How does this C++ code work? - c++

Question

enum STR2INT_ERROR { SUCCESS, OVERFLOW, UNDERFLOW, INCONVERTIBLE };
STR2INT_ERROR str2int (int &i, char const *s, int base = 0)
{
char *end;
long l;
errno = 0;
l = strtol(s, &end, base);
if ((errno == ERANGE && l == LONG_MAX) || l > INT_MAX) {
return OVERFLOW;
}
if ((errno == ERANGE && l == LONG_MIN) || l < INT_MIN) {
return UNDERFLOW;
}
if (*s == '\0' || *end != '\0') {
return INCONVERTIBLE;
}
i = l;
return SUCCESS;
}
I'm trying to write a program that can parse strings read in from a file into integer values. While looking for a method to do this I found this piece of code above on a stackoverflow post:
How to parse a string to an int in C++?
However, I can't understand how it works.
Specifically, why is the programmer checking if errno == ERANGE if errno is assigned to 0? (is ERANGE a special value? )
secondly, what does "char const *s" - in the arguments list- mean?
PS: I'm not very experienced when it comes to C++ programming.

Answer 1

The code is using strtol() to do the parsing. This is a standard C library function. You can find documentation on strtol() here amongst other places:
strtol() man page on die.net
The errno variable is a special global variable defined by the standard C library. If a function encounters an error it is set to an error code. So while errno is assigned zero at the start of the routine, the strtol() function will assign a new value to errno if it encounters an error. The following if-statements are checking for the overflow and underflow error conditions.
The char const *s parameter is the string to be parsed. Its a pointer to a constant (read-only) string of characters. By convention strings are terminated by a NULL byte.

Answer 2

Whenever I have done string to int conversions in C++ I used the atoi method. There should be plenty of examples online that suit what you want to do

Answer 3

Most of the specialness here is with errno, not the values being compared to.
errno is a global that's used by some (especially older) library functions to signal errors. You assign 0 to it (which implicitly means there's no problem). Then, if it runs into a problem, a library function can assign some non-zero value to it to tell you want went wrong.
After calling the library function, you then typically check 1) whether it's now non-zero, and 2) if so, what value it has. Based on the value that's been assigned, you can react to the type of error that arose.
I should add, however, that many uses of errno are mostly non-portable. The C standard says that errno exists, that no library function assigns 0 to errno, but not a lot more more than that. It does not specify what non-zero values any particular function may assign to it (well, it specifies some non-zero values that some functions assign, but doesn't limit assignments to those values or those functions).

Answer 4

First of all, this is clearly a C program in C++ disguise.
strtol is a function from standard C library, which does the actual work. Its doumentation may be accessed there: http://linux.die.net/man/3/strtol
All other things are just preliminaries and checks.
errno is a special global variable from the C library which may be modified by standard functions in order to set an appropriate error code (yes, it's C legacy and this is not thread-safe). Its value may be set to values defined in standard header "errno.h".

Answer 5

errno is a library-provided global variable that strtol (as well as other library functions) uses to indicate error conditions. In the above code strtol could change errno after the user set it to 0. ERANGE is indeed a named constant provided by the standard library, which stands for some special value used by strtol to indicate out-of-range errors.
Your char const *s question is too vague. What specifically do you not understand in it? The const part means that the user code inside str2int will not be allowed to modify the string pointed by s. The compiler will do its best to prevent any modifying (or potentially modifying) operations on string pointed by s.