Target address reversed - c++

Question

I use to code in Python. Now I'm trying C++. When I run the program I see the target address (w/ Wireshark) reverse, even if I use htonl. In Python this same program worked fine.
Follow the code. At the bottom I printed the result.
I'm using Ubuntu 12.04LTS and g++ (Ubuntu/Linaro 4.6.3).
//UdpClient.cpp
#include <iostream>
#include <string>
#include <sstream>
#include <sys/socket.h>
#include <sys/types.h>
#include <netdb.h>
#include <cstdlib>
#include <arpa/inet.h>
#include <typeinfo>
using namespace std;
int main(int argc, char* argv[])
{
int s, p, rb,rs;
int bytesend;
char buf[1024];
int len;
char ent[16];
char Porta[5];
unsigned long EndServ;
struct sockaddr_in UdpServer, UdpClient;
int UdpServerLen = sizeof(UdpServer);
//do text
string msg("The quick brown fox jumps over the lazy dog\n");
len = msg.copy(buf, msg.size(), 0);
buf[len] = '\0';
//do socket
s = socket(AF_INET, SOCK_DGRAM, 0);
if (s == -1){
cout << "No socket done\n";
}
else {
cout << "Socket done\n";
}
//populate UdpClient struct
UdpClient.sin_family = AF_INET;
UdpClient.sin_addr.s_addr = INADDR_ANY;
UdpClient.sin_port = 0;
//populate UdpServer struct
UdpServer.sin_family = AF_INET;
UdpServer.sin_addr.s_addr = inet_addr(argv[1]);
//check if addres is correct
cout << "ServerAddress: " << hex << UdpServer.sin_addr.s_addr << endl;
UdpServer.sin_port = htons(atoi(argv[2]));
//bind socket
rb = bind(s, (struct sockaddr *)&UdpClient, sizeof(UdpClient));
if (rb == 0){
cout << "Bind OK!\n";
}
else {
cout << "Bind NOK!!!\n";
close(s);
exit(1);
}
//send text to Server
cout << "UdpServSiz: " << sizeof(UdpServer) << endl;
rs = sendto(s, buf, 1024, 0, (struct sockaddr *)&UdpServer, sizeof(UdpServer));
if (rs == -1){
cout << "Message NOT sent!!!\n";
}
else {
cout << "Message SENT!!!\n";
}
close(s);
return 0;
}
/*
edison#edison-AO532h:~/CmmPGMs$ ./UdpClient 127.0.0.1 6789
Socket done
ServerAddress: 100007f (using htonl or not!!)
Bind OK!
Message SENT!!!
edison#edison-AO532h:~/CmmPGMs$
*/

Answer 1

Sounds like you're on ARM (Linaro)? In which case the endianness of the processor matches network order, so htonl and ntohl basically do nothing.