This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
What does void(U::*)(void) mean?
Considering the following:
template <class T>
class myButtoncb {
private:
T *ptr;
void (T::*cback) (void)
}
What I understand is:
void (*cback) (void)
Which is nothing but a function pointer that to a function that returns void, and takes no argument.
What I dont understand is, what is the importance of T::? Isn't it enough to declare
only like void (*cback) (void) ?
This says that it's a member function that has a this pointer. Otherwise, it would be a free function, wouldn't have any idea what object it was operating on, and wouldn't be able to access any non-static member functions or member variables.
From C++ FAQ
Is the type of "pointer-to-member-function" different from "pointer-to-function"?
Yep.
Link which I've provided to you has a lot of information about this topic.
The function, you pass there, must be declared inside the class T - the template parameter of myButtoncb. So you can use a function like the following:
class A
{
public:
void foo(void);
};
myButton<A> b;
b.cback = &A::foo;
Related
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How can I pass a member function where a free function is expected?
(9 answers)
how to pass a non static-member function as a callback?
(8 answers)
Pass Member Function as Parameter to other Member Function (C++ 11 <function>) [duplicate]
(2 answers)
Closed 4 months ago.
I need to change the prototype of a function pointer of a class. So, I was hoping inheriting it and doing the following would work, but it doesn't ("invalid use of non-static member function 'void B::myIntCallback(unsigned int)"):
class A {
public:
typedef void (*intCallback_t)(unsigned int myInt);
A(intCallback_t intCallback) {}
};
class B : A {
public:
typedef void (*charCallback_t)(unsigned char myChar);
B(charCallback_t charCallback) : A(this->myIntCallback) {
charCallback_ = charCallback;
}
private:
charCallback_t charCallback_;
void myIntCallback(unsigned int myInt) {
charCallback_((unsigned char)myInt);
}
};
Does anybody know how I can solve this? I can't change class A.
You are trying to pass a member function (B::myIntCallback) to a function pointer argument. Since the member function needs an object to be called on, his would require some kind of capturing, e.g. a lambda capturing this or an std::bind expression. Unfortunately, neither is possible with a plain function pointer, see also Passing capturing lambda as function pointer.
If possible, you may want to consider changing the class A to accept either a std::function or a template argument as the type of the callback. See also Should I use std::function or a function pointer in C++?.
This question already has answers here:
C++ Call Pointer To Member Function
(4 answers)
Calling C++ member functions via a function pointer
(10 answers)
Closed 9 months ago.
Consider this class:
class Downloader {
private:
bool video_or_audio;
// other variables [...]
// [...]
void downloadVideo(std::string videoURL);
void downloadAudio(std::string audioURL);
public:
void download();
}
Now, download() is defined this way:
void Downloader::download(){
std::ifstream url_list;
void (*download_func)(std::string) = video_or_audio == 0 ? downloadVideo : downloadAudio; // Compiler says here: "Reference to non static member function must be called".
if(video_or_audio == 0){
url_list.open("video_list.txt");
}
else{
url_list.open("audio_list.txt");
}
std::string url;
while(std::getline(url_list, url)){
download_func(url); // Calling the function pointed by the pointer defined in line 2 of the function download().
}
}
My compiler (clang) says: "Reference to non static member function must be called" in the second line of function download() definition. Why is this happening and how can I solve this problem?
A solution appears to be defining downloadVideo() and downloadAudio() functions to be static in the class declaration. However, if I do so, I cannot access private variables members of class Downloader, that's not desirable, as I need these variables.
Thank you!
Once calling a member function by pointer, you need to provide two things:
Member function itself
Address of particular instance of given class at which the member function to be called (because the function can access class members thus you have to advise which of the instances is the right one)
void (Downloader::*download_func)(std::string) = video_or_audio == 0 ? &Downloader::downloadVideo : &Downloader::downloadAudio; // Correct the signatures.
...
while(std::getline(url_list, url)){
(this->*download_func)(url);
}
So, here we changed download_func from "just function pointer" to a member function pointer. Then, later in the loop body, we call this member function on this instance (however you can pass an instance as a param if necessary).
This question already has answers here:
Callback functions in C++
(11 answers)
Closed 2 years ago.
I started using C++ recently and at one point I needed to set up a callback, i.e. call a function of another class and pass to it as a parameter the name of one of my own functions so that it calls it back. At first I tried this:
void myOtherFunction(void (*oneOfMyFunctions)(void)) {
oneOfMyFunctions();
}
Unfortunately this code doesn't support class member functions because it is (correct me if I am wrong) ...C code.
This can work.
void myOtherFunction(void (*oneOfMyFunctions)(void)) {
oneOfMyFunctions();
}
However, your problem may be due to trying to pass member functions into this function. If member_function is a member function of class A, the expression &member_function inside class A has a type of void (A::*)(void), not void (*)(void) like you want (that is, it wants an A pointer in addition to its normal parameters). You can use std::bind():
std::bind(&member_function, this)
to create a function object which can be called with an empty parameter list. However, then you would need to change your member function signature to something like this:
template <typename FuncType>
void myOtherFunction(FuncType oneOfMyFunctions) {
oneOfMyFunctions();
}
or, like Th0rgal may have said,
void myOtherFunction(std::function<void()> oneOfMyFunctions) {
oneOfMyFunctions();
}
Here is a working way to do that:
void myOtherFunction(std::function<void()> oneOfMyFunctions) {
oneOfMyFunctions();
}
And inside my class:
myOtherFunction([&] {
oneOfMyFunctions();
});
Some explanations:
In std::function<void()>, void is what is returned by the function and () contains the types of its parameters (mine is empty because it doesn't have any).
In the 2nd code I am using a lambda to keep the context, as a bind would do (but lambdas replace them).
This question already has answers here:
About Pointers To Functions in function declarations
(4 answers)
Closed 7 years ago.
In some C++ 98 code (meaning no, using std::function is not an option), I found the following construct:
class someClass
{
public:
typedef void callback();
void setCallback(callback c)
{
mCallback = c;
}
void callCallback()
{
if (mCallback)
mCallback();
}
private:
callback *mCallback;
};
This confused me. I am used to passing callback functions as a function pointer, so I would expect setCallback to take (*callback)() as argument.
However, the above code seems to work, and compiles without any (related) warnings.
Could someone tell me what is happening here? Is my callback function implicitly passed as a function pointer? Is it a good idea to use this instead of function pointers?
The only thing I could find is that this construction results in "parameter-declaration-clause" ambiguity (C++ 98 8.3p7). Is this the only downside? Are there any benefits?
Similarly to arrays, parameters of function type declare, in fact, a pointer to that type.
This question already has an answer here:
Factory Pattern: typedef Class *(createClassFunction)(void)
(1 answer)
Closed 8 years ago.
I've come across a declaration inside a C++ Struct{..} that I've never seen before.
Can anyone tell me what it means;
struct DerivedMesh {
char cd_flag;
void (*calcNormals)(DerivedMesh *dm); // <-- What is this?
It kind of looks like it's dereferencing a pointer called calcNormals, but that's all I can make out.
This is a C syntax for declaring function pointers.
In this particular example, DerivedMesh will have a member calcNormals that is a pointer to a function accepting single argument of type DerivedMesh*. It can be called like an ordinary function:
void foo(DerivedMesh* dm) { ... }
DerivedMesh dm;;
// Init members and set calcNormals to actual function
dm.cf_flag = whatever;
dm.calcNormals = foo;
dm.calcNormals(&dm); // calls foo
This
void (*calcNormals)(DerivedMesh *dm);
is class data member definition with name calcNormals that has type of pointer to function of type void( DerivedMesh * )