xslt compute value based on date - xslt

Question

Good Day,
I have an xml file that looks like:
<albums xmlns="http://www.someurl.com/schema">
<album>
<artist>Rush</artist>
<name>Moving Pictures</name>
<releaseDate>05-31-1981</releaseDate>
<album>
</albums>
what I want is to use xlst to display the artist, name, and how many years is been since the release date.
<div id="recordInfo">
<div class="col"><xsl:value-of select="/t:albums/t:album/t:artist"></div>
<div class="col"><xsl:value-of select="/t:albums/t:album/t:name"></div>
<!-- I want the value of 31 here -->
</div>
Does anyone have any idea of how to do that in XSLT?
TIA,
coson

Answer 1

This transformation:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vTokens" select="tokenize(/*, '-')"/>
<xsl:variable name="vDate" select=
"string-join(($vTokens[3], $vTokens[1], $vTokens[2]), '-')"/>
<xsl:template match="/*">
<xsl:sequence select=
"floor((current-date() - xs:date($vDate)) div xs:dayTimeDuration('P365D')) "/>
</xsl:template>
</xsl:stylesheet>
When applied on this XML document:
<t>05-31-1981</t>
produces the wanted, correct result:
31

Answer 2

Here's an XSLT 2.0 option...
XML Input
<albums xmlns="http://www.someurl.com/schema">
<album>
<artist>Rush</artist>
<name>Moving Pictures</name>
<releaseDate>05-31-1981</releaseDate>
</album>
</albums>
XSLT 2.0
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:t="http://www.someurl.com/schema" xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="albums">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="t:album">
<div id="recordInfo">
<xsl:apply-templates/>
</div>
</xsl:template>
<xsl:template match="t:artist|t:name">
<div class="col"><xsl:value-of select="."/></div>
</xsl:template>
<xsl:template match="t:releaseDate">
<xsl:variable name="vOrigDate" select="tokenize(.,'-')"/>
<xsl:variable name="vDate" select="xs:date(concat($vOrigDate[3],'-',$vOrigDate[1],'-',$vOrigDate[2]))" as="xs:date"/>
<div class="col"><xsl:value-of select="floor(days-from-duration(current-date() - $vDate) div 365)"/></div>
</xsl:template>
</xsl:stylesheet>
Output
<div id="recordInfo">
<div class="col">Rush</div>
<div class="col">Moving Pictures</div>
<div class="col">31</div>
</div>

Answer 3

This XSLT 1.0 template...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:t="http://www.someurl.com/schema"
exclude-result-prefixes="xsl t" >
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="current-year" select="2012" />
<xsl:template match="/">
<r>
<xsl:apply-templates select="t:albums/t:album" />
</r>
</xsl:template>
<xsl:template match="t:album">
<div id="recordInfo">
<div class="col"><xsl:value-of select="t:artist" /></div>
<div class="col"><xsl:value-of select="t:name" /></div>
<div class="col"><xsl:value-of select="$current-year - substring(t:releaseDate,7)" /></div>
</div>
</xsl:template>
</xsl:stylesheet>
...will yield this output...
<r>
<div id="recordInfo">
<div class="col">Rush</div>
<div class="col">Moving Pictures</div>
<div class="col">31</div>
</div>
</r>
I've used a variable to store the date. In practice you will use a function to get the current date. Which function depends on XSLT version and engine.