xsl choose in concat - xslt

Question

I have the following data:
XML
<team>
<rectx>30</rectx>
<diadata>
<bestAnd>-350</bestAnd>
</diadata>
<diadata>
<bestAnd>-250</bestAnd>
</diadata>
<diadata>
<bestAnd>-50</bestAnd>
</diadata>
</team>
XSL
<xsl:variable name="list">
<xsl:value-of select="'M'" />
<xsl:for-each select="/team/diadata/bestAnd">
<xsl:choose>
<xsl:when test=". <0">
<xsl:value-of select=".*-1+400" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="." />
</xsl:otherwise>
</xsl:choose>
<xsl:variable name="position" select="position()" />
<xsl:value-of select="concat(/team/rectx*$position+40,' ',.,' L')" />
</xsl:for-each>
</xsl:variable>
<xsl:variable name="finallist">
<xsl:value-of select="substring($list, 1, string-length($list) - 2)" />
</xsl:variable>
<text x="250" y="50"
style="font-family: Arial;
font-size : 24;
stroke : #000000;
fill : #000000;">
<xsl:value-of select="$finallist" />
</text>
The output has to be
M70 750 L100 650 L130 450
however with the choose statement it is
M75070 -350 L650100 -250 L450130 -50
so it does
"letter""y-val after calc""x-val" "y-val"
I can't understand why the concat does not work with the choose statement but without it works great. Prob is that I can't have negative numbers but instead need to take those and convert them to positive (*-1) and add 400.
Any ideas?

Answer 1

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:variable name="list">
<xsl:value-of select="'M'"/>
<xsl:for-each select="/team/diadata/bestAnd">
<xsl:variable name="position" select="position()"/>
<xsl:value-of select="concat(/team/rectx*$position+40,' ')"/>
<xsl:choose>
<xsl:when test=". <0">
<xsl:value-of select=".*-1+400"/>
<xsl:value-of select="' L'"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:variable>
</xsl:template>
</xsl:stylesheet>