Is it possible to put "delete" in comma expression

Is it possible to put "delete" in comma expression - c++

I would like to return some material in the struct referenced by a pointer and then delete the struct.
In Java, just return the value and the garbage collection system will delete the struct automatically.
But in C++, the way I can imagine is not very clean, that using a temporary variable to store the things for return, deleting the pointer and then returning the value stored.
I try another tricky way using comma expression as "return ptr->value, delete ptr", but there is a compile error says "void value not ignored as it ought to be".
Is there any possible way to achieve that more elegantly?
Thanks a lot.
Updated
Thanks a lot for suggestions from everybody. In fact the original motivation of my problem is about the comma expression which I would like to use for some shorter code. And I found the discussion is more about the usage of pointers in C++. It's also another very interesting topic.
I have used C for years so I am more familiar with raw pointer and have little experience with smart pointer. At my first thought, there are two basic conditions where we need pointers. One is reference to a large piece of memory allocated in heap and the other is for dynamically allocation such as link list node or tree node(eg. my original problem came out while writing a BST-like struct).
So in C++ programming, is smart pointer the best choice for both cases? If we consider the efficiency, such as working on some low level library, is it possible to encapsulate the raw pointer inside the class completely for less memory leak risk?

Sure. Don't use pointers, and if you must, use smart pointers (std::shared_ptr, std::unique_ptr).
In your case, it could be as simple as
//...
return obj.value; //no pointer needed
//automatic memory management
or
//...
return smartPtr->value; //smart pointer automatically cleans up after itself
You probably can't imagine the clean way of doing it in C++ because C++ is taught as C, with pointers and memory management issues. Proper C++ uses RAII and doesn't suffer from that.

No, in your case, because the function is supposed to return some value, but comma operator evaluates to the right most operand, which in your case is delete expression, which is just void.

The usual solution is, first, to not use pointers, so that there
is nothing to delete, and second, when there are other resources
to be cleaned up, to do the cleanup in a destructor, which will
automatically be called after the return statement has copied
the return value to where ever it has to copy it.
If you can return it, you can copy it, so it shouldn't be
allocated dynamically, The most notable exception is where
polymorphic objects are involved; polymorphism requires pointers
or references to work, and most of the time (although there are
exceptions), the polymorphic object will be dynamicallly
allocated. In this case, if the actual lifetime of the
polymorphic object corresponds to local scope, you can use
std::auto_ptr (or std::unique_ptr in the unlikely case that
you can count on C++11).

If you dynamically allocate a pointer inside a function. what you can do is:
consider you want to return an int variable
int foo()
{
MyStruct *obj;
obj=new MyStruct;
.....
int x=obj->value;
delete obj;
return x;
}
Or you can also do:
int foo()
{
MyStruct obj;
obj=new MyStruct;
.....
return obj.value;
}
this way you won't have to worry about memory leaks..
This is the easiest method. Sure you can use smart pointers. But at your level I would say stick with this method.

Related

Difference between Object object = new Object() and Object object [duplicate]

I'm coming from a Java background and have started working with objects in C++. But one thing that occurred to me is that people often use pointers to objects rather than the objects themselves, for example this declaration:
Object *myObject = new Object;
rather than:
Object myObject;
Or instead of using a function, let's say testFunc(), like this:
myObject.testFunc();
we have to write:
myObject->testFunc();
But I can't figure out why should we do it this way. I would assume it has to do with efficiency and speed since we get direct access to the memory address. Am I right?

It's very unfortunate that you see dynamic allocation so often. That just shows how many bad C++ programmers there are.
In a sense, you have two questions bundled up into one. The first is when should we use dynamic allocation (using new)? The second is when should we use pointers?
The important take-home message is that you should always use the appropriate tool for the job. In almost all situations, there is something more appropriate and safer than performing manual dynamic allocation and/or using raw pointers.
Dynamic allocation
In your question, you've demonstrated two ways of creating an object. The main difference is the storage duration of the object. When doing Object myObject; within a block, the object is created with automatic storage duration, which means it will be destroyed automatically when it goes out of scope. When you do new Object(), the object has dynamic storage duration, which means it stays alive until you explicitly delete it. You should only use dynamic storage duration when you need it.
That is, you should always prefer creating objects with automatic storage duration when you can.
The main two situations in which you might require dynamic allocation:
You need the object to outlive the current scope - that specific object at that specific memory location, not a copy of it. If you're okay with copying/moving the object (most of the time you should be), you should prefer an automatic object.
You need to allocate a lot of memory, which may easily fill up the stack. It would be nice if we didn't have to concern ourselves with this (most of the time you shouldn't have to), as it's really outside the purview of C++, but unfortunately, we have to deal with the reality of the systems we're developing for.
When you do absolutely require dynamic allocation, you should encapsulate it in a smart pointer or some other type that performs RAII (like the standard containers). Smart pointers provide ownership semantics of dynamically allocated objects. Take a look at std::unique_ptr and std::shared_ptr, for example. If you use them appropriately, you can almost entirely avoid performing your own memory management (see the Rule of Zero).
Pointers
However, there are other more general uses for raw pointers beyond dynamic allocation, but most have alternatives that you should prefer. As before, always prefer the alternatives unless you really need pointers.
You need reference semantics. Sometimes you want to pass an object using a pointer (regardless of how it was allocated) because you want the function to which you're passing it to have access that that specific object (not a copy of it). However, in most situations, you should prefer reference types to pointers, because this is specifically what they're designed for. Note this is not necessarily about extending the lifetime of the object beyond the current scope, as in situation 1 above. As before, if you're okay with passing a copy of the object, you don't need reference semantics.
You need polymorphism. You can only call functions polymorphically (that is, according to the dynamic type of an object) through a pointer or reference to the object. If that's the behavior you need, then you need to use pointers or references. Again, references should be preferred.
You want to represent that an object is optional by allowing a nullptr to be passed when the object is being omitted. If it's an argument, you should prefer to use default arguments or function overloads. Otherwise, you should preferably use a type that encapsulates this behavior, such as std::optional (introduced in C++17 - with earlier C++ standards, use boost::optional).
You want to decouple compilation units to improve compilation time. The useful property of a pointer is that you only require a forward declaration of the pointed-to type (to actually use the object, you'll need a definition). This allows you to decouple parts of your compilation process, which may significantly improve compilation time. See the Pimpl idiom.
You need to interface with a C library or a C-style library. At this point, you're forced to use raw pointers. The best thing you can do is make sure you only let your raw pointers loose at the last possible moment. You can get a raw pointer from a smart pointer, for example, by using its get member function. If a library performs some allocation for you which it expects you to deallocate via a handle, you can often wrap the handle up in a smart pointer with a custom deleter that will deallocate the object appropriately.

There are many use cases for pointers.
Polymorphic behavior. For polymorphic types, pointers (or references) are used to avoid slicing:
class Base { ... };
class Derived : public Base { ... };
void fun(Base b) { ... }
void gun(Base* b) { ... }
void hun(Base& b) { ... }
Derived d;
fun(d); // oops, all Derived parts silently "sliced" off
gun(&d); // OK, a Derived object IS-A Base object
hun(d); // also OK, reference also doesn't slice
Reference semantics and avoiding copying. For non-polymorphic types, a pointer (or a reference) will avoid copying a potentially expensive object
Base b;
fun(b); // copies b, potentially expensive
gun(&b); // takes a pointer to b, no copying
hun(b); // regular syntax, behaves as a pointer
Note that C++11 has move semantics that can avoid many copies of expensive objects into function argument and as return values. But using a pointer will definitely avoid those and will allow multiple pointers on the same object (whereas an object can only be moved from once).
Resource acquisition. Creating a pointer to a resource using the new operator is an anti-pattern in modern C++. Use a special resource class (one of the Standard containers) or a smart pointer (std::unique_ptr<> or std::shared_ptr<>). Consider:
{
auto b = new Base;
... // oops, if an exception is thrown, destructor not called!
delete b;
}
vs.
{
auto b = std::make_unique<Base>();
... // OK, now exception safe
}
A raw pointer should only be used as a "view" and not in any way involved in ownership, be it through direct creation or implicitly through return values. See also this Q&A from the C++ FAQ.
More fine-grained life-time control Every time a shared pointer is being copied (e.g. as a function argument) the resource it points to is being kept alive. Regular objects (not created by new, either directly by you or inside a resource class) are destroyed when going out of scope.

There are many excellent answers to this question, including the important use cases of forward declarations, polymorphism etc. but I feel a part of the "soul" of your question is not answered - namely what the different syntaxes mean across Java and C++.
Let's examine the situation comparing the two languages:
Java:
Object object1 = new Object(); //A new object is allocated by Java
Object object2 = new Object(); //Another new object is allocated by Java
object1 = object2;
//object1 now points to the object originally allocated for object2
//The object originally allocated for object1 is now "dead" - nothing points to it, so it
//will be reclaimed by the Garbage Collector.
//If either object1 or object2 is changed, the change will be reflected to the other
The closest equivalent to this, is:
C++:
Object * object1 = new Object(); //A new object is allocated on the heap
Object * object2 = new Object(); //Another new object is allocated on the heap
delete object1;
//Since C++ does not have a garbage collector, if we don't do that, the next line would
//cause a "memory leak", i.e. a piece of claimed memory that the app cannot use
//and that we have no way to reclaim...
object1 = object2; //Same as Java, object1 points to object2.
Let's see the alternative C++ way:
Object object1; //A new object is allocated on the STACK
Object object2; //Another new object is allocated on the STACK
object1 = object2;//!!!! This is different! The CONTENTS of object2 are COPIED onto object1,
//using the "copy assignment operator", the definition of operator =.
//But, the two objects are still different. Change one, the other remains unchanged.
//Also, the objects get automatically destroyed once the function returns...
The best way to think of it is that -- more or less -- Java (implicitly) handles pointers to objects, while C++ may handle either pointers to objects, or the objects themselves.
There are exceptions to this -- for example, if you declare Java "primitive" types, they are actual values that are copied, and not pointers.
So,
Java:
int object1; //An integer is allocated on the stack.
int object2; //Another integer is allocated on the stack.
object1 = object2; //The value of object2 is copied to object1.
That said, using pointers is NOT necessarily either the correct or the wrong way to handle things; however other answers have covered that satisfactorily. The general idea though is that in C++ you have much more control on the lifetime of the objects, and on where they will live.
Take home point -- the Object * object = new Object() construct is actually what is closest to typical Java (or C# for that matter) semantics.

Preface
Java is nothing like C++, contrary to hype. The Java hype machine would like you to believe that because Java has C++ like syntax, that the languages are similar. Nothing can be further from the truth. This misinformation is part of the reason why Java programmers go to C++ and use Java-like syntax without understanding the implications of their code.
Onwards we go
But I can't figure out why should we do it this way. I would assume it
has to do with efficiency and speed since we get direct access to the
memory address. Am I right?
To the contrary, actually. The heap is much slower than the stack, because the stack is very simple compared to the heap. Automatic storage variables (aka stack variables) have their destructors called once they go out of scope. For example:
{
std::string s;
}
// s is destroyed here
On the other hand, if you use a pointer dynamically allocated, its destructor must be called manually. delete calls this destructor for you.
{
std::string* s = new std::string;
delete s; // destructor called
}
This has nothing to do with the new syntax prevalent in C# and Java. They are used for completely different purposes.
Benefits of dynamic allocation
1. You don't have to know the size of the array in advance
One of the first problems many C++ programmers run into is that when they are accepting arbitrary input from users, you can only allocate a fixed size for a stack variable. You cannot change the size of arrays either. For example:
char buffer[100];
std::cin >> buffer;
// bad input = buffer overflow
Of course, if you used an std::string instead, std::string internally resizes itself so that shouldn't be a problem. But essentially the solution to this problem is dynamic allocation. You can allocate dynamic memory based on the input of the user, for example:
int * pointer;
std::cout << "How many items do you need?";
std::cin >> n;
pointer = new int[n];
Side note: One mistake many beginners make is the usage of
variable length arrays. This is a GNU extension and also one in Clang
because they mirror many of GCC's extensions. So the following
int arr[n] should not be relied on.
Because the heap is much bigger than the stack, one can arbitrarily allocate/reallocate as much memory as he/she needs, whereas the stack has a limitation.
2. Arrays are not pointers
How is this a benefit you ask? The answer will become clear once you understand the confusion/myth behind arrays and pointers. It is commonly assumed that they are the same, but they are not. This myth comes from the fact that pointers can be subscripted just like arrays and because of arrays decay to pointers at the top level in a function declaration. However, once an array decays to a pointer, the pointer loses its sizeof information. So sizeof(pointer) will give the size of the pointer in bytes, which is usually 8 bytes on a 64-bit system.
You cannot assign to arrays, only initialize them. For example:
int arr[5] = {1, 2, 3, 4, 5}; // initialization
int arr[] = {1, 2, 3, 4, 5}; // The standard dictates that the size of the array
// be given by the amount of members in the initializer
arr = { 1, 2, 3, 4, 5 }; // ERROR
On the other hand, you can do whatever you want with pointers. Unfortunately, because the distinction between pointers and arrays are hand-waved in Java and C#, beginners don't understand the difference.
3. Polymorphism
Java and C# have facilities that allow you to treat objects as another, for example using the as keyword. So if somebody wanted to treat an Entity object as a Player object, one could do Player player = Entity as Player; This is very useful if you intend to call functions on a homogeneous container that should only apply to a specific type. The functionality can be achieved in a similar fashion below:
std::vector<Base*> vector;
vector.push_back(&square);
vector.push_back(&triangle);
for (auto& e : vector)
{
auto test = dynamic_cast<Triangle*>(e); // I only care about triangles
if (!test) // not a triangle
e.GenericFunction();
else
e.TriangleOnlyMagic();
}
So say if only Triangles had a Rotate function, it would be a compiler error if you tried to call it on all objects of the class. Using dynamic_cast, you can simulate the as keyword. To be clear, if a cast fails, it returns an invalid pointer. So !test is essentially a shorthand for checking if test is NULL or an invalid pointer, which means the cast failed.
Benefits of automatic variables
After seeing all the great things dynamic allocation can do, you're probably wondering why wouldn't anyone NOT use dynamic allocation all the time? I already told you one reason, the heap is slow. And if you don't need all that memory, you shouldn't abuse it. So here are some disadvantages in no particular order:
It is error-prone. Manual memory allocation is dangerous and you are prone to leaks. If you are not proficient at using the debugger or valgrind (a memory leak tool), you may pull your hair out of your head. Luckily RAII idioms and smart pointers alleviate this a bit, but you must be familiar with practices such as The Rule Of Three and The Rule Of Five. It is a lot of information to take in, and beginners who either don't know or don't care will fall into this trap.
It is not necessary. Unlike Java and C# where it is idiomatic to use the new keyword everywhere, in C++, you should only use it if you need to. The common phrase goes, everything looks like a nail if you have a hammer. Whereas beginners who start with C++ are scared of pointers and learn to use stack variables by habit, Java and C# programmers start by using pointers without understanding it! That is literally stepping off on the wrong foot. You must abandon everything you know because the syntax is one thing, learning the language is another.
1. (N)RVO - Aka, (Named) Return Value Optimization
One optimization many compilers make are things called elision and return value optimization. These things can obviate unnecessary copys which is useful for objects that are very large, such as a vector containing many elements. Normally the common practice is to use pointers to transfer ownership rather than copying the large objects to move them around. This has lead to the inception of move semantics and smart pointers.
If you are using pointers, (N)RVO does NOT occur. It is more beneficial and less error-prone to take advantage of (N)RVO rather than returning or passing pointers if you are worried about optimization. Error leaks can happen if the caller of a function is responsible for deleteing a dynamically allocated object and such. It can be difficult to track the ownership of an object if pointers are being passed around like a hot potato. Just use stack variables because it is simpler and better.

Another good reason to use pointers would be for forward declarations. In a large enough project they can really speed up compile time.

In C++, objects allocated on the stack (using Object object; statement within a block) will only live within the scope they are declared in. When the block of code finishes execution, the object declared are destroyed.
Whereas if you allocate memory on heap, using Object* obj = new Object(), they continue to live in heap until you call delete obj.
I would create an object on heap when I like to use the object not only in the block of code which declared/allocated it.

C++ gives you three ways to pass an object: by pointer, by reference, and by value. Java limits you with the latter one (the only exception is primitive types like int, boolean etc). If you want to use C++ not just like a weird toy, then you'd better get to know the difference between these three ways.
Java pretends that there is no such problem as 'who and when should destroy this?'. The answer is: The Garbage Collector, Great and Awful. Nevertheless, it can't provide 100% protection against memory leaks (yes, java can leak memory). Actually, GC gives you a false sense of safety. The bigger your SUV, the longer your way to the evacuator.
C++ leaves you face-to-face with object's lifecycle management. Well, there are means to deal with that (smart pointers family, QObject in Qt and so on), but none of them can be used in 'fire and forget' manner like GC: you should always keep in mind memory handling. Not only should you care about destroying an object, you also have to avoid destroying the same object more than once.
Not scared yet? Ok: cyclic references - handle them yourself, human. And remember: kill each object precisely once, we C++ runtimes don't like those who mess with corpses, leave dead ones alone.
So, back to your question.
When you pass your object around by value, not by pointer or by reference, you copy the object (the whole object, whether it's a couple of bytes or a huge database dump - you're smart enough to care to avoid latter, aren't you?) every time you do '='. And to access the object's members, you use '.' (dot).
When you pass your object by pointer, you copy just a few bytes (4 on 32-bit systems, 8 on 64-bit ones), namely - the address of this object. And to show this to everyone, you use this fancy '->' operator when you access the members. Or you can use the combination of '*' and '.'.
When you use references, then you get the pointer that pretends to be a value. It's a pointer, but you access the members through '.'.
And, to blow your mind one more time: when you declare several variables separated by commas, then (watch the hands):
Type is given to everyone
Value/pointer/reference modifier is individual
Example:
struct MyStruct
{
int* someIntPointer, someInt; //here comes the surprise
MyStruct *somePointer;
MyStruct &someReference;
};
MyStruct s1; //we allocated an object on stack, not in heap
s1.someInt = 1; //someInt is of type 'int', not 'int*' - value/pointer modifier is individual
s1.someIntPointer = &s1.someInt;
*s1.someIntPointer = 2; //now s1.someInt has value '2'
s1.somePointer = &s1;
s1.someReference = s1; //note there is no '&' operator: reference tries to look like value
s1.somePointer->someInt = 3; //now s1.someInt has value '3'
*(s1.somePointer).someInt = 3; //same as above line
*s1.somePointer->someIntPointer = 4; //now s1.someInt has value '4'
s1.someReference.someInt = 5; //now s1.someInt has value '5'
//although someReference is not value, it's members are accessed through '.'
MyStruct s2 = s1; //'NO WAY' the compiler will say. Go define your '=' operator and come back.
//OK, assume we have '=' defined in MyStruct
s2.someInt = 0; //s2.someInt == 0, but s1.someInt is still 5 - it's two completely different objects, not the references to the same one

But I can't figure out why should we use it like this?
I will compare how it works inside the function body if you use:
Object myObject;
Inside the function, your myObject will get destroyed once this function returns. So this is useful if you don't need your object outside your function. This object will be put on current thread stack.
If you write inside function body:
Object *myObject = new Object;
then Object class instance pointed by myObject will not get destroyed once the function ends, and allocation is on the heap.
Now if you are Java programmer, then the second example is closer to how object allocation works under java. This line: Object *myObject = new Object; is equivalent to java: Object myObject = new Object();. The difference is that under java myObject will get garbage collected, while under c++ it will not get freed, you must somewhere explicitly call `delete myObject;' otherwise you will introduce memory leaks.
Since c++11 you can use safe ways of dynamic allocations: new Object, by storing values in shared_ptr/unique_ptr.
std::shared_ptr<std::string> safe_str = make_shared<std::string>("make_shared");
// since c++14
std::unique_ptr<std::string> safe_str = make_unique<std::string>("make_shared");
also, objects are very often stored in containers, like map-s or vector-s, they will automatically manage a lifetime of your objects.

Technically it is a memory allocation issue, however here are two more practical aspects of this.
It has to do with two things:
1) Scope, when you define an object without a pointer you will no longer be able to access it after the code block it is defined in, whereas if you define a pointer with "new" then you can access it from anywhere you have a pointer to this memory until you call "delete" on the same pointer.
2) If you want to pass arguments to a function you want to pass a pointer or a reference in order to be more efficient. When you pass an Object then the object is copied, if this is an object that uses a lot of memory this might be CPU consuming (e.g. you copy a vector full of data). When you pass a pointer all you pass is one int (depending of implementation but most of them are one int).
Other than that you need to understand that "new" allocates memory on the heap that needs to be freed at some point. When you don't have to use "new" I suggest you use a regular object definition "on the stack".

Well the main question is Why should I use a pointer rather than the object itself? And my answer, you should (almost) never use pointer instead of object, because C++ has references, it is safer then pointers and guarantees the same performance as pointers.
Another thing you mentioned in your question:
Object *myObject = new Object;
How does it work? It creates pointer of Object type, allocates memory to fit one object and calls default constructor, sounds good, right? But actually it isn't so good, if you dynamically allocated memory (used keyword new), you also have to free memory manually, that means in code you should have:
delete myObject;
This calls destructor and frees memory, looks easy, however in big projects may be difficult to detect if one thread freed memory or not, but for that purpose you can try shared pointers, these slightly decreases performance, but it is much easier to work with them.
And now some introduction is over and go back to question.
You can use pointers instead of objects to get better performance while transferring data between function.
Take a look, you have std::string (it is also object) and it contains really much data, for example big XML, now you need to parse it, but for that you have function void foo(...) which can be declarated in different ways:
void foo(std::string xml);
In this case you will copy all data from your variable to function stack, it takes some time, so your performance will be low.
void foo(std::string* xml);
In this case you will pass pointer to object, same speed as passing size_t variable, however this declaration has error prone, because you can pass NULL pointer or invalid pointer. Pointers usually used in C because it doesn't have references.
void foo(std::string& xml);
Here you pass reference, basically it is the same as passing pointer, but compiler does some stuff and you cannot pass invalid reference (actually it is possible to create situation with invalid reference, but it is tricking compiler).
void foo(const std::string* xml);
Here is the same as second, just pointer value cannot be changed.
void foo(const std::string& xml);
Here is the same as third, but object value cannot be changed.
What more I want to mention, you can use these 5 ways to pass data no matter which allocation way you have chosen (with new or regular).
Another thing to mention, when you create object in regular way, you allocate memory in stack, but while you create it with new you allocate heap. It is much faster to allocate stack, but it is kind a small for really big arrays of data, so if you need big object you should use heap, because you may get stack overflow, but usually this issue is solved using STL containers and remember std::string is also container, some guys forgot it :)

Let's say that you have class A that contain class B When you want to call some function of class B outside class A you will simply obtain a pointer to this class and you can do whatever you want and it will also change context of class B in your class A
But be careful with dynamic object

There are many benefits of using pointers to object -
Efficiency (as you already pointed out). Passing objects to
functions mean creating new copies of object.
Working with objects from third party libraries. If your object
belongs to a third party code and the authors intend the usage of their objects through pointers only (no copy constructors etc) the only way you can pass around this
object is using pointers. Passing by value may cause issues. (Deep
copy / shallow copy issues).
if the object owns a resource and you want that the ownership should not be sahred with other objects.

This is has been discussed at length, but in Java everything is a pointer. It makes no distinction between stack and heap allocations (all objects are allocated on the heap), so you don't realize you're using pointers. In C++, you can mix the two, depending on your memory requirements. Performance and memory usage is more deterministic in C++ (duh).

Object *myObject = new Object;
Doing this will create a reference to an Object (on the heap) which has to be deleted explicitly to avoid memory leak.
Object myObject;
Doing this will create an object(myObject) of the automatic type (on the stack) that will be automatically deleted when the object(myObject) goes out of scope.

A pointer directly references the memory location of an object. Java has nothing like this. Java has references that reference the location of object through hash tables. You cannot do anything like pointer arithmetic in Java with these references.
To answer your question, it's just your preference. I prefer using the Java-like syntax.

The key strength of object pointers in C++ is allowing for polymorphic arrays and maps of pointers of the same superclass. It allows, for example, to put parakeets, chickens, robins, ostriches, etc. in an array of Bird.
Additionally, dynamically allocated objects are more flexible, and can use HEAP memory whereas a locally allocated object will use the STACK memory unless it is static. Having large objects on the stack, especially when using recursion, will undoubtedly lead to stack overflow.

One reason for using pointers is to interface with C functions. Another reason is to save memory; for example: instead of passing an object which contains a lot of data and has a processor-intensive copy-constructor to a function, just pass a pointer to the object, saving memory and speed especially if you're in a loop, however a reference would be better in that case, unless you're using an C-style array.

In areas where memory utilization is at its premium , pointers comes handy. For example consider a minimax algorithm, where thousands of nodes will be generated using recursive routine, and later use them to evaluate the next best move in game, ability to deallocate or reset (as in smart pointers) significantly reduces memory consumption. Whereas the non-pointer variable continues to occupy space till it's recursive call returns a value.

I will include one important use case of pointer. When you are storing some object in the base class, but it could be polymorphic.
Class Base1 {
};
Class Derived1 : public Base1 {
};
Class Base2 {
Base *bObj;
virtual void createMemerObects() = 0;
};
Class Derived2 {
virtual void createMemerObects() {
bObj = new Derived1();
}
};
So in this case you can't declare bObj as an direct object, you have to have pointer.

tl;dr: Don't "use a pointer rather than the object itself" (usually)
You asked why you should prefer a pointer rather than the object itself. Well, you shouldn't, as a general rule.
Now, there are indeed multiple exceptions to this rule, and other answers have spelled them out. The thing is, these days, many of these exceptions are no longer valid! Let us consider the exceptions listed in the accepted answer:
You need reference semantics.
If you need reference semantics, use references, not pointers; see #ST3's answer's answer. In fact, one could argue that, in Java, what you pass around are usually references.
You need polymorphism.
If you know the set of classes you'll be working with, very often you can just use an std::variant<ClassA, ClassB, ClassC> (see description here) and operate on them using a visitor pattern. Now, granted, C++'s variant implementation is not the prettiest sight; but I'd usually prefer it over getting down-and-dirty with pointers.
You want to represent that an object is optional
Absolutely don't use pointers for that. You have std::optional, and unlike std::variant, it's quite convenient. Use that instead. nullopt is an empty (or "null") optional. And - it's not a pointer.
You want to decouple compilation units to improve compilation time.
You can use references rather than pointers to achieve this as well. To use Object& in a piece of code, it's sufficient to say class Object;, i.e. to use a forward-declaration.
You need to interface with a C library or a C-style library.
Yeah, well, if you work with code that already uses pointers, then - you have to use pointers yourself, can't get around that :-( and C doesn't have references.
Also, some people may tell you to use pointers to avoid making copies of objects. Well this is not really a problem for return values, due to the return-value and named-return-value optimizations (RVO and NRVO). And in other cases - references avoid copying just fine.
The bottom-line rule is still the same as the accepted answer, though: Only use a pointer when you have a good reason to need one.
PS - If you do need a pointer, you should still avoid using new and delete directly. You will probably be better served by a smart pointer - which is automagically freed (not like in Java, but still).

With pointers ,
can directly talk to the memory.
can prevent lot of memory leaks of a program by manipulating pointers.

"Necessity is the mother of invention."
The most of important difference that I would like to point out is the outcome of my own experience of coding.
Sometimes you need to pass objects to functions. In that case, if your object is of a very big class then passing it as an object will copy its state (which you might not want ..AND CAN BE BIG OVERHEAD) thus resulting in an overhead of copying object .while pointer is fixed 4-byte size (assuming 32 bit). Other reasons are already mentioned above...

There are many excellent answers already, but let me give you one example:
I have an simple Item class:
class Item
{
public:
std::string name;
int weight;
int price;
};
I make a vector to hold a bunch of them.
std::vector<Item> inventory;
I create one million Item objects, and push them back onto the vector. I sort the vector by name, and then do a simple iterative binary search for a particular item name. I test the program, and it takes over 8 minutes to finish executing. Then I change my inventory vector like so:
std::vector<Item *> inventory;
...and create my million Item objects via new. The ONLY changes I make to my code are to use the pointers to Items, excepting a loop I add for memory cleanup at the end. That program runs in under 40 seconds, or better than a 10x speed increase.
EDIT: The code is at http://pastebin.com/DK24SPeW
With compiler optimizations it shows only a 3.4x increase on the machine I just tested it on, which is still considerable.

I don't understand the point of pointers to classes [duplicate]

I'm coming from a Java background and have started working with objects in C++. But one thing that occurred to me is that people often use pointers to objects rather than the objects themselves, for example this declaration:
Object *myObject = new Object;
rather than:
Object myObject;
Or instead of using a function, let's say testFunc(), like this:
myObject.testFunc();
we have to write:
myObject->testFunc();
But I can't figure out why should we do it this way. I would assume it has to do with efficiency and speed since we get direct access to the memory address. Am I right?

There are many use cases for pointers.
Polymorphic behavior. For polymorphic types, pointers (or references) are used to avoid slicing:
class Base { ... };
class Derived : public Base { ... };
void fun(Base b) { ... }
void gun(Base* b) { ... }
void hun(Base& b) { ... }
Derived d;
fun(d); // oops, all Derived parts silently "sliced" off
gun(&d); // OK, a Derived object IS-A Base object
hun(d); // also OK, reference also doesn't slice
Reference semantics and avoiding copying. For non-polymorphic types, a pointer (or a reference) will avoid copying a potentially expensive object
Base b;
fun(b); // copies b, potentially expensive
gun(&b); // takes a pointer to b, no copying
hun(b); // regular syntax, behaves as a pointer
Note that C++11 has move semantics that can avoid many copies of expensive objects into function argument and as return values. But using a pointer will definitely avoid those and will allow multiple pointers on the same object (whereas an object can only be moved from once).
Resource acquisition. Creating a pointer to a resource using the new operator is an anti-pattern in modern C++. Use a special resource class (one of the Standard containers) or a smart pointer (std::unique_ptr<> or std::shared_ptr<>). Consider:
{
auto b = new Base;
... // oops, if an exception is thrown, destructor not called!
delete b;
}
vs.
{
auto b = std::make_unique<Base>();
... // OK, now exception safe
}
A raw pointer should only be used as a "view" and not in any way involved in ownership, be it through direct creation or implicitly through return values. See also this Q&A from the C++ FAQ.
More fine-grained life-time control Every time a shared pointer is being copied (e.g. as a function argument) the resource it points to is being kept alive. Regular objects (not created by new, either directly by you or inside a resource class) are destroyed when going out of scope.

Another good reason to use pointers would be for forward declarations. In a large enough project they can really speed up compile time.

In C++, objects allocated on the stack (using Object object; statement within a block) will only live within the scope they are declared in. When the block of code finishes execution, the object declared are destroyed.
Whereas if you allocate memory on heap, using Object* obj = new Object(), they continue to live in heap until you call delete obj.
I would create an object on heap when I like to use the object not only in the block of code which declared/allocated it.

C++ gives you three ways to pass an object: by pointer, by reference, and by value. Java limits you with the latter one (the only exception is primitive types like int, boolean etc). If you want to use C++ not just like a weird toy, then you'd better get to know the difference between these three ways.
Java pretends that there is no such problem as 'who and when should destroy this?'. The answer is: The Garbage Collector, Great and Awful. Nevertheless, it can't provide 100% protection against memory leaks (yes, java can leak memory). Actually, GC gives you a false sense of safety. The bigger your SUV, the longer your way to the evacuator.
C++ leaves you face-to-face with object's lifecycle management. Well, there are means to deal with that (smart pointers family, QObject in Qt and so on), but none of them can be used in 'fire and forget' manner like GC: you should always keep in mind memory handling. Not only should you care about destroying an object, you also have to avoid destroying the same object more than once.
Not scared yet? Ok: cyclic references - handle them yourself, human. And remember: kill each object precisely once, we C++ runtimes don't like those who mess with corpses, leave dead ones alone.
So, back to your question.
When you pass your object around by value, not by pointer or by reference, you copy the object (the whole object, whether it's a couple of bytes or a huge database dump - you're smart enough to care to avoid latter, aren't you?) every time you do '='. And to access the object's members, you use '.' (dot).
When you pass your object by pointer, you copy just a few bytes (4 on 32-bit systems, 8 on 64-bit ones), namely - the address of this object. And to show this to everyone, you use this fancy '->' operator when you access the members. Or you can use the combination of '*' and '.'.
When you use references, then you get the pointer that pretends to be a value. It's a pointer, but you access the members through '.'.
And, to blow your mind one more time: when you declare several variables separated by commas, then (watch the hands):
Type is given to everyone
Value/pointer/reference modifier is individual
Example:
struct MyStruct
{
int* someIntPointer, someInt; //here comes the surprise
MyStruct *somePointer;
MyStruct &someReference;
};
MyStruct s1; //we allocated an object on stack, not in heap
s1.someInt = 1; //someInt is of type 'int', not 'int*' - value/pointer modifier is individual
s1.someIntPointer = &s1.someInt;
*s1.someIntPointer = 2; //now s1.someInt has value '2'
s1.somePointer = &s1;
s1.someReference = s1; //note there is no '&' operator: reference tries to look like value
s1.somePointer->someInt = 3; //now s1.someInt has value '3'
*(s1.somePointer).someInt = 3; //same as above line
*s1.somePointer->someIntPointer = 4; //now s1.someInt has value '4'
s1.someReference.someInt = 5; //now s1.someInt has value '5'
//although someReference is not value, it's members are accessed through '.'
MyStruct s2 = s1; //'NO WAY' the compiler will say. Go define your '=' operator and come back.
//OK, assume we have '=' defined in MyStruct
s2.someInt = 0; //s2.someInt == 0, but s1.someInt is still 5 - it's two completely different objects, not the references to the same one

But I can't figure out why should we use it like this?
I will compare how it works inside the function body if you use:
Object myObject;
Inside the function, your myObject will get destroyed once this function returns. So this is useful if you don't need your object outside your function. This object will be put on current thread stack.
If you write inside function body:
Object *myObject = new Object;
then Object class instance pointed by myObject will not get destroyed once the function ends, and allocation is on the heap.
Now if you are Java programmer, then the second example is closer to how object allocation works under java. This line: Object *myObject = new Object; is equivalent to java: Object myObject = new Object();. The difference is that under java myObject will get garbage collected, while under c++ it will not get freed, you must somewhere explicitly call `delete myObject;' otherwise you will introduce memory leaks.
Since c++11 you can use safe ways of dynamic allocations: new Object, by storing values in shared_ptr/unique_ptr.
std::shared_ptr<std::string> safe_str = make_shared<std::string>("make_shared");
// since c++14
std::unique_ptr<std::string> safe_str = make_unique<std::string>("make_shared");
also, objects are very often stored in containers, like map-s or vector-s, they will automatically manage a lifetime of your objects.

Technically it is a memory allocation issue, however here are two more practical aspects of this.
It has to do with two things:
1) Scope, when you define an object without a pointer you will no longer be able to access it after the code block it is defined in, whereas if you define a pointer with "new" then you can access it from anywhere you have a pointer to this memory until you call "delete" on the same pointer.
2) If you want to pass arguments to a function you want to pass a pointer or a reference in order to be more efficient. When you pass an Object then the object is copied, if this is an object that uses a lot of memory this might be CPU consuming (e.g. you copy a vector full of data). When you pass a pointer all you pass is one int (depending of implementation but most of them are one int).
Other than that you need to understand that "new" allocates memory on the heap that needs to be freed at some point. When you don't have to use "new" I suggest you use a regular object definition "on the stack".

Well the main question is Why should I use a pointer rather than the object itself? And my answer, you should (almost) never use pointer instead of object, because C++ has references, it is safer then pointers and guarantees the same performance as pointers.
Another thing you mentioned in your question:
Object *myObject = new Object;
How does it work? It creates pointer of Object type, allocates memory to fit one object and calls default constructor, sounds good, right? But actually it isn't so good, if you dynamically allocated memory (used keyword new), you also have to free memory manually, that means in code you should have:
delete myObject;
This calls destructor and frees memory, looks easy, however in big projects may be difficult to detect if one thread freed memory or not, but for that purpose you can try shared pointers, these slightly decreases performance, but it is much easier to work with them.
And now some introduction is over and go back to question.
You can use pointers instead of objects to get better performance while transferring data between function.
Take a look, you have std::string (it is also object) and it contains really much data, for example big XML, now you need to parse it, but for that you have function void foo(...) which can be declarated in different ways:
void foo(std::string xml);
In this case you will copy all data from your variable to function stack, it takes some time, so your performance will be low.
void foo(std::string* xml);
In this case you will pass pointer to object, same speed as passing size_t variable, however this declaration has error prone, because you can pass NULL pointer or invalid pointer. Pointers usually used in C because it doesn't have references.
void foo(std::string& xml);
Here you pass reference, basically it is the same as passing pointer, but compiler does some stuff and you cannot pass invalid reference (actually it is possible to create situation with invalid reference, but it is tricking compiler).
void foo(const std::string* xml);
Here is the same as second, just pointer value cannot be changed.
void foo(const std::string& xml);
Here is the same as third, but object value cannot be changed.
What more I want to mention, you can use these 5 ways to pass data no matter which allocation way you have chosen (with new or regular).
Another thing to mention, when you create object in regular way, you allocate memory in stack, but while you create it with new you allocate heap. It is much faster to allocate stack, but it is kind a small for really big arrays of data, so if you need big object you should use heap, because you may get stack overflow, but usually this issue is solved using STL containers and remember std::string is also container, some guys forgot it :)

Let's say that you have class A that contain class B When you want to call some function of class B outside class A you will simply obtain a pointer to this class and you can do whatever you want and it will also change context of class B in your class A
But be careful with dynamic object

There are many benefits of using pointers to object -
Efficiency (as you already pointed out). Passing objects to
functions mean creating new copies of object.
Working with objects from third party libraries. If your object
belongs to a third party code and the authors intend the usage of their objects through pointers only (no copy constructors etc) the only way you can pass around this
object is using pointers. Passing by value may cause issues. (Deep
copy / shallow copy issues).
if the object owns a resource and you want that the ownership should not be sahred with other objects.

This is has been discussed at length, but in Java everything is a pointer. It makes no distinction between stack and heap allocations (all objects are allocated on the heap), so you don't realize you're using pointers. In C++, you can mix the two, depending on your memory requirements. Performance and memory usage is more deterministic in C++ (duh).

Object *myObject = new Object;
Doing this will create a reference to an Object (on the heap) which has to be deleted explicitly to avoid memory leak.
Object myObject;
Doing this will create an object(myObject) of the automatic type (on the stack) that will be automatically deleted when the object(myObject) goes out of scope.

A pointer directly references the memory location of an object. Java has nothing like this. Java has references that reference the location of object through hash tables. You cannot do anything like pointer arithmetic in Java with these references.
To answer your question, it's just your preference. I prefer using the Java-like syntax.

The key strength of object pointers in C++ is allowing for polymorphic arrays and maps of pointers of the same superclass. It allows, for example, to put parakeets, chickens, robins, ostriches, etc. in an array of Bird.
Additionally, dynamically allocated objects are more flexible, and can use HEAP memory whereas a locally allocated object will use the STACK memory unless it is static. Having large objects on the stack, especially when using recursion, will undoubtedly lead to stack overflow.

One reason for using pointers is to interface with C functions. Another reason is to save memory; for example: instead of passing an object which contains a lot of data and has a processor-intensive copy-constructor to a function, just pass a pointer to the object, saving memory and speed especially if you're in a loop, however a reference would be better in that case, unless you're using an C-style array.

In areas where memory utilization is at its premium , pointers comes handy. For example consider a minimax algorithm, where thousands of nodes will be generated using recursive routine, and later use them to evaluate the next best move in game, ability to deallocate or reset (as in smart pointers) significantly reduces memory consumption. Whereas the non-pointer variable continues to occupy space till it's recursive call returns a value.

I will include one important use case of pointer. When you are storing some object in the base class, but it could be polymorphic.
Class Base1 {
};
Class Derived1 : public Base1 {
};
Class Base2 {
Base *bObj;
virtual void createMemerObects() = 0;
};
Class Derived2 {
virtual void createMemerObects() {
bObj = new Derived1();
}
};
So in this case you can't declare bObj as an direct object, you have to have pointer.

With pointers ,
can directly talk to the memory.
can prevent lot of memory leaks of a program by manipulating pointers.

"Necessity is the mother of invention."
The most of important difference that I would like to point out is the outcome of my own experience of coding.
Sometimes you need to pass objects to functions. In that case, if your object is of a very big class then passing it as an object will copy its state (which you might not want ..AND CAN BE BIG OVERHEAD) thus resulting in an overhead of copying object .while pointer is fixed 4-byte size (assuming 32 bit). Other reasons are already mentioned above...

There are many excellent answers already, but let me give you one example:
I have an simple Item class:
class Item
{
public:
std::string name;
int weight;
int price;
};
I make a vector to hold a bunch of them.
std::vector<Item> inventory;
I create one million Item objects, and push them back onto the vector. I sort the vector by name, and then do a simple iterative binary search for a particular item name. I test the program, and it takes over 8 minutes to finish executing. Then I change my inventory vector like so:
std::vector<Item *> inventory;
...and create my million Item objects via new. The ONLY changes I make to my code are to use the pointers to Items, excepting a loop I add for memory cleanup at the end. That program runs in under 40 seconds, or better than a 10x speed increase.
EDIT: The code is at http://pastebin.com/DK24SPeW
With compiler optimizations it shows only a 3.4x increase on the machine I just tested it on, which is still considerable.

How to enforce non-ownership of a pointer?

I have a method which creates an object in an auto_ptr, sticks that auto_ptr into a vector, and then returns a raw pointer to the object for convenience.
The problem with this design is that it returns a raw pointer. It's really easy for the caller to misunderstand that this pointer is non-owned and wrap the result of this call into a managed pointer, which causes a memory access violation when that memory gets double free'd.
int main (void)
{
{
std::auto_ptr<int> foo = ThisMethodReturnsNonOwningPtr(); // Uhoh
}
ThisMethodUsesThePtr(); // Crash
return 0;
}
Ideally, I would like to return something like a pointer which can not be converted to a managed pointer so I don't have to worry about the caller doing this.
Alternatively, I might just return an index into the array, but it's real convenient just being able to pass the pointer around, and who knows maybe I will end up shuffling or sorting the array later.

First, if you can stick an auto_ptr into a vector, it's time to
upgrade your compiler or your library. This hasn't been legal
since the first standard in 1998. If you've got C++11, you can
use std::unique_ptr; if not, you'll need to keep raw pointers
in the vector. In both cases, you'll want to wrap the vector:
with std::unique_ptr, so that the client doesn't have to do
anything fancy to get the actual pointer, and with raw pointers,
so that you can manage the memory associated with them.
For the rest, just return a raw pointer. If you have
programmers that go around deleting random pointers, you're sunk
anyway; most of the time, raw pointers are for navigation, and
are just as likely to point to an object with static lifetime as
to anything else.

Stop using auto_ptr and start using unique_ptr or shared_ptr. The latter has reference counting so you can safely return the object and others can use it. The data it points to will not be freed until all references are released.
there is no other alternative if you need to safely return a pointer to the object and still be able to alter the vector. You could use a unique_ptr to prevent a caller from treating the returned pointer as if it owned it.
Last resort is to slap comments on the code to say that the vector owns the object and the pointer is only to be used as a convenience. Its not as good as getting the compiler to check calling code, but it can be the only way if you restrict your options as you mentioned.

Create a wrapper class template raw_ptr<T> which encapsulates a T*.
If you now implement operator* and operator-> but no conversion operator, you can no longer assign this pointer to another smart pointer, because that assignment would require two custom conversions (raw_ptr<T> → T* → smart_ptr<T>), which is not allowed in C++.
Notice that, as others have said, you should not use auto_ptr<T> – it’s deprecated for good reasons. Use std::unique_ptr<T> instead. For one thing, you cannot actually safely stick auto_ptrs into a std::vector, great care has to be taken to not accidentally copy (and thus invalidate) such pointers.

I'm always reluctant to write answers that depend on boost since not everyone is able to use it and it's almost always overkill to pull it in for just one little thing, but if you have it anyway, you could return a boost::optional<&>. On the surface it doesn't seem an optional reference could work, but it (mostly) does. See boost's documentation.
This would give you the nullability you require (return boost::none to indicate an error) while making it very clear that the caller is not to take ownership of the object.

If you don't want the object to be deleted in conventional means using delete operator, you could make the destructor of the class private and implement destroy() function which self-destructs the object.
Better would be if you could make the function return something like shared_ptr.
A third option could be just to have a class something like template<typename> struct non_ownership_ptr; which the function returns instead of a raw pointer. This pointer class just holds the pointer and you would have to explicitly use auto_ptr<T> p=foo().non_owned_ptr; to avoid (or at least reduce) accidental assignment to auto_ptr or such.

Why should I use a pointer rather than the object itself?

I'm coming from a Java background and have started working with objects in C++. But one thing that occurred to me is that people often use pointers to objects rather than the objects themselves, for example this declaration:
Object *myObject = new Object;
rather than:
Object myObject;
Or instead of using a function, let's say testFunc(), like this:
myObject.testFunc();
we have to write:
myObject->testFunc();
But I can't figure out why should we do it this way. I would assume it has to do with efficiency and speed since we get direct access to the memory address. Am I right?

There are many use cases for pointers.
Polymorphic behavior. For polymorphic types, pointers (or references) are used to avoid slicing:
class Base { ... };
class Derived : public Base { ... };
void fun(Base b) { ... }
void gun(Base* b) { ... }
void hun(Base& b) { ... }
Derived d;
fun(d); // oops, all Derived parts silently "sliced" off
gun(&d); // OK, a Derived object IS-A Base object
hun(d); // also OK, reference also doesn't slice
Reference semantics and avoiding copying. For non-polymorphic types, a pointer (or a reference) will avoid copying a potentially expensive object
Base b;
fun(b); // copies b, potentially expensive
gun(&b); // takes a pointer to b, no copying
hun(b); // regular syntax, behaves as a pointer
Note that C++11 has move semantics that can avoid many copies of expensive objects into function argument and as return values. But using a pointer will definitely avoid those and will allow multiple pointers on the same object (whereas an object can only be moved from once).
Resource acquisition. Creating a pointer to a resource using the new operator is an anti-pattern in modern C++. Use a special resource class (one of the Standard containers) or a smart pointer (std::unique_ptr<> or std::shared_ptr<>). Consider:
{
auto b = new Base;
... // oops, if an exception is thrown, destructor not called!
delete b;
}
vs.
{
auto b = std::make_unique<Base>();
... // OK, now exception safe
}
A raw pointer should only be used as a "view" and not in any way involved in ownership, be it through direct creation or implicitly through return values. See also this Q&A from the C++ FAQ.
More fine-grained life-time control Every time a shared pointer is being copied (e.g. as a function argument) the resource it points to is being kept alive. Regular objects (not created by new, either directly by you or inside a resource class) are destroyed when going out of scope.

Another good reason to use pointers would be for forward declarations. In a large enough project they can really speed up compile time.

In C++, objects allocated on the stack (using Object object; statement within a block) will only live within the scope they are declared in. When the block of code finishes execution, the object declared are destroyed.
Whereas if you allocate memory on heap, using Object* obj = new Object(), they continue to live in heap until you call delete obj.
I would create an object on heap when I like to use the object not only in the block of code which declared/allocated it.

C++ gives you three ways to pass an object: by pointer, by reference, and by value. Java limits you with the latter one (the only exception is primitive types like int, boolean etc). If you want to use C++ not just like a weird toy, then you'd better get to know the difference between these three ways.
Java pretends that there is no such problem as 'who and when should destroy this?'. The answer is: The Garbage Collector, Great and Awful. Nevertheless, it can't provide 100% protection against memory leaks (yes, java can leak memory). Actually, GC gives you a false sense of safety. The bigger your SUV, the longer your way to the evacuator.
C++ leaves you face-to-face with object's lifecycle management. Well, there are means to deal with that (smart pointers family, QObject in Qt and so on), but none of them can be used in 'fire and forget' manner like GC: you should always keep in mind memory handling. Not only should you care about destroying an object, you also have to avoid destroying the same object more than once.
Not scared yet? Ok: cyclic references - handle them yourself, human. And remember: kill each object precisely once, we C++ runtimes don't like those who mess with corpses, leave dead ones alone.
So, back to your question.
When you pass your object around by value, not by pointer or by reference, you copy the object (the whole object, whether it's a couple of bytes or a huge database dump - you're smart enough to care to avoid latter, aren't you?) every time you do '='. And to access the object's members, you use '.' (dot).
When you pass your object by pointer, you copy just a few bytes (4 on 32-bit systems, 8 on 64-bit ones), namely - the address of this object. And to show this to everyone, you use this fancy '->' operator when you access the members. Or you can use the combination of '*' and '.'.
When you use references, then you get the pointer that pretends to be a value. It's a pointer, but you access the members through '.'.
And, to blow your mind one more time: when you declare several variables separated by commas, then (watch the hands):
Type is given to everyone
Value/pointer/reference modifier is individual
Example:
struct MyStruct
{
int* someIntPointer, someInt; //here comes the surprise
MyStruct *somePointer;
MyStruct &someReference;
};
MyStruct s1; //we allocated an object on stack, not in heap
s1.someInt = 1; //someInt is of type 'int', not 'int*' - value/pointer modifier is individual
s1.someIntPointer = &s1.someInt;
*s1.someIntPointer = 2; //now s1.someInt has value '2'
s1.somePointer = &s1;
s1.someReference = s1; //note there is no '&' operator: reference tries to look like value
s1.somePointer->someInt = 3; //now s1.someInt has value '3'
*(s1.somePointer).someInt = 3; //same as above line
*s1.somePointer->someIntPointer = 4; //now s1.someInt has value '4'
s1.someReference.someInt = 5; //now s1.someInt has value '5'
//although someReference is not value, it's members are accessed through '.'
MyStruct s2 = s1; //'NO WAY' the compiler will say. Go define your '=' operator and come back.
//OK, assume we have '=' defined in MyStruct
s2.someInt = 0; //s2.someInt == 0, but s1.someInt is still 5 - it's two completely different objects, not the references to the same one

But I can't figure out why should we use it like this?
I will compare how it works inside the function body if you use:
Object myObject;
Inside the function, your myObject will get destroyed once this function returns. So this is useful if you don't need your object outside your function. This object will be put on current thread stack.
If you write inside function body:
Object *myObject = new Object;
then Object class instance pointed by myObject will not get destroyed once the function ends, and allocation is on the heap.
Now if you are Java programmer, then the second example is closer to how object allocation works under java. This line: Object *myObject = new Object; is equivalent to java: Object myObject = new Object();. The difference is that under java myObject will get garbage collected, while under c++ it will not get freed, you must somewhere explicitly call `delete myObject;' otherwise you will introduce memory leaks.
Since c++11 you can use safe ways of dynamic allocations: new Object, by storing values in shared_ptr/unique_ptr.
std::shared_ptr<std::string> safe_str = make_shared<std::string>("make_shared");
// since c++14
std::unique_ptr<std::string> safe_str = make_unique<std::string>("make_shared");
also, objects are very often stored in containers, like map-s or vector-s, they will automatically manage a lifetime of your objects.

Technically it is a memory allocation issue, however here are two more practical aspects of this.
It has to do with two things:
1) Scope, when you define an object without a pointer you will no longer be able to access it after the code block it is defined in, whereas if you define a pointer with "new" then you can access it from anywhere you have a pointer to this memory until you call "delete" on the same pointer.
2) If you want to pass arguments to a function you want to pass a pointer or a reference in order to be more efficient. When you pass an Object then the object is copied, if this is an object that uses a lot of memory this might be CPU consuming (e.g. you copy a vector full of data). When you pass a pointer all you pass is one int (depending of implementation but most of them are one int).
Other than that you need to understand that "new" allocates memory on the heap that needs to be freed at some point. When you don't have to use "new" I suggest you use a regular object definition "on the stack".

Well the main question is Why should I use a pointer rather than the object itself? And my answer, you should (almost) never use pointer instead of object, because C++ has references, it is safer then pointers and guarantees the same performance as pointers.
Another thing you mentioned in your question:
Object *myObject = new Object;
How does it work? It creates pointer of Object type, allocates memory to fit one object and calls default constructor, sounds good, right? But actually it isn't so good, if you dynamically allocated memory (used keyword new), you also have to free memory manually, that means in code you should have:
delete myObject;
This calls destructor and frees memory, looks easy, however in big projects may be difficult to detect if one thread freed memory or not, but for that purpose you can try shared pointers, these slightly decreases performance, but it is much easier to work with them.
And now some introduction is over and go back to question.
You can use pointers instead of objects to get better performance while transferring data between function.
Take a look, you have std::string (it is also object) and it contains really much data, for example big XML, now you need to parse it, but for that you have function void foo(...) which can be declarated in different ways:
void foo(std::string xml);
In this case you will copy all data from your variable to function stack, it takes some time, so your performance will be low.
void foo(std::string* xml);
In this case you will pass pointer to object, same speed as passing size_t variable, however this declaration has error prone, because you can pass NULL pointer or invalid pointer. Pointers usually used in C because it doesn't have references.
void foo(std::string& xml);
Here you pass reference, basically it is the same as passing pointer, but compiler does some stuff and you cannot pass invalid reference (actually it is possible to create situation with invalid reference, but it is tricking compiler).
void foo(const std::string* xml);
Here is the same as second, just pointer value cannot be changed.
void foo(const std::string& xml);
Here is the same as third, but object value cannot be changed.
What more I want to mention, you can use these 5 ways to pass data no matter which allocation way you have chosen (with new or regular).
Another thing to mention, when you create object in regular way, you allocate memory in stack, but while you create it with new you allocate heap. It is much faster to allocate stack, but it is kind a small for really big arrays of data, so if you need big object you should use heap, because you may get stack overflow, but usually this issue is solved using STL containers and remember std::string is also container, some guys forgot it :)

Let's say that you have class A that contain class B When you want to call some function of class B outside class A you will simply obtain a pointer to this class and you can do whatever you want and it will also change context of class B in your class A
But be careful with dynamic object

There are many benefits of using pointers to object -
Efficiency (as you already pointed out). Passing objects to
functions mean creating new copies of object.
Working with objects from third party libraries. If your object
belongs to a third party code and the authors intend the usage of their objects through pointers only (no copy constructors etc) the only way you can pass around this
object is using pointers. Passing by value may cause issues. (Deep
copy / shallow copy issues).
if the object owns a resource and you want that the ownership should not be sahred with other objects.

This is has been discussed at length, but in Java everything is a pointer. It makes no distinction between stack and heap allocations (all objects are allocated on the heap), so you don't realize you're using pointers. In C++, you can mix the two, depending on your memory requirements. Performance and memory usage is more deterministic in C++ (duh).

Object *myObject = new Object;
Doing this will create a reference to an Object (on the heap) which has to be deleted explicitly to avoid memory leak.
Object myObject;
Doing this will create an object(myObject) of the automatic type (on the stack) that will be automatically deleted when the object(myObject) goes out of scope.

A pointer directly references the memory location of an object. Java has nothing like this. Java has references that reference the location of object through hash tables. You cannot do anything like pointer arithmetic in Java with these references.
To answer your question, it's just your preference. I prefer using the Java-like syntax.

The key strength of object pointers in C++ is allowing for polymorphic arrays and maps of pointers of the same superclass. It allows, for example, to put parakeets, chickens, robins, ostriches, etc. in an array of Bird.
Additionally, dynamically allocated objects are more flexible, and can use HEAP memory whereas a locally allocated object will use the STACK memory unless it is static. Having large objects on the stack, especially when using recursion, will undoubtedly lead to stack overflow.

One reason for using pointers is to interface with C functions. Another reason is to save memory; for example: instead of passing an object which contains a lot of data and has a processor-intensive copy-constructor to a function, just pass a pointer to the object, saving memory and speed especially if you're in a loop, however a reference would be better in that case, unless you're using an C-style array.

In areas where memory utilization is at its premium , pointers comes handy. For example consider a minimax algorithm, where thousands of nodes will be generated using recursive routine, and later use them to evaluate the next best move in game, ability to deallocate or reset (as in smart pointers) significantly reduces memory consumption. Whereas the non-pointer variable continues to occupy space till it's recursive call returns a value.

I will include one important use case of pointer. When you are storing some object in the base class, but it could be polymorphic.
Class Base1 {
};
Class Derived1 : public Base1 {
};
Class Base2 {
Base *bObj;
virtual void createMemerObects() = 0;
};
Class Derived2 {
virtual void createMemerObects() {
bObj = new Derived1();
}
};
So in this case you can't declare bObj as an direct object, you have to have pointer.

With pointers ,
can directly talk to the memory.
can prevent lot of memory leaks of a program by manipulating pointers.

"Necessity is the mother of invention."
The most of important difference that I would like to point out is the outcome of my own experience of coding.
Sometimes you need to pass objects to functions. In that case, if your object is of a very big class then passing it as an object will copy its state (which you might not want ..AND CAN BE BIG OVERHEAD) thus resulting in an overhead of copying object .while pointer is fixed 4-byte size (assuming 32 bit). Other reasons are already mentioned above...

There are many excellent answers already, but let me give you one example:
I have an simple Item class:
class Item
{
public:
std::string name;
int weight;
int price;
};
I make a vector to hold a bunch of them.
std::vector<Item> inventory;
I create one million Item objects, and push them back onto the vector. I sort the vector by name, and then do a simple iterative binary search for a particular item name. I test the program, and it takes over 8 minutes to finish executing. Then I change my inventory vector like so:
std::vector<Item *> inventory;
...and create my million Item objects via new. The ONLY changes I make to my code are to use the pointers to Items, excepting a loop I add for memory cleanup at the end. That program runs in under 40 seconds, or better than a 10x speed increase.
EDIT: The code is at http://pastebin.com/DK24SPeW
With compiler optimizations it shows only a 3.4x increase on the machine I just tested it on, which is still considerable.

Best way of returning a pointer

I have seen at least 5 C++ tutorial sites that return pointers this way:
int* somefunction(){
int x = 5;
int *result = &x;
return result;
}
Is that not a very, VERY bad idea? My logic tells me that the returned pointer's value can be overwritten at any time. I would rather think that this would be the right solution:
int* somefuntion(){
int x = 5;
int* result = new int;
*(result) = x;
return result;
}
And then leave the calling function to delete the pointer. Or am i wrong?

Your instinct about the problem is correct- UB is the result. However, your proposed solution is le bad. "Leave the caller to delete it" is hideously error prone and unadvisable. Instead, return it in some owning class that properly encapsulates it's intended usage- preferably std::unique_ptr<int>.

Yes, the first option will return a dangling pointer, and leads to undefined behavior. Your second option is correct, although you could just write:
int* somefuntion(){
return new int(5);
}
or having a static variable inside the method and returning its address.

Yes, the first example is not good as you'll be returning a pointer to memory that the system may re-purpose for something else. The second example is better, but still risks leaking memory as it's not clear to the caller of somefunction that it's their responsibility to delete the memory that's pointed at.
Something like this might be better:
std::unique_ptr<int> somefunction(){
int x = 5;
std::unique_ptr<int> result( new int );
*result = x;
return result;
}
This way, the unique_ptr will take care of delete'ing the memory that you new'ed, and will helpfully help to eliminate potential memory leaks.

Your question mixes several different issues into one. In reality, the main question here is whether you really need that mixture.
There's no such thing as "returning a pointer" by itself. You don't "return a pointer" just because you want to "return a pointer". Returning pointers is done for some specific reason and that reason will dictate how it is done and what needs to be done in order to ensure that it works properly.
Your original example does not really illustrate that since in your original example there's simply no meaningful reason to return a pointer. It looks like you can simply return an int.
For example, in many cases you'll want to return a pointer because it is a pointer to a dynamically allocated object, i.e. an object whose lifetime is not subject to scoping rules of the language. Note that the casual relationship in this case works in the opposite direction: you need a dynamic object -> you have to return a pointer. That way, not the other way around. In you example you seem to use it backwards: I want to return a pointer -> I have to allocate the object dynamically. That latter reasoning is fundamentally flawed, although one might see it used more often than one would expect.
If you really need a dynamically allocated object (for which, as I said above, the main reason is to override the scope-based lifetime rules of the language), then a matter of memory ownership becomes an issue. In order to know when this memory can/has to be deallocated and who has to deallocate it, you have to implement either exclusive (one designated owner at any moment) or shared (like reference counting) ownership scheme. It can be done with raw pointers, but a better idea would be to use various smart pointer classes provided by the libraries.
But in many situations you can also return pointers to non-dynamic objects (static or automatic), which is perfectly fine assuming that the lifetime of these pointers is the same or shorter than the lifetime of the objects they point to.
In other words, the reasoning behind the decision to return a pointer is not really different between C and C++. It is more design/intent-related than language-related. It is just that C++ provides you with more tools to make your life easier once you already decided to return a pointer. (Which sometimes works as incentive for C++ programmers to overuse concealed pointers).
In any case, again, this is an issue of what functionality you are trying to implement. Once you know that, you can make a good decision about whether you should "return a pointer" or not. And if you finally decided to return a pointer, it will help you to choose the proper return method. That's how it works. Trying to think about it backwards ("I just want to return a pointer, but I don't have a real reason for it yet") will only produce academically useless answers, each of which can be shown to be "wrong" in some specific circumstances.

As you suspected and others clarified, the first method is clearly wrong. Although C++ is a systems language and there are some circumstances where you might want do do this (it would return a particular, relative location on the stack, on most systems), it's ALMOST NEVER right. The second method is much more sane.
However, neither method should be encouraged in C++. One of the main points of C++ is that you now have references and exceptions rather than just the pointers of C. So what you do is return a reference, and allow new to throw an exception up the stack, if the memory allocation fails.

Don't forget to
delete
pointer after invocation of your method, which is correct.

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