how to convert const WCHAR * to const char * - c++

Question

CString output ;
const WCHAR* wc = L"Hellow World" ;
if( wc != NULL )
{
output.Append(wc);
}
printf( "output: %s\n",output.GetBuffer(0) );

Answer 1

you can also try this:
#include <comdef.h> // you will need this
const WCHAR* wc = L"Hello World" ;
_bstr_t b(wc);
const char* c = b;
printf("Output: %s\n", c);
_bstr_t implements following conversion operators, which I find quite handy:
operator const wchar_t*( ) const throw( );
operator wchar_t*( ) const throw( );
operator const char*( ) const;
operator char*( ) const;
EDIT: clarification with regard to answer comments: line const char* c = b; results in a narrow character copy of the string being created and managed by the _bstr_t instance which will release it once when it is destroyed. The operator just returns a pointer to this copy. Therefore, there is no need to copy this string. Besides, in the question, CString::GetBuffer returns LPTSTR (i.e. TCHAR*) and not LPCTSTR (i.e. const TCHAR*).
Another option is to use conversion macros:
USES_CONVERSION;
const WCHAR* wc = L"Hello World" ;
const char* c = W2A(wc);
The problem with this approach is that the memory for converted string is allocated on stack, so the length of the string is limited. However, this family of conversion macros allow you to select the code page which is to be used for the conversion, which is often needed if wide string contains non-ANSI characters.

Answer 2

You can use sprintf for this purpose:
const char output[256];
const WCHAR* wc = L"Hellow World" ;
sprintf(output, "%ws", wc );

Answer 3

My code for Linux
// Debian GNU/Linux 8 "Jessie" (amd64)
#include <locale.h>
#include <stdlib.h>
#include <stdio.h>
// Use wcstombs(3) to convert Unicode-string (wchar_t *) to UTF-8 (char *)
// http://man7.org/linux/man-pages/man3/wcstombs.3.html
int f(const wchar_t *wcs) {
setlocale(LC_ALL,"ru_RU.UTF-8");
printf("Sizeof wchar_t: %d\n", sizeof(wchar_t));
// on Windows, UTF-16 is internal Unicode encoding (UCS2 before WinXP)
// on Linux, UCS4 is internal Unicode encoding
for (int i = 0; wcs[i] > 0; i++) printf("%2d %08X\n",i,wcs[i]);
char s[256];
size_t len = wcstombs(s,wcs,sizeof(s));
if (len > 0) {
s[len] = '\0';
printf("mbs: %s\n",s);
for (int i = 0; i < len; i++)
printf("%2d %02X\n",i,(unsigned char)s[i]);
printf("Size of mbs, in bytes: %d\n",len);
return 0;
}
else return -1;
}
int main() {
f(L"Привет"); // 6 symbols
return 0;
}
How to build
#!/bin/sh
NAME=`basename $0 .sh`
CC=/usr/bin/g++-4.9
INCS="-I."
LIBS="-L."
$CC ${NAME}.c -o _${NAME} $INCS $LIBS
Output
$ ./_test
Sizeof wchar_t: 4
0 0000041F
1 00000440
2 00000438
3 00000432
4 00000435
5 00000442
mbs: Привет
0 D0
1 9F
2 D1
3 80
4 D0
5 B8
6 D0
7 B2
8 D0
9 B5
10 D1
11 82
Size of mbs, in bytes: 12

Answer 4

It's quite easy, because CString is just a typedef for CStringT, and you also have access to CStringA and CStringW (you should read the documentation about the differences).
CStringW myString = L"Hello World";
CString myConvertedString = myString;

Answer 5

You could do this, or you could do something cleaner:
std::wcout << L"output: " << output.GetString() << std::endl;

Answer 6

You can use the std::wcsrtombs function.
Here is a C++17 overload set for conversion:
#include <iostream> // not required for the conversion function
// required for conversion
#include <cuchar>
#include <cwchar>
#include <stdexcept>
#include <string>
#include <string_view> // for std::wstring_view overload
std::string to_string(wchar_t const* wcstr){
auto s = std::mbstate_t();
auto const target_char_count = std::wcsrtombs(nullptr, &wcstr, 0, &s);
if(target_char_count == static_cast<std::size_t>(-1)){
throw std::logic_error("Illegal byte sequence");
}
// +1 because std::string adds a null terminator which isn't part of size
auto str = std::string(target_char_count, '\0');
std::wcsrtombs(str.data(), &wcstr, str.size() + 1, &s);
return str;
}
std::string to_string(std::wstring const& wstr){
return to_string(wstr.c_str());
}
std::string to_string(std::wstring_view const& view){
// wstring because wstring_view is not required to be null-terminated!
return to_string(std::wstring(view));
}
int main(){
using namespace std::literals;
std::cout
<< to_string(L"wchar_t const*") << "\n"
<< to_string(L"std::wstring"s) << "\n"
<< to_string(L"std::wstring_view"sv) << "\n";
}
If you use Pre-C++17, you should urgently update your compiler! ;-)
If this is really not possible, here is a C++11 version:
#include <iostream> // not required for the conversion function
// required for conversion
#include <cwchar>
#include <stdexcept>
#include <string>
std::string to_string(wchar_t const* wcstr){
auto s = std::mbstate_t();
auto const target_char_count = std::wcsrtombs(nullptr, &wcstr, 0, &s);
if(target_char_count == static_cast<std::size_t>(-1)){
throw std::logic_error("Illegal byte sequence");
}
// +1 because std::string adds a null terminator which isn't part of size
auto str = std::string(target_char_count, '\0');
std::wcsrtombs(const_cast<char*>(str.data()), &wcstr, str.size() + 1, &s);
return str;
}
std::string to_string(std::wstring const& wstr){
return to_string(wstr.c_str());
}
int main(){
std::cout
<< to_string(L"wchar_t const*") << "\n"
<< to_string(std::wstring(L"std::wstring")) << "\n";
}

Answer 7

You can use sprintf for this purpose, as #l0pan mentions (but I used %ls instead of %ws):
char output[256];
const WCHAR* wc = L"Hello World" ;
sprintf(output, "%ws", wc ); // did not work for me (Windows, C++ Builder)
sprintf(output, "%ls", wc ); // works