I have a model:
class Tour(models.Model):
owner_id = models.ForeignKey(User)
name = models.CharField(max_length=50)
location = models.ManyToManyField(Location)
subscribers = models.ManyToManyField(User, related_name="sub")
tour_date = models.DateField(null=True)
description = models.CharField(max_length=300, null=True)
And a template that includes this form:
<form method="post" action="/mytours/">
{% csrf_token %}
<input name="name" value="{{ name }}" class="pull-left" type="text" placeholder="Type the tour name... "></br>
<input name="tour_date" value="{{ tour_date }}" type="text" id="datepicker" placeholder="Pick a tour date..."/>
<button class="btn" data-dismiss="modal" aria-hidden="true">Cancel</button>
<button type="submit" class="btn btn-primary">Save</button>
</form>
And in my views I am trying to add to my database what is filled in the form:
if request.method == 'POST':
location = Location.objects.get(id=1)
name = request.POST.get('name', '')
tour_date = request.POST.get('tour_date', '')
tour = Tour()
tour.owner_id = user.pk
tour.name = name
tour.tour_date = tour_date
tour.location = location
tour.save()
c = {'name':name, 'tour_date':tour_date, 'tour':tour}
c.update(csrf(request))
return render_to_response("myTours.html", c)
I am new in django and I don't know where is the problem.
You're misunderstanding what to do with the CSRF token. You're creating it on POST, but the point is to create it for the original display of the form on the GET request. It is checked by the middleware on POST, so you don't need to add it there.
You should use the render call as recommended by surfeurX, but on the call that displays the form in the first place.
What I do when I implement forms in django is writing a form class and creating an instance of it in the view. Then pass the instance to the template.
# form class eg. in models.py
from django import forms
class TourForm(forms.Form):
name = forms.CharField(max_length=50)
# in the view
if request.method == 'POST':
form = TourForm(request.POST)
if form.is_valid():
# do your stuff here with form data
else:
form = TourForm() # An unbound form
return render(request, 'myTours.html', {
'form': form,
})
in your template you can display the generated form like this:
<form action="/mytours/" method="post">{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Save" class="btn btn-primary" />
</form>
for further information just look inside the official django forms documentation
You probably need to add django.middleware.csrf.CsrfViewMiddleware to MIDDLEWARE_CLASSES and add a RequestContext to your response:
return render_to_response("myTours.html", c, context_instance=RequestContext(request))
https://docs.djangoproject.com/en/1.3/ref/contrib/csrf/
How do you render your template ??? I think your csrf_token doesn't print any hidden input, add "request" in your template context like:
return render(request, "template.html", {"var": var})
https://docs.djangoproject.com/en/dev/topics/http/shortcuts/#render
Related
Tags will not store in database in Django
def addque(request):
if request.method == "POST":
user = request.user
if user.is_anonymous:
return redirect('addquery')
if user.is_active:
question = request.POST['question']
body = request.POST['body']
tags = request.POST['tags']
aquuid = request.user.aquuid
addquery = Question(question=question, user_id=aquuid, que_body=body, tags=tags)
addquery.save()
return redirect('addquery')
else:
return render(request, 'question/ask.html')
After giving the input the data is stored in the tags field but, not saving in the database. I can manually insert data through the admin panel successfully but not as a non-staff user. I have installed taggit and placed it in the installed_apps in settings.py. What is the issue with the code?
Tags are Many-to-Many objects and you can't add those to an object until the object has been saved. The documentation shows that you need to use .add() to add tags to a model instance. Your code should be:
addquery = Question(question=question, user_id=aquuid, que_body=body)
addquery.save()
addquery.tags.add(tags)
As an aside, you might be better served by a ModelForm which can handle the tags and all of this stuff that you're doing:
question = request.POST['question']
body = request.POST['body']
tags = request.POST['tags']
https://django-taggit.readthedocs.io/en/latest/forms.html
Use model form
In html use id of forms like this
HTML
<form action="{% url 'addquery' %}" method="post">
{% csrf_token %}
<div class="psrelative">
<input id="id_question" name="question" type="text" maxlength="300" tabindex="100" placeholder="e.g. Is there an R function for finding the index of an element in a vector?" class="s-input js-post-title-field" value="" data-min-length="15" data-max-length="150" autocomplete="off" required>
</div>
<textarea name="que_body" id="id_que_body" class="textarea-body"></textarea required>
<div class="psrelative">
<input id="id_tags" name="tags" type="text" maxlength="300" tabindex="100"
placeholder="e.g. (ruby-on-rails vba spring)" class="s-input js-post-title-field" value="" data-min-length="15" data-max-length="150" autocomplete="off" required>
</div>
<button class="review-question-btn" type="submit" tabindex="120"> Submit your question
</button>
</form>
Forms.py
from django import forms
from .models import Question
class Addqueform(forms.ModelForm):
class Meta:
model = Question
fields = ['question','que_body','tags']
Views.py
from .forms import Addqueform
def addque(request):
queform = Addqueform(request.POST)
if request.method == "POST":
user = request.user
if user.is_anonymous:
return redirect('addquery')
if user.is_active:
if queform.is_valid():
aquuid = request.user.aquuid
question = queform.cleaned_data['question']
body = queform.cleaned_data['que_body']
tags = queform.cleaned_data['tags']
addquery = Question(question=question, user_id=aquuid, que_body=body)
for tag in tags:
addquery.tags.add(tag)
addquery.save()
return redirect('addquery')
else:
queform = Addqueform()
return render(request, 'question/ask.html', {'form': queform})
else:
return render(request, 'question/ask.html', {'form': queform})
I think It will Work
I've created a custom HTML form for my model, just like I want to add a post from the front-end. I already created a page with the name add-post.html
<form method="POST" action="">
{% csrf_token %}
<input name="title" type="text">
<textarea spellcheck="false" name="description"></textarea>
<input type="file" name="image" #change="fileName" multiple />
<select required name="priority">
<option value="Low" selected>Low</option>
<option value="Medium">Medium</option>
<option value="High">High</option>
</select>
<input type="checkbox" name="on_hold">
<button type="submit">Add ToDo</button>
</form>
Here's my model.py
class Todo(models.Model):
title = models.CharField(max_length=100)
image = models.ImageField(null=True, blank=True, upload_to='todo/images/')
description = RichTextField()
Low, Medium, High = 'Low', 'Medium', 'High'
priorities = [
(Low, 'Low'),
(Medium, 'Medium'),
(High, 'High'),
]
priority = models.CharField(
max_length=50,
choices=priorities,
default=Low,
)
on_hold = models.BooleanField(default=False)
No, I want to use the above custom HTML form to post data and save it to this model database. instead of using {% form.as_p %}
And I also created a particular page to update this post from the front-end but don't know how to make it work.
Can you please guide me on how can I save data from the custom form and also update it from the custom form?
Appreciate your response :)
#Mubasher Rehman - You are almost there
forms.py
class TodoCreationForm(forms.ModelForm):
class Meta:
model = Todo
fields = ('title','image','description','priorities','priority','on_hold',)
views.py
from django.contrib.messages.views import SuccessMessageMixin
from django.views.generic import CreateView
class CreatProduct(SuccessMessageMixin,CreateView):
model = Todo
form_class = TodoCreationForm
template_name = "add_post.html"
success_message = "Todo was created successfully"
error_message = "Error saving the Todo, check fields below."
add_post.html
<form method="POST" enctype="multipart/form-data">
{% csrf_token %}
{{form.as_p}}
<button type="submit" class="btn btn-primary">Submit</button>
</form>
#Mubasher Rehman - I fought this problem myself for awhile and finally found a solution. My situation was much different than yours, but try this:
In your views.py overwrite the form_valid method like so:
def form_valid(self, form):
if self.request.POST:
if form.is_valid():
t= Todo.objects.create(title='title', image='image', description='description', priority='priority', on_hold='on_hold')
t.save()
return super(ModelView, self).form_valid(form)
I want to have an input field as a button in my template. Just like this.I am manually rendering form fields in my template.So, how do i create a field like that in my form.
Formfield in forms.py
class DetailForm(forms.Form):
owner=forms.CharField(widget=forms.TextInput(attrs={'class':'form-control'}))
views.py
def getDetail(request):
form=DetailForm()
return render(request,'materials/addpage.html',{'form':form})
and template,
<div class="form-group">
{{form.owner}}
</div>
A minimal example of using buttons as input in Django looks like this:
Template:
<form method="POST">
{% csrf_token %}
<input type="submit" name="btn" value="yes">
<input type="submit" name="btn" value="no">
</form>
{{ val }}
Form:
class Fooform(forms.Form):
btn = forms.CharField()
View:
def test_view(request):
if request.method == 'POST':
form = Fooform(request.POST)
if form.is_valid():
val = form.cleaned_data.get("btn")
else:
form = Fooform()
return render(request, 'template.html', locals())
Libraries like crispy-forms have button widgets.
I have another model which is like below
class Status(models.Model):
name = models.ForeignKey(User, on_delete=models.CASCADE)
status = models.BooleanField(default=False)
I just want to create a form which will render all users from django User model with upper model connected. When click single Status button it will just save that field. I'm using CreateView. How to do that?
<form method="post" action="">
User1 <input type="checkbox" name="status" />
<input type="submit" name="submit" value="Status"/>
</form>
<form method="post" action="">
User2 <input type="checkbox" name="status" />
<input type="submit" name="submit" value="Status"/>
</form>
<form method="post" action="">
User3 <input type="checkbox" name="status" />
<input type="submit" name="submit" value="Status"/>
</form>
You could use Formsets from Django. Through this way, you can set 2 forms in one, get fields from both forms and save them with a single button.
For example, you have two models bounded by a ForeignKey in your models.py file :
class MyModelA(models.Model):
field1 = ...
field2 = ...
class MyModelB(models.Model):
field1 = ...
field2 = models.ForeignKey(MyModelA, ...)
Then, in your forms.py file, you have to bound these both forms thanks to formsets :
from django.forms.models import inlineformset_factory
from .models import MyModelA, MyModelB
MyFormSet = inlineformset_factory(MyModelA, MyModelB, form=MyModelBForm, extra=1, max_num=1)
With this line, your models will be set into the same django form in your template.
Now, in your views.py file, you have to call your formset :
class MyClassCreateView(CreateView):
model = MyModelA
template_name = 'path/to/your/template'
def get_context_data(self, **kwargs):
context = super(MyClassCreateView, self).get_context_data(**kwargs)
context['my_form'] = MyFormSet(self.request.POST or None)
return context
def form_valid(self, form):
context = self.get_context_data()
document = context['my_form']
if document.is_valid():
self.object = form.save()
document.instance = self.object
document.save()
return super(MyClassCreateView, self).form_valid(form)
And finally, in your template.html file, you can call your formset :
<form method="post" action="" novalidate>
{% csrf_token %}
{{ form }}
{{ my_form }}
<input type="submit" class="btn btn-default" value="{% trans 'Save' %}" />
</form>
Hopfully it could help you to set your Django formsets
I have a model:
class PartnerPrefs(models.Model):
partner = models.ForeignKey(Partner)
theme = models.IntegerField()
email = models.EmailField()
logo_file = models.ImageField(upload_to='logos/')
And my forms:
class PartnerPrefsForm(ModelForm):
theme = forms.ChoiceField(
choices=THEME_CHOICE,
widget=forms.Select(),
initial='1',
)
class Meta:
model = PartnerPrefs
exclude = ('partner',)
And my views:
...
if request.method == 'POST':
prefsform = PartnerPrefsForm(request.FILES, request.POST)
if prefsform.is_valid():
# do stuff
And finally my template:
<form enctype='multipart/form-data' form action='.' method='post'>
{% csrf_token %}
{{ prefsform.as_p }}
<input type="submit" value="Submit" />
</form>
Whenever I submit the form all field come back with This field is required.... If I eliminate the ImageField from the form, then it works fine. I cannot find what the problem is.
The issue turned out to be the order in which request.POST and request.FILES are passed to the from. request.POST must go first.