Fortran: Integer to String Example - fortran

Question

I'm trying to write a simple Fortran code, for practicing. It is supposed to multiply numbers in a range. Each time, the resulting product is converted into a string because I want to see if it consists of the same digits.
I tested the way I transform an integer into a string and typed the components of the string, and everything was going correctly. Then, I need to compare the components of the string, for which I use string(number:number). But I couldn't get the code to do this correctly.
Here's the code and the output:
program test
implicit none
character(10) myString
character(1) a,b,c,d,e,f
integer::i,j,k
do i=900,901,1
j=900
k=i*j
write(*,*)'k =', k
write(myString,'(i10)') k
write(*,*)'myString = ', myString
a=myString(1:1)
b=myString(2:2)
c=myString(3:3)
d=myString(4:4)
e=myString(5:5)
f=myString(6:6)
print*,a,b,c,d,e,f
if (d==f) then
print*,'hobla'
else
print*,'fobla'
end if
end do
stop
end program test
So I defined characters: a,b,c,d,e,f to contain the components of the string. And used myString(i:i) to locate each component and store it in one of the characters a,b,c,d,e,f.
But it seems only the first two are working correctly, the rest is not being stored!
Output:
k = 810000
myString = 810000
81
fobla
k = 810900
myString = 810900
81
fobla
Notice 81. This was supposed to give 810000 the first time, and print "hobla". And give 810900 the second time and print "fobla". But this didn't happen!
Can anybody show me how to let myString accept the zeros as characters?

Answer 1

This statement
write(myString,'(i10)') k
writes the value of k into a 10-character field. Since k has only 6 significant digits the first 4 characters in myString are filled with blanks. Then you assign the first 6 characters of myString (that is 4 blanks and the digits 8 and 1) to the variables a,b,c,d,e,f and print them out -- 4 blanks and 2 digits.
Try printing out the other characters in positions 7..10 of myString and you should see your 'missing' digits.

Answer 2

Okay, so I figured out the problem. Consider the following modifications to your code:
program test
implicit none
character(10) myString
character(1) a,b,c,d,e,f
integer::i,j,k
do i=900,901,1
j=900
k=i*j
write(*,*)'k =', k
write(myString,'(i10)') k
write(*,*)'myString = ', myString
a=myString(1:1)
b=myString(2:2)
c=myString(3:3)
d=myString(4:4)
e=myString(5:5)
f=myString(6:6)
write(*,*) a
write(*,*) b
write(*,*) c
write(*,*) d
write(*,*) e
write(*,*) f
if (d==f) then
print*,'hobla'
else
print*,'fobla'
end if
end do
stop
end program test
The resulting output is:
k = 810000
myString = 810000
8
1
fobla
k = 810900
myString = 810900
8
1
fobla
This happens because the I format right-justifies numbers when printed. So there is a bunch of leading white-spaces because your number is only 6 digits while your string you are writing into is 10. So you get 4 leading spaces.
If you change your format string so you have:
write(myString,'(i10.10)') k
then instead of padding with spaces it will pad with 0's. That way you can always have digits to compare if you would rather.