Model:
class Exercise (models.Model):
name_e = models.CharField(max_length=50)
class Subject (models.Model):
name_s = models.CharField(max_length=50)
exercise = models.ForeignKey(Exercise)
View:
exercise_all = Exercise.objects.all()
subject_all = Subject.objects.all()
My SQL table contain subjects and exercises connected via ForeignKey
I pass view variables as a context to the template:
{% for e_field in exercise_all %}
<table>
<tr><th>Header</th></tr>
{% for s_field in subject_all %}
<tr><td>{{ e_field.name_e }}</td></tr>
{% endfor %}
</table>
{% endfor %}
If I have, let's say, 3 types of Exercises and 10 Subjects connected with Exercises (subject1->exercise1, subject2->exercise1, subject3->exercise1, subject4->exercise2 etc.)
I want to display 3 tables in a template and each table will display only tr/subjects corresponding to table/exercise. I tried with {% if ... in ... %} but maybe i should do some function in view.
In this case you should be able to say:
{% for e_field in exercise_all %}
<table>
<tr><th>Header</th></tr>
{% for s_field in e_field.subject_set.all %}
<tr><td>{{ e_field.name_e }}</td></tr>
{% endfor %}
</table>
{% endfor %}
Related
I have the following template:
{% extends "artdb/base.html" %}
{% block content1 %}
<h4>Persons:</h4>
<ul>
{% for p in ans %}
<h5>First name: {{p.firstName}}</h5>
<h5>Last name: {{p.lastName}}</h5>
<h5>Phone: {{p.phoneNumber}}</h5>
<h5>Adress: {{p.streetAdress}}</h5>
<h5>Zip Code: {{p.zipcode}}</h5>
<h5>City: {{p.city}}</h5>
<hr>
{% endfor %}
</ul>
{% endblock content1 %}
{% block content2 %}
<h4>Roles:</h4>
<ul>
{% for p in ans %}
<h5>Role:{{p.persons.role}}</h5>
<hr>
{% endfor %}
</ul>
{% endblock content2 %}
and the model:
class Person(models.Model):
mail=models.EmailField()
firstName=models.CharField(max_length=200)
lastName=models.CharField(max_length=200)
phoneNumber=PhoneNumberField()
streetAdress=models.CharField(max_length=200)
zipcode=models.CharField(max_length=200)
city=models.CharField(max_length=200,default="Göteborg")
country=models.CharField(max_length=200,default="Sweden")
def __str__(self):
return "%s %s" % (self.firstName,self.lastName)
class Meta:
ordering = ('firstName','lastName')
class Role(models.Model):
role=models.CharField(max_length=200)
person=models.ManyToManyField(Person)
def __str__(self):
return self.role
class Meta:
ordering = ('role',)
But when I run the above code the only output that I get is from the block content1, i.e I cannot access the role content. I thought that role.persons.role would do it but apperantley not. There is a many-to-many relationship between perssons and roles.
Any ideas?
This should work
{% block content2 %}
<h4>Roles:</h4>
<ul>
{% for p in ans %}
{% for role in p.role_set.all %}
<h5>Role:{{ role }}</h5>
<hr>
{% endfor %}
{% endfor %}
</ul>
{% endblock content2 %}
We have to create a second for loop, since a many to many relationship will always return a list. Not a single instance. So essentially it's just like accessing a 2d array.
In Django you only have to define a n:n relationship on one end. Django will then automatically add it to the other model as well. It does this by taking the related model name and suffixing _set. So if we want to reference all of the roles attached to a person, it would be person.role_set. The other way around it would be role.person like you defined in the model.
I'm working on a Django web app and have the following query:
I have a model called 'AppQoSList' which lists the applications available to all users.
I have then another model called 'BasicAppSDWANProfiles' which has a ManyToMany relationship with 'AppQoSList' .
In short, it means a user can have multiple 'BasicAppSDWANProfiles' associated to his account and multiple AppQoS can be within a particular BasicAppSDWANProfiles:
class AppQoSList(models.Model):
app_qos_name = models.CharField(max_length=50, blank=None, null=True)
app_qos_description = models.CharField(max_length=500)
def __str__(self):
return u'%s' % self.app_qos_name
class BasicAppSDWANProfiles(models.Model):
profile_name = models.CharField(max_length=30)
profile_basic_app_qos = models.ManyToManyField(AppQoSList)
tenant_id = models.ForeignKey(Tenant, default=3)
I'm facing issue in my template when I try to display the list of apps available and the associated BasicAppSDWANProfile:
{% for app in apps %}
{% for profile_app in sdwan_prof %}
{% for specific_app in profile_app.profile_basic_app_qos.all %}
{% ifchanged specific_app.pk %}
{% if app.pk == specific_app.pk %}
<td><h4><span class="label label-primary">{{ profile_app.profile_name }}</span></h4></td>
{% else %}
<td><h4><span class="label label-warning">Not Assigned</span></h4></td>
{% endif %}
{% endifchanged %}
{% endfor %}
{% endfor %}
{% endfor %}
Issue with this code is that 'Not Assigned' is displayed 6 times on each row (which corresponds to the number of Apps found in BasicAppSDWANProfiles associated with this user) whereas I would like to display it only once:
Would you have any solution for this ?
Thanks in advance.
I was able to address this issue.
First I did clean up my view code to remove duplicate 'Not Assigned' values.
I pass to my template context a dictionary with only apps that have a profile assigned such as below:
{'citrix-static': 'DPS-BLACKLIST',
'exchange': 'DPS-BLACKLIST',
'ms-lync-audio': 'DPS-WHITELIST',
'ms-update': 'DPS-GREYLIST',
'rtp': 'DPS-WHITELIST',
'share-point': 'DPS-WHITELIST'}
In my template, I only loop through this dictionary:
{% for k,v in app_prof_assign.items %}
{% if app.app_qos_name == k %}
<td><h4><span class="label label-primary">{{ v }}</span></h4></td>
{% endif %}
{% endfor %}
I then simply check if the app is not in the profile dictionary, outside the loop:
{% if app.app_qos_name not in app_prof_assign %}
<td><h4><span class="label label-warning">Not Assigned</span></h4></td>
{% endif %}
Finally, I can get the table populated as expected:
I have this models:
class House(models.Model):
name = models.CharField()
class BedRoom(models.Model):
name = models.CharField()
class Catalog(models.Model):
name = models.CharField()
house = models.ForeignKey(House)
bedroom = models.ForeignKey(BedRoom)
at admin.py Catalog is inline to House
class CatalogInline(admin.TabularInline):
model = Catalog
class HomeAdmin(admin.ModelAdmin):
inline = [CatalogInline]
then I need obtain at view the list of Bedrooms from House Catalog, at Home model I have:
def bedrooms(self):
return self.catalog_set.all()
but when I do at template obtaining "houses" from a view:
{% for house in houses %}
{% for h in house %}
<p>{{h.name}}</p>
{% endfor %}
{% endfor %}
I get an error:
'Catalog' object is not iterable
what I'm doing wrong?
I should define the model in a different way?
As I mentioned, you don't seem to actually be calling the bedrooms method. I guess (and it is just a guess) you mean this:
{% for house in houses %}
{% for h in house.bedrooms %}
<p>{{h.name}}</p>
{% endfor %}
{% endfor %}
The bedrooms method is pointless though, as you can just as easily do this:
{% for house in houses %}
{% for h in house.catalog_set.all %}
<p>{{h.name}}</p>
{% endfor %}
{% endfor %}
I have a model called Subtopic. One of my templates runs a forloop on an object, returning a different field for each cell of a table row.
Two of the table cells look up a field which is a ManytoMany foreign key, both to the same foreign model, Resource. I want each to display different results, based on the value of a boolean field within the Resource model.
What you see below is currently working fine, but doesn't attempt to filter by the boolean field.
models.py:
class ICTResourceManager(models.Manager):
def get_query_set(self):
return super(ICTResourceManager, self).get_query_set().filter('is_ict': True)
class NonICTResourceManager(models.Manager):
def get_query_set(self):
return super(NonICTResourceManager, self).get_query_set().filter('is_ict': False)
class Resource(models.Model):
subtopics = models.ManyToManyField(Subtopic)
external_site = models.ForeignKey(ExternalSite)
link_address = models.URLField(max_length=200, unique=True, verify_exists=False)
requires_login = models.BooleanField()
is_ict = models.BooleanField()
flags = models.ManyToManyField(Flag, blank=True)
comment = models.TextField()
def __unicode__(self):
return u'%s %s' % (self.external_site, self.link_address)
objects = models.Manager()
ict_objects = ICTResourceManager()
nonict_objects = NonICTResourceManager()
class Meta:
ordering = ['external_site', 'link_address']
views.py:
def view_ks5topic(request, modulecode, topicshortname):
listofsubtopics = Subtopic.objects.filter(topic__module__code__iexact = modulecode, topic__shortname__iexact = topicshortname)
themodule = Module.objects.get(code__iexact = modulecode)
thetopic = Topic.objects.get(module__code__iexact = modulecode, shortname__iexact = topicshortname)
return render_to_response('topic_page.html', locals())
My template:
{% for whatever in listofsubtopics %}
<tr>
<td>
{{ whatever.objective_html|safe }}
<p>
{% if request.user.is_authenticated %}
{% with 'objective' as column %}
{% include "edit_text.html" %}
{% endwith %}
{% else %}
{% endif %}
</td>
<td>
{% regroup whatever.resource_set.all by external_site.name as resource_list %}
{% for external_site in resource_list %}
<h4>{{ external_site.grouper }}</h4>
<ul>
{% for item in external_site.list %}
<li>{{ item.comment }}</li>
{% endfor %}
</ul>
{% endfor %}
</td>
</tr>
{% endfor %}
As you can see, I've added extra managers to the model to do the filtering for me, but when I replace the appropriate lines in the template, I just get blanks. I have tried: for external_site.ict_objects in resource_list and for item.ict_objects in resource_list and <a href="{{ item.ict_objects.link_address }}">. If this were in the view I could probably do the filter just by .filter('is_ict': True), but with this being inside a forloop I don't know where to do the filtering.
I also tried writing regroup whatever.resource_set.filter('is_ict': True) in the template, but the syntax for regrouping seems to use resource_set.all rather than resource_set.all() (and I don't know why) so the filter text doesn't work here.
Turns out it was possible to do it using a custom template filter. The original efforts to filter within the template weren't working, given that as is well documented the template language is not a fully-fledged python environment. My original question remains open for anyone who knows an alternative method that more directly addresses the question I was originally asking, but here's how I did it:
myapp_extras.py:
from django import template
register = template.Library()
def ict(value, arg):
"filters on whether the is_ict Boolean is true"
return value.filter(is_ict=arg)
register.filter('ict', ict)
My template, note the use of the custom filter in line 2:
<td>
{% regroup whatever.resource_set.all|ict:1 by external_site.name as resource_list %}
{% for external_site in resource_list %}
<h4>{{ external_site.grouper }}</h4>
<ul>
{% for item in external_site.list %}
<li>{{ item.comment }}</li>
{% endfor %}
</ul>
{% endfor %}
</td>
After this I was able to remove the additional custom managers from the model.
One further question, when filtering for the boolean is_ict field, I found that I had to use filter(is_ict=1) and filter(is_ict=0). Is that the only way to refer to a True or False value?
how do i implement the tree structure in django templates with out using django-mptt.
i have model.
class Person(TimeStampedModel):
name = models.CharField(max_length=32)
parent = models.ForeignKey('self', null=True, blank=True, related_name='children')
now i want ..
Parent
Child 1
subchild 1.1
subchild 1.2
nextsubchild 1.2.1
Child 2
Child 3
there names should be click able to show their profile.
I just finished implementing this. I wanted a tree structure for a sub-navigation, but I did not want to do anything strange with recursive templates.
The solution I implemented is very simple: I simply recurse in the view (in my case a generic helper function) and flatten out the hierarchical structure into a simple list. Then, in my template I just use a for loop to iterate over the list.
Each element in the list can be one of three things: "in", the object, or "out". In my case, I'm constructing a series of ul li elements in the view, so when I encounter "in" I create a new ul, when I encounter "out" I close the ul. Otherwise, I render the item.
My template code looks like this:
<ul>
{% for item in sub_nav %}
{% if item == "in" %}
<ul>
{% else %}
{% if item == "out" %}
</ul>
</li>
{% else %}
<li>
<a href='{{item.full_url}}'>{{item.name}}</a>
{% if item.leaf %}
</li>
{% endif %}
{% endif %}
{% endif %}
{% endfor %}
</ul>
The code in the helper function looks like this:
def get_category_nav(request,categories=None):
"""Recursively build a list of product categories. The resulting list is meant to be iterated over in a view"""
if categories is None:
#get the root categories
categories = ProductCategory.objects.filter(parent=None)
categories[0].active=True
else:
yield 'in'
for category in categories:
yield category
subcats = ProductCategory.objects.select_related().filter(parent=category)
if len(subcats):
category.leaf=False
for x in get_category_nav(request,subcats):
yield x
else:
category.leaf=True
yield 'out'
Using those snippets, you should be able to build any sort of hierarchical tree you'd like without doing any recursion in the template, and keeping all the logic in the view.
I know there was already an accepted answer for this, but I thought I'd post the technique in case it helps anyone else.
from Django while loop question and
http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#inclusion-tags
# view.py
#register.inclusion_tag('children.html')
def children_tag(person):
children = person.children.all()
return {'children': children}
# children.html
<ul>
{% for child in children %}
<li> {{ child }}</li>
{% if child.children.count > 0 %}
{% children_tag child %}
{% endif %}
{% endfor %}
</ul>
# your template
{% children_tag parent %}
These are great answers but I consolidated a bit and put it on the actual model.
class RecursiveThing(models.Model):
name = models.CharField(max_length=32)
parent = models.ForeignKey('self', related_name='children', blank=True, null=True)
def as_tree(self):
children = list(self.children.all())
branch = bool(children)
yield branch, self
for child in children:
for next in child.as_tree():
yield next
yield branch, None
And then in your template:
<ul>
{% for thing in things %}
{% for branch, obj in thing.as_tree %}
{% if obj %}
<li>{{ obj.name }}
{% if branch %}
<ul>
{% else %}
</li>
{% endif %}
{% else %}
{% if branch %}
</ul>
{% endif %}
{% endif %}
{% endfor %}
{% endfor %}
</ul>
It's very simple
All you have to do in your view is get all objects:
people = Person.objects.all()
Then in your template :
{% for person in people %}
<li>- {{person.name}} </li>
{% for child in person.children.all %}
<ul>* {{child.nom}} </ul>
{% endfor %}
</li>
{% endfor %}