This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to stop C++ console application from exiting immediately?
I'm working with c++ and when I run my console program, it instantly exits. I can't read input from in my main method/set breakpoints because the main method is defined in another library.
So, I'm asking how can I prevent the console application from exiting by using a setting in visual studio?
Try running with Ctrl+F5. This will stop the console at the end of the execution.
If I understood correctly you can't read the output of your program because console closes immediately. To prevent this you can call system("pause"); just before returning from main.
int main()
{
// processing...
system("pause");
return 0;
}
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I don't understand. I wrote a "hello world" program and run it, console only shows up immediately and turns itself off.
You guys can help me please
I want to use vscode console to input the result then print it with the line "press any key to countinue" like DevC++. I want it to not turn itself off when I haven't entered all the cases
After your while loop, add: _getch();
std::cout << "press any key to countinue...";
int c = _getch();
Then the application will wait untill you press a key.
What's happening is when the caSe is zero the application leaves the loop. Then there is no code left and the application exits.
But please remove the second image and replace the first with your code. We love to copy your code to help you out. The programs output you should write out too, although in this case not needed when you write clearly what is happening. And state clearly what you want to do.
Try adding this in the last place.
system("pause");
This question already has answers here:
Windows console application - signal for closing event
(1 answer)
Gracefully terminate a Boost Asio based Windows console application
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Closed 5 years ago.
I have a small(ish) command-line application that talks to some custom hardware.
Right now, you run the executable, and it pops up a console window, and does it's thing. I'm handling SIGINT and SIGTERM so if you hit ctrl+c in the console window, it shuts down gracefully, and releases the custom hardware.
However, if kill the application by simply closing the console window (click the "x" in the corner), it seems to basically be immediately killed, with no time to do any cleanup.
I'd like to be able to do my shutdown procedures if the console is closed. I've not had much luck trying to find out what, exactly, is even happening to my process when it's console is closed.
And as soon as I ask the question, I find Gracefully terminate a Boost Asio based Windows console application, which exactly answers it (I'm even using boost-asio!).
This question already has answers here:
How to stop C++ console application from exiting immediately?
(35 answers)
Closed 5 years ago.
I just started using Visual Studio to write C++ code on Windows 10 and I am using the console application template. My problem is that the console disappears immediately after showing the output of my program even when I simply run a "hello world" example. I tried all kinds of tricks to implement delay but no success.
I usually put a std::cin line just before main returns. This will cause it to wait for input before continuing.
You can do the following( assuming that you are not waiting for user input, in that case you can just follow Rich's answer ) :
Run it in debugging with a breakpoint on the last line before the main returns.
Use a system("pause") at the end before the main returns.( suggesting this just because it's just a hello world program in Visual Studio )
A great way to pause the console in Visual Studios for your purposes is to use system("pause"); Though its not portable to other OS and some anti-virus systems don't like it. For your purposes it should work well and is easy to see what the line does.
Hope this helps.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
How to stop C++ console application from exiting immediately?
I'm currently learning C++ and cant figure out how to stop the application from exiting when I want to show the user some data, and have time to read it. How may i do that?
Update: Somehow I pause the application and when the user click a button it exits.
I assume you're on Windows.
This can turn into a long debate, but generally there are two main ways people do it:
(recommended) Add cin.get(); to the end of your program. This will cause your program to stop until the user hits enter, then it will continue and quit.
This will work on Windows and Linux.
Add system("PAUSE"); at the end of your program. This will cause your program to print something like Press any key to continue. . . and when you hit a key, the program will continue and quit.
There is a chance that the PAUSE command doesn't do that and can order pizza, launch the missiles, or something else.
This only works for Windows but you won't need it when you go to linux anyway.
std::cout << "Press enter to exit" << std::endl;
cin.get();
exit(1);
If you want to pause your program until the user presses a key, you can use cin.get(). But really, the program should terminate when it's finished. Otherwise, it's useless in pipelines and the like.
If your program's window goes away when it's finished, then something is wrong with the way you launched it. Whether the window stays when the program is done is up to the thing that launches the program and sets up the window, not the program. This problem is usually caused by launching CLI programs from a GUI. If you want to launch from a GUI, write a GUI program. Otherwise, launch terminal programs from the terminal.
Do not use system("pause");. It makes your program unportable. And if you ever run it on a system whose pause command does something other than what you want, you may have a very angry user on your hands.
Do not use getch. That's a Windows console function and a Curses function. It's not part of C++. (Unless you are specifically developing for a platform that has this function and you are sure it does what you want. But this one function would be a really silly reason to make your program unportable.)
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
How to keep the console window open in visual c++?
I have a program that runs on my home machine, but on another machine it quits instantly when being executed. The console window opens and closes so fast that I can't read the output. How can I make sure this output stays visible, so I can read what it's trying to tell me?
Since it's a console application run it from a cmd window.
You can set Visual Studio to break when an exception is thrown (of course this will only work if an uncaught exception is what is causing your program to terminate early).