My dataset is:
ID AGE
1 65
1 66
1 67
1 68
1 69
1 70
1 71
2 70
2 71
2 72
3 68
3 69
3 70
[...]
My (basic) question is: which is the most direct way for obtaining a dataset with ID records starting with 65 <= AGE <= 68? (in the above example I would like to get the first 7 rows and the last three). Thanks!
Just to have another method...
proc sql;
delete from input_dataset I where not exists
(select 1 from input_dataset D where I.id=D.id having 65 le min(age) le 68);
quit;
If you want to create a new dataset, the same basic query would work as part of a SELECT, reversing the NOT.
data input_dataset;
input ID AGE;
cards;
1 65
1 66
1 67
1 68
1 69
1 70
1 71
2 70
2 71
2 72
;
run;
proc sort data=input_dataset out=sorted;
by ID;
run;
data work.first_age65to68;
set sorted;
retain keepit 0;
by ID;
if first.ID then do;
if AGE ge 65 and AGE le 68 then keepit=1;
else keepit=0;
end;
if keepit;
drop keepit;
run;
Related
Hopefully a easy one.
I am fairly new to SAS.
I am trying to read data using following SAS code (as per given in lecture notes), but it is not producing proper SAS dataset because of some character length issue. I tried : and & some hit and trial but not able to fix it. Can anyone kindly explain me on how can I fix this?
data SMSA_subset_weather;
length city $ 27;
input city & JanTemp JulyTemp RelHum Rain;
datalines;
Akron, OH 27 71 59 36
Albany-Schenectady-Troy, NY 23 72 57 35
Baltimore, MD 35 77 55 43
Allentown, Bethlehem, PA-NJ 29 74 54 44
Atlanta, GA 45 79 56 47
;
run
;
I am using SAS ON DEMAND. When I use dsd it is giving me the desired output, like below:
data SMSA_subset_weather;
infile datalines delimiter=" " dsd;
length city $ 27;
input city & JanTemp JulyTemp RelHum Rain;
datalines;
"Akron, OH" 27 71 59 36
"Albany-Schenectady-Troy, NY" 23 72 57 35
"Baltimore, MD" 35 77 55 43
"Allentown, Bethlehem, PA-NJ" 29 74 54 44
"Atlanta, GA" 45 79 56 47
;
run
;
I am achieving this by modifying the instream data and using dsd option. But I assume I cant handle if there were more of such observations.
You need a second space following the city name, or quotation marks.
When using a delimiter that may appear in the data, you can use the & as you do in order to ask SAS to read until it finds two consecutive delimiters. (You also can use DSD option and quotation marks.)
So here:
data SMSA_subset_weather;
length city $ 27;
input city & JanTemp JulyTemp RelHum Rain;
datalines;
Akron, OH 27 71 59 36
Albany-Schenectady-Troy, NY 23 72 57 35
Baltimore, MD 35 77 55 43
Allentown, Bethlehem, PA-NJ 29 74 54 44
Atlanta, GA 45 79 56 47
;
run
;
Or here, using DSD with quotation marks:
data SMSA_subset_weather;
length city $ 27;
infile datalines dsd dlm=' ';
input city JanTemp JulyTemp RelHum Rain;
datalines;
"Akron, OH" 27 71 59 36
"Albany-Schenectady-Troy, NY" 23 72 57 35
"Baltimore, MD" 35 77 55 43
"Allentown, Bethlehem, PA-NJ" 29 74 54 44
"Atlanta, GA" 45 79 56 47
;
run
;
I am currently practicing SAS programming on using two SAS dataset(sample and master) . Below are the hypothetical or dummy data created for illustration purpose to solve my problem through SAS programming . I would like to extract the data for the id's in sample dataset from master dataset(test). I have given an example with few id's as sample dataset, for which i need to extract next 12 month information from master table(test) for each id's based on the yearmonth information( desired output given in the third output).
Below is the code to extract the previous 12 month data but i am not getting idea to extract next 12 month records as pulled for previous months, Can anyone help me in solving this problem using SAS programming with optimized way.
proc sort data=test;
by id yearmonth;
run;
data result;
set test;
array prev_month {13} PREV_MONTH_0-PREV_MONTH_12;
by id;
if first.id then do;
do i =1 to 13;
prev_month(i)=0;
end;
end;
do i = 13 to 2 by -1;
prev_month(i)=prev_month(i-1);
end;
prev_month(1)=no_of_cust;
drop i prev_month_0;
retain prev_month:;
run;
data sample1;
set sample(drop=no_of_cust);
run;
proc sort data=sample1;
by id yearmonth;
run;
data all;
merge sample1(in=a) result(in=b);
by id yearmonth;
if a;
run;
One sample dataset (dataset name - sample).
ID YEARMONTH NO_OF_CUST
1 200909 50
1 201005 65
1 201008 78
1 201106 95
2 200901 65
2 200902 45
2 200903 69
2 201005 14
2 201006 26
2 201007 98
One master dataset - dataset name (test) (huge dataset over the year for each id from start of the account to till date.)
ID YEARMONTH NO_OF_CUST
1 200808 125
1 200809 125
1 200810 111
1 200811 174
1 200812 98
1 200901 45
1 200902 74
1 200903 73
1 200904 101
1 200905 164
1 200906 104
1 200907 22
1 200908 35
1 200909 50
1 200910 77
1 200911 86
1 200912 95
1 201001 95
1 201002 87
1 201003 79
1 201004 71
1 201005 65
1 201006 66
1 201007 66
1 201008 78
1 201009 88
1 201010 54
1 201011 45
1 201012 100
1 201101 136
1 201102 111
1 201103 17
1 201104 77
1 201105 111
1 201106 95
1 201107 79
1 201108 777
1 201109 758
1 201110 32
1 201111 15
1 201112 22
2 200711 150
2 200712 150
2 200801 44
2 200802 385
2 200803 65
2 200804 66
2 200805 200
2 200806 333
2 200807 285
2 200808 265
2 200809 222
2 200810 220
2 200811 205
2 200812 185
2 200901 65
2 200902 45
2 200903 69
2 200904 546
2 200905 21
2 200906 256
2 200907 214
2 200908 14
2 200909 44
2 200910 65
2 200911 88
2 200912 79
2 201001 65
2 201002 45
2 201003 69
2 201004 54
2 201005 14
2 201006 26
2 201007 98
Desired Output should like below,
ID YEARMONTH NO_OF_CUST AFTER_MONTH_1 AFTER_MONTH_2 AFTER_MONTH_3 AFTER_MONTH_4 AFTER_MONTH_5 AFTER_MONTH_6 AFTER_MONTH_7 AFTER_MONTH_8 AFTER_MONTH_9 AFTER_MONTH_10 AFTER_MONTH_11 AFTER_MONTH_12
1 200909 50 77 86 95 95 87 79 71 65 66 66 78 88
Step1: Join your sample table with the main(test) table and using intnx to get all the values for next 12 months.
Step2: Making a column names "after month"
Step3: Transpose to get your final output
proc sql;
create table abc as
select a.id,a.yearmonth,b.yearmonth as yearmonth1, b.no_of_cust
from
sample a
left join
test b
on a.id = b.id and a.yearmonth <= b.yearmonth <= intnx("month",a.yearmonth,12)
order by a.id,a.yearmonth,b.yearmonth;
quit;
data abc1(drop=col yearmonth1);
set abc;
by id yearmonth;
if first.yearmonth then col=-1;
col+1;
columns = compress("after_month_"||col);
run;
proc transpose data=abc1 out=abc2(rename=(after_month_0 = no_of_cust) drop=_name_);
by id yearmonth;
id columns;
var no_of_cust;
run;
My Output:
Or
If you want to make changes in your query then you could use the below code.
proc sort data=test;
by id descending yearmonth;
run;
data result;
set test;
array after_month {13} after_MONTH_0-after_MONTH_12;
by id;
if first.id then do;
do i = 1 to 13;
after_month(i) = 0;
end;
end;
do i = 13 to 2 by -1;
after_month(i) = after_month(i-1);
end;
after_month(1) = NO_OF_CUST;
drop i after_MONTH_0;
retain after_MONTH:;
run;
data sample1;
set sample(drop=no_of_cust);
run;
proc sort data=result;
by id yearmonth;
run;
proc sort data=sample1;
by id yearmonth;
run;
data all;
merge sample1(in=a) result(in=b);
by id yearmonth;
if a;
run;
Let me know in case of any queries.
This is my first foray into using SAS macros, and I'm following this page from the amazing UCLA Stats Consulting Group. I'm interested in using macro variables in PROC MIXED to avoid copying and pasting blocks of code (my actual data set has ~400 variables).
My example modifies the UCLA example to have students in many schools.
data hsb3;
input id school female race ses prog
read write math science socst;
datalines;
1 1 0 4 1 1 57 52 41 47 57
2 1 1 4 2 3 68 59 53 63 61
3 1 0 2 3 1 44 33 54 58 31
4 1 0 4 3 3 63 44 47 53 56
5 1 0 4 2 2 47 51 43 50 61
6 1 1 4 2 2 44 52 51 50 61
7 1 0 3 2 1 50 59 60 56 52
8 1 0 1 2 2 34 46 52 53 57
9 1 0 4 2 2 63 57 51 63 61
19 2 0 3 1 2 57 63 41 63 61
20 2 1 4 2 2 60 57 51 58 31
21 2 0 4 3 2 57 55 51 53 56
22 2 0 4 3 2 73 46 71 50 61
23 2 0 4 2 1 54 65 57 50 61
24 2 1 4 2 2 45 60 50 56 52
25 2 0 3 2 1 42 63 43 53 57
26 2 0 1 1 2 34 57 51 63 61
27 2 0 4 2 2 63 49 60 55 31
10 3 1 3 2 2 57 55 51 55 31
11 3 1 4 3 3 60 46 71 31 56
12 3 1 4 2 2 57 66 57 55 61
13 3 0 3 3 2 50 60 50 31 61
14 3 0 4 3 2 57 57 57 55 46
15 3 0 3 3 3 68 55 50 31 56
16 3 0 4 1 2 34 46 43 50 56
17 3 0 4 3 2 34 65 51 50 56
18 3 0 4 1 2 63 60 60 47 57
28 4 1 3 2 2 57 52 52 53 61
29 4 1 4 2 3 60 57 51 63 61
30 4 1 1 2 2 57 65 51 55 46
31 4 0 4 3 2 73 60 71 31 56
32 4 0 4 3 2 54 63 57 55 46
33 4 0 3 1 2 45 57 50 31 56
34 4 0 1 1 1 42 49 43 50 56
35 4 0 4 3 2 47 52 51 50 56
36 4 0 4 2 1 57 57 60 56 52
;
run;
The UCLA example shows how to use macro variables with proc reg to do several simple linear regression models to predict reading score with any of the other variables:
%let indvars = write math female socst;
proc reg data = hsb3;
model read = &indvars;
run;
quit;
To do this taking school into account, we can use PROC MIXED instead:
proc mixed data = hsb3;
class school;
model read = &indvars;
random school;
run;
quit;
But what I really want to do is to see if any of the scores differ by gender (still taking school into account).
%let scores = read write math science socst;
proc mixed data = hsb3;
class school;
model &scores = female;
random school;
run;
quit;
Now I get the error:
NOTE: The SAS System stopped processing this step because of errors.
167 class school;
168 model &indvars = female;
-
22
200
NOTE: Line generated by the macro variable "INDVARS".
1 write math female socst
----
73
ERROR 22-322: Syntax error, expecting one of the following: a name, ;, (, *, -, /, :, #,
_CHARACTER_, _CHAR_, _NUMERIC_, |.
ERROR 200-322: The symbol is not recognized and will be ignored.
ERROR 73-322: Expecting an =.
Somehow the macro variable is not working. Is there a problem with using macro variables as a response variable in PROC MIXED? They work as a response variable in PROC REG....
proc reg data = hsb3;
model &scores = female;
run;
quit;
Your problem doesn't have anything to do with macro variables or macro code. Instead you are not creating a valid MODEL statement to use in PROC MIXED.
The MODEL statement names a single dependent variable ...
Try transforming the data perhaps?
%let scores = read write math science socst;
data want ; set hsb3 ;
array scores &scores ;
do i=1 to dim(scores);
score=scores(i);
name=vname(scores(i));
output;
end;
run;
proc sort; by name ; run;
proc mixed data = want;
by name;
class school;
model score = female;
random school;
run;
I am new to SAS I have SAS data like (It does not contain Obs column)
Obs ID Name Score1 Score2 Score3
1 101 90 95 98
2 203 78 77 75
3 223 88 67 75
4 280 68 87 75
.
.
.
.
100 468 78 77 75
I want data having row number 2 6 8 10 34. Output should look like
Obs ID Name Score1 Score2 Score3
1 203 78 77 75
2 227 88 67 75
3 280 68 87 75
.
.
.
Thanks in advance.
The other answer is ok for small tables, but if you are working with a very large table it's inefficient as it reads every row in the table to see whether it has the right row number. Here's a more direct approach:
data example;
do i = 2, 6, 8, 10;
set sashelp.class point = i;
output;
end;
stop;
run;
This picks out just the rows you actually want and doesn't read all the others.
You can loop through each line of data with a data step and only output the lines when you are in the n'th loop with a condition like this.
data test;
set LIB.TABLE;
if _N_ in (2, 6, 8, 10, 34) then output;
run;
where _N_ will correspond to the number of the line in this case.
I have this data set:
data a1q1;
input pid los age gender $ temp wbc anti service $ ;
cards;
1 5 30 F 99 82 2 M
2 10 73 F 98 52 1 M
3 6 40 F 99 122 2 S
4 11 47 F 98 42 2 S
5 5 25 F 99 112 2 S
6 14 82 M 97 61 2 S
7 30 60 M 100 81 1 M
8 11 56 F 99 72 2 M
9 17 43 F 98 72 2 M
10 3 50 M 98 122 1 S
11 9 59 F 98 72 1 M
12 3 4 M 98 32 2 S
13 8 22 F 100 111 2 S
14 8 33 F 98 141 1 S
15 5 20 F 98 112 1 S
16 5 32 M 99 92 2 S
17 7 36 M 99 61 2 S
18 4 69 M 98 62 2 S
19 3 47 M 97 51 2 M
20 7 22 M 98 62 2 S
21 9 11 M 98 102 2 S
22 11 19 M 99 141 2 S
23 11 67 F 98 42 2 M
24 9 43 F 99 52 2 S
25 4 41 F 98 52 2 M
;
I need to use PROC SGPLOT to output an identical, if not, similar barchart that would be outputted from the following PROC:
proc gchart data = a1q1;
vbar wbc / group = gender;
run;
I need PROC SGPLOT to group the two genders together and not stack them. I have tried coding this way but to no avail:
proc sgplot data = a1q1;
vbar wbc / group= gender response =wbc stat=freq nostatlabel;
run;
How would I go about coding to get the output I need?
Thank you for your time!
Sounds like you should use SGPANEL, not SGPLOT. SGPLOT can make grouped bar charts, but not automatically make histogram bins without using a format (you could do that if you want) and doesn't support group with the histogram plot. However, SGPANEL can handle that.
proc sgpanel data=a1q1;
panelby gender;
histogram wbc;
run;