I need a regex for allowing list of special characters((_-.$#?,:'/!) and letters supporting utf-8 languages.
I tried
/^[\_\-\.\$#\?\,\:\'\/\!]*$/
but typing letters in English and Tamil shows invalid.
You need to escape the hyphen for it to be valid. You also don't need to escape most of the other characters - inside of brackets, almost everything is literal.
/[_\-.$#?,:'/!]*/
I have no idea if your regex engine supports \p{L}. You can try this:
^[_\-.\$#\?\,\:\'/!\p{L}]*$
or this one:
^[_\-.\$#\?\,\:\'/!\w]*$
The last one also matches digits.
Related
I have a question:
I want to do a validation for the first and the last name with RegEx.
I want to do it with only Hebrew and English without numbers.
Someone can help me to do that code?
Seemingly Hebrew has the range \u0590-\u05fe (according to this nice JavaScript Unicode Regex generator`.
/^[a-z\u0590-\u05fe]+$/i
While the selected answer is correct about "Hebrew" the OP wanted to limit validation to only Hebrew and English letters. The Hebrew Unicode adds a lot of punctuation and symbols (as you can see in the table here) irrelevant for such validation. If you want only Hebrew letters (along with English letters) the regex would be:
/^[a-z\u05D0-\u05EA]+$/i
I would consider adding ' (single quote) as well, for foreign consonants that are missing in Hebrew (such as G in George and Ch in Charlie) make use of it along with a letter:
/^[a-z\u05D0-\u05EA']+$/i
English & Hebrew FULL regex
I'm using the above regex on my application. My users are just fine with it:
RegExp(r'^[a-zA-Z\u0590-\u05FF\u200f\u200e ]+$');
The regex supports:
English letters (includes Capital letters). a-zA-Z
Hebrew (includes special end-letters). \u0590-\u05FF
change direction unicodes (RLM, LRM). \u200f\u200e
White space.
Enjoy!
Try this. Not sure if it will work. If not, these references should help.
[A-Za-z\u0590-\u05FF]*
Hebrew Unicode
Unicode in Regular Expressions
Hebrew letters only:
/^[\u0590-\u05ea]+$/i
You can also use \p{Hebrew} in your regex to detect any Hebrew unicode characters (if you're regex engine supports it).
Well, the RegEx pattern is between two /'s. The i at the end is a flag that says to be indifferent to the cases. ^ means the start of a line, and $ means the end of a line. Brackets ([ and ]) means either of the characters inside the brackets. - means a range. Note that the characters are ordinal, so a-z or א-ת make sense; a-z means all letters from and include a to and include z. The same goes for א-ת. + means one or more of the preceding. So this pattern matches every sequence of letters from English or Hebrew.
P.S.: Also, note that the flavor of the RegEx is different in different languages and platforms. for example in Sublime Text the pattern would be: (?i)^[א-תa-z]+$.
/^[א-תa-z]+$/i
I have a regex for matching letters, numbers and some special characters as follows: ^[A-za-z0-9 .#&,’()+/:]*$
I need to add a single hyphen to this list, not allowing multiple hyphens, but I'm not quite sure how to do it. I saw something along the lines of -{1} but I don't know how to add that to the existing rexex.
I'm using C++ and Qt5.
How about:
^[A-za-z0-9 .#&,’()+/:]*-?[A-za-z0-9 .#&,’()+/:]*$
that could be reduce to:
^[\w .#&,’()+/:]*-?[\w .#&,’()+/:]*$
I don't know if C++ support it, but it could be reduced to:
^([\w .#&,’()+/:])*-?(?1)*$
^[A-za-z0-9.#&,’()+/:]*-[A-za-z0-9.#&,’()+/:]*$ allows a single hyphen anywhere in the string.
Note that the hyphen may come at any part (at the beginning or end of the string also) and it is mandatory also.
To make the hyphen optional, use ^[A-za-z0-9.#&,’()+/:]*-?[A-za-z0-9.#&,’()+/:]*$
I have two strings
100-2000
and
100-X200-2012
I try to write regex that match both strings like below by saying that if the second hyphen start with X ignore it
[0-9]+-[a-zA-Z0-9 \-X]+-[0-9]
but it fail to match it, I am not sure how to match it with my criteria ?
do you mean this:
[0-9]+-[^X][a-zA-Z0-9 \-]*-[0-9]+
It can be something like this
(\d*)(-X\d*|)-(\d{4})
Since you haven't specified a tool, I'll go with the .NET regex flavor (my personal favorite):
\d+(-[ \w-[_X]][ \w-[_]]+)?-\d+
\d is the same as [0-9]
In .NET, you can use character class subtraction to remove particular elements from a characters class. In this case, I've included a space and a \w (which is the same as [0-9a-zA-Z_]) within the character class and then subtracted the underscore and uppercase X.
Another option is to use negative lookahead:
\d+(-(?!X)[ 0-9a-zA-Z]+)?-\d+
I like this even better, but not all flavors of regex support it.
I am trying to get one regular expression that does the following:
makes sure there are no white-space characters
minimum length of 8
makes sure there is at least:
one non-alpha character
one upper case character
one lower case character
I found this regular expression:
((?=.*[^a-zA-Z])(?=.*[a-z])(?=.*[A-Z])(?!\s).{8,})
which takes care of points 2 and 3 above, but how do I add the first requirement to the above regex expression?
I know I can do two expressions the one above and then
\s
but I'd like to have it all in one, I tried doing something like ?!\s but I couldn't get it to work. Any ideas?
^(?=.*[^a-zA-Z])(?=.*[a-z])(?=.*[A-Z])\S{8,}$
should do. Be aware, though, that you're only validating ASCII letters. Is Ä not a letter for your requirements?
\S means "any character except whitespace", so by using this instead of the dot, and by anchoring the regex at the start and end of the string, we make sure that the string doesn't contain any whitespace.
I also removed the unnecessary parentheses around the entire expression.
Tim's answer works well, and is a good reminder that there are many ways to solve the same problem with regexes, but you were on the right track to finding a solution yourself. If you had changed (?!\s) to (?!.*\s) and added the ^ and $ anchors to the end, it would work.
^((?=.*[^a-zA-Z])(?=.*[a-z])(?=.*[A-Z])(?!.*\s).{8,})$
I need a regular expression to allow the user to enter an alphanumeric string that starts with a letter (not a digit).
This should work in any of the Regular Expression (RE) engines. There is a nicer syntax in the PCRE world but I prefer mine to be able to run anywhere:
^[A-Za-z][A-Za-z0-9]*$
Basically, the first character must be alpha, followed by zero or more alpha-numerics. The start and end tags are there to ensure that the whole line is matched. Without those, you may match the AB12 of the "###AB12!!!" string.
Full explanation:
^ start tag.
[A-Za-z] any one of the upper/lower case letters.
[A-Za-z0-9] any one of the upper/lower case letters or digits,
* repeated zero or more times.
$ end tag
Update:
As Richard Szalay rightly points out, this is ASCII only (or, more correctly, any encoding scheme where the A-Z, a-z and 0-9 groups are contiguous) and only for the "English" letters.
If you want true internationalized REs (only you know whether that is a requirement), you'll need to use one of the more appropriate RE engines, such as the PCRE mentioned above, and ensure it's compiled for Unicode mode. Then you can use "characters" such as \p{L} and \p{N} for letters and numerics respectively. I think the RE in that case would be:
^\p{L}[\pL\pN]*$
but I'm not certain. I've never used REs for our internationalized software. See here for more than you ever wanted to know about PCRE.
I think this should do the work:
^[A-Za-z][A-Za-z0-9]*$
You're looking for a pattern like this:
^[a-zA-Z][a-zA-Z0-9]*$
That one requires one letter and any number of letters/numbers after that. You may want to adjust the allowed lengths.