Counting the frequency of characters in a file. C++ - c++

Question

The task is to print the (given text file) encountered Latin characters using the frequency table (without distinguishing between uppercase and lowercase letters) to file f1. The table must be sorted alphabetically.
So far my program only counts the letter A. I'm having problems with creating the loops which go through the whole alphabet and prints the table into another file, could you help me with those?
#include <stdio.h>
const char FILE_NAME[] = "yo.txt";
#include <stdlib.h>
#include <iostream>
using namespace std;
int main() {
int count = 0; /* number of characters seen */
FILE *in_file; /* input file */
/* character or EOF flag from input */
int ch;
in_file = fopen(FILE_NAME, "r");
if (in_file == NULL) {
printf("Cannot open %s\n", FILE_NAME);
system("Pause");
exit(8);
}
while (1) {
char cMyCharacter = 'A';
int value = (int)cMyCharacter;
ch = fgetc(in_file);
if (ch == EOF){
break;
}
int file_character = (int) ch;
if (file_character == value || file_character == value+ 32) {
count++;
}
}
printf("Number of characters in %s is %d\n", FILE_NAME, count);
char cMyCharacter = 'A';
int iMyAsciiValue = (int)cMyCharacter;
cout << iMyAsciiValue;
system("Pause");
fclose(in_file);
return 1;
}

Answer 1

First, get an array of size 26 for frequencies of a to z
int freq[26] = {0};
freq[0] for 'a', freq[1] for 'b', etc.
Second, change
if (file_character == value || file_character == value+ 32)
to
if (file_character >= 'a' && file_character <= 'z')
for all the lower-case alphabets (i.e. 'a' to 'z').
Third, get index and count by
freq[file_character - 'a']++;
, file_character - 'a' calculates the index, and the rest does count.
Fourth, print the freq array.
Fifth, add
else if (file_character >= 'A' && file_character <= 'Z')
for upper-case characters, and change subsequent codes accordingly.
It is your homework, you should try to figure out the whole program yourself. I hope this answer provides enough hints for you.