get the xml attribute value using xslt tree wise - xslt

Question

This is my xml file:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="try.xsl"?>
<oneday>
<team1 id="1" team="India">
<team2 id="2" team="gujarat">
<team3 id="3" team="guj11"></team3>
</team2>
</team1>
</oneday>
This is my xsl file:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:output method="text" />
<xsl:template match="*">
<xsl:value-of select="local-name()"/>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="text()[normalize-space(.)]">
<xsl:value-of select="concat(':', .)"/>
</xsl:template>
</xsl:stylesheet>
This is my output:
oneday
team1
team2
team3
But I want to output something like this:
oneday
team1:India
team2:Gujarat
team3:Guj11

Answer 1

How's this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:template match="*">
<xsl:apply-templates select="ancestor::*" mode="spacing" />
<xsl:value-of select="local-name()"/>
<xsl:if test="#team">
<xsl:value-of select="concat(':', #team)"/>
</xsl:if>
<xsl:text>
</xsl:text>
<xsl:apply-templates select="*" />
</xsl:template>
<xsl:template match="*" mode="spacing">
<xsl:text> </xsl:text>
</xsl:template>
</xsl:stylesheet>
When run on your sample XML, this produces:
oneday
team1:India
team2:gujarat
team3:guj11
When run on a slightly more complex XML:
<oneday>
<team1 id="1" team="India">
<team2 id="2" team="gujarat">
<team3 id="3" team="guj11"></team3>
</team2>
<team6 team="Mumbai" />
</team1>
<team4 team="France">
<team5 team="Paris" />
</team4>
</oneday>
It produces:
oneday
team1:India
team2:gujarat
team3:guj11
team6:Mumbai
team4:France
team5:Paris