdminSite()
you should use a custom name parameter (not 'admin'):
admin_site = MyAdminSite(name='myadmin')

Can I have two urls.py with different names?

In Django, is it possible to have two different files with url patterns, neither of which is called urls.py ? Or does Django rely on there being only one set of url patterns per Django app, and that it must be called urls.py ?
I'm using Django CMS and I want to split an app across two apphooks and two menus. So I've tried splitting urls.py into pub_urls.py and train_urls.py but I appear to have broken things by doing that, despite the cms_app.py naming the correct urls - eg:
from cms.app_base import CMSApp
from cms.apphook_pool import apphook_pool
from django.utils.translation import ugettext_lazy as _
from resources.menu import TrainingMenu, PublicationMenu
class PublicationApp(CMSApp):
name = _("Publication App") # give your app a name, this is required
urls = ["resources.pub_urls"] # link your app to url configuration(s)
menus = [PublicationMenu]
class TrainingApp(CMSApp):
name = _("Training App") # give your app a name, this is required
urls = ["resources.train_urls"] # link your app to url configuration(s)
menus = [TrainingMenu]
apphook_pool.register(PublicationApp) # register your app
apphook_pool.register(TrainingApp) # register your app
Is something like this possible? Or do I have to split this into two different apps?
There is nothing to stop your urls.py simply acting as a way of including multiple other urls files:
urls.py:
from django.conf.urls.defaults import patterns, include
urlpatterns = urlpatterns + patterns('',
(r'^', include('pub_urls')),
(r'^', include('train_urls')))
pub_urls.py:
from django.conf.urls.defaults import patterns, url
urlpatterns = patterns('',
(r'^$', 'homeview'),
(r'^stuff/$', 'stuffview')
)
etc.
ROOT_URLCONF in your settings file points to the root url file.
Django doesn't care what your urlpatterns file is called. The default base urlconf is by convention called urls.py, but in fact that's just a setting and can be overridden. After that, you need to explicitly include urlconfs by module name, so again it makes no difference what they're called.
I'm not familiar with Django-CMS and I don't know what it's doing in its CMSApp class, but I suspect you're going to have to dig into that to see what's going on.
It is configurable using ROOT_URLCONF setting.
From django docs
ROOT_URLCONF
A string representing the full Python import path to your root URLconf.
For example: "mydjangoapps.urls". Can be overridden on a per-request basis
by setting the attribute urlconf on the incoming HttpRequest object. See How
Django processes a request for details.
You can also write/get a middleware which can set it appropriately depending upon the host or other parameters in the request.

django ignoring admin.py

I am trying to enable the admin for my app. I managed to get the admin running, but I can't seem to make my models appear on the admin page.
I tried following the tutorial (here) which says:
(Quote)
Just one thing to do: We need to tell
the admin that Poll objects have an
admin interface. To do this, create a
file called admin.py in your polls
directory, and edit it to look like
this:
from polls.models import Poll from
django.contrib import admin
admin.site.register(Poll)
(end quote)
I added an admin.py file as instructed, and also added the following lines into urls.py:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
...
(r'^admin/', include(admin.site.urls)),
)
but it appears to have no effect. I even added a print 1 at the first line of admin.py and I see that the printout never happens, So I guess django doesn't know about my admin.py. As said, I can enter the admin site, I just don't see anything other than "groups", "users" and "sites".
What step am I missing?
You need to ensure you have app containing Poll listed in INSTALLED_APPS :)
Also: If you're adding the admin.py file with the dev server running, make sure to restart it. This tripped me up for a minute. :)