I've been thinking about the possible use of delete this in c++, and I've seen one use.
Because you can say delete this only when an object is on heap, I can make the destructor private and stop objects from being created on stack altogether. In the end I can just delete the object on heap by saying delete this in a random public member function that acts as a destructor. My questions:
1) Why would I want to force the object to be made on the heap instead of on the stack?
2) Is there another use of delete this apart from this? (supposing that this is a legitimate use of it :) )
Any scheme that uses delete this is somewhat dangerous, since whoever called the function that does that is left with a dangling pointer. (Of course, that's also the case when you delete an object normally, but in that case, it's clear that the object has been deleted). Nevertheless, there are somewhat legitimate cases for wanting an object to manage its own lifetime.
It could be used to implement a nasty, intrusive reference-counting scheme. You would have functions to "acquire" a reference to the object, preventing it from being deleted, and then "release" it once you've finished, deleting it if noone else has acquired it, along the lines of:
class Nasty {
public:
Nasty() : references(1) {}
void acquire() {
++references;
}
void release() {
if (--references == 0) {
delete this;
}
}
private:
~Nasty() {}
size_t references;
};
// Usage
Nasty * nasty = new Nasty; // 1 reference
nasty->acquire(); // get a second reference
nasty->release(); // back to one
nasty->release(); // deleted
nasty->acquire(); // BOOM!
I would prefer to use std::shared_ptr for this purpose, since it's thread-safe, exception-safe, works for any type without needing any explicit support, and prevents access after deleting.
More usefully, it could be used in an event-driven system, where objects are created, and then manage themselves until they receive an event that tells them that they're no longer needed:
class Worker : EventReceiver {
public:
Worker() {
start_receiving_events(this);
}
virtual void on(WorkEvent) {
do_work();
}
virtual void on(DeleteEvent) {
stop_receiving_events(this);
delete this;
}
private:
~Worker() {}
void do_work();
};
1) Why would I want to force the object to be made on the heap instead of on the stack?
1) Because the object's lifetime is not logically tied to a scope (e.g., function body, etc.). Either because it must manage its own lifespan, or because it is inherently a shared object (and thus, its lifespan must be attached to those of its co-dependent objects). Some people here have pointed out some examples like event handlers, task objects (in a scheduler), and just general objects in a complex object hierarchy.
2) Because you want to control the exact location where code is executed for the allocation / deallocation and construction / destruction. The typical use-case here is that of cross-module code (spread across executables and DLLs (or .so files)). Because of issues of binary compatibility and separate heaps between modules, it is often a requirement that you strictly control in what module these allocation-construction operations happen. And that implies the use of heap-based objects only.
2) Is there another use of delete this apart from this? (supposing that this is a legitimate use of it :) )
Well, your use-case is really just a "how-to" not a "why". Of course, if you are going to use a delete this; statement within a member function, then you must have controls in place to force all creations to occur with new (and in the same translation unit as the delete this; statement occurs). Not doing this would just be very very poor style and dangerous. But that doesn't address the "why" you would use this.
1) As others have pointed out, one legitimate use-case is where you have an object that can determine when its job is over and consequently destroy itself. For example, an event handler deleting itself when the event has been handled, a network communication object that deletes itself once the transaction it was appointed to do is over, or a task object in a scheduler deleting itself when the task is done. However, this leaves a big problem: signaling to the outside world that it no longer exists. That's why many have mentioned the "intrusive reference counting" scheme, which is one way to ensure that the object is only deleted when there are no more references to it. Another solution is to use a global (singleton-like) repository of "valid" objects, in which case any accesses to the object must go through a check in the repository and the object must also add/remove itself from the repository at the same time as it makes the new and delete this; calls (either as part of an overloaded new/delete, or alongside every new/delete calls).
However, there is a much simpler and less intrusive way to achieve the same behavior, albeit less economical. One can use a self-referencing shared_ptr scheme. As so:
class AutonomousObject {
private:
std::shared_ptr<AutonomousObject> m_shared_this;
protected:
AutonomousObject(/* some params */);
public:
virtual ~AutonomousObject() { };
template <typename... Args>
static std::weak_ptr<AutonomousObject> Create(Args&&... args) {
std::shared_ptr<AutonomousObject> result(new AutonomousObject(std::forward<Args>(args)...));
result->m_shared_this = result; // link the self-reference.
return result; // return a weak-pointer.
};
// this is the function called when the life-time should be terminated:
void OnTerminate() {
m_shared_this.reset( NULL ); // do not use reset(), but use reset( NULL ).
};
};
With the above (or some variations upon this crude example, depending on your needs), the object will be alive for as long as it deems necessary and that no-one else is using it. The weak-pointer mechanism serves as the proxy to query for the existence of the object, by possible outside users of the object. This scheme makes the object a bit heavier (has a shared-pointer in it) but it is easier and safer to implement. Of course, you have to make sure that the object eventually deletes itself, but that's a given in this kind of scenario.
2) The second use-case I can think of ties in to the second motivation for restricting an object to be heap-only (see above), however, it applies also for when you don't restrict it as such. If you want to make sure that both the deallocation and the destruction are dispatched to the correct module (the module from which the object was allocated and constructed), you must use a dynamic dispatching method. And for that, the easiest is to just use a virtual function. However, a virtual destructor is not going to cut it because it only dispatches the destruction, not the deallocation. The solution is to use a virtual "destroy" function that calls delete this; on the object in question. Here is a simple scheme to achieve this:
struct CrossModuleDeleter; //forward-declare.
class CrossModuleObject {
private:
virtual void Destroy() /* final */;
public:
CrossModuleObject(/* some params */); //constructor can be public.
virtual ~CrossModuleObject() { }; //destructor can be public.
//.... whatever...
friend struct CrossModuleDeleter;
template <typename... Args>
static std::shared_ptr< CrossModuleObject > Create(Args&&... args);
};
struct CrossModuleDeleter {
void operator()(CrossModuleObject* p) const {
p->Destroy(); // do a virtual dispatch to reach the correct deallocator.
};
};
// In the cpp file:
// Note: This function should not be inlined, so stash it into a cpp file.
void CrossModuleObject::Destroy() {
delete this;
};
template <typename... Args>
std::shared_ptr< CrossModuleObject > CrossModuleObject::Create(Args&&... args) {
return std::shared_ptr< CrossModuleObject >( new CrossModuleObject(std::forward<Args>(args)...), CrossModuleDeleter() );
};
The above kind of scheme works well in practice, and it has the nice advantage that the class can act as a base-class with no additional intrusion by this virtual-destroy mechanism in the derived classes. And, you can also modify it for the purpose of allowing only heap-based objects (as usually, making constructors-destructors private or protected). Without the heap-based restriction, the advantage is that you can still use the object as a local variable or data member (by value) if you want, but, of course, there will be loop-holes left to avoid by whoever uses the class.
As far as I know, these are the only legitimate use-cases I have ever seen anywhere or heard of (and the first one is easily avoidable, as I have shown, and often should be).
The general reason is that the lifetime of the object is determined by some factor internal to the class, at least from an application viewpoint. Hence, it may very well be a private method which calls delete this;.
Obviously, when the object is the only one to know how long it's needed, you can't put it on a random thread stack. It's necessary to create such objects on the heap.
It's generally an exceptionally bad idea. There are a very few cases- for example, COM objects have enforced intrusive reference counting. You'd only ever do this with a very specific situational reason- never for a general-purpose class.
1) Why would I want to force the object to be made on the heap instead of on the stack?
Because its life span isn't determined by the scoping rule.
2) Is there another use of delete this apart from this? (supposing that this is a legitimate use of it :) )
You use delete this when the object is the best placed one to be responsible for its own life span. One of the simplest example I know of is a window in a GUI. The window reacts to events, a subset of which means that the window has to be closed and thus deleted. In the event handler the window does a delete this. (You may delegate the handling to a controller class. But the situation "window forwards event to controller class which decides to delete the window" isn't much different of delete this, the window event handler will be left with the window deleted. You may also need to decouple the close from the delete, but your rationale won't be related to the desirability of delete this).
delete this;
can be useful at times and is usually used for a control class that also controls the lifetime of another object. With intrusive reference counting, the class it is controlling is one that derives from it.
The outcome of using such a class should be to make lifetime handling easier for users or creators of your class. If it doesn't achieve this, it is bad practice.
A legitimate example may be where you need a class to clean up all references to itself before it is destructed. In such a case, you "tell" the class whenever you are storing a reference to it (in your model, presumably) and then on exit, your class goes around nulling out these references or whatever before it calls delete this on itself.
This should all happen "behind the scenes" for users of your class.
"Why would I want to force the object to be made on the heap instead of on the stack?"
Generally when you force that it's not because you want to as such, it's because the class is part of some polymorphic hierarchy, and the only legitimate way to get one is from a factory function that returns an instance of a different derived class according to the parameters you pass it, or according to some configuration that it knows about. Then it's easy to arrange that the factory function creates them with new. There's no way that users of those classes could have them on the stack even if they wanted to, because they don't know in advance the derived type of the object they're using, only the base type.
Once you have objects like that, you know that they're destroyed with delete, and you can consider managing their lifecycle in a way that ultimately ends in delete this. You'd only do this if the object is somehow capable of knowing when it's no longer needed, which usually would be (as Mike says) because it's part of some framework that doesn't manage object lifetime explicitly, but does tell its components that they've been detached/deregistered/whatever[*].
If I remember correctly, James Kanze is your man for this. I may have misremembered, but I think he occasionally mentions that in his designs delete this isn't just used but is common. Such designs avoid shared ownership and external lifecycle management, in favour of networks of entity objects managing their own lifecycles. And where necessary, deregistering themselves from anything that knows about them prior to destroying themselves. So if you have several "tools" in a "toolbelt" then you wouldn't construe that as the toolbelt "owning" references to each of the tools, you think of the tools putting themselves in and out of the belt.
[*] Otherwise you'd have your factory return a unique_ptr or auto_ptr to encourage callers to stuff the object straight into the memory management type of their choice, or you'd return a raw pointer but provide the same encouragement via documentation. All the stuff you're used to seeing.
A good rule of thumb is not to use delete this.
Simply put, the thing that uses new should be responsible enough to use the delete when done with the object. This also avoids the problems with is on the stack/heap.
Once upon a time i was writing some plugin code. I believe i mixed build (debug for plugin, release for main code or maybe the other way around) because one part should be fast. Or maybe another situation happened. Such main is already released built on gcc and plugin is being debugged/tested on VC. When the main code deleted something from the plugin or plugin deleted something a memory issue would occur. It was because they both used different memory pools or malloc implementations. So i had a private dtor and a virtual function called deleteThis().
-edit- Now i may consider overloading the delete operator or using a smart pointer or simply just state never delete a function. It will depend and usually overloading new/delete should never be done unless you really know what your doing (dont do it). I decide to use deleteThis() because i found it easier then the C like way of thing_alloc and thing_free as deleteThis() felt like the more OOP way of doing it
Related
Is it allowed to delete this; if the delete-statement is the last statement that will be executed on that instance of the class? Of course I'm sure that the object represented by the this-pointer is newly-created.
I'm thinking about something like this:
void SomeModule::doStuff()
{
// in the controller, "this" object of SomeModule is the "current module"
// now, if I want to switch over to a new Module, eg:
controller->setWorkingModule(new OtherModule());
// since the new "OtherModule" object will take the lead,
// I want to get rid of this "SomeModule" object:
delete this;
}
Can I do this?
The C++ FAQ Lite has a entry specifically for this
https://isocpp.org/wiki/faq/freestore-mgmt#delete-this
I think this quote sums it up nicely
As long as you're careful, it's OK for an object to commit suicide (delete this).
Yes, delete this; has defined results, as long as (as you've noted) you assure the object was allocated dynamically, and (of course) never attempt to use the object after it's destroyed. Over the years, many questions have been asked about what the standard says specifically about delete this;, as opposed to deleting some other pointer. The answer to that is fairly short and simple: it doesn't say much of anything. It just says that delete's operand must be an expression that designates a pointer to an object, or an array of objects. It goes into quite a bit of detail about things like how it figures out what (if any) deallocation function to call to release the memory, but the entire section on delete (§[expr.delete]) doesn't mention delete this; specifically at all. The section on destructors does mention delete this in one place (§[class.dtor]/13):
At the point of definition of a virtual destructor (including an implicit definition (15.8)), the non-array deallocation function is determined as if for the expression delete this appearing in a non-virtual destructor of the destructor’s class (see 8.3.5).
That tends to support the idea that the standard considers delete this; to be valid -- if it was invalid, its type wouldn't be meaningful. That's the only place the standard mentions delete this; at all, as far as I know.
Anyway, some consider delete this a nasty hack, and tell anybody who will listen that it should be avoided. One commonly cited problem is the difficulty of ensuring that objects of the class are only ever allocated dynamically. Others consider it a perfectly reasonable idiom, and use it all the time. Personally, I'm somewhere in the middle: I rarely use it, but don't hesitate to do so when it seems to be the right tool for the job.
The primary time you use this technique is with an object that has a life that's almost entirely its own. One example James Kanze has cited was a billing/tracking system he worked on for a phone company. When you start to make a phone call, something takes note of that and creates a phone_call object. From that point onward, the phone_call object handles the details of the phone call (making a connection when you dial, adding an entry to the database to say when the call started, possibly connect more people if you do a conference call, etc.) When the last people on the call hang up, the phone_call object does its final book-keeping (e.g., adds an entry to the database to say when you hung up, so they can compute how long your call was) and then destroys itself. The lifetime of the phone_call object is based on when the first person starts the call and when the last people leave the call -- from the viewpoint of the rest of the system, it's basically entirely arbitrary, so you can't tie it to any lexical scope in the code, or anything on that order.
For anybody who might care about how dependable this kind of coding can be: if you make a phone call to, from, or through almost any part of Europe, there's a pretty good chance that it's being handled (at least in part) by code that does exactly this.
If it scares you, there's a perfectly legal hack:
void myclass::delete_me()
{
std::unique_ptr<myclass> bye_bye(this);
}
I think delete this is idiomatic C++ though, and I only present this as a curiosity.
There is a case where this construct is actually useful - you can delete the object after throwing an exception that needs member data from the object. The object remains valid until after the throw takes place.
void myclass::throw_error()
{
std::unique_ptr<myclass> bye_bye(this);
throw std::runtime_exception(this->error_msg);
}
Note: if you're using a compiler older than C++11 you can use std::auto_ptr instead of std::unique_ptr, it will do the same thing.
One of the reasons that C++ was designed was to make it easy to reuse code. In general, C++ should be written so that it works whether the class is instantiated on the heap, in an array, or on the stack. "Delete this" is a very bad coding practice because it will only work if a single instance is defined on the heap; and there had better not be another delete statement, which is typically used by most developers to clean up the heap. Doing this also assumes that no maintenance programmer in the future will cure a falsely perceived memory leak by adding a delete statement.
Even if you know in advance that your current plan is to only allocate a single instance on the heap, what if some happy-go-lucky developer comes along in the future and decides to create an instance on the stack? Or, what if he cuts and pastes certain portions of the class to a new class that he intends to use on the stack? When the code reaches "delete this" it will go off and delete it, but then when the object goes out of scope, it will call the destructor. The destructor will then try to delete it again and then you are hosed. In the past, doing something like this would screw up not only the program but the operating system and the computer would need to be rebooted. In any case, this is highly NOT recommended and should almost always be avoided. I would have to be desperate, seriously plastered, or really hate the company I worked for to write code that did this.
It is allowed (just do not use the object after that), but I wouldn't write such code on practice. I think that delete this should appear only in functions that called release or Release and looks like: void release() { ref--; if (ref<1) delete this; }.
Well, in Component Object Model (COM) delete this construction can be a part of Release method that is called whenever you want to release aquisited object:
void IMyInterface::Release()
{
--instanceCount;
if(instanceCount == 0)
delete this;
}
This is the core idiom for reference-counted objects.
Reference-counting is a strong form of deterministic garbage collection- it ensures objects manage their OWN lifetime instead of relying on 'smart' pointers, etc. to do it for them. The underlying object is only ever accessed via "Reference" smart pointers, designed so that the pointers increment and decrement a member integer (the reference count) in the actual object.
When the last reference drops off the stack or is deleted, the reference count will go to zero. Your object's default behavior will then be a call to "delete this" to garbage collect- the libraries I write provide a protected virtual "CountIsZero" call in the base class so that you can override this behavior for things like caching.
The key to making this safe is not allowing users access to the CONSTRUCTOR of the object in question (make it protected), but instead making them call some static member- the FACTORY- like "static Reference CreateT(...)". That way you KNOW for sure that they're always built with ordinary "new" and that no raw pointer is ever available, so "delete this" won't ever blow up.
You can do so. However, you can't assign to this. Thus the reason you state for doing this, "I want to change the view," seems very questionable. The better method, in my opinion, would be for the object that holds the view to replace that view.
Of course, you're using RAII objects and so you don't actually need to call delete at all...right?
This is an old, answered, question, but #Alexandre asked "Why would anyone want to do this?", and I thought that I might provide an example usage that I am considering this afternoon.
Legacy code. Uses naked pointers Obj*obj with a delete obj at the end.
Unfortunately I need sometimes, not often, to keep the object alive longer.
I am considering making it a reference counted smart pointer. But there would be lots of code to change, if I was to use ref_cnt_ptr<Obj> everywhere. And if you mix naked Obj* and ref_cnt_ptr, you can get the object implicitly deleted when the last ref_cnt_ptr goes away, even though there are Obj* still alive.
So I am thinking about creating an explicit_delete_ref_cnt_ptr. I.e. a reference counted pointer where the delete is only done in an explicit delete routine. Using it in the one place where the existing code knows the lifetime of the object, as well as in my new code that keeps the object alive longer.
Incrementing and decrementing the reference count as explicit_delete_ref_cnt_ptr get manipulated.
But NOT freeing when the reference count is seen to be zero in the explicit_delete_ref_cnt_ptr destructor.
Only freeing when the reference count is seen to be zero in an explicit delete-like operation. E.g. in something like:
template<typename T> class explicit_delete_ref_cnt_ptr {
private:
T* ptr;
int rc;
...
public:
void delete_if_rc0() {
if( this->ptr ) {
this->rc--;
if( this->rc == 0 ) {
delete this->ptr;
}
this->ptr = 0;
}
}
};
OK, something like that. It's a bit unusual to have a reference counted pointer type not automatically delete the object pointed to in the rc'ed ptr destructor. But it seems like this might make mixing naked pointers and rc'ed pointers a bit safer.
But so far no need for delete this.
But then it occurred to me: if the object pointed to, the pointee, knows that it is being reference counted, e.g. if the count is inside the object (or in some other table), then the routine delete_if_rc0 could be a method of the pointee object, not the (smart) pointer.
class Pointee {
private:
int rc;
...
public:
void delete_if_rc0() {
this->rc--;
if( this->rc == 0 ) {
delete this;
}
}
}
};
Actually, it doesn't need to be a member method at all, but could be a free function:
map<void*,int> keepalive_map;
template<typename T>
void delete_if_rc0(T*ptr) {
void* tptr = (void*)ptr;
if( keepalive_map[tptr] == 1 ) {
delete ptr;
}
};
(BTW, I know the code is not quite right - it becomes less readable if I add all the details, so I am leaving it like this.)
Delete this is legal as long as object is in heap.
You would need to require object to be heap only.
The only way to do that is to make the destructor protected - this way delete may be called ONLY from class , so you would need a method that would ensure deletion
Is it allowed to delete this; if the delete-statement is the last statement that will be executed on that instance of the class? Of course I'm sure that the object represented by the this-pointer is newly-created.
I'm thinking about something like this:
void SomeModule::doStuff()
{
// in the controller, "this" object of SomeModule is the "current module"
// now, if I want to switch over to a new Module, eg:
controller->setWorkingModule(new OtherModule());
// since the new "OtherModule" object will take the lead,
// I want to get rid of this "SomeModule" object:
delete this;
}
Can I do this?
The C++ FAQ Lite has a entry specifically for this
https://isocpp.org/wiki/faq/freestore-mgmt#delete-this
I think this quote sums it up nicely
As long as you're careful, it's OK for an object to commit suicide (delete this).
Yes, delete this; has defined results, as long as (as you've noted) you assure the object was allocated dynamically, and (of course) never attempt to use the object after it's destroyed. Over the years, many questions have been asked about what the standard says specifically about delete this;, as opposed to deleting some other pointer. The answer to that is fairly short and simple: it doesn't say much of anything. It just says that delete's operand must be an expression that designates a pointer to an object, or an array of objects. It goes into quite a bit of detail about things like how it figures out what (if any) deallocation function to call to release the memory, but the entire section on delete (§[expr.delete]) doesn't mention delete this; specifically at all. The section on destructors does mention delete this in one place (§[class.dtor]/13):
At the point of definition of a virtual destructor (including an implicit definition (15.8)), the non-array deallocation function is determined as if for the expression delete this appearing in a non-virtual destructor of the destructor’s class (see 8.3.5).
That tends to support the idea that the standard considers delete this; to be valid -- if it was invalid, its type wouldn't be meaningful. That's the only place the standard mentions delete this; at all, as far as I know.
Anyway, some consider delete this a nasty hack, and tell anybody who will listen that it should be avoided. One commonly cited problem is the difficulty of ensuring that objects of the class are only ever allocated dynamically. Others consider it a perfectly reasonable idiom, and use it all the time. Personally, I'm somewhere in the middle: I rarely use it, but don't hesitate to do so when it seems to be the right tool for the job.
The primary time you use this technique is with an object that has a life that's almost entirely its own. One example James Kanze has cited was a billing/tracking system he worked on for a phone company. When you start to make a phone call, something takes note of that and creates a phone_call object. From that point onward, the phone_call object handles the details of the phone call (making a connection when you dial, adding an entry to the database to say when the call started, possibly connect more people if you do a conference call, etc.) When the last people on the call hang up, the phone_call object does its final book-keeping (e.g., adds an entry to the database to say when you hung up, so they can compute how long your call was) and then destroys itself. The lifetime of the phone_call object is based on when the first person starts the call and when the last people leave the call -- from the viewpoint of the rest of the system, it's basically entirely arbitrary, so you can't tie it to any lexical scope in the code, or anything on that order.
For anybody who might care about how dependable this kind of coding can be: if you make a phone call to, from, or through almost any part of Europe, there's a pretty good chance that it's being handled (at least in part) by code that does exactly this.
If it scares you, there's a perfectly legal hack:
void myclass::delete_me()
{
std::unique_ptr<myclass> bye_bye(this);
}
I think delete this is idiomatic C++ though, and I only present this as a curiosity.
There is a case where this construct is actually useful - you can delete the object after throwing an exception that needs member data from the object. The object remains valid until after the throw takes place.
void myclass::throw_error()
{
std::unique_ptr<myclass> bye_bye(this);
throw std::runtime_exception(this->error_msg);
}
Note: if you're using a compiler older than C++11 you can use std::auto_ptr instead of std::unique_ptr, it will do the same thing.
One of the reasons that C++ was designed was to make it easy to reuse code. In general, C++ should be written so that it works whether the class is instantiated on the heap, in an array, or on the stack. "Delete this" is a very bad coding practice because it will only work if a single instance is defined on the heap; and there had better not be another delete statement, which is typically used by most developers to clean up the heap. Doing this also assumes that no maintenance programmer in the future will cure a falsely perceived memory leak by adding a delete statement.
Even if you know in advance that your current plan is to only allocate a single instance on the heap, what if some happy-go-lucky developer comes along in the future and decides to create an instance on the stack? Or, what if he cuts and pastes certain portions of the class to a new class that he intends to use on the stack? When the code reaches "delete this" it will go off and delete it, but then when the object goes out of scope, it will call the destructor. The destructor will then try to delete it again and then you are hosed. In the past, doing something like this would screw up not only the program but the operating system and the computer would need to be rebooted. In any case, this is highly NOT recommended and should almost always be avoided. I would have to be desperate, seriously plastered, or really hate the company I worked for to write code that did this.
It is allowed (just do not use the object after that), but I wouldn't write such code on practice. I think that delete this should appear only in functions that called release or Release and looks like: void release() { ref--; if (ref<1) delete this; }.
Well, in Component Object Model (COM) delete this construction can be a part of Release method that is called whenever you want to release aquisited object:
void IMyInterface::Release()
{
--instanceCount;
if(instanceCount == 0)
delete this;
}
This is the core idiom for reference-counted objects.
Reference-counting is a strong form of deterministic garbage collection- it ensures objects manage their OWN lifetime instead of relying on 'smart' pointers, etc. to do it for them. The underlying object is only ever accessed via "Reference" smart pointers, designed so that the pointers increment and decrement a member integer (the reference count) in the actual object.
When the last reference drops off the stack or is deleted, the reference count will go to zero. Your object's default behavior will then be a call to "delete this" to garbage collect- the libraries I write provide a protected virtual "CountIsZero" call in the base class so that you can override this behavior for things like caching.
The key to making this safe is not allowing users access to the CONSTRUCTOR of the object in question (make it protected), but instead making them call some static member- the FACTORY- like "static Reference CreateT(...)". That way you KNOW for sure that they're always built with ordinary "new" and that no raw pointer is ever available, so "delete this" won't ever blow up.
You can do so. However, you can't assign to this. Thus the reason you state for doing this, "I want to change the view," seems very questionable. The better method, in my opinion, would be for the object that holds the view to replace that view.
Of course, you're using RAII objects and so you don't actually need to call delete at all...right?
This is an old, answered, question, but #Alexandre asked "Why would anyone want to do this?", and I thought that I might provide an example usage that I am considering this afternoon.
Legacy code. Uses naked pointers Obj*obj with a delete obj at the end.
Unfortunately I need sometimes, not often, to keep the object alive longer.
I am considering making it a reference counted smart pointer. But there would be lots of code to change, if I was to use ref_cnt_ptr<Obj> everywhere. And if you mix naked Obj* and ref_cnt_ptr, you can get the object implicitly deleted when the last ref_cnt_ptr goes away, even though there are Obj* still alive.
So I am thinking about creating an explicit_delete_ref_cnt_ptr. I.e. a reference counted pointer where the delete is only done in an explicit delete routine. Using it in the one place where the existing code knows the lifetime of the object, as well as in my new code that keeps the object alive longer.
Incrementing and decrementing the reference count as explicit_delete_ref_cnt_ptr get manipulated.
But NOT freeing when the reference count is seen to be zero in the explicit_delete_ref_cnt_ptr destructor.
Only freeing when the reference count is seen to be zero in an explicit delete-like operation. E.g. in something like:
template<typename T> class explicit_delete_ref_cnt_ptr {
private:
T* ptr;
int rc;
...
public:
void delete_if_rc0() {
if( this->ptr ) {
this->rc--;
if( this->rc == 0 ) {
delete this->ptr;
}
this->ptr = 0;
}
}
};
OK, something like that. It's a bit unusual to have a reference counted pointer type not automatically delete the object pointed to in the rc'ed ptr destructor. But it seems like this might make mixing naked pointers and rc'ed pointers a bit safer.
But so far no need for delete this.
But then it occurred to me: if the object pointed to, the pointee, knows that it is being reference counted, e.g. if the count is inside the object (or in some other table), then the routine delete_if_rc0 could be a method of the pointee object, not the (smart) pointer.
class Pointee {
private:
int rc;
...
public:
void delete_if_rc0() {
this->rc--;
if( this->rc == 0 ) {
delete this;
}
}
}
};
Actually, it doesn't need to be a member method at all, but could be a free function:
map<void*,int> keepalive_map;
template<typename T>
void delete_if_rc0(T*ptr) {
void* tptr = (void*)ptr;
if( keepalive_map[tptr] == 1 ) {
delete ptr;
}
};
(BTW, I know the code is not quite right - it becomes less readable if I add all the details, so I am leaving it like this.)
Delete this is legal as long as object is in heap.
You would need to require object to be heap only.
The only way to do that is to make the destructor protected - this way delete may be called ONLY from class , so you would need a method that would ensure deletion
I've found this class definition (T has to derive from TBase),
passResponsabilityToBarDestructor is not the actual name of the
function, sadly.
template<typename T>
class Foo
{
public:
Foo(const std::string& aName, Bar& aBar)
{
const TBase* myObj = static_cast<const TBase*>(new T);
NiceNameSpace::passResponsabilityToBarDestructor(aName, myObj, aBar);
}
virtual ~Foo() {}
};
I'm wondering if it is well designed.
When I write a class I tend to avoid delegating destruction since I
don't know if the delegated class (in this case Bar) is going to be modified
by someone not aware of the fact that passResponsabilityToBarDestructor has to call
a member function of aBar saving the pointer myObj somewhere and deleting it
when myObj get destroyed.
I would like to know:
if this class is well designed
if my design efforts (when I cannot use smart pointers I get headaches trying to
write classes destroying stuff in the same class constructing it) are a waste of time.
Delegation of destruction actually helps in many cases. I have come across code - where the cost of destruction is quite heavy, so the designers don't want to destroy the object during the call flow - instead delegate it to another thread level and delete it in background (ideally when system is not busy). In such cases, the garbage collector (in another thread) destroys the object.
This also sometimes used for quick switch of data (for cases of data refresh) and delete the old data at ease. I think it is a similar concept as in gc of Java.
Regarding as to whether this particular design is efficient/useful, may be if you add overall concept, it may help us to add some suggestion. Effectively, I have given some hint on second part of your question. HTH!
I'm coming from C# and trying to translate some of my practices into C++. I've used dependency injection in various places throughout my code using raw pointers. Then I decide to replace the raw pointers with std::shared_ptr's. As part of that process it was suggested that I consider using stack allocated automatic variables rather than dynamically allocating them (see this question although that question was in the context of unique_ptr so maybe that is different).
I believe the below example shows the use of automatic variables.
class MyClass
{
public:
MyClass(ApplicationService& app): appService_(app)
{
}
~MyClass()
{
appService_.Destroy(something);
}
private:
ApplicationService& appService_;
}
class ConsumerClass
{
DoSomething()
{
CustomApplicationService customAppService;
MyClass myclass(customAppService);
myclass...
}
}
In the above example, when customAppservice and myclass go out of scope how do I know which will be destroyed first? If customAppService is destroyed first than the MyClass destructor will fail. Is this a good reason to use shared_ptr instead in this scenario or is there a clean way around this?
UPDATE
ApplicationService is a class that is a wrapper around global functions needed to interact with a 3rd party library that my code uses. I have this class as I believe it's the standard way to support unit testing and stubbing/mocking of free standing functions. This class simply delegates calls to the corresponding global functions. The call appService_.Destroy(something); is actually destroying an object used by each specific instance of MyClass not destroying anything do with the Application class itself.
The answer is: you don't need to know, as your design is broken, anyway.
First, a Destroy sounds like a bad idea, furthermore if called in an object that is not responsible for the destruction of the other object. The code from the Destroy method belongs into ApplicationService's destructor (which is hopefully virtual, although in this case it doesn't actually need to), which in contrast to C# gets called at a perfectly determined point in time.
Once you've done this, you will (hopefully) realize, that it is not the responsibility of MyClass to destroy the appService_, as it does not own it. It is the responsibility of the ConsumerClass (or rather the DoSomething method), which really manages the actual service and which does actually destroy it automatically once you've moved Destroy's code into the destructor. Isn't it nice how RAII does make happen everything in a clean and automatic way?
class MyClass
{
public:
MyClass(ApplicationService& app): appService_(app)
{
}
private:
ApplicationService& appService_;
}
class ConsumerClass
{
DoSomething()
{
CustomApplicationService customAppService;
MyClass myclass(customAppService);
myclass...
}
}
class ApplicationService
{
public:
virtual ~ApplicationService()
{
//code from former Destroy method
}
}
class CustomApplicationService
{
public:
virtual ~CustomApplicationService()
{
//code from former Destroy method
}
}
This is IMHO the perfect clean C++ way around it and the problem is definitely not a reason to spam shared_ptrs. Even if you really need a dedicated Destroy method and cannot move the code into the destructor (which I would take as a motivation for overthinking the design), then you would still call Destroy from DoSomething as again, MyClass is not responsible for destroying the appService_.
EDIT: According to you update (and my stupid overlooking of the something argument), your design seems indeed quite correct (at least if you cannot mess with changing the ApplicationService), sorry.
Allthough class members should get destroyed in reverse order of construction, I'm not sure this also holds for local automatic variables. What you could do to make sure the destructors get called in a defined order is introduce nested scopes using simple blocks:
void DoSomething()
{
CustomApplicationService customAppService;
{
MyClass myclass(customAppService);
myclass...
} // myclass destroyed
} // customAppService destroyed
Of course there is still completely no need to use dynamic allocation, let aside shared_ptrs. Although the nested blocks blow the code a bit, it is nothing against the ugliness of dynamic allocation applied in a non-dynamic way and without reason and it at least "looks nice in a semantic way" with customAppService's declaration on top of the block ;)
In C++, objects, in general, are destroyed in the order that is exact opposite of the order they were created in.
Based on your example, MyClass will be destroyed before CustomApplicationService
The exception is when a destructor is called explicitly. However, I don't think you should concern yourself with this exception at this stage.
Another subtlety is called static initialization order fiasco . However, this does not apply to automatic (stack) variables.
Edit:
From C++2003 - looked for 'reverse order'
6.6.0.2
On exit from a scope (however accomplished), destructors (12.4) are called for all
constructed objects with automatic storage duration (3.7.2) (named objects or
temporaries) that are declared in that scope, in the reverse order of their
declaration. ... [Note: However, the program can be terminated (by calling exit()
or abort()(18.3), for example) without destroying class objects with automatic
storage duration. ]
If I have a factory, that creates an object and returns a pointer to it, what will be a better way to delete it:
By delete call in the "user" code, or by a new DestructObject function which I should have together with the factory?
In the general case, the factory might not use plain old new to allocate the object. It may use object and/or page pooling, malloc with placement new, or something even more exotic (memory mapping?). There are at least three ways to handle this that I can think of:
Have the factory supply a recycle method to be called when you are done with the object.
Return a smart pointer that knows how to do away with the object once no referers remain.
Implement a custom delete operator in the object itself.
I hesitate to recommend one over the other, since I haven't given it enough thought in the last five minutes to proffer a definitive opinion, but I would tend to favour the last option in combination with a regular smart pointer like boost/tr1::shared_ptr.
The best way to delete it manually would be not at all.
The following code provides an opportunity not to think about who should remove the newly created object.
class FooFactory
{
public:
static std::auto_ptr<Foo> CreateInstance();
};
// transmit ownership of created object from factory to 'a' variable
std::auto_ptr<Foo> a = FooFactory::CreateInstance();
// using the created object is not required
FooFactory::CreateInstance();
The most versatile solution for this problem is to derive your class from a base class that has a virtual "killing" function. Something like this:
class IDisposable {
public:
virtual void Release() = 0;
};
It's generally believed that polymorphic objects should have virtual destructors to support proper object cleanup. However this is incomplete, because it doesn't account for potentially different memory management of objects.
On the other hand this method doesn't require to use virtual destructors. It's now replaced by Release function that does both: invokation of the correct destructor and releasing the memory by the appropriate means.
takes care of the object destr
both: destruct
The object returned from the factory will implement this "interface".