Nginx - Rewrite the request_uri before uwsgi_pass - regex

Question

I have a Nginx vhost than is configured as such:
...
location /one {
include uwsgi_params;
uwsgi_pass unix:///.../one.sock;
}
location /two {
include uwsgi_params;
uwsgi_pass unix:///.../two.sock
}
...
This is a simplified configuration of course
When I request /one/something I would like my Python script to receive /something as request_uri.
I'm using BottlePy but would like this to be handled by Nginx and not in my Python code.
Can I do something like uwsgi_param REQUEST_URI replace($request_uri, '^/one', '')?
Edit
Here is the request from my Python code:
[pid: 30052|app: 0|req: 1/1] () {42 vars in 844 bytes} [Tue Aug 21 14:22:07 2012] GET /one/something => generated 0 bytes in 4 msecs (HTTP/1.1 200) 2 headers in 85 bytes (0 switches on core 0)
So Python is OK but uWSGI is not.
How to fix that?

Answer 1

location /one {
rewrite /one/(.+) /$1 break;
include uwsgi_params;
uwsgi_pass unix:///.../one.sock;
}

Answer 2

I know this thread is old, but there is another way to solve this if you are using uWSGI to run your python app.
[uwsgi]
route-uri = ^/one/(.*) rewrite:/$1

Answer 3

I just met the same problem, and here is a solution
location /one {
include uwsgi_params;
uwsgi_pass unix:///.../one.sock;
uwsgi_param SCRIPT_NAME /one;
uwsgi_modifier1 30;
}
You can found more about uwsgi_modifier1 here:
http://uwsgi-docs.readthedocs.org/en/latest/Nginx.html#hosting-multiple-apps-in-the-same-process-aka-managing-script-name-and-path-info

Answer 4

I've solved that in another way:
[uwsgi]
module = wsgi:application
master = true
processes = 10
socket = 127.0.0.1:9090
mount = /one=customscript.py
manage-script-name = true
nginx
location /one {
include uwsgi_params;
uwsgi_pass 127.0.0.1:9090;
}