How would I get this to UV map correctly? - c++

Alright so I have my code to draw out a big landscape using C++ and DirectX. I had it textured with one texture and then needed to add more. I saw people doing it where they had 1 texture image and the image contained 2 textures. Thats what I made, it's a 256x128 image. My problem now is that since my terrain automatically generated the coordinates to UV map 1 texture now it is displaying both textures. I need to make it so when the height of the world is high enough it is 1 texture and everything under is another texture. My code for the UV coordinates,
Vertices[y * WIDTH * x].U = x / 1.28;
Vertices[y * WIDTH * x].V = y / 1.28;
those are my mapping coordinates, X is the current X value of the vertice it is drawing and the Y value is its current y position. The heightmap is 128x128 so I divided by 1.28 to make it so that each polygon had the texture UV mapped on it. The height is calculated as well since I am loading a heightmap and im trying to get it so when it is high enough it UV maps 1 half of the image and if it is the other it UV maps the other side of the image. Someone please help!

bool topTexture = height[x][y] > threshold;
float u = x / 1.28;
float v = y / 1.28;
Vertices[y * WIDTH * x].U = (u - (int)u) / 2 + (topTexture ? 0.5 : 0);
Vertices[y * WIDTH * x].V = (v - (int)v) / 2 + (topTexture ? 0.5 : 0);
You may want to blend the two textures at the threshold level. Then, you have to do it in the PixelShader.

Related

Clipping triangles in screen space per pixel

As I understand it, in OpenGL polygons are usually clipped in clip space and only those triangles (or parts of the triangles if the clipping process splits them) that survive the comparison with +- w. This then requires implementation of a polygon clipping algorithm such as Sutherland-Hodgman.
I am implementing my own CPU rasterizer and for now would like to avoid doing that. I have the NDC coordinates of vertices available (not really normalized since I did not clip anything so the positions may not be in range [-1, 1]). I would like to interpolate these values for all pixels and only draw pixels the NDC coordinates of which fall within [-1, 1] in the x, y and z dimensions. I would then additionally perform the depth test.
Would this work? If yes what would the interpolation look like? Can I use the OpenGl spec (page 427 14.9) formula for attribute interpolation as described here? Alternatively, should I use the formula 14.10 which is used for depth (z) interpolation for all 3 coordinates (I don't really understand why a different one is used there)?
Update:
I have tried interpolating the NDC values per pixel by two methods:
w0, w1, w2 are the barycentric weights of the vertices.
1) float x_ndc = w0 * v0_NDC.x + w1 * v1_NDC.x + w2 * v2_NDC.x;
float y_ndc = w0 * v0_NDC.y + w1 * v1_NDC.y + w2 * v2_NDC.y;
float z_ndc = w0 * v0_NDC.z + w1 * v1_NDC.z + w2 * v2_NDC.z;
2)
float x_ndc = (w0*v0_NDC.x/v0_NDC.w + w1*v1_NDC.x/v1_NDC.w + w2*v2_NDC.x/v2_NDC.w) /
(w0/v0_NDC.w + w1/v1_NDC.w + w2/v2_NDC.w);
float y_ndc = (w0*v0_NDC.y/v0_NDC.w + w1*v1_NDC.y/v1_NDC.w + w2*v2_NDC.y/v2_NDC.w) /
(w0/v0_NDC.w + w1/w1_NDC.w + w2/v2_NDC.w);
float z_ndc = w0 * v0_NDC.z + w1 * v1_NDC.z + w2 * v2_NDC.z;
The clipping + depth test always looks like this:
if (-1.0f < z_ndc && z_ndc < 1.0f && z_ndc < currentDepth &&
1.0f < y_ndc && y_ndc < 1.0f &&
-1.0f < x_ndc && x_ndc < 1.0f)
Case 1) corresponds to using equation 14.10 for their interpolation. Case 2) corresponds to using equation 14.9 for interpolation.
Results documented in gifs on imgur.
1) Strange things happen when the second cube is behind the camera or when I go into a cube.
2) Strange artifacts are not visible but as the camera approaches vertices, they start disappearing. And since this is the perspective correct interpolation of attributes vertices (nearer to the camera?) have greater weight so as soon as a vertex gets clipped this information is interpolated with strong weight to the triangle pixels.
Is all of this expected or have I done something wrong?
Clipping against the near plane is not strictly necessary, unless the triangle goes to or past 0 in the camera-space Z. Once that happens, the homogeneous coordinate math gets weird.
Most hardware only bothers to clip triangles if they extend more than a screen's width outside the clip space or if they cross the camera-Z of zero. This kind of clipping is called "guard-band clipping", and it saves a lot of performance, since clipping isn't cheap.
So yes, the math can work fine. The main thing you have to do, when setting up your scan lines, is figure out where each of them start/end on screen. The interpolation math is the same either way.
I don't see any reason why this wouldn't work. But it will be ways slower than traditional clipping. Note, that you might get into trouble with triangles close to the projection center since they will be vanishingly small and might cause problems in the barycentric coordinate calculation.
The difference between equation 14.9 and 14.10 is, that depth is basically z/w (and remapped to [0, 1]). Since the perspective divide has already happened, it has to be left away during interpolation.

DirectX Converting Pixel World Position to Shadow Map Position Gives Weird, Tiled Results

I've been trying for some time now to get a screen-space pixel (provided by a deferred HLSL shader) to convert to light space. The results have been surprising to me as my light rendering seems to be tiling the depth buffer.
Importantly, the scene camera (or eye) and the light being rendered from start in the same position.
First, I extract the world position of the pixel using the code below:
float3 eye = Eye;
float4 position = {
IN.texCoord.x * 2 - 1,
(1 - IN.texCoord.y) * 2 - 1,
zbuffer.r,
1
};
float4 hposition = mul(position, EyeViewProjectionInverse);
position = float4(hposition.xyz / hposition.w, hposition.w);
float3 eyeDirection = normalize(eye - position.xyz);
The result seems to be correct as rendering the XYZ position as RGB respectively yields this (apparently correct) result:
The red component seems to be correctly outputting X as it moves to the right, and blue shows Z moving forward. The Y factor also looks correct as the ground is slightly below the Y axis.
Next (and to be sure I'm not going crazy), I decided to output the original depth buffer. Normally I keep the depth buffer in a Texture2D called DepthMap passed to the shader as input. In this case, however, I try to undo the pixel transformation by offsetting it back into the proper position and multiplying it by the eye's view-projection matrix:
float4 cpos = mul(position, EyeViewProjection);
cpos.xyz = cpos.xyz / cpos.w;
cpos.x = cpos.x * 0.5f + 0.5f;
cpos.y = 1 - (cpos.y * 0.5f + 0.5f);
float camera_depth = pow(DepthMap.Sample(Sampler, cpos.xy).r, 100); // Power 100 just to visualize the map since scales are really tiny
return float4(camera_depth, camera_depth, camera_depth, 1);
This yields a correct looking result as well (though I'm not 100% sure about the Z value). Also note that I've made the results exponential to better visualize the depth information (this is not done when attempting live comparisons):
So theoretically, I can use the same code to convert that pixel world position to light space by multiplying by the light's view-projection matrix. Correct? Here's what I tried:
float4 lpos = mul(position, ShadowLightViewProjection[0]);
lpos.xyz = lpos.xyz / lpos.w;
lpos.x = lpos.x * 0.5f + 0.5f;
lpos.y = 1 - (lpos.y * 0.5f + 0.5f);
float shadow_map_depth = pow(ShadowLightMap[0].Sample(Sampler, lpos.xy).r, 100); // Power 100 just to visualize the map since scales are really tiny
return float4(shadow_map_depth, shadow_map_depth, shadow_map_depth, 1);
And here's the result:
And another to show better how it's mapping to the world:
I don't understand what is going on here. It seems it might have something to do with the projection matrix, but I'm not that good with math to know for sure what is happening. It's definitely not the width/height of the light map as I've tried multiple map sizes and the projection matrix is calculated using FOV and aspect ratios never inputing width/height ever.
Finally, here's some C++ code showing how my perspective matrix (used for both eye and light) is calculated:
const auto ys = std::tan((T)1.57079632679f - (fov / (T)2.0));
const auto xs = ys / aspect;
const auto& zf = view_far;
const auto& zn = view_near;
const auto zfn = zf - zn;
row1(xs, 0, 0, 0);
row2(0, ys, 0, 0);
row3(0, 0, zf / zfn, 1);
row4(0, 0, -zn * zf / zfn, 0);
return *this;
I'm completely at a loss here. Any guidance or recommendations would be greatly appreciated!
EDIT - I also forgot to mention that the tiled image is upside down as if the y flip broke it. That's strange to me as it's required to get it back to eye texture space correctly.
I did some tweaking and fixed things here and there. Ultimately, my biggest issue was an unexpectedly transposed matrix. It's a bit complicated as to how the matrix got transposed, but that's why things were flipped. I also changed to D32 depth buffers (though I'm not sure that helped any) and made sure that any positions divided by their W affected all component (including W).
So code like this: hposition.xyz = hposition.xyz / hposition.w
became this: hposition = hposition / hposition.w
After all this tweaking, it's starting to look more like a shadow map.
Oh and the transposed matrix was the ViewProjection of the light.

How to convert a 3D point cloud to a depth image?

For my work I have to convert a point cloud to a grey scale (depth) image meaning that the z coordinate of each XYZ point in the cloud represents a shade of grey. For mapping a Z coordinate from the [z_min, z_max] interval to the [0..255] interval I used the map function of Arduino:
float map(float x, float in_min, float in_max, float out_min, float out_max)
{ return (x - in_min) * (out_max - out_min) / (in_max - in_min) + out_min; }
With that done I need to write the result to an image, the problem being that the clouds that I have can have millions of points so I can't just write them 1 by 1 to an image in order. Let's say that I have 3000x1000 ordered XY points. How would I do if I wanted to write them to a 700x300 pixels image? I hope the question is clear, thanks in advance for answering.
I have managed to find a solution to my problem. It is a fairy long algorithm for stack overflow but bear with me. The idea is write a vector of XY grey scale points as a pgm file.
Step 1: cloud_to_greyscale - function that converts an XYZ Point Cloud into a vector of XY grey scale points and that receives a cloud as a parameter:
for each point pt in cloud
point_xy_greyscale.x <- pt.x
point_xy_greyscale.y <- pt.y
point_xy_greyscale.greyscale <- map(pt.z, z_min, z_max, 0, 255)
greyscale_vector.add(point_xy_greyscale)
loop
return greyscale_vector
Step 2: greyscale_to_image - function that writes the previously returned vector as a greyscale_image, a class that has a width, a height and a _pixels member corresponding to a double dimensional array of unsigned short usually. The function receives the following parameters: a greyscale_vector (to be turned into the image) and an x_epsilon that will help us delimit the x pixel coordinates for our points, knowing that the x point coordinates are floats (and thus not suitable as array indices).
A little background info: I work on something called widop clouds so in my 3D space x is the width, y is the depth and z is the height. Also worth noting is the fact that y is an integer so for my problem, the height of the image is easy to find: it's y_max - y_min. To find the width of the image, follow the algorithm below and if it isn't clear I will answer any questions and I'm open to suggestions.
img_width <- 0; // image width
img_height <- y_max - y_min + 1 // image height
// determining image width
for each point greyscale_xy_point in greyscale_vector
point_x_cell <- (pt.x - x_min) * x_epsilon * 10
if point_x_cell > img_width
img_width <- point_x_cell + 1
loop
// defining and initializing image with the calculated height and width
greyscale_img(img_width, img_height)
// initializing greyscale image points
for y <- 0 to greyscale_img.height
for x <- 0 to greyscale_img.width
greyscale_img[y][x] = 0
loop
loop
// filling image with vector data
for each point point_xy_greyscale in greyscale_vector
image_x = (point_xy_greyscale.x - x_min) * x_epsilon * 10
image_y = point_xy_greyscale.y - y_min
greyscale_image[image_y][image_x] = point_xy_greyscale.greyscale
loop
return greyscale_image
The only thing left to do is to write the image to the file, but that is easy to do, you can just find the format rules in the previous link related to the pgm format. I hope this helps someone.
EDIT_1: I added a picture of the result. It is supposed to be a railway and the reason it's fairly dark is that there are some objects that are tall so ground objects are darker.
depth image of railway

Isometric coordinates, diamond shape, unwanted space between tiles

I'm working with SMFL/C++ to make a 2D isometric game engine, i got this when i do the isometric calculations :
Here is my formula to calculate isometric coordinates in my 2D engine :
For I-J coordinates i have :
x = (I - J) * (tileWidth / 2);
y = (J + I) * (tileHeight / 2);
//Totally working with classics tiles
EDIT: My problem is due to my tiles' shape wich is a cube, but i don't have a clue about how to fix it. Did i really have to do somes complicated maths to handle 3D objetcs(i would rather avoid this) or i can just change the formula a little bit ?
EDIT 2: Solution : int isoY = (x + y) * (height / 4);
First if it is a 2D engine I wonder why there are 3 dimensions, why and how you use z in your engine.
Assuming you want to have a plan of tiles in isometric projection ((x,y) in pixels) given the coordinates (I,J) in number of tiles in orthographic projection.
In that case your formula for x and y are fine by me given tileWidth and tileHeight are correct (i.e. value in isometric projection). And you shouldn't have to use any z.
On the other hand if your problem is to get (x,y) pixels coordinates of a 3D object given (x,y,z) cartesian coordinates i suggest you read this: Computing the Pixel Coordinates of a 3D Point
In case i assumed wrong I'll edit or delete.

Perspective correct texture mapping; z distance calculation might be wrong

I'm making a software rasterizer, and I've run into a bit of a snag: I can't seem to get perspective-correct texture mapping to work.
My algorithm is to first sort the coordinates to plot by y. This returns a highest, lowest and center point. I then walk across the scanlines using the delta's:
// ordering by y is put here
order[0] = &a_Triangle.p[v_order[0]];
order[1] = &a_Triangle.p[v_order[1]];
order[2] = &a_Triangle.p[v_order[2]];
float height1, height2, height3;
height1 = (float)((int)(order[2]->y + 1) - (int)(order[0]->y));
height2 = (float)((int)(order[1]->y + 1) - (int)(order[0]->y));
height3 = (float)((int)(order[2]->y + 1) - (int)(order[1]->y));
// x
float x_start, x_end;
float x[3];
float x_delta[3];
x_delta[0] = (order[2]->x - order[0]->x) / height1;
x_delta[1] = (order[1]->x - order[0]->x) / height2;
x_delta[2] = (order[2]->x - order[1]->x) / height3;
x[0] = order[0]->x;
x[1] = order[0]->x;
x[2] = order[1]->x;
And then we render from order[0]->y to order[2]->y, increasing the x_start and x_end by a delta. When rendering the top part, the delta's are x_delta[0] and x_delta[1]. When rendering the bottom part, the delta's are x_delta[0] and x_delta[2]. Then we linearly interpolate between x_start and x_end on our scanline. UV coordinates are interpolated in the same way, ordered by y, starting at begin and end, to which delta's are applied each step.
This works fine except when I try to do perspective correct UV mapping. The basic algorithm is to take UV/z and 1/z for each vertex and interpolate between them. For each pixel, the UV coordinate becomes UV_current * z_current. However, this is the result:
The inversed part tells you where the delta's are flipped. As you can see, the two triangles both seem to be going towards different points in the horizon.
Here's what I use to calculate the Z at a point in space:
float GetZToPoint(Vec3 a_Point)
{
Vec3 projected = m_Rotation * (a_Point - m_Position);
// #define FOV_ANGLE 60.f
// static const float FOCAL_LENGTH = 1 / tanf(_RadToDeg(FOV_ANGLE) / 2);
// static const float DEPTH = HALFHEIGHT * FOCAL_LENGTH;
float zcamera = DEPTH / projected.z;
return zcamera;
}
Am I right, is it a z buffer issue?
ZBuffer has nothing to do with it.
THe ZBuffer is only useful when triangles are overlapping and you want to make sure that they are drawn correctly (e.g. correctly ordered in the Z). The ZBuffer will, for every pixel of the triangle, determine if a previously placed pixel is nearer to the camera, and if so, not draw the pixel of your triangle.
Since you are drawing 2 triangles which don't overlap, this can not be the issue.
I've made a software rasterizer in fixed point once (for a mobile phone), but I don't have the sources on my laptop. So let me check tonight, how I did it. In essence what you've got is not bad! A thing like this could be caused by a very small error
General tips in debugging this is to have a few test triangles (slope left-side, slope right-side, 90 degree angles, etc etc) and step through it with the debugger and see how your logic deals with the cases.
EDIT:
peudocode of my rasterizer (only U, V and Z are taken into account... if you also want to do gouraud you also have to do everything for R G and B similar as to what you are doing for U and V and Z:
The idea is that a triangle can be broken down in 2 parts. The top part and the bottom part. The top is from y[0] to y[1] and the bottom part is from y[1] to y[2]. For both sets you need to calculate the step variables with which you are interpolating. The below example shows you how to do the top part. If needed I can supply the bottom part too.
Please note that I do already calculate the needed interpolation offsets for the bottom part in the below 'pseudocode' fragment
first order the coords(x,y,z,u,v) in the order so that coord[0].y < coord[1].y < coord[2].y
next check if any 2 sets of coordinates are identical (only check x and y). If so don't draw
exception: does the triangle have a flat top? if so, the first slope will be infinite
exception2: does the triangle have a flat bottom (yes triangles can have these too ;^) ) then the last slope too will be infinite
calculate 2 slopes (left side and right side)
leftDeltaX = (x[1] - x[0]) / (y[1]-y[0]) and rightDeltaX = (x[2] - x[0]) / (y[2]-y[0])
the second part of the triangle is calculated dependent on: if the left side of the triangle is now really on the leftside (or needs swapping)
code fragment:
if (leftDeltaX < rightDeltaX)
{
leftDeltaX2 = (x[2]-x[1]) / (y[2]-y[1])
rightDeltaX2 = rightDeltaX
leftDeltaU = (u[1]-u[0]) / (y[1]-y[0]) //for texture mapping
leftDeltaU2 = (u[2]-u[1]) / (y[2]-y[1])
leftDeltaV = (v[1]-v[0]) / (y[1]-y[0]) //for texture mapping
leftDeltaV2 = (v[2]-v[1]) / (y[2]-y[1])
leftDeltaZ = (z[1]-z[0]) / (y[1]-y[0]) //for texture mapping
leftDeltaZ2 = (z[2]-z[1]) / (y[2]-y[1])
}
else
{
swap(leftDeltaX, rightDeltaX);
leftDeltaX2 = leftDeltaX;
rightDeltaX2 = (x[2]-x[1]) / (y[2]-y[1])
leftDeltaU = (u[2]-u[0]) / (y[2]-y[0]) //for texture mapping
leftDeltaU2 = leftDeltaU
leftDeltaV = (v[2]-v[0]) / (y[2]-y[0]) //for texture mapping
leftDeltaV2 = leftDeltaV
leftDeltaZ = (z[2]-z[0]) / (y[2]-y[0]) //for texture mapping
leftDeltaZ2 = leftDeltaZ
}
set the currentLeftX and currentRightX both on x[0]
set currentLeftU on leftDeltaU, currentLeftV on leftDeltaV and currentLeftZ on leftDeltaZ
calc start and endpoint for first Y range: startY = ceil(y[0]); endY = ceil(y[1])
prestep x,u,v and z for the fractional part of y for subpixel accuracy (I guess this is also needed for floats)
For my fixedpoint algorithms this was needed to make the lines and textures give the illusion of moving in much finer steps then the resolution of the display)
calculate where x should be at y[1]: halfwayX = (x[2]-x[0]) * (y[1]-y[0]) / (y[2]-y[0]) + x[0]
and same for U and V and z: halfwayU = (u[2]-u[0]) * (y[1]-y[0]) / (y[2]-y[0]) + u[0]
and using the halfwayX calculate the stepper for the U and V and z:
if(halfwayX - x[1] == 0){ slopeU=0, slopeV=0, slopeZ=0 } else { slopeU = (halfwayU - U[1]) / (halfwayX - x[1])} //(and same for v and z)
do clipping for the Y top (so calculate where we are going to start to draw in case the top of the triangle is off screen (or off the clipping rectangle))
for y=startY; y < endY; y++)
{
is Y past bottom of screen? stop rendering!
calc startX and endX for the first horizontal line
leftCurX = ceil(startx); leftCurY = ceil(endy);
clip the line to be drawn to the left horizontal border of the screen (or clipping region)
prepare a pointer to the destination buffer (doing it through array indexes everytime is too slow)
unsigned int buf = destbuf + (ypitch) + startX; (unsigned int in case you are doing 24bit or 32 bits rendering)
also prepare your ZBuffer pointer here (if you are using this)
for(x=startX; x < endX; x++)
{
now for perspective texture mapping (using no bilineair interpolation you do the following):
code fragment:
float tv = startV / startZ
float tu = startU / startZ;
tv %= texturePitch; //make sure the texture coordinates stay on the texture if they are too wide/high
tu %= texturePitch; //I'm assuming square textures here. With fixed point you could have used &=
unsigned int *textPtr = textureBuf+tu + (tv*texturePitch); //in case of fixedpoints one could have shifted the tv. Now we have to multiply everytime.
int destColTm = *(textPtr); //this is the color (if we only use texture mapping) we'll be needing for the pixel
dummy line
dummy line
dummy line
optional: check the zbuffer if the previously plotted pixel at this coordinate is higher or lower then ours.
plot the pixel
startZ += slopeZ; startU+=slopeU; startV += slopeV; //update all interpolators
} end of x loop
leftCurX+= leftDeltaX; rightCurX += rightDeltaX; leftCurU+= rightDeltaU; leftCurV += rightDeltaV; leftCurZ += rightDeltaZ; //update Y interpolators
} end of y loop
//this is the end of the first part. We now have drawn half the triangle. from the top, to the middle Y coordinate.
// we now basically do the exact same thing but now for the bottom half of the triangle (using the other set of interpolators)
sorry about the 'dummy lines'.. they were needed to get the markdown codes in sync. (took me a while to get everything sort off looking as intended)
let me know if this helps you solve the problem you are facing!
I don't know that I can help with your question, but one of the best books on software rendering that I had read at the time is available online Graphics Programming Black Book by Michael Abrash.
If you are interpolating 1/z, you need to multiply UV/z by z, not 1/z. Assuming you have this:
UV = UV_current * z_current
and z_current is interpolating 1/z, you should change it to:
UV = UV_current / z_current
And then you might want to rename z_current to something like one_over_z_current.