I'm having trouble with a regular expression, I have several images with file name that need changing. I've done them by hand. It was quick easy and painless. However, I wanted to know what I needed to do as a simple replacement reg ex using JavaScript. And that's when it doesn't quite work out. The image is called "muti blossom 02.png" and it's going to be re-sized and saved out as JPEGs with the name "iOS_multi_BLOSSOM_2048.jpg". The others are of the same form but have different nouns; winter, leaf, circus etc.
The file-name is structured as follows:
"mutli" at the start (lower case),
white space,
the noun (lower case),
white-space,
a number (that may have a preceding 0 and may be one or two digits),
file extension which may be .png or .psd (lowercase).
It then needs to be changed to:
iOS_multi (camel case as written),
noun (UPPERCASE),
2048 (new fixed size),
new file extension .jpg(lowercase).
I know that ([a-z]+\s) matches "multi" and that (\s\d+.[a-z]+$) will match the numbers and file extension, but have no idea how to successfully match the bit in the middle as well. And do the uppercase on the noun. But I'm sure there is someone else that does. Thank you.
In JavaScript regex you cannot do this with a replace as it is not possible to uppercase the replacement text. However the match method will return an array which you can then manipulate.
var oldImageName = "multi blossom 02.png";
var matches = oldImageName.match(/multi (\w+) \d{1,2}\.(?:png|psd)/);
var newImageName = "iOS_multi_" + matches[1].toUpperCase() + "_2048.jpg";
Note: this assumes that the "noun" is a single word with no spaces
I was searching for "javascript Regex to replace characters that Windows doesn't accept in a filename" but found nothing,
so here is regex to strip chars from filename that windows filesistem do not allow (/\:?<>|"):
var originalFileName='some filename:with"forbidden/>\? chars.in';
var strippedFileName=originalFileName.replace(/[/\\:?<>|\"]+/g, "")
console.log(strippedFileName);
Related
So I had this code working for a few months already, lets say I have a table called Categories, which has a string column called name, so I receive a string and I want to know if any category was mentioned (a mention occur when the string contains the substring: #name_of_a_category), the approach I follow for this was something like below:
categories.select { |category_i| content_received.downcase.match(/##{category_i.downcase}/)}
That worked pretty well until today suddenly started to receive an exception unmatched close parenthesis, I realized that the categories names can contain special chars so I decided to not consider special chars or spaces anymore (don't want to add restrictions to the user and at the same time don't want to deal with those cases so the policy is just to ignore it).
So the question is there a clean way of removing these special chars (maintaining the #) and matching the string (don't want to modify the data just ignore it while looking for mentions)?
You can also use
prep_content_received = content_received.gsub(/[^\w\s]|_/,'')
p categories.select { |c|
prep_content_received.match?(/\b#{c.gsub(/[^\w\s]|_/, '').strip()}\b/i)
}
See the Ruby demo
Details:
The prep_content_received = content_received.gsub(/[^\w\s]|_/,'') creates a copy of content_received with no special chars and _. Using it once reduced overhead if there are a lot of categories
Then, you iterate over the categories list, and each time check if the prep_content_received matches \b (word boundary) + category with all special chars, _ and leading/trailing whitespace stripped from it + \b in a case insensitive way (see the /i flag, no need to .downcase).
So after looking around I found some answers on the platform but nothing with my specific requirements (maybe I missed something, if so please let me know), and this is how I fix it for my case:
content_received = 'pepe is watching a #comedy :)'
categories = ['comedy :)', 'terror']
temp_content = content_received.downcase
categories.select { |category_i| temp_content.gsub(/[^\sa-zA-Z0-9]/, '#' => '#').match?(/##{category_i.downcase.
gsub(/[^\sa-zA-Z0-9]/, '')}/) }
For the sake of the example, I reduced the categories to a simple array of strings, basically the first gsub, remove any character that is not a letter or a number (any special character) and replace each # with an #, the second gsub is a simpler version of the first one.
You can test the snippet above here
I could use some help writing a regex. I have the following text:
DEFINE BROWSE BW_SC20SDAN
&ANALYZE-SUSPEND _UIB-CODE-BLOCK _DISPLAY-FIELDS BW_SC20SDAN C-Win _FREEFORM
QUERY BW_SC20SDAN NO-LOCK DISPLAY
ZTYACC.prime COLUMN-LABEL "" FORMAT "X(35)"
ZUNACT.sec COLUMN-LABEL " " FORMAT "X(30)"
INFDON.sep COLUMN-LABEL "" FORMAT "99/99/9999"
IF INFDON.top THEN "S" ELSE (IF INFDON.REPORT THEN "R" ELSE (IF INFDON.prime <> "" THEN INFDON.prime ELSE "")) COLUMN-LABEL "R" FORMAT "X(1)"
/* _UIB-CODE-BLOCK-END */
&ANALYZE-RESUME
WITH SEPARATORS SIZE 83.57 BY 5.08
BGCOLOR 15 FGCOLOR 1 FONT 6 FIT-LAST-COLUMN.
I have to find this whole block in a text file, so far I have this regex:
(?:DEFINE|DEF)\s([\w\s]*)BROWSE\s+([\w-]+)\s+([^.]*)\.
My problem is that it selects only this :
DEFINE BROWSE BW_SC20SDAN
&ANALYZE-SUSPEND _UIB-CODE-BLOCK _DISPLAY-FIELDS BW_SC20SDAN C-Win _FREEFORM
QUERY BW_SC20SDAN NO-LOCK DISPLAY
ZTYACC.
When I want to select until the final point. Basically, the rule I want to apply is "until next dot followed by \s".
But I can't figure out how to write this regex.
Allow "non-dot" [^.] OR "dots not followed by space" \.(?!\s):
DEF(INE)?\s([\w\s]*)BROWSE\s+([\w-]+)\s+(([^.]|\.(?!\s))*)\.
Note also the simplification of the leading term.
Probably the most readable way to do that is
(?:DEFINE|DEF)\s([\w\s]*)BROWSE[\S\s]+?\.\s
You turn the + operator lazy with ?, meaning by default it matches everything until it hits the first period followed by a space.
If you have the option to use an ungreedy regex library, the simplest yet closest to what you specified would be
DEFINE\s+BROWSE.*?\.\s
Note, however, that the trailing whitespace may not be there at the end of your input text, leaving the last statement unmatched.
You may find it useful to have a lexer (scanner) like flex or ANTLR tokenize your string. This approach has the advantage that the lexer takes care of the white space and lets you specify the form of the block of interest in more detail.
I'm converting a text file to a Tab-Delimited text file, and ran into a bit of a snag. I can get everything I need to work the way I want except for one small part.
One field I'm working with has the home addresses of the subjects as a single entry ("1234 Happy Lane Somewhere, St 12345") and I need each broken down by Street(Tab)City(Tab)State(Tab)Zip. The one part I'm hung up on is the Tab between the State and the Zip.
I've been using input=input.Replace throughout, and it's worked well so far, but I can't think of how to untangle this one. The wildcards I'm used to don't seem to be working, I can't replace ("?? #####") with ("??" + ControlChars.Tab + "#####")...which I honestly didn't expect to work, but it's the only idea on the matter I had.
I've read a bit about using Regex, but have no experience with it, and it seems a bit...overwhelming.
Is Regex my best option for this? If not, are there any other suggestions on solutions I may have missed?
Thanks for your time. :)
EDIT: Here's what I'm using so far. It makes some edits to the line in question, taking care of spaces, commas, and other text I don't need, but I've got nothing for the State/Zip situation; I've a bad habit of wiping something if it doesn't work, but I'll append the last thing I used to the very end, if that'll help.
If input Like "Guar*###/###-####" Then
input = input.Replace("Guar:", "")
input = input.Replace(" ", ControlChars.Tab)
input = input.Replace(",", ControlChars.Tab)
input = "C" + ControlChars.Tab + strAccount + ControlChars.Tab + input
End If
input = System.Text.RegularExpressions.Regex.Replace(" #####", ControlChars.Tab + "#####") <-- Just one example of something that doesn't work.
This is what's written to input in this example
" Guar: LASTNAME,FIRSTNAME 999 E 99TH ST CITY,ST 99999 Tel: 999/999-9999"
And this is what I can get as a result so far
C 99999/9 LASTNAME FIRSTNAME 999 E 99TH ST CITY ST 99999 999/999-9999
With everything being exactly what I need besides the "ST 99999" bit (with actual data obviously omitted for privacy and professional whatnots).
UPDATE: Just when I thought it was all squared away, I've got another snag. The raw data gives me this.
# TERMINOLOGY ######### ##/##/#### # ###.##
And the end result is giving me this, because this is a chunk of data that was just fine as-is...before I removed the Tabs. Now I need a way to replace them after they've been removed, or to omit this small group of code from a document-wide Tab genocide I initiate the code with.
#TERMINOLOGY###########/##/########.##
Would a variant on rgx.Replace work best here? Or can I copy the code to a variable, remove Tabs from the document, then insert the variable without losing the tabs?
I think what you're looking for is
Dim r As New System.Text.RegularExpressions.Regex(" (\d{5})(?!\d)")
Dim input As String = rgx.Replace(input, ControlChars.Tab + "$1")
The first line compiles the regular expression. The \d matches a digit, and the {5}, as you can guess, matches 5 repetitions of the previous atom. The parentheses surrounding the \d{5} is known as a capture group, and is responsible for putting what's captured in a pseudovariable named $1. The (?!\d) is a more advanced concept known as a negative lookahead assertion, and it basically peeks at the next character to check that it's not a digit (because then it could be a 6-or-more digit number, where the first 5 happened to get matched). Another version is
" (\d{5})\b"
where the \b is a word boundary, disallowing alphanumeric characters following the digits.
I had this question a couple of times before, and I still couldn't find a good answer..
In my current problem, I have a console program output (string) that looks like this:
Number of assemblies processed = 1200
Number of assemblies uninstalled = 1197
Number of failures = 3
Now I want to extract those numbers and to check if there were failures. (That's a gacutil.exe output, btw.) In other words, I want to match any number [0-9]+ in the string that is preceded by 'failures = '.
How would I do that? I want to get the number only. Of course I can match the whole thing like /failures = [0-9]+/ .. and then trim the first characters with length("failures = ") or something like that. The point is, I don't want to do that, it's a lame workaround.
Because it's odd; if my pattern-to-match-but-not-into-output ("failures = ") comes after the thing i want to extract ([0-9]+), there is a way to do it:
pattern(?=expression)
To show the absurdity of this, if the whole file was processed backwards, I could use:
[0-9]+(?= = seruliaf)
... so, is there no forward-way? :T
pattern(?=expression) is a regex positive lookahead and what you are looking for is a regex positive lookbehind that goes like this (?<=expression)pattern but this feature is not supported by all flavors of regex. It depends which language you are using.
more infos at regular-expressions.info for comparison of Lookaround feature scroll down 2/3 on this page.
If your console output does actually look like that throughout, try splitting the string on "=" when the word "failure" is found, then get the last element (or the 2nd element). You did not say what your language is, but any decent language with string splitting capability would do the job. For example
gacutil.exe.... | ruby -F"=" -ane "print $F[-1] if /failure/"
Can anyone help me with a regex to turn:
filename_author
to
author_filename
I am using MS Word 2003 and am trying to do this with Word's Find-and-Replace. I've tried the use wildcards feature but haven't had any luck.
Am I only going to be able to do it programmatically?
Here is the regex:
([^_]*)_(.*)
And here is a C# example:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main()
{
String test = "filename_author";
String result = Regex.Replace(test, #"([^_]*)_(.*)", "$2_$1");
}
}
Here is a Python example:
from re import sub
test = "filename_author";
result = sub('([^_]*)_(.*)', r'\2_\1', test)
Edit: In order to do this in Microsoft Word using wildcards use this as a search string:
(<*>)_(<*>)
and replace with this:
\2_\1
Also, please see Add power to Word searches with regular expressions for an explanation of the syntax I have used above:
The asterisk (*) returns all the text in the word.
The less than and greater than symbols (< >) mark the start and end
of each word, respectively. They
ensure that the search returns a
single word.
The parentheses and the space between them divide the words into
distinct groups: (first word) (second
word). The parentheses also indicate
the order in which you want search to
evaluate each expression.
Here you go:
s/^([a-zA-Z]+)_([a-zA-Z]+)$/\2_\1/
Depending on the context, that might be a little greedy.
Search pattern:
([^_]+)_(.+)
Replacement pattern:
$2_$1
In .NET you could use ([^_]+)_([^_]+) as the regex and then $2_$1 as the substitution pattern, for this very specific type of case. If you need more than 2 parts it gets a lot more complicated.
Since you're in MS Word, you might try a non-programming approach. Highlight all of the text, select Table -> Convert -> Text to Table. Set the number of columns at 2. Choose Separate Text At, select the Other radio, and enter an _. That will give you a table. Switch the two columns. Then convert the table back to text using the _ again.
Or you could copy the whole thing to Excel, construct a formula to split and rejoin the text and then copy and paste that back to Word. Either would work.
In C# you could also do something like this.
string[] parts = "filename_author".Split('_');
return parts[1] + "_" + parts[0];
You asked about regex of course, but this might be a good alternative.