checking a member of struct to be only alphabetic - c++

Question

I tried to use,
if(isalpha(card[i].name))
...
but it says that i can't use it with char type here is my code:
This is the struct:
struct firm {
unsigned egn;
char name[80];
char lastname[80];
char department[80];
unsigned salary;
}card[100];
This is the function where i want to make the check if only letters then to continue:
void enter()
{
int i, n;
char temp[80];
do{
cout<<"Enter how many workers you want to add: ";cin>>n;
}while(!(n>0 && n<101));
for(i=top;i<n;i++)
{/*ЕГН + проверка*/
cout<<"Enter EGN: ";do{
cin>>temp;
if((strlen(temp)!=10))
cout<<"Enter EGN: ";
}while(strlen(temp)!=10);
card[i].egn = (unsigned) atoi (temp);
/*Име Фамилия*/
cout<<"Enter name(only letters): ";cin>>card[i].name;
cout<<"Enter lastname(only letters): ";cin>>card[i].lastname;
cout<<"Enter department: ";cin>>card[i].department;
cout<<"Enter salary: ";cin>>temp;
card[i].salary = (unsigned) atoi (temp);
}
}
When i try to use this kind of code:
cout<<"Enter name(only letters): ";do{
cin>>card[i].name;
if(isalpha(card[i].name))
.....;
and it says that i can't use char in int (isalpha uses int? )

Answer 1

You need to loop over every character of the string, isalpha() only tests a single character.

Answer 2

You cannot use isalpha on an entire char array, only on individual characters. To check that every character in a char array is alphabetical, you can use the std::all_of algorithm:
auto name_begin = std::begin(card[i].name);
auto name_end = std::end(card[i].name);
bool name_alpha = std::all_of(name_begin, std::find(name_begin, name_end, '\0'), std::isalpha);
if (name_alpha) {
std::cout << "It's alphabetical!" << std::endl;
}
If you're using a compiler without the necessary C++11 support, you can do:
char* name_begin = card[i].name;
bool name_alpha = std::all_of(name_begin, name_begin+std::strlen(name_begin), std::isalpha);
if (name_alpha) {
std::cout << "It's alphabetical!" << std::endl;
}
Then the boring way without using the standard library algorithms:
bool name_alpha = true;
for (char* character = card[i].name; *character != '\0'; character++) {
if (!std::isalpha(*character)) {
name_alpha = false;
break;
}
}
if (name_alpha) {
std::cout << "It's alphabetical!" << std::endl;
}

Answer 3

The problem is that name is itself an array of chars, so you need to test each each element something like this:
.....
cout<<"Enter name(only letters): ";do{
cin>>card[i].name;
bool bIsAlpha = true;
for (int j = 0; j < strlen(card[i].name); ++j)
{
if(!isalpha(card[i].name[j]))
{
bIsAlpha = false;
break;
}
}
if (bIsAlpha)
{
.....;
}