Updating form in Django. How to design? - django

Question

I'm a django newbie.
I have this model:
class Item(models.Model):
name = models.CharField(max_length=255)
quantity = models.IntegerField()
How to create view to update quantity of my all Item?
views:
def item_list(request):
item = Product.objects.all()[:6]
return render_to_response('item.html',{'item':item},context_instance=RequestContext(request))
form:
from django import forms
class QuantityForm(forms.Form):
quan = forms.IntegerField()
template:
{% for i in item %}
{{ i.name }}
{{ i.quantity }}
{% endfor %}
I'm trying to do something like this(after clicking "update" value quantity in my model should be actualize):
Please any help. Thanks

Answer 1

First you need a view, which retrieves item id and quantity value, updates relative Item instance and redirects you back to the page. Here is an example:
from django.views.decorators.http import require_http_methods
from django.shortcuts import redirect, get_object_or_404
#require_http_methods(["POST"])
def update_item(request)
id = request.POST.get('id', None) #retrieve id
quantity = request.POST.get('q', None) #retrieve quantity
item = get_object_or_404(Item, id=id) #if no item found raise page not found
if quantity:
#updating item quantity
item.quantity = quantity
item.save()
return redirect('my-item-list-view-name')
Also you need to create urlpattern for the view in your urls.py. For example:
...
url(r'^update-item/$', 'update_item', name='update_item'),
...
Then you can make a forms for each item on a template:
{% for i in item %}
<form action="{% url 'update_item' %}" method="post">
{% csrf_token %}
{{ i.name }}
<input name="id" type="hidden" value="{{ i.id }}" />
<input name="q" type="text" value="{{ i.quantity }}" />
<input type="submit" value="update" />
</form>
{% endfor %}
I'm trying to offer a solution as simple as possible. You should know that django provides a lot of cool stuff, that can help your to solve your problem much efficiently, such as forms, modelforms, formsets...

Answer 2

You can either create a ModelForm for your item and then use Formsets or if you can use jquery to submit a ajax request to a django view that updates the item for the selected model
$('<yourbuttonclass').onClick(function(e){
e.preventdefault()
$.post(urlToPost, dataFromTextField&csrfmiddlewaretken={{csrf_token}})
.success('Successfully Updated')
....
In your view:
#Get the item id from urlconf
#ajax_request
def update_view(request, item_id)
#Update your item
return {'Success': 'Updated to blah'}
I like to use the ajax_request decorator from here for sending ajax response. You can also send a HTTPResponse('Successfully updated')
If you want to creating a Restful resource would be a great way too and then you get an interface to create, update, read and delete from a single pattern. Read up on Django Tastypie

Answer 3

in views.py :
if request.method=='POST':
if 'txt1' in request.POST:
if request.POST['txt1']!='':
obj=Item.objects.get(pk=request.POST['item1'])
obj.quantity=request.POST['txt1']
obj.save()
if 'txt2' in request.POST:
if request.POST['txt2']!='':
obj=Item.objects.get(pk=request.POST['item2'])
obj.quantity=request.POST['txt2']
obj.save()
if 'txt3' in request.POST:
if request.POST['txt3']!='':
obj=Item.objects.get(pk=request.POST['item3'])
obj.quantity=request.POST['txt3']
obj.save()
#continue this code for all 6 items
update:
of course U can put this in a loop:
for i in range(1,6):
if 'txt'+str(i) in request.POST:
if request.POST['txt'+str(i)]!='':
obj=Item.objects.get(pk=request.POST['item'+str(i)]
obj.quantity=request.POST['txt'+str(i)]
obj.save()
in template:
<form method='POST' action=''>
{% for i in item %}
{{ i.name }}:<input type='text' id='txt{{forloop.counter}}' value='{{ i.quantity }}' /><input type='hidden' id='item{{forloop.counter}}' value='{{item.pk}}' /><input type='submit' value='increase' id='sbm{{forloop.counter}}' />
{% endfor %}
</form>
update: forloop.counter is the current for counter,1,2,3...