I have an the input xml as:
<group>
<item>
<id>item 1</id>
<CategoryName>blue</CategoryName>
<id>item 2</id>
<CategoryName>orange</CategoryName>
<id>item 3</id>
<CategoryName>green</CategoryName>
</item>
</group>
and I want to transform it to
<group>
<item>
<itemNode><id>item 1</id><itemNode>
<Color>blue</Color>
<itemNode><id>item 2</id><itemNode>
<Color>orange</Color>
<itemNode><id>item 3</id><itemNode>
<Color>green</Color>
</item>
When I use xpath, it shows itemNodes tags first and then Color tags but not in the sequence the data was orignally in.
Any ideas how I can transform but still maintain the sequence?
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="item">
<group>
<item>
<xsl:for-each select="id">
<xsl:variable name="pos" select="position()" />
<itemNode><id><xsl:value-of select="."/></id></itemNode>
<color><xsl:value-of select="../CategoryName[$pos]"/></color>
</xsl:for-each>
</item>
</group>
</xsl:template>
</xsl:stylesheet>
Related
Please note that source xml fieldscome in sequence means one student's info then another student info.
Can you help on the XSLT to break xml as one group node for each student
My Input is Below
<?xml version="1.0" encoding="UTF-8" ?>
<root>
<item>
<columnName>StudentID</columnName>
<value>2356</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Java</value>
</item>
<item>
<columnName>City</columnName>
<value>Chicago</value>
</item>
<item>
<columnName>StudentID</columnName>
<value>4578</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Net</value>
</item>
<item>
<columnName>City</columnName>
<value>NewYork</value>
</item>
<item>
<columnName>StudentID</columnName>
<value>5892</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Office</value>
</item>
<item>
<columnName>City</columnName>
<value>Dallas</value>
</item>
</root>
I need Output
<?xml version="1.0" encoding="UTF-8" ?>
<root>
<Record>
<item>
<columnName>StudentID</columnName>
<value>2356</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Java</value>
</item>
<item>
<columnName>City</columnName>
<value>Chicago</value>
</item>
</Record>
<Record>
<item>
<columnName>StudentID</columnName>
<value>4578</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Net</value>
</item>
<item>
<columnName>City</columnName>
<value>NewYork</value>
</item>
</Record>
<Record>
<item>
<columnName>StudentID</columnName>
<value>5892</value>
</item>
<item>
<columnName>StudentName</columnName>
<value>Office</value>
</item>
<item>
<columnName>City</columnName>
<value>Dallas</value>
</item>
</Record>
</root>
Please note that source xml fileds come in sequence means one student info then another student info.
Can you help on the XSLT to break xml as one group node for each student
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" encoding="utf-8" indent="yes"/>
<xsl:template match="root">
<root>
<Record>
<xsl:apply-templates select="data"/>
</Record>
<Record/>
</root>
</xsl:template>
<xsl:template match="data">
<data>
<xsl:apply-templates select="columnName"/>
<xsl:apply-templates select="value"/>
</data>
</xsl:template>
<xsl:template match="columnName">
<columnName>
<xsl:value-of select="."/>
</columnName>
</xsl:template>
<xsl:template match="value">
<value>
<xsl:value-of select="."/>
</value>
</xsl:template>
</xsl:stylesheet>
Please note that source xml fileds come in sequence means one student info then another student info.
Can you help on the XSLT to break xml as one group node for each student
Assuming that items always come in groups of three, you could do simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/root">
<xsl:copy>
<xsl:for-each select="item[position() mod 3 = 1]">
<Record>
<xsl:copy-of select=". | following-sibling::item[position() < 3]"/>
</Record>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I'm trying to get my head over nested grouping and sorting while using for-each-group.
My idea is to order and group items at first by producer. Then when I have this producer groups I'd like to sort each of them by code. However currently the order of code doesn't work as I'd like to. In following example the problem is with item with code=01001-064-03. It should be grouped together with all other items whose code starts with 01001 but it isn't. If I move entire item/code[text()='01001-064-03'] (the last one) to the beginning of xml then grouping works ok.
Please what is my issue here?
Thanks
<items>
<change_date>#11.11.2020 7:42:13</change_date>
<result>
<item>
<code>01001-064-01</code>
<producer>prod1</producer>
</item>
<item>
<code>01001-064-02</code>
<producer>prod1</producer>
</item>
<item>
<code>def</code>
<producer>prod1</producer>
</item>
<item>
<code>ghi</code>
<producer>prod2</producer>
</item>
<item>
<code>jkl</code>
<producer>prod3</producer>
</item>
<item>
<code>abc</code>
<producer>prod3</producer>
</item>
<item>
<code>def</code>
<producer>prod4</producer>
</item>
<item>
<code>ghi</code>
<producer>prod4</producer>
</item>
<item>
<code>jkl</code>
<producer>prod5</producer>
</item>
<item>
<code>01001-064-03</code>
<producer>prod1</producer>
</item>
</result>
</items>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
xmlns:map="http://www.w3.org/2005/xpath-functions/map"
xmlns:array="http://www.w3.org/2005/xpath-functions/array"
xmlns:mf="http://example.com/mf"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-copy"/>
<xsl:output method="xml" indent="yes" html-version="5"/>
<xsl:function name="mf:same-product" as="xs:boolean">
<xsl:param name="left" as="xs:string"/>
<xsl:param name="right" as="xs:string"/>
<xsl:variable name="leftParsed" select="mf:get-regexp-group($left, 1)"/>
<xsl:variable name="rightParsed" select="mf:get-regexp-group($right, 1)"/>
<xsl:sequence select="matches($leftParsed, $rightParsed)"/>
</xsl:function>
<xsl:function name="mf:get-regexp-group" as="xs:string">
<xsl:param name="text" as="xs:string"/>
<xsl:param name="groupNumber" as="xs:integer"/>
<xsl:variable name="result">
<xsl:analyze-string select="$text" regex="(^[a-zA-Z0-9]+)(.*)">
<xsl:matching-substring>
<xsl:value-of select="regex-group($groupNumber)"/>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:variable>
<xsl:sequence select="$result"/>
</xsl:function>
<xsl:template match="items">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="change_date"/>
<xsl:template match="result">
<data>
<xsl:for-each-group select="item" group-by="producer">
<xsl:sort select="producer"/>
<xsl:for-each-group select="current-group()" group-starting-with="item[not(mf:same-product(code, preceding-sibling::item[1]/code))]">
<xsl:sort select="code"/>
<group>
<xsl:apply-templates select="current-group()" />
</group>
</xsl:for-each-group>
</xsl:for-each-group>
</data>
</xsl:template>
<xsl:template match="item">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>
fiddle example here
I'm using xslt 2.0 with saxon-he 10.3.
EDIT:
So as #michael.hor257k asked for better explanation I'll try to do my best:
Each item is product. This product has producer and has code (product code). I want to group all products of producer by code. However codes are not same for similar products so the similarity is matched by function mf:same-product. For example two similar products could be 01001-064-01 and 01001-064-02 here I check the first prefix 01001 and if it matches it means both products should be added to same group.
expected result should look like this:
<?xml version="1.0" encoding="UTF-8"?>
<data>
<group>
<item>
<code>01001-064-01</code>
<producer>prod1</producer>
</item>
<item>
<code>01001-064-02</code>
<producer>prod1</producer>
</item>
<item>
<code>01001-064-03</code>
<producer>prod1</producer>
</item>
</group>
<group>
<item>
<code>def</code>
<producer>prod1</producer>
</item>
</group>
<group>
<item>
<code>ghi</code>
<producer>prod2</producer>
</item>
</group>
<group>
<item>
<code>abc</code>
<producer>prod3</producer>
</item>
</group>
<group>
<item>
<code>jkl</code>
<producer>prod3</producer>
</item>
</group>
<group>
<item>
<code>def</code>
<producer>prod4</producer>
</item>
</group>
<group>
<item>
<code>ghi</code>
<producer>prod4</producer>
</item>
</group>
<group>
<item>
<code>jkl</code>
<producer>prod5</producer>
</item>
</group>
</data>
Perhaps a composite group-by suffices:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-skip"/>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="change_date"/>
<xsl:template match="result">
<data>
<xsl:for-each-group select="item" composite="yes" group-by="producer, code => replace('[^a-z0-9].*$', '', 'i')">
<xsl:sort select="producer"/>
<xsl:sort select="code"/>
<group>
<xsl:apply-templates select="current-group()" />
</group>
</xsl:for-each-group>
</data>
</xsl:template>
<xsl:template match="item">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>
https://xsltfiddle.liberty-development.net/ei5R4uT/10
That is XSLT 3 which Saxon 9.8 and later (e.g. Saxon 10) support, if you really need to do it with an XSLT 2.0 processor then a nested for-each-group group-by or a concatenated grouping key can achieve the same as the composite grouping key in the above XSLT 3.
My idea is to order and group items at first by producer. Then when I have this producer groups I'd like to sort each of them by code.
If that's all you want to do, why isn't it sufficient to do:
XSLT 3.0
<xsl:stylesheet version="3.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="result">
<xsl:for-each-group select="item" group-by="producer">
<xsl:sort select="producer"/>
<group>
<xsl:apply-templates select="current-group()">
<xsl:sort select="code"/>
</xsl:apply-templates>
</group>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
I'm using xslt 2.0 with saxon-he 10.3.
Actually, you are using XSLT 3.0.
I have a list of values that I need to summarize distinct item quantities. A simple version would look like this:
<?xml version="1.0" encoding="UTF-8"?>
<Items xmlns:boomi="http://boomi.com/custom-function">
<Item>
<id>801</id>
<qty>0</qty>
</Item>
<Item>
<id>802</id>
<qty>1</qty>
</Item>
<Item>
<id>802</id>
<qty>1</qty>
</Item>
</Items>
I'm using the following XSLT
<Items>
<xsl:for-each select="distinct-values(/Items/Item/id)" >
<Item>
<id>
<xsl:value-of select="current()" />
</id>
</Item>
</xsl:for-each>
</Items>
To generate the following document
<?xml version="1.0" encoding="UTF-8"?>
<Items xmlns:boomi="http://boomi.com/custom-function">
<Item>
<id>801</id>
</Item>
<Item>
<id>802</id>
</Item>
</Items>
But I also need to include quantities. I've tried a few things, this being the closest, but doesn't work:
<Items>
<xsl:for-each select="distinct-values(/Items/Item/id)" >
<Item>
<id>
<xsl:value-of select="current()" />
<xsl:value-of select="sum(/Items/Item[id=current()]/qty)" />
</id>
</Item>
</xsl:for-each>
</Items>
I think it's not working because current() is an actual node? I'm trying to get to this:
<?xml version="1.0" encoding="UTF-8"?>
<Items xmlns:boomi="http://boomi.com/custom-function">
<Item>
<id>801</id>
<qty>0</qty>
</Item>
<Item>
<id>802</id>
<qty>2</qty>
</Item>
</Items>
Am I going about this in completely the wrong way? Thanks.
Here is the(a) solution using XSLT 2.0 indicated by michael.hor257k
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:boomi="http://boomi.com/custom-function">
<xsl:template match="/">
<Items>
<xsl:for-each-group select="/Items/Item" group-by="id" >
<Item>
<id>
<xsl:value-of select="current-grouping-key()" />
</id>
<qty>
<xsl:value-of select="sum(current-group()/qty)" />
</qty>
</Item>
</xsl:for-each-group>
</Items>
</xsl:template>
</xsl:stylesheet>
I need to split the following XML file based on a predetermined value, for this example, lets assume I want to limit the "Item" node to three (3) within each file created.
Here's a sample input XML file:
<Items>
<Item>
<Title>Title 1</Title>
<DueDate>01-02-2008</DueDate>
</Item>
<Item>
<Title>Title 2</Title>
<DueDate>01-02-2009</DueDate>
</Item>
<Item>
<Title>Title 3</Title>
<DueDate>01-02-2010</DueDate>
</Item>
<Item>
<Title>Title 4</Title>
<DueDate>01-02-2011</DueDate>
</Item>
<Item>
<Title>Title 5</Title>
<DueDate>01-02-2012</DueDate>
</Item>
<Item>
<Title>Title 6</Title>
<DueDate>01-02-2013</DueDate>
</Item>
<Item>
<Title>Title 7</Title>
<DueDate>01-02-2013</DueDate>
</Item>
</Items>
The desired output based on the threshold value of 3, would be three files, two of which contain 3 "Item", and the last one containing the remaining "items", which would be one.
Here's a sample of my XSLT which does allow me to split them for each item, which results into seven separate files, however, what I desire is to limit the size of the file based on a certain limit of "Item" node per file.
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" indent="yes" name="xml" />
<xsl:template match="/">
<xsl:for-each select="//Item">
<xsl:variable name="nTitle" select="Title"/>
<xsl:variable name="filename" select="concat('Items\',$nTitle,'-','.xml')" />
<xsl:value-of select="$filename" />
<xsl:result-document href="{$filename}" format="xml">
<xsl:copy-of select="."/>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This stylesheet:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="pItemsNumber" select="3"/>
<xsl:template match="Items">
<xsl:for-each-group select="Item"
group-adjacent="(position()-1) idiv $pItemsNumber">
<xsl:result-document href="Items\{current-grouping-key()}.xml">
<Items>
<xsl:copy-of select="current-group()"/>
</Items>
</xsl:result-document>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<Items>
<Item>
<Title>Title 1</Title>
<DueDate>01-02-2008</DueDate>
</Item>
<Item>
<Title>Title 2</Title>
<DueDate>01-02-2009</DueDate>
</Item>
<Item>
<Title>Title 3</Title>
<DueDate>01-02-2010</DueDate>
</Item>
</Items>
<?xml version="1.0" encoding="UTF-8"?>
<Items>
<Item>
<Title>Title 4</Title>
<DueDate>01-02-2011</DueDate>
</Item>
<Item>
<Title>Title 5</Title>
<DueDate>01-02-2012</DueDate>
</Item>
<Item>
<Title>Title 6</Title>
<DueDate>01-02-2013</DueDate>
</Item>
</Items>
<?xml version="1.0" encoding="UTF-8"?>
<Items>
<Item>
<Title>Title 7</Title>
<DueDate>01-02-2013</DueDate>
</Item>
</Items>
Edit: Oops!
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pSplitNum" select="3"/>
<xsl:template match="node()|#*" name="identity">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Item[position() mod $pSplitNum eq 1]">
<xsl:result-document href=
"file{position()}-{min((position()+$pSplitNum -1, count(/*/Item)))}.xml">
<Items>
<xsl:call-template name="identity"/>
<xsl:apply-templates mode="copy" select=
"following-sibling::Item[position() lt $pSplitNum]"/>
</Items>
</xsl:result-document>
</xsl:template>
<xsl:template match="/*"><xsl:apply-templates/></xsl:template>
<xsl:template match="Item[position() mod $pSplitNum ne 1]"/>
</xsl:stylesheet>
when applied on the provided XML document:
<Items>
<Item>
<Title>Title 1</Title>
<DueDate>01-02-2008</DueDate>
</Item>
<Item>
<Title>Title 2</Title>
<DueDate>01-02-2009</DueDate>
</Item>
<Item>
<Title>Title 3</Title>
<DueDate>01-02-2010</DueDate>
</Item>
<Item>
<Title>Title 4</Title>
<DueDate>01-02-2011</DueDate>
</Item>
<Item>
<Title>Title 5</Title>
<DueDate>01-02-2012</DueDate>
</Item>
<Item>
<Title>Title 6</Title>
<DueDate>01-02-2013</DueDate>
</Item>
<Item>
<Title>Title 7</Title>
<DueDate>01-02-2013</DueDate>
</Item>
</Items>
produces the wanted three xml files:
Saxon 9.1.0.5J from Saxonica
Java version 1.6.0_22
Stylesheet compilation time: 645 milliseconds
Processing file:/C:/Program%20Files/Java/jre6/bin/marrowtr.xml
Building tree for file:/C:/Program%20Files/Java/jre6/bin/marrowtr.xml using class net.sf.saxon.tinytree.TinyBuilder
Tree built in 10 milliseconds
Tree size: 38 nodes, 119 characters, 0 attributes
Loading net.sf.saxon.event.MessageEmitter
Writing to file:/C:/Program%20Files/Java/jre6/bin/file1-3.xml
Writing to file:/C:/Program%20Files/Java/jre6/bin/file4-6.xml
Writing to file:/C:/Program%20Files/Java/jre6/bin/file7-7.xml
Execution time: 101 milliseconds
Memory used: 11453088
NamePool contents: 20 entries in 20 chains. 6 prefixes, 7 URIs
Do note:
This is a simple application of the identity rule pattern.
Every Item starting a new file is matched and it causes the wrapping in a top element, processing of itself and the next $pSplitNum -1 (or whatever remains in the last group), and outputting this as a single result-document (file).
The name of every file created is: "filex-y.xml", where x and y are the starting and ending indexes of the Item elements written in the file.
Every Item that isn't starting a new file is deleted by an empty matching template. Such elements are processed in "copy" mode.
You could implement a counter that is declared outside of your loop. When the counter hits 3, reset it and set a new filename. Otherwise, increment and append to the existing filename.
I have an xml file like this:
<root>
<item>
<name>one</name>
<status>good</status>
</item>
<item>
<name>two</name>
<status>good</status>
</item>
<item>
<name>three</name>
<status>bad</status>
</item>
<item>
<name>four</name>
<status>ugly</status>
</item>
<item>
<name>five</name>
<status>bad</status>
</item>
</root>
I want to transform this using XSLT to get something like:
<root>
<items><status>good</status>
<name>one</name>
<name>two</name>
</items>
<items><status>bad</status>
<name>three</name>
<name>five</name>
</items>
<items><status>ugly</status>
<name>four</name>
</items>
</root>
In other words, I get a list of items, each with a status, and I want to turn it into a list of statuses, each with a list of items.
My initial thought was to do apply-templates matching each status type in turn, but that means I have to know the complete list of statuses. Is there a better way to do it?
Thanks for any help.
Muench to the rescue!
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" encoding="UTF-8"/>
<xsl:key name="muench" match="/root/item/status" use="."/>
<xsl:template match="/">
<root>
<xsl:for-each select="/root/item/status[generate-id() = generate-id(key('muench',.)[1])]">
<xsl:call-template name="pivot">
<xsl:with-param name="status" select="."/>
</xsl:call-template>
</xsl:for-each>
</root>
</xsl:template>
<xsl:template name="pivot">
<xsl:param name="status"/>
<items>
<status><xsl:value-of select="$status"/></status>
<xsl:for-each select="/root/item[status=$status]">
<name><xsl:value-of select="name"/></name>
</xsl:for-each>
</items>
</xsl:template>
</xsl:stylesheet>
Yes, this can be done in XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<!-- -->
<xsl:key name="kStatByVal"
match="status" use="."/>
<!-- -->
<xsl:key name="kItemByStat"
match="item" use="status"/>
<!-- -->
<xsl:variable name="vDoc" select="/"/>
<xsl:template match="/">
<top>
<xsl:for-each select=
"/*/*/status[generate-id()
=
generate-id(key('kStatByVal',.)[1])
]">
<items>
<status><xsl:value-of select="."/></status>
<xsl:for-each select="key('kItemByStat', .)">
<xsl:copy-of select="name"/>
</xsl:for-each>
</items>
</xsl:for-each>
</top>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the original XML document:
<root>
<item>
<name>one</name>
<status>good</status>
</item>
<item>
<name>two</name>
<status>good</status>
</item>
<item>
<name>three</name>
<status>bad</status>
</item>
<item>
<name>four</name>
<status>ugly</status>
</item>
<item>
<name>five</name>
<status>bad</status>
</item>
</root>
The wanted result is produced:
<top>
<items>
<status>good</status>
<name>one</name>
<name>two</name>
</items>
<items>
<status>bad</status>
<name>three</name>
<name>five</name>
</items>
<items>
<status>ugly</status>
<name>four</name>
</items>
</top>
Do note the use of:
The Muenchian method for grouping
The use of <xsl:key> and the key() function
It depends about your xslt engine. If you're using xslt 1.0 without any extension, then your approach is certainly the best.
On the other side, if you're allowed to use exslt (especially the node-set extension) or xslt 2.0, then you could do it in a more generic way:
Collect all the available statuses
Create a node-set from the obtained result
Iterating on this node set, create your pivot by filtering you status base on the current element in your iteration.
But before doing that, consider that it may be overkill if you only have a few set of statuses and that adding another status is quite rare.
In XSLT 2.0 you can replace the muenchian grouping by its standard grouping mechanism. Applied to the given answer the xslt would look like:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" encoding="UTF-8"/>
<xsl:key name="muench" match="/root/item/status" use="."/>
<xsl:template match="/">
<root>
<xsl:for-each-group select="/root/item/status" group-by="key('muench', .)">
<xsl:call-template name="pivot">
<xsl:with-param name="status" select="."/>
</xsl:call-template>
</xsl:for-each-group>
</root>
</xsl:template>
<xsl:template name="pivot">
<xsl:param name="status"/>
<items>
<status><xsl:value-of select="$status"/></status>
<xsl:for-each select="/root/item[status=$status]">
<name><xsl:value-of select="name"/></name>
</xsl:for-each>
</items>
</xsl:template>
</xsl:stylesheet>