Reading binary text into array? - c++

I have a program that I need to read binary text into. I read the binary text via a redirection:
readData will be an executable made by my Makefile.
Example: readData < binaryText.txt
What I want to do is read the binary text, and store each character in the binary text file as a character inside a char array. The binary text is made up of 32 This is my attempt at doing so...
unsigned char * buffer;
char d;
cin.seekg(0, ios::end);
int length = cin.tellg();
cin.seekg(0, ios::beg);
buffer = new unsigned char [length];
while(cin.get(d))
{
cin.read((char*)&buffer, length);
cout << buffer[(int)d] << endl;
}
However, I keep getting a segmentation fault on this. Might anyone have any ideas on how to read binary text into a char array? Thanks!

I'm more a C programmer rather than a C++, but I think that you should have started your while loop
while(cin.get(&d)){

The easiest would be like this:
std::istringstream iss;
iss << std::cin.rdbuf();
// now use iss.str()
Or, all in one line:
std::string data(static_cast<std::istringstream&>(std::istringstream() << std::cin.rdbuf()).str());

Something like this should do the trick.
You retrieve the filename from the arguments and then read the whole file in one shot.
const char *filename = argv[0];
vector<char> buffer;
// open the stream
std::ifstream is(filename);
// determine the file length
is.seekg(0, ios_base::end);
std::size_t size = is.tellg();
is.seekg(0, std::ios_base::beg);
// make sure we have enough memory space
buffer.reserve(size);
buffer.resize(size, 0);
// load the data
is.read((char *) &buffer[0], size);
// close the file
is.close();
You then just need to iterate over the vector to read characters.

The reason why you are getting segmentation fault is because you are trying to access an array variable using a character value.
Problem:
buffer[(int)d] //d is a ASCII character value, and if the value exceeds the array's range, there comes the segfault.
If what you want is an character array, you already have that from cin.read()
Solution:
cin.read(reinterpret_cast<char*>(buffer), length);
If you want to print out, just use printf
printf("%s", buffer);
I used reinterpret_cast because it thought it is safe to convert to signed character pointer since most characters that are used would range from 0 ~ 127. You should know that character values from 128 to 255 would be converted wrongly.

Related

Load shellcode from file to char* comes strange characters in end of text

I have a char array[] and is like following:
// MessageBox
char xcode[] = "\x31\xc9\x64\x8b\x41\x30\x8b\x40\xc\x8b\x70\x14\xad\x96\xad\x8b\x58\x10\x8b\x53\x3c\x1\xda\x8b\x52\x78\x1\xda\x8b\x72\x20\x1\xde\x31\xc9\x41\xad\x1\xd8\x81\x38\x47\x65\x74\x50\x75\xf4\x81\x78\x4\x72\x6f\x63\x41\x75\xeb\x81\x78\x8\x64\x64\x72\x65\x75\xe2\x8b\x72\x24\x1\xde\x66\x8b\xc\x4e\x49\x8b\x72\x1c\x1\xde\x8b\x14\x8e\x1\xda\x31\xc9\x53\x52\x51\x68\x61\x72\x79\x41\x68\x4c\x69\x62\x72\x68\x4c\x6f\x61\x64\x54\x53\xff\xd2\x83\xc4\xc\x59\x50\x51\x66\xb9\x6c\x6c\x51\x68\x33\x32\x2e\x64\x68\x75\x73\x65\x72\x54\xff\xd0\x83\xc4\x10\x8b\x54\x24\x4\xb9\x6f\x78\x41\x0\x51\x68\x61\x67\x65\x42\x68\x4d\x65\x73\x73\x54\x50\xff\xd2\x83\xc4\x10\x68\x61\x62\x63\x64\x83\x6c\x24\x3\x64\x89\xe6\x31\xc9\x51\x56\x56\x51\xff\xd0";
Then i had inserted all this content of variable above into a file (file with UTF-8 format and content without the "") and tried load this way:
ifstream infile;
infile.open("shellcode.bin", std::ios::in | std::ios::binary);
infile.seekg(0, std::ios::end);
size_t file_size_in_byte = infile.tellg();
char* xcode = (char*)malloc(sizeof(char) * file_size_in_byte);
infile.seekg(0, std::ios::beg);
infile.read(xcode, file_size_in_byte);
printf("%s\n", xcode); // << prints content of xcode after load from file
if (infile.eof()) {
size_t bytes_really_read = infile.gcount();
}
else if (infile.fail()) {
}
infile.close();
I'm seeing some strange characters in end of text see:
What is need to fix it?
The issue is that the printf format specifier "%s" requires that the string is null-terminated. In your case, the null-terminator just happens to be after those characters you're seeing, but nothing guarantees where the null is unless you put one there.
Since you're using C++, one way to print the characters is to use the write() function available for streams:
#include <iostream>
//...
std::cout.write(xcode, file_size_in_bytes);
The overall point is this -- if you have a character array that is not null-terminated and contains data, you must either:
Put the null in the right place before using the array in functions that look for the null-terminator or
Use functions that state how many characters to process from the character array.
The answer above uses item 2.

Problems with file i/o using strings in c++ [duplicate]

Im having problems writing string into a binary file. This is my code:
ofstream outfile("myfile.txt", ofstream::binary);
std::string text = "Text";
outfile.write((char*) &text, sizeof (string));
outfile.close();
Then, I try to read it,
char* buffer = (char*) malloc(sizeof(string));
ifstream infile("myfile.txt", ifstream::binary);
infile.read(buffer, sizeof (prueba));
std::string* elem = (string*) buffer;
cout << *elem;
infile.close();
I just cant get it to work. I am sorry, I am just desperate. Thank you!
To write a std::string to a binary file, you need to save the string length first:
std::string str("whatever");
size_t size=str.size();
outfile.write(&size,sizeof(size));
outfile.write(&str[0],size);
To read it in, reverse the process, resizing the string first so you will have enough space:
std::string str;
size_t size;
infile.read(&size, sizeof(size));
str.resize(size);
infile.read(&str[0], size);
Because strings have a variable size, unless you put that size in the file you will not be able to retrieve it correctly. You could rely on the '\0' marker that is guaranteed to be at the end of a c-string or the equivalent string::c_str() call, but that is not a good idea because
you have to read in the string character by character checking for the null
a std::string can legitimately contain a null byte (although it really shouldn't because calls to c_str() are then confusing).
the line
outfile.write((char*) &text, sizeof (string));
is not correct
sizeof(string) doesn't return the length of the string, it returns the sizeof the string type in bytes.
also do not cast text to char* using a C cast, you can get hold of the char* by using the appropriate member function text.c_str()
you can simply write
outfile << text;
instead.
Why are you using pointers to std::string class?
You should not use sizeof with std::string, as it returns the size of the std::string object, and not the real size of the string inside.
You should try:
string text = "Text";
outfile.write(text.c_str(), text.size());
or
outfile << text;
Should probably also use c_str() to get the char pointer too, instead of that straight crazy cast.
Your code is wrong wrong way you are using to write & read the file
and file extension error you are trying to read text file .txt
correct code
Write to file
std::string text = "Text";
ofstream outfile("myfile.dat", ofstream::binary | ios::out);
outfile.write(&text,sizeof (string));//can take type
outfile.write(&text,sizeof (text));//can take variable name
outfile.close();
reading file
char* buffer = (char*) malloc(sizeof(string));
ifstream infile("myfile.dat", ifstream::binary | ios::in);
infile.read(buffer, sizeof (prueba));
std::string* elem = (string*) buffer;
cout << *elem;
infile.close();
Try This it will work
I had the same problem. I found the perfect answer here: Write file in binary format
Key issues: use string::length to get the length of the string when writing out and use resize() before reading the string. And both for reading and writing, use mystring.c_str() instead the string itself.
Try this code snippet.
/* writing string into a binary file */
fstream ifs;
ifs.open ("c:/filename.exe", fstream::binary | fstream::in | fstream::out);
if (ifs.is_open())
{
ifs.write("string to binary", strlen("string to binary"));
ifs.close();
}
Here is a good example.

Quickly convert raw data to hex string in c++

I'm reading data from a file and trying to display the raw data as 2 digit hex strings.
I'm using the Qt framework, specifically the QTextEdit.
I've tried a bunch of different approaches and have almost accomplished what I want it to do, however it has some unexpected errors I don't know anything about.
Currently this is my implementation:
1) Read in the data:
ifstream file (filePath, ios::in|ios::binary|ios::ate);
if (file.is_open())
{
size = file.tellg();
memblock = new char [size+1];
file.seekg(0, ios::beg);
file.read(memblock, size);
file.close();
}
2) Create a single QString that will be used (because QTextEdit requires a QString):
QString s;
3) Loop through the array appending each successive character to the QString s.
int count = 0;
for(i=0;i<size;i++)
{
count++;;
s.append(QString::number(memblock[i], 16).toUpper());
s.append("\t");
if (count == 16)
{
s.append("\n");
count -= 16;
}
}
Now this works fine, except when it reaches a character FF, it appears as FFFFFFFFFFFFFFFF
So my main questions are:
Why do only the 'FF' characters appear as 'FFFFFFFFFFFFFFFF' instead?
Is there a way to convert the char data to base 16 strings without using QString::number?
I want this implementation to be as fast as possible, so if something like sprintf could work, please let me know, as I would guess that might be faster that QString::number.
QString can't be used for binary data. You should use QByteArray instead. It can be easily created from char* buffer and can be easily converted to hex string using toHex.
QByteArray array(memblock, size);
textEdit->setText(QString(array.toHex()));
QString::number doesn't have an overload that takes a char, so your input is being promoted to an int; consequently you're seeing the effects of sign extension. You should be seeing similar behavior for any input greater than 0x7F.
Try casting the data prior to calling the function.
s.append(QString::number(static_cast<unsigned char>(memblock[i]), 16).toUpper());

Best way to compare input values to read values from files

I am relatively new to c++ programming and I have hit one of my first major snags in all of this..
I am trying to figure out how to read a value/character from a generic ".txt" file that is on notepad. With that comparison I want to determine whether or not to read that entire line, but I can't seem to just read the single one or two digit number, I got it to read the whole line using { 'buffername'.getline(variable, size) } but when I try to change the 'size' to a specific number it gives me a comparison error saying that its invalid to switch to 'int' or 'char' (depending on how I declare the variable).
Any help is appreciated.
Thanks
int length = 2;
char * buffer;
ifstream is;
is.open ("test.txt", ios::binary );
// allocate memory:
buffer = new char [length];
// read 2 char
is.read (buffer,length);
//Compare the character and decide
delete[] buffer;
return 0;
You'll want to use an ifstream to get the value (ref 1).
Something like the following should work. Here I use a word of type std::string, but you can replace that with other types to read them (ie: int, double, etc...).
std::ifstream f("somefile.txt");
std::string word;
std::string line;
if(f >> word){
if(<the comparison>){
line = f.getline();
}
}
Here's an extended example of how to use the ifstream
First of all, for performance reasons it is a bad idea to read 1 byte at a time.
I suggest this alternative:
You would be better off reading in the whole line, and then using character array.
char variable[1000];
read your line in from the file into variable.
if (variable[1]=='c') { printf("Byte 2 (remember 0 offset) is compared for the letter c";}
getting a 2 digit #
number=((variable[3]-48)*10)+(variable[4]-48);
You have to subtract 48 because in ASCII the number 0 is 48.

C++ Char pointer to char array

None of the posted answers I've read work, so I'm asking again.
I'm trying to copy the string data pointed to by a char pointer into a char array.
I have a function that reads from a ifstream into a char array
char* FileReader::getNextBytes(int numberOfBytes) {
char *buf = new char[numberOfBytes];
file.read(buf, numberOfBytes);
return buf;
}
I then have a struct :
struct Packet {
char data[MAX_DATA_SIZE]; // can hold file name or data
} packet;
I want to copy what is returned from getNextBytes(MAX_DATA_SIZE) into packet.data;
EDIT: Let me show you what I'm getting with all the answers gotten below (memcpy, strcpy, passing as parameter). I'm thinking the error comes from somewhere else. I'm reading a file as binary (it's a png). I'll loop while the fstream is good() and read from the fstream into the buf (which might be the data array). I want to see the length of what I've read :
cout << strlen(packet.data) << endl;
This returns different sizes every time:
8
529
60
46
358
66
156
After that, apparently there are no bytes left to read although the file is 13K + bytes long.
This can be done using standard library function memcpy, which is declared in / :
strcpy(packet.data, buf);
This requires file.read returns proper char series that ends with '\0'. You might also want to ensure numberOfBytes is big enough to accommodate the whole string. Otherwise you could possibly get segmentation fault.
//if buf not properly null terminated added a null char at the end
buf[numberofbytes] = "\0"
//copy the string from buf to struc
strcpy(packet.data, buf);
//or
strncpy(packet.data, buf);
Edit:
Whether or not this is being handled as a string is a very important distinction. In your question, you referred to it as a "string", which is what got us all confused.
Without any library assistance:
char result = reader.getNextBytes(MAX_DATA_SIZE);
for (int i = 0; i < MAX_DATA_SIZE; ++MAX_DATA_SIZE) {
packet.data[i] = result[i];
}
delete [] result;
Using #include <cstring>:
memcpy(packet.data, result, MAX_DATA_SIZE);
Or for extra credit, rewrite getNextBytes so it has an output parameter:
char* FileReader::getNextBytes(int numberOfBytes, char* buf) {
file.read(buf, numberOfBytes);
return buf;
}
Then it's just:
reader.getNextBytes(MAX_DATA_SIZE, packet.data);
Edit 2:
To get the length of a file:
file.seekg (0, ios::end);
int length = file.tellg();
file.seekg (0, ios::beg);
And with that in hand...
char* buffer = new char[length];
file.read(buffer, length);
Now you have the entire file in buffer.
strlen is not a valid way to determine the amount of binary data. strlen just reads until it finds '\0', nothing more. If you want to read a chunk of binary data, just use a std::vector, resize it to the amount of bytes you read from the file, and return it as value. Problem solved.