Django-models: Choices,select,widget How to change default options of widget - django

Question

I have problem with models for example i have
fallBack = models.CharField(max_length=100, choices=FALLBACK, default = 99,blank = True,null = True)
FALLBACK = (
(u'99','-'),
(u'standard', u'Standard TPF deactivation/exlusion applies'),
(u'fallback', u'Fallback script provided'),
(u'na',u'N/A'),
(u'other',u'Other'),
)
if i will use in template
{% for obj in form.forms %}
{{obj.fallBack}}
{% endfor %}
it will return sthing like this
<select name="form-0-fallBack" id="id_form-0-fallBack">
<option value="">---------</option>
<option value="99" selected="selected">-</option>
<option value="standard">Standard TPF deactivation/exlusion applies</option>
<option value="fallback">Fallback script provided</option>
<option value="na">N/A</option>
<option value="other">Other</option>
</select>
But i wanna make something like this:
<select **onchange="javascript:make()"** name="form-0-fallBack" id="id_form-0-fallBack">
<option value="">---------</option>
<option value="99" selected="selected">-</option>
<option value="standard">Standard TPF deactivation/exlusion applies</option>
<option value="fallback">Fallback script provided</option>
<option value="na">N/A</option>
<option value="other">Other</option>
</select>
How to do that ??
I can write in template this secound option instead of {{obj.fallBack}} but then my formset.is_valid() dont work , and when i will do something like this:
1)I will choose from fallBack second option(Standard TPF deactivation/exlusion applies)
2) submit,
3) I have some error in other place in template
4) Then my obj.fallBack returning to default option (99 , -)
Thanks for help

Answer 1

Check out the django documentation on Widgets
widget=forms.Select(attrs={'onchange': 'javascript:make()'})
This looks like a ModelForm, check out how to specify widgets for ModelForms