I have two images, A and B, and I need to estimate B's quantization table and compress A using this table. What is the best way to do this, using libjpeg or, even better, opencv?
I've used libjpeg's utility 'djpeg' to find the quantization table of a image, but I'm not sure how to interpret its output and use it with libjpeg. Besides, I need to find this matrix and do the compression from inside my program, which renders (I think) 'djpeg' unusable in this case.
Following, is the output of 'djpeg' for a test image, running it with:
djpeg -v -v cat1.jpg > /dev/null
Start of Image
JFIF APP0 marker: version 1.01, density 96x96 1
Define Quantization Table 0 precision 0
5 3 3 5 7 12 15 18
4 4 4 6 8 17 18 17
4 4 5 7 12 17 21 17
4 5 7 9 15 26 24 19
5 7 11 17 20 33 31 23
7 11 17 19 24 31 34 28
15 19 23 26 31 36 36 30
22 28 29 29 34 30 31 30
Define Quantization Table 1 precision 0
5 5 7 14 30 30 30 30
5 6 8 20 30 30 30 30
7 8 17 30 30 30 30 30
14 20 30 30 30 30 30 30
30 30 30 30 30 30 30 30
30 30 30 30 30 30 30 30
30 30 30 30 30 30 30 30
30 30 30 30 30 30 30 30
Start Of Frame 0xc0: width=450, height=320, components=3
Component 1: 2hx2v q=0
Component 2: 1hx1v q=1
Component 3: 1hx1v q=1
Define Huffman Table 0x00
0 1 5 1 1 1 1 1
1 0 0 0 0 0 0 0
Define Huffman Table 0x10
0 2 1 3 3 2 4 3
5 5 4 4 0 0 1 125
Define Huffman Table 0x01
0 3 1 1 1 1 1 1
1 1 1 0 0 0 0 0
Define Huffman Table 0x11
0 2 1 2 4 4 3 4
7 5 4 4 0 1 2 119
Start Of Scan: 3 components
Component 1: dc=0 ac=0
Component 2: dc=1 ac=1
Component 3: dc=1 ac=1
Ss=0, Se=63, Ah=0, Al=0
End Of Image
Thanks in advance!
Related
I have two sheets in an Excel workbook. I need the formula which creates tables by using vlookup.
I have 10 columns and 10 rows like this
1 2 3 4 5 6 7 8 9 10
2
3
4
5
6
7
8
9
10
I have tried to use Vlookup with sum but not get the actual results.
The expected result should be like this
1 2 3 4 5 6 7 8 9 10
2 4 6 8 10 12 14 16 18 20
3 6 9 12 15 18 21 24 27 30
4 8 12 16 20 24 28 32 36 40
5 10 15 20 25 30 35 40 45 50
6 12 18 24 30 36 42 48 54 60
7 14 21 28 35 42 49 56 63 70
8 16 24 32 42 48 56 64 72 80
9 18 27 36 49 54 63 72 81 90
10 20 30 40 50 60 70 80 90 100
I'm attempting to format a table of 40 different age-race-sex strata to be inputted into R-INLA and noticed that it's important to include all strata (even if they are not present in a county). These should be zeros. However, at this point my table only contains records for strata that are not empty. I can identify places where strata are missing for each county by looking at my strata variable and finding the breaks in the series 1 through 40 (marked with a red x in the image below).
In these places (marked by the red x) I need to add the missing rows and fill in the corresponding county code, strata code, population=0, and the correct corresponding race, sex, age code for the strata.
If I can figure out a way to add an empty row in the spaces with the red Xs from the image, and correctly assign the strata code (and county code) to these empty/missing rows, I am able to populate the rest of the values with the code below:
recode race = 1 & sex= 1 & age =4 if strata = 4
...etc
I'm wondering if there is a way to add the missing rows using an if statement that considers the fact that there are supposed to be forty strata for each county code. It would be ideal if this could populate the correct county code and strata code as well!
Dataex sample data:
* Example generated by -dataex-. To install: ssc install dataex
clear
input float OID str5 fips_statecounty double population byte(race sex age) float strata
1 "" 672 1 1 1 1
2 "" 1048 1 1 2 2
3 "" 883 1 1 3 3
4 "" 1129 1 1 4 4
5 "" 574 1 2 1 5
6 "" 986 1 2 2 6
7 "" 899 1 2 3 7
8 "" 1820 1 2 4 8
9 "" 96 2 1 1 9
10 "" 142 2 1 2 10
11 "" 81 2 1 3 11
12 "" 99 2 1 4 12
13 "" 71 2 2 1 13
14 "" 125 2 2 2 14
15 "" 103 2 2 3 15
16 "" 162 2 2 4 16
17 "" 31 3 1 1 17
18 "" 32 3 1 2 18
19 "" 18 3 1 3 19
20 "" 31 3 1 4 20
21 "" 22 3 2 1 21
22 "" 28 3 2 2 22
23 "" 28 3 2 3 23
24 "" 44 3 2 4 24
25 "" 20 4 1 1 25
26 "" 24 4 1 2 26
27 "" 21 4 1 3 27
28 "" 43 4 1 4 28
29 "" 19 4 2 1 29
30 "" 26 4 2 2 30
31 "" 24 4 2 3 31
32 "" 58 4 2 4 32
33 "" 6 5 1 1 33
34 "" 11 5 1 2 34
35 "" 13 5 1 3 35
36 "" 7 5 1 4 36
37 "" 7 5 2 1 37
38 "" 9 5 2 2 38
39 "" 10 5 2 3 39
40 "" 11 5 2 4 40
41 "01001" 239 1 1 1 1
42 "01001" 464 1 1 2 2
43 "01001" 314 1 1 3 3
44 "01001" 232 1 1 4 4
45 "01001" 284 1 2 1 5
46 "01001" 580 1 2 2 6
47 "01001" 392 1 2 3 7
48 "01001" 440 1 2 4 8
49 "01001" 41 2 1 1 9
50 "01001" 38 2 1 2 10
51 "01001" 23 2 1 3 11
52 "01001" 26 2 1 4 12
53 "01001" 34 2 2 1 13
54 "01001" 52 2 2 2 14
55 "01001" 40 2 2 3 15
56 "01001" 50 2 2 4 16
57 "01001" 4 3 1 1 17
58 "01001" 2 3 1 2 18
59 "01001" 3 3 1 3 19
60 "01001" 6 3 2 1 21
61 "01001" 4 3 2 2 22
62 "01001" 6 3 2 3 23
63 "01001" 4 3 2 4 24
64 "01001" 1 4 1 4 28
65 "01003" 1424 1 1 1 1
66 "01003" 2415 1 1 2 2
67 "01003" 1680 1 1 3 3
68 "01003" 1823 1 1 4 4
69 "01003" 1545 1 2 1 5
70 "01003" 2592 1 2 2 6
71 "01003" 1916 1 2 3 7
72 "01003" 2527 1 2 4 8
73 "01003" 68 2 1 1 9
74 "01003" 82 2 1 2 10
75 "01003" 52 2 1 3 11
76 "01003" 54 2 1 4 12
77 "01003" 72 2 2 1 13
78 "01003" 129 2 2 2 14
79 "01003" 81 2 2 3 15
80 "01003" 106 2 2 4 16
81 "01003" 10 3 1 1 17
82 "01003" 14 3 1 2 18
83 "01003" 8 3 1 3 19
84 "01003" 4 3 1 4 20
85 "01003" 8 3 2 1 21
86 "01003" 14 3 2 2 22
87 "01003" 17 3 2 3 23
88 "01003" 10 3 2 4 24
89 "01003" 4 4 1 1 25
90 "01003" 1 4 1 3 27
91 "01003" 2 4 1 4 28
92 "01003" 2 4 2 1 29
93 "01003" 3 4 2 2 30
94 "01003" 4 4 2 3 31
95 "01003" 10 4 2 4 32
96 "01003" 5 5 1 1 33
97 "01003" 4 5 1 2 34
98 "01003" 3 5 1 3 35
99 "01003" 5 5 1 4 36
100 "01003" 5 5 2 2 38
end
label values race race
label values sex sex
My answer to your previous question
Nested for-loop: error variable already defined
detailed how to create a minimal dataset with all strata present. Therefore you should just merge that with your main dataset and replace missings on the absent strata with whatever your other software expects, zeros it seems.
The complication most obvious at this point is you need to factor in a county variable. I can't see any information on how many counties you have in your dataset, which may affect what is practical. You should be able to break down the preparation into: first, prepare a minimal county dataset with identifiers only; then merge that with a complete strata dataset.
I need to create DXF files containing curves and spline.
I am since long able to create simple DXF R12 File like this:
0
SECTION
2
ENTITIES
0
POLYLINE
8
0
66
1
10
0.0
20
0.0
30
0.0
70
0
75
6
62
1
0
VERTEX
8
0
10
1044.52
20
825.596
30
0.0
0
VERTEX
8
0
10
1044.52
20
700.099
30
0.0
0
SEQEND
0
ENDSEC
0
EOF
According to the DXF documentation (https://www.autodesk.com/techpubs/autocad/acad2000/dxf/polyline_dxf_06.htm and also http://paulbourke.net/dataformats/dxf/dxf10.html) even R12 POLYLINES can be given a "SPLINE" attribute, so i tried this:
0
SECTION
2
ENTITIES
0
POLYLINE
8
0
66
1
10
0.0
20
0.0
30
0.0
70
4
62
1
0
VERTEX
8
0
10
1044.52
20
1825.596
30
0.0
70
8
0
VERTEX
8
0
10
644.52
20
1025.596
30
0.0
70
8
0
VERTEX
8
0
10
544.52
20
325.596
30
0.0
70
8
0
VERTEX
8
0
10
44.52
20
25.596
30
0.0
70
8
0
VERTEX
8
0
10
1044.52
20
700.099
30
0.0
0
SEQEND
0
ENDSEC
0
EOF
But this still shows only straight lines.
Is it possible to create DXF Files with SPLINE content in DXF 12
Can anybody point to SEIMPLE sample of how to create a spline in
a DXF file
Started with the information in
https://forums.autodesk.com/t5/visual-lisp-autolisp-and-general/manually-writing-a-minimal-dxf/td-p/2081140
and was able to make a headerless, tableless file.dxf
which succesfully draws two lines
MinTwoLines.dxf
0
SECTION
2
ENTITIES
0
LINE
8
DXF_Lines_LayerName
10
0.0
20
0.0
30
0.0
11
1.0
21
0.0
31
0.0
0
LINE
8
DXF_Lines_LayerName
10
1.0
20
0.0
30
0.0
11
1.0
21
0.0
31
2.0
0
ENDSEC
0
EOF
Plopping a SPLINE ENTITY into the same location as the LINE failed.
so nabbed the splineA.dxf file from
https://github.com/jscad/sample-files/blob/master/dxf/dxf-parser/splines.dxf
and incrementally hacked off bits until no more could be successfully removed.
The files resulting from laminating the below files can be successfully imported into Rhino 7.
The file lamination commands in Windows are:\
to make a single file with only the FourPoint spline
copy MinSplineHead.txt+FourPointSplineBody.txt+MinSplineTail.txt MinSpline.dxf
to make a single file with only the TwentyOnePoint spline
copy MinSplineHead.txt+TwentyOnePointSplineBody.txt+MinSplineTail.txt MinSpline.dxf
to make a single file with both splines
copy MinSplineHead.txt+FourPointSplineBody.txt+TwentyOnePointSplineBody.txt+MinSplineTail.txt MinSpline.dxf
MinSplineHead.txt
0
SECTION
2
HEADER
9
$ACADVER
1
AC1021
0
ENDSEC
0
SECTION
2
TABLES
0
TABLE
2
LAYER
5
2
330
0
100
AcDbSymbolTable
70
1
0
LAYER
5
10
330
2
100
AcDbSymbolTableRecord
100
AcDbLayerTableRecord
2
0
70
0
62
7
6
CONTINUOUS
370
0
390
F
0
ENDTAB
0
TABLE
2
BLOCK_RECORD
5
1
330
0
100
AcDbSymbolTable
70
2
0
BLOCK_RECORD
5
1F
330
1
100
AcDbSymbolTableRecord
100
AcDbBlockTableRecord
2
*Model_Space
70
0
280
1
281
0
0
BLOCK_RECORD
5
1E
330
1
100
AcDbSymbolTableRecord
100
AcDbBlockTableRecord
2
*Paper_Space
70
0
280
1
281
0
0
ENDTAB
0
ENDSEC
0
SECTION
2
ENTITIES
FourPointSplineBody.txt
0
SPLINE
8
DXF_Spline_LayerName
100
AcDbSpline
70
8
71
2
72
7
73
4
74
0
42
1e-07
43
1e-07
40
0
40
0
40
0
40
0.5
40
1
40
1
40
1
10
0
20
0
30
0
10
122.4
20
-38.5
30
0
10
77.5
20
149.5
30
0
10
200
20
100
30
0
TwentyOnePointSplineBody.txt
0
SPLINE
8
DXF_Spline_LayerName
100
AcDbSpline
70
0
71
3
72
25
73
21
74
0
42
0.00000
43
0.00000
40
0.0
40
0.0
40
0.0
40
0.0
40
0.02777
40
0.05555
40
0.08333
40
0.11111
40
0.13888
40
0.16666
40
0.19444
40
0.22222
40
0.25
40
0.27777
40
0.30555
40
0.33333
40
0.36111
40
0.38888
40
0.41666
40
0.44444
40
0.47222
40
0.5
40
0.5
40
0.5
40
0.5
10
7.000
20
-4.000
30
-5.500
10
7.288
20
-4.008
30
-5.492
10
7.955
20
-4.029
30
-5.416
10
8.881
20
-4.062
30
-5.168
10
9.750
20
-4.097
30
-4.763
10
10.535
20
-4.136
30
-4.213
10
11.213
20
-4.177
30
-3.535
10
11.763
20
-4.222
30
-2.750
10
12.168
20
-4.270
30
-1.881
10
12.416
20
-4.321
30
-0.955
10
12.500
20
-4.375
30
-0.000
10
12.416
20
-4.432
30
0.955
10
12.168
20
-4.492
30
1.881
10
11.763
20
-4.556
30
2.750
10
11.213
20
-4.622
30
3.535
10
10.535
20
-4.691
30
4.213
10
9.750
20
-4.764
30
4.763
10
8.881
20
-4.840
30
5.168
10
7.955
20
-4.918
30
5.416
10
7.288
20
-4.975
30
5.492
10
7.000
20
-5.000
30
5.500
MinSplineTail.txt
0
ENDSEC
0
EOF
Hi so I have created the nested list/matrix:
q)m:((1 2 3);(4 5 6);(7 8 9))
q)m
1 2 3
4 5 6
7 8 9
I have also identified the middle column in the list:
q)a:m[0;1],m[1;1],m[2;1]
I now want to replace the middle row (4 5 6) with a to finish with m looking like:
q)m
1 2 3
2 5 8
7 8 9
You've already seen you can index into the matrix with syntax like m[0;1], where 0 refers to the first level of nesting and 1 refers to the second level
KDB also allows you to assign to an index of a list in a similar way e.g.
q)l:1 2 3 4
q)l[1]:20
q)l
1 20 3 4
So you can use something similar in this example:
q)m[1]:a
q)m
1 2 3
2 5 8
7 8 9
As an aside, KDB also allows you to leave out an index, in which case it will take all items from the corresponding level of nesting, e.g.
q)m[0] /first level of nesting i.e. first row
1 2 3
q)m[;0] /second level of nesting i.e. first column
1 4 7
Hope that helps
Jonathon McMurray
AquaQ Analytics
You want to generalise for larger matrices (which must also be square) so your answer needs two parts:
how to construct a
how to insert it
for row/col x where x<count m.
The general expression you want is simply m[x;]:m[;x], because m[x;] denotes row x and m[;x] denotes column x.
See Q for Mortals 3.11.3 Two- and Three-Dimensional Matrices
You can make this a function of the index and the matrix:
q)show m:5 5#1_til 26
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
q){y[x;]:y[;x];:y}[3;m]
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
4 9 14 19 24
21 22 23 24 25
Just adding another approach for you.
q)m:8 cut til 64
q)0 0+\:til 8
0 1 2 3 4 5 6 7
0 1 2 3 4 5 6 7
q)(m)./:flip 0 0+\:til 8
0 9 18 27 36 45 54 63
q)#[m;4;:;(m)./:flip 0 0+\:til 8]
0 1 2 3 4 5 6 7
8 9 10 11 12 13 14 15
16 17 18 19 20 21 22 23
24 25 26 27 28 29 30 31
0 9 18 27 36 45 54 63
40 41 42 43 44 45 46 47
48 49 50 51 52 53 54 55
56 57 58 59 60 61 62 63
q)
For fun, here it is in a function which takes the length&width of the matrix and replaces the 'middle' row with the diagonal values
q){n:x*x;m:x cut til n;#[m;x div 2;:;](m)./:flip 0 0+\:til x}8
0 1 2 3 4 5 6 7
8 9 10 11 12 13 14 15
16 17 18 19 20 21 22 23
24 25 26 27 28 29 30 31
0 9 18 27 36 45 54 63
40 41 42 43 44 45 46 47
48 49 50 51 52 53 54 55
56 57 58 59 60 61 62 63
q){n:x*x;m:x cut til n;#[m;x div 2;:;](m)./:flip 0 0+\:til x}5
0 1 2 3 4
5 6 7 8 9
0 6 12 18 24
15 16 17 18 19
20 21 22 23 24
q){n:x*x;m:x cut til n;#[m;x div 2;:;](m)./:flip 0 0+\:til x}4
0 1 2 3
4 5 6 7
0 5 10 15
12 13 14 15
q)
q)#[((1 2 3);(4 5 6);(7 8 9));1;:;(2;5;8)]
1 2 3
2 5 8
7 8 9
Indexing in q can be straight forward and I believe a intermediate can be omitted:
q)m:((1 2 3);(4 5 6);(7 8 9))
q)m[1]:m[;1]
q)m
1 2 3
2 5 8
7 8 9
I like to know is there a way to doing auto looping / counter batch, updating SQL column like using OFFSET / FETCH NEXT method
QUESTION : Below table have 20 rows, I like to update DealerId column the First 4 rows as 1,2,3,4 and the next subsequent 4 rows repeating as 1,2,3,4 values
Something like below
NEED TO MODIFY TABLE
Id DealerId
1 1 1
2 2 2
3 3 3
4 4 4
5 5 1
6 6 2
7 7 3
8 8 4
9 9 1
10 10 2
11 11 3
12 12 4
13 13 1
14 14 2
15 15 3
16 16 4
17 17 1
18 18 2
19 19 3
20 20 4
ORIGINAL TABLE
Id DealerId StoreId TerminalId MessageNo CreatedDate
1 1 86 5027 029500021201403031434350039 2014-03-03 14:34:37.347
2 2 86 5027 029500021201403031434350039 2014-03-05 10:31:59.903
3 3 86 5027 029500021201403031434350039 2014-03-05 10:33:41.293
4 4 86 5027 029500021201403031434350039 2014-03-05 10:46:50.057
5 5 86 5027 029500021201403031434350039 2014-03-05 10:50:23.910
6 6 33 5338 004000003201403051508010255 2014-03-05 15:08:03.247
7 7 26 5595 704201181201403061024330013 2014-03-06 10:24:34.590
8 8 26 5595 704201181201403061026180022 2014-03-06 10:26:19.517
9 9 33 5338 004000003201403061043150312 2014-03-06 10:43:16.013
10 10 86 5027 029500021201403031434350039 2014-03-06 14:27:51.717
11 11 86 5027 029500021201403031434350039 2014-03-06 14:38:40.593
12 12 86 5027 029500021201403031434350039 2014-03-06 14:44:25.947
13 13 521 4905 051100003002447 2014-03-07 12:51:07.487
14 14 521 4905 051100003002447 2014-03-07 12:55:07.300
15 15 521 4905 051100003002447 2014-03-07 12:56:24.793
16 16 521 4905 051100003002447 2014-03-07 12:57:43.123
17 17 521 4905 051100003002447 2014-03-07 14:15:11.093
18 18 632 5120 088800003201403071441280026 2014-03-07 14:41:29.733
19 19 632 5120 088800003201403071456500050 2014-03-07 14:56:51.727
20 20 632 5120 088800003201403071459240064 2014-03-07 14:59:24.953
Assuming that all id's are consequently, starting from 1:
In MySQL:
update OriginalTable
set DealreId = mod(id-1, 4)+1
and in Microsoft SQL Server:
update OriginalTable
set DealreId = ((id-1)%4)+1
And if the id's are not consequently (or are not starting from 1) you can use cursor to update it one by one:
DECLARE c1 CURSOR FOR
SELECT id, dealerId
FROM OriginalTable
ORDER BY id, dealerId
OPEN c1
declare #id int
declare #dealerId int
declare #i int
set #i = 1
FETCH NEXT FROM c1
INTO #id, #dealerId
while ##FETCH_STATUS = 0
BEGIN
update OriginalTable
set dealerId = #i
where current of c1
if (#i < 4)
set #i = #i + 1
else
set #i = 1
FETCH NEXT FROM c1
INTO #id, #dealerId
END