I parse an xml with my xslt and get the result as a xml.
i need to format numbers with apostrophe as delimiter for a tousand, million, etc...
eg: 1234567 = 1'234'567
now the problem is how do i get these apostrophes in there?
<xsl:value-of select="format-number(/path/to/number, '###'###'###'###')" />
this doesn't work because the apostrophe itself is already delimiting the start of the format.
is there a simple solution to that (maybe escaping the apostrophe like in c#?
The answer depends on whether you are using 1.0 or 2.0.
In 2.0, you can escape the string delimiter by doubling it (for example 'it''s dark'), and you can escape the attribute delimiter by using an XML entity such as ". So you could write:
<xsl:value-of select="format-number(/path/to/number, '###''###''###''###')" />
In 1.0, you can escape the attribute delimiter by using an XML entity, but there is no way of escaping the string delimiter. So you could switch your delimiters and use
<xsl:value-of select='format-number(/path/to/number, "###'###'###'###")' />
The other way - probably easier - is to put the string in a variable:
<xsl:variable name="picture">###'###'###'###</xsl:variable>
<xsl:value-of select="format-number(/path/to/number, $picture)" />
After some research we came up with this solution:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:decimal-format name='ch' grouping-separator="'" />
<xsl:template match="/">
<xsl:value-of select='format-number(/the/path/of/the/number, "###'###'###", "ch")'/>
...
Related
How can I use the apostrophe ' character in a list? The following code fails, because the list contains an unescaped character in word "Fruit's 13". I tried escape it by backslash character and also by ', but none of them worked.
<xsl:param name="unsorted-values" as="xs:string*" select="'Apple','Banana','Fruit's 13'"/>
<xsl:param name="values" as="xs:string*">
<xsl:perform-sort select="$unsorted-values">
<xsl:sort select="string-length()" order="descending"/>
</xsl:perform-sort>
</xsl:param>
In XPath 2 and later in string literal delimited by single quotes (apostrophs) you can double '' a single quote/apostroph to have it escaped inside the string value, most attributes of XSLT like select use XPath expressions so there you can use that syntax.
Of course in the context of XSLT/XML you could also use select="'Apple', 'Banana', "Fruit's 13"".
XPath 3.1 syntax section for that is in https://www.w3.org/TR/xpath-31/#prod-xpath31-StringLiteral.
Using Saxon 9.7, XSLT 3.0, I'm trying to select square bracketed terms from a string of text and then remove duplicate values of the terms.
So far I have found a template which selects the substrings I want and a function that tokenizes the string and then removes duplicate values.
However, I haven't been able to get the correct regex for the tokenizing of the string.
Here is my XML of the full text
<column>
<columnDerivationPrompt>Option 1: (No visit windowing)</columnDerivationPrompt>
<columnDerivationDescription>Set to collected visit name [EG.VISIT] Set to 'POST-BASELINE MINIMUM' for the new observation generated for derviation type minimum [ADEG.DTYPE] = 'MINIMUM'
Set to 'POST-BASELINE MAXIMUM' for the new observation generated for derviation type maximum [ADEG.DTYPE]= 'MAXIMUM'
</columnDerivationDescription>
<columnDerivationPrompt>Option 2: (User defined visit windows)</columnDerivationPrompt>
<columnDerivationDescription>Set to a re-defined visit range based on user-defined input, using formatting of Analysis Relative Day [ADEG.ADY] range in conjunction with Analysis Window Target [ADEG.AWTARGET] and Analysis Window Diff from Target [ADEG.AWTDIFF] to determine analysis visit.
Set to 'POST-BASELINE MINIMUM' for the new observation generated for derviation type minimum [ADEG.DTYPE] = 'MINIMUM'
Set to 'POST-BASELINE MAXIMUM' for the new observation generated for derviation type maximum [ADEG.DTYPE]= 'MAXIMUM'
</columnDerivationDescription>
</column>
The string of terms taken from the text that I need to remove duplicates from
EG.VISIT ADEG.DTYPE ADEG.DTYPE ADEG.ADY ADEG.AWTARGET ADEG.AWTDIFF ADEG.DTYPE ADEG.DTYPE
What I would like to see
EG.VISIT ADEG.DTYPE ADEG.ADY ADEG.AWTARGET ADEG.AWTDIFF
my XSLT template and function
<xsl:variable name="test">
<xsl:if test="contains($string,'[')">
<xsl:variable name="relevant-part" select="substring-before(substring-after($string,'['),']')"/>
<xsl:variable name="remainder" select="substring-after($string,']')"/>
<xsl:value-of select="$relevant-part"/>
<xsl:if test="contains($remainder,'[')">
<xsl:text disable-output-escaping="yes"> </xsl:text>
</xsl:if>
<xsl:call-template name="find-relevant-text">
<xsl:with-param name="string" select="$remainder"/>
</xsl:call-template>
</xsl:if>
</xsl:variable>
<xsl:value-of select="myfn:sortCSV($test)"/>
</xsl:template>
<xsl:function name="myfn:sortCSV" as="xs:string*">
<xsl:param name="csvString" as="xs:string"/>
<!-- Split up string and remove duplicates -->
<xsl:variable name="values" select="distinct-values(tokenize($csvString,'\W+\.\W+'))" as="xs:string*"/>
<!-- Return all elements, sorted -->
<xsl:for-each select="$values">
<xsl:sort/>
<!-- We don't return empty strings -->
<xsl:sequence select=".[.!='']"/>
</xsl:for-each>
</xsl:function>
\W+\.\W+ is the regex I have been using to identify e.g. EG.VISIT or ADEG.DTYPE. So any pattern including CC.CCCC to CCCC.CCCCCCCC (where C is a char [A-Z]).
The output I am getting is
EG.VISIT ADEG.DTYPE ADEG.DTYPE ADEG.ADY ADEG.AWTARGET ADEG.AWTDIFF ADEG.DTYPE ADEG.DTYPE
So no duplicates have been removed.
QUESTION:
Can anyone see where I am going wrong with my expression or code?
As for your regular expression, note that a \W matches a non-word char and cannot match uppercase (nor lowercase) letters. \w matches a word char.
However, best is to restrict it to [A-Z]+\.[A-Z]+ since you say the items you want to match follow the uppercase+.+uppercase pattern.
See the regex demo
I would use analyze-string, either with XSLT 2.0 the XSLT xsl:anyalyze-string or with XSLT 3.0 the function of the same name, using that approach it is a one-liner:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
exclude-result-prefixes="xs math fn"
version="3.0">
<xsl:template match="column">
<xsl:value-of select="distinct-values(analyze-string(., '\[([A-Z]+\.[A-Z]+)\]')//fn:match/fn:group[#nr = 1])"/>
</xsl:template>
</xsl:stylesheet>
Output is EG.VISIT ADEG.DTYPE ADEG.ADY ADEG.AWTARGET ADEG.AWTDIFF.
If you want to sort the extracted strings then use <xsl:value-of select="sort(distinct-values(analyze-string(., '\[([A-Z]+\.[A-Z]+)\]')//fn:match/fn:group[#nr = 1]))"/>.
How can I create the entity ' ', if I have the part starting with the '#' in a variable?
When I try to do something like this:
concat('&', '#160;')
I get an syntax error in XMLspy.
Does it have to be an entity (actually you mean a "character reference"), or will it do just to output a non-breaking space character?
To do the latter, given that $var holds "#160", in XSLT 2.0 you can use
<xsl:value-of select="codepoints-to-string(number(substring($var, 2)))"/>
The problem with your code is that, in XML, you cannot use a standalone &, so it should be like this:
concat('&', '#160;')
which outputs   if the output method is xml and if text.
disable-output-escaping helps to force in xml output:
<xsl:value-of select="concat('&', '#160;')" disable-output-escaping="yes"/>
Another way to replace a character by an arbitrary string is using character maps:
<xsl:output use-character-maps="foo"/>
<xsl:character-map name="foo">
<xsl:output-character character="&" string="&"/>
</xsl:character-map>
<xsl:template match="/">
<xsl:value-of select="concat('&', '#160;')"/>
</xsl:template>
I have a string like this
"My string"
Now I want to replace my with best so that the output will be like best string.
I have tried some thing like this
<xsl:value-of select="replace( 'my string',my,best)"/>
but probably its a wrong syntax
I have googled a lot but found nothing..every where the mechanism to do this XSLT 1.0 is explained.Can any one tell me how to do it in XSLT 2.0 ,The easy way compared to 1.0
Given:
<xsl:variable name="s1" select="'My string'"/>
Simply use:
<xsl:value-of select="replace($s1, 'My', 'best')"/>
Note that a regular expression is applied. Meaning:
<xsl:value-of select="replace('test.replace', '.', ':')"/>
Becomes:
::::::::::::
Be sure to escape the characters that have special meaning to the regular expression interpreter:
<xsl:value-of select="replace('test.replace', '\.', '::')"/>
Becomes:
test::replace
First check, if your xslt processor (saxxon) is the latest release. Then you have to set
<xsl:stylesheet version="2.0" in the head of your xslt-stylesheet. That's it.
Your code was fine, besides you forgot the apostrophs:
<xsl:value-of select="replace( 'my string',my,best)"/>
must be
<xsl:value-of select="replace('my string','my','best')"/>
Given the following XML:
<table>
<col width="12pt"/>
<col width="24pt"/>
<col width="12pt"/>
<col width="48pt"/>
</table>
How can I convert the width attributes to numeric values that can be used in mathematical expressions? So far, I have used substring-before to do this. Here is an example template (XSLT 2.0 only) that shows how to sum the values:
<xsl:template match="table">
<xsl:text>Col sum: </xsl:text>
<xsl:value-of select="sum(
for $w
in col/#width
return number(substring-before($w, 'pt'))
)"/>
</xsl:template>
Now my questions:
Is there a more efficient way to do the conversion than substring-before?
What if I don't know the text after the numbers? Any way to do it without using regular expressions?
This is horrible, but depending on just how much you know about the potetntial set of non-numeric characters, you could strip them with translate():
translate("12jfksjkdfjskdfj", "abcdefghijklmnopqrstuvwxyz", "")
returns
"12"
which you can then pass to number() as currently.
(I said it was horrible. Note that translate() is case sensitive, too)
I found this answer from Dimitre Novatchev that provides a very clever XPATH solution that doesn't use regex:
translate(., translate(.,'0123456789', ''), '')
It uses the nested translate to strip all the numbers from the string, which yields all other characters, which are used as the values for the wrapping translate function to strip out and return just the number characters.
Applied to your template:
<xsl:template match="table">
<xsl:text>Col sum: </xsl:text>
<xsl:value-of select="sum(
for $w
in col/#width
return number(translate($w, translate($w,'0123456789', ''), ''))
)"/>
</xsl:template>
If you are using XSLT 2.0 is there a reason why you want to avoid using regex?
The most simple solution would probably be to use the replace function with a regex pattern to match on any non-numeric character and replace with empty string.:
replace($w,'[^0-9]','')