I have to make my homework. It is console application which uses an array of structs that keep information about a computer(brand, year of manufactoring, weight and inventory number). So I wrote a completely working program, but I want to use a dynamic array, because I dont know how many records the user will input.
Is there way to do this. To add new records in array until the user say n/N? Any suggestions?
This is my version of program:
#include "stdafx.h"
#include <iostream>
using namespace std;
struct ComputerInfo
{
char computerMark[20], invertarNumber[6];
unsigned int year;
float weight;
};
ComputerInfo computerArray[300];
ComputerInfo AddComputers(ComputerInfo compterArray[], int counter)
{
cout << "Enter mark of the computer: ";
cin >> computerArray[counter].computerMark;
cout << "Enter year of establish: ";
cin>> computerArray[counter].year;
while ((computerArray[counter].year < 1973)
|| (computerArray[counter].year > 2013))
{
cout << "INVALID YEAR!!!" << endl;
cout << "Enter year of establish: ";
cin>> computerArray[counter].year;
}
cout << "Enter computer weidth: ";
cin >> computerArray[counter].weight;
cout << "Enter computer invertar number(up to six digits): ";
cin >> computerArray[counter].invertarNumber;
return computerArray[counter];
}
void ShowRecords()
{
int counter = 0;
while (computerArray[counter].year != 0)
{
cout << "Mark: " << computerArray[counter].computerMark << endl;
cout << "Year: " << computerArray[counter].year << endl;
cout << "Weidth: " << computerArray[counter].weight << endl;
cout << "Inv. number: " << computerArray[counter].invertarNumber << endl << endl;
counter++;
}
}
void MoreThanTenYearsOld(ComputerInfo computerArray[])
{
int counter = 0;
float counterOldComputers = 0;
float computerPer = 0;
while (computerArray[counter].year == 0)
{
if (computerArray[counter].year <= 2003)
{
counterOldComputers++;
}
counter++;
}
computerPer = counterOldComputers / 3;
cout << endl;
cout << "Percantage of old computers is: " << computerPer << endl;
}
int main()
{
int counter = 0;
float computerPer = 0;
char answer = 'y';
for (int i = 0; i <= 299; i++)
{
strcpy(computerArray[i].computerMark,"");
}
while((answer == 'Y') || (answer == 'y'))
{
computerArray[counter] = AddComputers(computerArray, counter);
cout << endl;
cout << "Do you want to enter more records (Y/N): ";
cin >> answer;
cout << endl;
counter++;
}
MoreThanTenYearsOld(computerArray);
return 0;
}
Yes. Instead of your array, use
std::vector<ComputerInfo> computerArray;
and you can add as many objects as you want:
ComputerInfo c;
// read the data
computerArray.push_back(c);
now, computerArray[0] will have the info in c.
You'll need to #include <vector>.
Also, instead of char computerMark[20] you can use a std::string.
You have two options:
1) Use std::vector instead of an array. This is a very powerful tool and certainly worth learning how to use.
2) Dynamically allocate the array and resize it as you add more items. Basically this means writing your own version of std::vector. This is a good way to strengthen your programming skills. You will learn what goes into writing standard classes and functions. However, I advise using std::vector in more serious programming because it has already been thoroughly tested and debugged.
Related
I am not sure how to connect a part of an array or if it is even possible.
My code is as follows:
#include <algorithm>
#include <iostream>
using namespace std;
int main()
{
string name;
string date[3];
double height[3];
double enter;
cout << "Enter name of a pole vaulter: ";
cin >> name;
cout << "Enter date of first vault: ";
cin >> date[0];
cout << "Enter height of first vault: ";
cin >> enter;
if (enter >= 2.0)
{
if (enter <= 5.0)
{
height[0] = enter;
}
else
{
cout << "Incorrect Value";
abort();
}
}
else
{
cout << "Incorrect Value";
abort();
}
cout << "Enter date of second vault: ";
cin >> date[1];
cout << "Enter height of second vault: ";
cin >> enter;
if (enter >= 2.0)
{
if (enter <= 5.0)
{
height[1] = enter;
}
else
{
cout << "Incorrect Value";
abort();
}
}
else
{
cout << "Incorrect Value";
abort();
}
cout << "Enter date of third vault: ";
cin >> date[2];
cout << "Enter height of third vault: ";
cin >> enter;
if (enter >= 2.0)
{
if (enter <= 5.0)
{
height[2] = enter;
}
else
{
cout << "Incorrect Value";
abort();
}
}
else
{
cout << "Incorrect Value";
abort();
}
int len = sizeof(height) / sizeof(height[0]);
sort(height, height + len, greater<int>());
cout << "Stats for " << name << ":" << endl;
for (int i = 0; i < len; i++) {
cout << height[i] << " ";
}
cout << height[0];
}
I am trying to enter dates and a double value, and then organize the double values in descending order and keep the dates with the corresponding value. I am not sure if this is possible, any alternative way of completing this would be helpful.
Thank you
Group of data, data sorting, multiple data points that should be aligned/connected to their respective other data points. I think the best solution here would be the use of a struct or class with vectors:
Let's say you want a variable that contains both your date and number. We can construct a class or structure for that:
#include <iostream>
using namespace std;
struct str1
{
string date;
double number;
};
class cls1
{
public:
string date;
double number;
};
int main()
{
str1 ob1;
cls1 ob2;
ob1.date = "somedate";
ob1.number = 12345;
cin >> ob1.date;
cout << ob1.date << " " << ob1.number << endl;
ob2.date = "somedate2";
ob2.number = 54321;
cin >> ob2.number;
cout << ob2.date << " " << ob2.number << endl;
return 0;
}
Having a class or struct enables you to use objects (variables made from those structs or classes). Every object created has their own place in memory for storing both date and number. You can use, find, search any of these variables and have access to both values this way.
Grouping them up so there's a list of them can be done in vectors.
Vectors are like better arrays. They not only have a dynamical size (meaning its size can change and doesnt stay static like in arrays), but they also have quite a bit ready made functions for you to use:
bool sortingFunction(int &a, int &b)
{
if (a > b) return true;
else return false;
}
int main2()
{
vector<int> numbers;
//to add
numbers.emplace_back(5); //5 is the number to add
//to remove
numbers.erase(numbers.begin() + 2); //2 is the index of the variable to delete
//to sort
sort(numbers.begin(), numbers.end(), sortingFunction);
return 0;
}
Vectors need the #include <vector> header.
Sort is a function that sorts. Needs #include <algorithm> header.
Sort function is neat because you can define the logic behind how you want to sort the vector or array with a seperate function that returns either true or false.
For your example you could do something like this in the end:
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
struct myType
{
string date;
double number;
};
bool sortByDate(myType &a, myType &b)
{
if (a.date > b.date) return true;
else return false;
}
bool sortByNumber(myType &a, myType &b)
{
if (a.number > b.number) return true;
else return false;
}
int main()
{
vector<myType> variables;
int num;
cout << "how many do you want to add" << endl;
cin >> num;
for(int i = 0; i < num; i++)
{
myType tmp;
cout << "Enter date of var" << i+1 << ": ";
cin >> tmp.date;
cout << "Enter number of var" << i+1 << ": ";
cin >> tmp.number;
variables.emplace_back(tmp);
}
//after that you can use the vector as you want...
//sort
sort(variables.begin(), variables.end(), sortByDate);
sort(variables.begin(), variables.end(), sortByNumber);
//delete
variables.erase(variables.begin()+5);
//or clear the entire thing
variables.clear();
//Either way each item in the vector consists of both number and date thus even
//if you sort the vector the values are still connected at the same position
return 0;
}
I'm working on a program that I've seen other people do online except I'm trying to use functions to complete it to make it somewhat more challenging for me to help me better understand pointers and vectors. The problem I'm having in xcode is I keep getting this error..
Expected ';' after top level declarator
right here on my code,
void showMenu(menuItemType (&menu_List)[8])[], vector<int> numbers) //<<< Error
{
cout << fixed << setprecision(2);
...
Where I am trying to use vector numbers in my function. Basically I want the numbers from the function passed back so that I can use them in another function I have not created yet. I've googled this error and it seems like no one can give a straight answer on how to fix this problem. Is anyone familiar with how to correct this? By no means is this code finished I'm just trying to get information regarding vectors as a parameter because from what I'm seeing syntax wise on other sites it looks to be correct. Thanks for your feedback.
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
#include <sstream>
#include <iterator>
using namespace std;
struct menuItemType{
string menuItem;
double menuPrice;
};
void getData(menuItemType (&mlist)[8]);
void showMenu(menuItemType (&menu_List)[8], vector<int> numbers);
int main() {
vector<int> temp;
menuItemType menuList[8];
getData(menuList);
showMenu(menuList,temp);
/*
cout << menuList[0].menuItem << " " << menuList[0].menuPrice << endl;
cout << menuList[1].menuItem << " " << menuList[1].menuPrice << endl;
*/
return 0;
}
void getData(menuItemType (&mlist)[8]){
string Str;
ifstream infile;
infile.open("cafe135.txt");
if(infile.is_open())
{
for (int i = 0; i < 8; ++i){
infile >> mlist[i].menuItem >> mlist[i].menuPrice;
}
}
else cout << "Unable to open file";
}
void showMenu(menuItemType (&menu_List)[8])[], vector<int> numbers)
{
cout << fixed << setprecision(2);
string choice;
cout << "Would you like to view the menu? [Y] or [N]: ";
cin >> choice;
cout << endl;
int x = 3;
int count = 1;
while (choice != "Y" && choice != "N" && choice != "y" && choice != "n")
{
if (count == 4){
return;
}
cout << "Error! Please try again ["
<< x
<< "] selections remaining: ";
cin >> choice;
cout << endl;
x--;
count++;
}
if (choice == "N" || choice == "n"){
return;
}
else
{
cout << "___________ Breakfast Menu ___________" << endl;
for (int i = 0; i < sizeof(menu_List)/sizeof(menu_List[0]); ++i)
{
cout << "Item "
<< (i+1)
<< ": "
<< menu_List[i].menuItem
<< " "
<< menu_List[i].menuPrice
<< endl;
}
cout << endl;
string itemSelection = " ";
//int str_length = 0;
cout << "Select your item numbers separated"
<< " by spaces (e.g. 1 3 5) Select 0 to cancel order: ";
cin.ignore();
getline(cin, itemSelection);
if (itemSelection == "0")
{
return;
}
vector<int> vectorItemSelection;
stringstream text_stream(itemSelection);
string item;
while (getline(text_stream, item, ' '))
{
vectorItemSelection.push_back(stoi(item));
}
int n = vectorItemSelection.size();
int arr[n];
for (int i = 0; i < n; i++)
{
arr[i] = vectorItemSelection[i];
}
}
}
Compare how menu_List is declared in this line
void showMenu(menuItemType (&menu_List)[8], vector<int> numbers);
and this line
void showMenu(menuItemType (&menu_List)[8])[], vector<int> numbers)
The first one is correct.
But I have to agree with the comments above, you are mixing up a lot of different things here. Just use vectors, 99% of the time it's the right thing to do anyway. and it's easier to learn one thing at a time.
Prefer to write your code like this
void getData(vector<menuItemType>&);
void showMenu(vector<menuItemType>&, vector<int> numbers);
int main() {
vector<int> temp;
vector<menuItemType> menuList(8);
...
See? Just use vectors everywhere.
I've started to learn how to code in C++ on my spare time, using different sites and apps that someone who has also learned C++ online provided me with. By now, I know the most basic commands. I've tried an exercise given by a program, and I'm given the information that someone is going on a vacation, and needs to know how much baggage he can bring with him. The limit to how many baggages he can carry is 45, and I have to display a different output if the baggages are below, above or the same as the limit (45 baggages). I have done some coding, and I ended up with this:
#include <iostream>
using namespace std;
int main()
{
const int limit = 45;
int bag;
cout << "Please type your number here: ";
cin >> bag;
string yn;
int keep = 0;
if (limit < bag)
{
cout << "You passed the limit." << endl;
};
if (limit == bag)
{
cout << "Just enough." << endl;
};
if (limit > bag)
{
cout << "You got space." << endl;
};
++keep;
while(keep > 0)
{
int keep = 0;
cout << "Do you want to try another number?" << endl;
cin >> yn;
cout << endl;
if(yn == "yes")
{
int bag = 0;
cout << "Please type your number here: ";
cin >> bag;
if (limit < bag)
{
cout << "You passed the limit." << endl;
};
if (limit == bag)
{
cout << "Just enough." << endl;
};
if (limit > bag)
{
cout << "You got space." << endl;
};
}
else
{
return 0;
}
}
}
I have developed it more than needed -as you can see-, out of my own interest in the problem. I have copied and pasted the 3 IF commands as seen above, and I believe that there is an easier way, with less code, do solve this. What I have thought of is if I could go back and execute some line of code again, either from a line and below (e.g. from line 45 and below), or specific lines of code (e.g. from line 45 to line 60).
I would appreciate it if you thought of another way to solve this problem and posted your code below.
Thank you for your reply.
We all started writing our first C++ program at some time, so allow me to give you some additional feedback:
First of all, avoid writing using namespace std;
Secondly, naming - what is bag, limit, keep and yn? Wouldn't it be much easier to read and understand if they were called bagSize, maximumPermittedBagSize, inputFromUser (you don't really need the variable keep, see below)?
Finally, here is a (roughly) refactored version your program, with duplication removed and comments added.
#include <iostream>
int main()
{
const int maximumPermittedBagSize = 45;
// Loops forever, the user exits by typing anything except 'yes' laster
while(true)
{
std::cout << "Please type your number here: " << std::endl;
//Declare (and initialize!) variables just before you need them
int bagSize = 0;
std::cin >> bagSize;
if (bagSize > maximumPermittedBagSize)
{
std::cout << "You passed the limit." << std::endl;
}
else if (bagSize == maximumPermittedBagSize )
{
std::cout << "Just enough." << std::endl;
}
else
{
std::cout << "You got space." << std::endl;
}
std::cout << "Do you want to try another number?" << std::endl;
std::string inputFromUser = "";
std::cin >> inputFromUser;
std::cout << std::endl;
//Leave the loop if the user does not answer yes
if(inputFromUser != "yes")
{
return 0;
}
}
}
You can simply run a while loop and do like this:
#include <iostream>
using namespace std;
int main()
{
const int limit = 45;
int bag;
string yn = "yes";
while(yn == "yes")
{
cout << "Please type your number here: ";
cin >> bag;
if (limit < bag)
{
cout << "You passed the limit." << endl;
}
else if (limit == bag)
{
cout << "Just enough." << endl;
}
else if (limit > bag)
{
cout << "You got space." << endl;
}
cout << "Do you want to try another number?" << endl;
cin >> yn;
cout << endl;
}
}
I've come across a little problem, how do I print the winning candidate's name? See the instructions here are, input five names, their number of votes and percentage of votes, whoever has the highest wins. I don't know if I did my code right, but it works.. well except for the name part. I've tried everything from a lot of for loops to transfer the array or what.
I'm almost done with the code.
Here's the code
#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
char candidates[50];
int votes[5]={0};
float percent[5]={0};
int a,b,c,d,e,i;
int maxx;
int champ=0;
char winner[50];
cout << "Enter the candidates' last names: ";
cout << endl;
for(a=1;a<=5;a++)
{
cout << a << ". ";
cin >> candidates;
}
cout << endl;
cout << "Enter their number of votes: " << endl;
for(b=1;b<=5;b++)
{
cout << b << ". ";
cin >> votes[b];
}
cout << endl;
cout << "percentage of votes: " << endl;
for(c=1;c<=5;c++)
{
cout << c << ". ";
percent[c]=votes[c]*0.2;
printf("%.2f\n", percent[c]);
}
cout <<"Candidates\t\tVotes\t\t% of Votes" << endl;
for(int k=1;k<=5;k++)
{
cout << candidates[k] << "\t\t\t" << votes[k] << "\t\t\t";
printf("%.2f\n", percent[k]);
}
maxx=percent[0];
for(d=1;d<=5;d++)
{
if(maxx<percent[d]);
{
//what happens here?
}
}
return 0;
}
You should keep a 2d array of characters or array of string for storing candidate names instead of a 1-d array.
char candidates[5][10]; //
for(int i = 0; i < 5; i++)
{
cin >> candidates[i];
}
Then keep a variable to store index for winning candidate
int winIndex = 0;
int winPercent = 0;
for(int i = 0; i < 5; i++)
{
if(percent[i] > winPercent)
{
winPercent = percent;
winIndex = i;
}
}
Finally print name of winning candidate;
cout << candidates[winIndex];
In object oriented approach, you may create a class with following information
class Candidate
{
string name;
int votes;
float percent;
};
Use string candidates[50]; instead of char candidates[50];
then cin >> candidates[a];
I'm new to this site and programming in C++ language this semester.
I have been really trying for 2 days and have asked classmates but they do not know either. A classmate said to use the 2D arrays but I don't know what that is and my professor has not gone over 2D arrays.
I am stuck and would really appreciate help.
The input file contains this:
Plain_Egg 1.45
Bacon_and_Egg 2.45
Muffin 0.99
French_Toast 1.99
Fruit_Basket 2.49
Cereal 0.69
Coffee 0.50
Tea 0.75
idk how to display all the "users" orders
Basically a receipt, like he orders this and how many, then ask "u want anything else?", then take the order number and how many again, THEN at the end give back a receipt that looks like this
bacon_and_eggs $2.45
Muffin $0.99
Coffee $0.50
Tax $0.20
Amount Due $4.14
Here is my code:
// Libraries
#include <iostream>
#include <string>
#include <iomanip>
#include <fstream>
#include <cmath>
using namespace std;
//structures
struct menuItemType {
string itemName;
double itemCost;
};
// Prototypes
void header();
void readData(menuItemType menu[]);
void Display(menuItemType menu[]);
int main() {
header();
menuItemType menu [8];
readData(menu);
Display(menu);
//system("pause");
return 0;
}
void header() {
char c= 61;
for (int i=0; i < 64; i++) {
cout << c;
}
cout << c << endl;
cout << endl;
cout << "Breakfast Menu" <<endl;
for (int i=0; i < 64; i++) {
cout << c;
}
cout << "" << c << endl;
cout << endl;
}
void readData(menuItemType item[]) {
int i=0;
ifstream in;
in.open("input.txt");
cout << fixed << setprecision(2);
while(!in.eof()) {
in >> item[i].itemName >> item[i].itemCost;
++i;
}
}
void Display(menuItemType item[]) {
int choice = 0, quantity = 0;
double total = 0.0, totalF = 0.0, tax = 0.0;
char exit = 'y';
int j = 1, z = 1, i = 1;
//the Menu
for (int i=0; i<8; i++){
cout << j << ". " << setw(18) << left << item[i].itemName << "$" << setw(10) << item[i].itemCost << endl;
j++;
}
cout << endl;
while(exit == 'y' || exit == 'Y') {
cout << "Please Enter your Selection or 0 to Exit : ";
cin >> choice;
if(cin.fail()) {
cout << "*******Invalid selection*******" << endl;
cin.clear();
cin.ignore(1000,'\n');
} else if (choice==0) {break; }
else {
cout<< "Enter Quantity: ";
cin>> quantity;
if (quantity==0) { break;}
else {
choice--;
total += (quantity * item[choice].itemCost);
tax = (total * .05);
totalF = total + tax;
cout << endl;
}
cout << endl;
cout << "======================================================" << endl;
cout << item[choice].itemName << "\t\t" << item[choice].itemCost << endl;
cout << "======================================================" << endl;
cout << "Do you want to continue (Y/N): ";
cin >> exit;
}
}
}
First off, you don't need a two dimensional array for this! You already have a one dimensional array of a suitable structure, as far as I can tell: Something which stores the name of the object and its price. What is somewhat missing is how many objects are currently in the array and how much space it has. If you want to go with the content of the entire array, make sure that you objects are correctly initialized, e.g., that the names are empty (this happens automatically, actually) and that the prices are zero (this does not).
I'm not sure if it is a copy&paste errors but the headers are incorrectly included. The include directives should look something like this:
#include <iostream>
The actual loop reading the values doesn't really work: You always need to check that the input was successful after you tried to read! Also, using eof() for checking that the loop ends is wrong (I don't know where people pick this up from; any book recommending the use of eof() for checking input loops is only useful for burning). The loop should look something like this:
while (i < ArraySize && in >> item[i].itemName >> item[i].itemCost)
++i;
}
This also fixes the potential boundary overrun in case there is more input than the array can consume. You might want to consider using a std::vector<Item> instead: this class keeps track of how many elements there are and you can append new elements as needed.
Note that you didn't quite say what you are stuck with: You'd need to come up with a clearer description of what your actual problem is. The above is just correcting existing errors and readjusting the direction to look into (i.e., forget about two dimensional arrays for now).