Django alter current URL name and arguments - django

Question

In my Django URLs, I have many URL patterns that end with :
(redirect/(?P<redirect_to>\w+))
Which means that these URLs can be (or not) ending by /redirect/TARGET/. These URL patterns have other named arguments (mostly one : pk)
Now, I'd like, in the templates used by these URL patterns, to be able to alter the current page path, by just adding the redirect_to argument, and keeping the other arguments and URL reverse name untouched.
I was able to get the URL reverse name in the template, by adding resolve(path).url_name to the current context, and then to use that with the {% url %} template tag.
I'd like to know if there is any easy way to dynamically add the arguments (from resolve(path).kwargs) to the URL reverse tag ?

Answer 1

I think you should create a custom tag for this (replacing your {% url %} tag with {% url_redirect "your_new_destination" %}).
in your_app/templatetags/my_custom_tags.py:
from django.core.urlresolvers import reverse, resolve
#register.simple_tag(takes_context=True)
def url_redirect(context, new_destination):
match = resolve(context.request.path)
match.kwargs['redirect_to'] = new_destination
return reverse(match.url_name, args=match.args, kwargs=match.kwargs)
in your template:
{% load my_custom_tags %}
{% url_redirect "your_new_destination" %}
Please note that you need to add 'django.core.context_processors.request' to your TEMPLATE_CONTEXT_PROCESSORS in order for this snippet to work.