change of xml structure using xslt - xslt

Question

I want to convert the following source xml structure to the target xml structure using xslt transformation. I am mot able to convert the following source xml to target xml using xslt. Please help us in coneverting this.
Source XML
<XxhrPiEmpcompOutIntCollection>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp1
</competencyName>
<proficiencyLevel>
Prof1
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp2
</competencyName>
<proficiencyLevel>
Prof2
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
</XxhrPiEmpcompOutIntCollection>
Target xml
<EmployeeCompetencyRequest>
<EmployeeNumber>200000562</EmployeeNumber>
<Competencies>
<Competency>
<Name>Comp1</Name>
<ProficiencyLevel>Prof1</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
<Competency>
<Name>Comp2</Name>
<ProficiencyLevel>Prof2</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
</Competencies>
</<EmployeeCompetencyRequest>

Answer 1

Some hint :
<EmployeeCompetencyRequest>
template match /XxhrPiEmpcompOutIntCollection
for-each-group XxhrPiEmpcompOutInt group by employeeNumber
<EmployeeNumber> value-of current-group-key </EmployeeNumber>
<Competencies>
for-each current-group
<Competency>
value-of name
value-of proficiencyLevel
</competency>
/for-each
</Competencies>
/for-each-group
<EmployeeCompetencyRequest>
Hope you can finish it.

Answer 2

You can group users with for-each-group:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:for-each-group select="//XxhrPiEmpcompOutInt" group-by="employeeNumber">
<Name><xsl:value-of select="current-grouping-key()"/></Name>
<Competencies>
<xsl:for-each select="current-group()">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="profiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:for-each-group>
</EmployeeCompetencyRequest>
</xsl:template>
Salut,

Answer 3

For XSLT 1.0 you must group widht xsl:key:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="groups" match="/XxhrPiEmpcompOutIntCollection/XxhrPiEmpcompOutInt" use="employeeNumber" />
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:apply-templates select="//XxhrPiEmpcompOutInt[generate-id() = generate-id(key('groups', employeeNumber)[1])]"/>
</EmployeeCompetencyRequest>
</xsl:template>
<xsl:template match="XxhrPiEmpcompOutInt">
<Name><xsl:value-of select="employeeNumber"/></Name>
<Competencies>
<xsl:for-each select="key('groups', employeeNumber)">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="proficiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:template>
</xsl:stylesheet>
I can't test it with Oracle ...