OpenCV - get grey value from an image - c++

Hello everybody right now I'm trying to getting grey value for every pixel in an image
what I mean with grey value is the white or black level from an image let's say 0 for white and 1 for black. for an example for this image
the value I want will be like
0 0 0 0 0 0
0 1 1 1 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 0 0 0 0
is this possible? if yes how to do it with OpenCV in C? or if it's impossible with OpenCV is there any other library that can do this?

What you ask is certainly possible but how it can be done depends on a lot of things. If you use C++, on SO we generally expect you to use the C++ interface which means you have a cv::Mat object and loaded the image with something like this: (using namespace cv)
#include <opencv2/core/core.hpp>
Mat mat_gray = imread(path, CV_LOAD_IMAGE_GRAYSCALE);
or by
Mat mat = imread(path); // and assuming it was originally a color image...
Mat mat_gray;
cvtColor(mat, mat_gray, CV_BGR2GRAY); //...convert it to grayscale.
Now, if you just want to access pixel values one-by-one, you use _Tp& mat.at<_Tp>(int x,int y);. That is:
for(int x=0; x<mat_gray.rows; ++x)
for(int y=0; y<mat_gray.cols; ++y)
mat_gray.at<uchar>(x,y); // if mat.type == CV_8U
You can look up your type here, which you should use in place of uchar if the mat.type is other than CV_8U.
As for the pure C interface, you can check this answer. But if you use C++, you should definitely use the C++ interface.

Related

OpenCV: OutputArray usage without copy

I need to extend kernel from one channel to more channels. For example from
0 1 0
1 -4 1
0 1 0
to
0 0 0 1 1 1 0 0 0
1 1 1 -4 -4 -4 1 1 1
0 0 0 1 1 1 0 0 0
following standard three channels cv::Mat.
I have following code:
void createKernel(InputArray _A, InputArray _B, OutputArray _kernel, const int chn)
{
Mat A = _A.getMat();
Mat B = _B.getMat();
Mat kernel;
Mat kernelOneChannel = A * B;
std::vector<Mat> channels;
for (int i = 0; i < chn; i++)
{
channels.push_back(kernelOneChannel);
}
merge(channels, kernel);
kernel.copyTo(_kernel);
}
One channel kernel is copied to std:vector as many times based on the chn. After that is one multi channel cv::Mat created.
My question is about the last line kernel.copyTo(_kernel). In many examples what I have seen, this is the way how to deal with Outputarray. Is this copyTo really needed? It seems to me like waste of memory and time to copy already computed kernel to the _kernel. Is there any solution without this data copy from one structure to another?
My question is strictly related to OpenCV and mentioned structures.
Thanks in advance.
In your specific case you can pass _kernel variable directly to merge call to avoid unnessesary copy:
merge(channels, _kernel)
In general case the OutputArray object is supposed to be used in the following way:
_outArr.create(size, type);
Mat outMat = _outArr.getMat();
Now the outMat variable can be filled without extra copies.

How to create circular mask for Mat object in OpenCV / C++?

My goal is to create a circular mask on a Mat object, so e.g. for a Mat looking like this:
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
...modify it such that I obtain a "circular shape" of 1s within it, so .e.g.
0 0 0 0 0
0 0 1 0 0
0 1 1 1 0
0 0 1 0 0
0 0 0 0 0
I am currently using the following code:
typedef struct {
double radius;
Point center;
} Circle;
...
for (Circle c : circles) {
// get the circle's bounding rect
Rect boundingRect(c.center.x-c.radius, c.center.y-c.radius, c.radius*2,c.radius*2);
// obtain the image ROI:
Mat circleROI(stainMask_, boundingRect);
int radius = floor(radius);
circle(circleROI, c.center, radius, Scalar::all(1), 0);
}
The problem is that after my call to circle, there is at most only one field in the circleROI set to 1... According to my understanding, this code should work because circle is supposed to use the information about the center and the radius to modify circleROI such that all points that are within the area of the circle should be set to 1... does anyone have an explanation for me what I am doing wrong? Am I taking the right approach to the problem but the actual issue might be somewhere else (this is very much possible too, since I am a novice to C++ and OpenCv)?
Note that I also tried to modify the last parameter in the circle call (which is the thickness of the circle outline) to 1 and -1, without any effect.
It is because you're filling your circleROI with a coordinate of the circle in the big mat. Your circle coordinate inside the circleROI should be relative to the circleROI, which is, in your case: new_center = (c.radius, c.radius), new_radius = c.radius.
Here is a snipcode for the loop:
for (Circle c : circles) {
// get the circle's bounding rect
Rect boundingRect(c.center.x-c.radius, c.center.y-c.radius, c.radius*2+1,c.radius*2+1);
// obtain the image ROI:
Mat circleROI(stainMask_, boundingRect);
//draw the circle
circle(circleROI, Point(c.radius, c.radius), c.radius, Scalar::all(1), -1);
}
Take a look at: getStructuringElement
http://docs.opencv.org/modules/imgproc/doc/filtering.html

Better ways to create a rectangular mask by openCV

Creating a mask in openCV
/** result I want
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 1 1 1 1 0 0
0 0 1 1 1 1 0 0
0 0 1 1 1 1 0 0
0 0 1 1 1 1 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
*/
cv::Mat mask = cv::Mat::zeros(8, 8, CV_8U);
std::cout<<"before : \n"<<mask<<std::endl;
for(int i = 2; i != 6; ++i)
{
auto ptr = mask.ptr<uchar>(i) + 2;
for(int j = 0; j != 4; ++j)
{
*ptr++ = 1;
}
}
std::cout<<"after : \n"<<mask<<std::endl;
Do openCV provide us any build in function to create a mask like this?
It is trivial to create a function fot this task, but the function of openCV
always faster than naive handcrafted codes
sure, there's an easier way, use the roi operator:
cv::Mat mask = cv::Mat::zeros(8, 8, CV_8U); // all 0
mask(Rect(2,2,4,4)) = 1;
done!
If some one is looking for creating a non rectangular mask and then to apply it on the image then have a look here :
Mat& obtainIregularROI(Mat& origImag, Point2f topLeft, Point2f topRight, Point2f botLeft, Point2f botRight){
static Mat black(origImag.rows, origImag.cols, origImag.type(), cv::Scalar::all(0));
Mat mask(origImag.rows, origImag.cols, CV_8UC1, cv::Scalar(0));
vector< vector<Point> > co_ordinates;
co_ordinates.push_back(vector<Point>());
co_ordinates[0].push_back(topLeft);
co_ordinates[0].push_back(botLeft);
co_ordinates[0].push_back(botRight);
co_ordinates[0].push_back(topRight);
drawContours( mask,co_ordinates,0, Scalar(255),CV_FILLED, 8 );
origImag.copyTo(black,mask);
return black;
}
"black" is the image where we will finally obtain the result by cropping out the irregular ROI from the original image.
static Mat black(origImag.rows, origImag.cols, origImag.type(), cv::Scalar::all(0));
The "mask" is a Mat, initialized as the same size of original image and filled with 0.
Mat mask(origImag.rows, origImag.cols, CV_8UC1, cv::Scalar(0));
Putting the coordinates in ANTICLOCKWISE direction
vector< vector<Point> > co_ordinates;
co_ordinates.push_back(vector<Point>());
co_ordinates[0].push_back(topLeft);
co_ordinates[0].push_back(botLeft);
co_ordinates[0].push_back(botRight);
co_ordinates[0].push_back(topRight);
Now generating the mask actually
drawContours( mask,co_ordinates,0, Scalar(255),CV_FILLED, 8 );
At the end copy the masked portion/ROI from original image (origImag) and paste on the portion of ROI from the original image (using mask) into image named as "black"
origImag.copyTo(black,mask);

OpenCV imencode pgm doesn't encode the correct format

I am trying to encode a Mat CV_32FC1 image to send it over the internet with base64, the process works but the OpenCV encodes in the wrong format. Example:
vector<unsigned char> buffer;
vector<int> compression_params;
compression_params.push_back(CV_IMWRITE_PXM_BINARY);
compression_params.push_back(0);
cv::imencode(".pgm", desc, buffer, compression_params);
printf("%s", &buffer[0]);
This generates the following output:
P2
64 15
255
0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0
etc..
According to the compression parameter and the first parameter (P2) it shouldn't be encoded as a binary format, it should be ASCII. (Source)
In itself this isn't a problem, but when I change compression_params.push_back(0) to compression_params.push_back(1) I get this output (without image data):
P5
64 15
255
I am using OpenCV 2.4.4 on iOS, how can I fix this or alternatively how can I send a Mat the good way without losing data?
Don't know if you have resolved your problem but I figured out the problem and it might apply to your case too even though you are using the iOS version, which I am not familiar with:
How do I capture images in OpenCV and saving in pgm format?

going from Inverse discrete FFT to spectrogram

I need to locate some generic C++ library that takes the inverse fft output (fftw_complex format, i.e. two doubles) and converts this data to an image file such as png. I can waterfall the dffts to obtain the 2d data (and use 10log10(rere+imim) to obtain magnitudes for each frequency component) but I don't know which image library will work.
I did use an older program called zimage at one time, but it seems no longer available. I do not have MATLAB on my Ubuntu 9.10 system (but I do have Octave)
Can Octave generate the waterfall images? I also need to convert the spectrogram into a wav sound file too.
Any ideas??
The easiest image format to create is PNM. You can print it as a text file, and then convert it using most graphics programs. Here is an example from the Wikipedia page:
P2 24 7 15
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 3 3 3 3 0 0 7 7 7 7 0 0 11 11 11 11 0 0 15 15 15 15 0
0 3 0 0 0 0 0 7 0 0 0 0 0 11 0 0 0 0 0 15 0 0 15 0
0 3 3 3 0 0 0 7 7 7 0 0 0 11 11 11 0 0 0 15 15 15 15 0
0 3 0 0 0 0 0 7 0 0 0 0 0 11 0 0 0 0 0 15 0 0 0 0
0 3 0 0 0 0 0 7 7 7 7 0 0 11 11 11 11 0 0 15 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Save that text in a file named "feep.pgm", and you'll see what I mean.
http://en.wikipedia.org/wiki/Netpbm_format
You'll have to scale your 10log10 information to pixel values.
OpenCV is one library that can handle PNG files, among a variety of other formats. It should be readily available on your Ubuntu 9.10 system using apt get libcv-dev (from memory, you may have to double-check the package name).
/*
* compile with:
*
* g++ -Wall -ggdb -I. -I/usr/include/opencv -L /usr/lib -lm -lcv -lhighgui -lcvaux filename.cpp -o filename.out
*/
#include <cv.h>
#include <highgui.h>
/*
* Your image dimensions.
*/
int width;
int height;
CvSize size = cvSize(width, height);
/*
* Create 3-channel image, unsigned 8-bit per channel.
*/
IplImage *image = cvCreateImage(size, IPL_DEPTH_8U, 3);
for (int i = 0; i < width; ++i)
for (int j = 0; j < height; ++j)
{
unsigned int r;
unsigned int g;
unsigned int b;
/*
* Keep in mind that OpenCV stores things in BGR order.
*/
CvScalar bgr = cvScalar(b, g, r);
cvSet2D(image, i, j, bgr);
}
cvSaveImage("filename.png", image);
cvReleaseImage(&image);