I made a Bash script to download this page http://php.net/downloads.php and then search for the first occurrence of the latest PHP filename, version and MD5sum. Right now I have it working but broken up into two different sed commands. When I try to put the regexps into a single one it wont match. I believe it has to do with the newlines present.
How do I go about using one single sed pattern where I get all three matches in either an array (preferred) or seperated by spaces.
Btw, it does not have to be sed. I just want something where the system that the script will be run on will likely work, so no perl for instance.
wget -q http://php.net/downloads.php
FILE_INFO=$(sed -nr "s/.*(php-([0-9\.]+)\.tar\.bz2).*/\1 \2/p;T;q" downloads.php)
MD5SUM=$(sed -nr "s/.*md5: ([0-9a-f]{32}).*/\1/p;T;q" downloads.php)
echo $FILE_INFO
echo $MD5SUM
These are the two lines from the file in question and it needs to extract the info from:
PHP 5.4.5 (tar.bz2) [10,754Kb] - 19 July 2012<br />
<span class="md5sum">md5: ffcc7f4dcf2b79d667fe0c110e6cb724</span>
This might work for you (GNU sed):
sed '\|<a href="/get/php|!d;N;s/.*\(php-\([0-9\.]\+\)\.tar\.bz2\).*md5: \([0-9a-f]\{32\}\).*/\1 \2 \3/;q' file
sed -nr 's/.*(php-([0-9\.]+)\.tar\.bz2).*/\1 \2/p;s/.*md5: ([0-9a-f]{32}).*/\1/p;T;' downloads.php
Related
I have a txt file under CentOS in which I want to replace any "\t\n" with "\t\t". I tried this:
sed -i -E 's/\t\n/\t\t/g' myfile.txt
but it doesn't work. I don't know if CentOS doesn't support regex in sed.
Any help is appreciated!
p.s.
Input(two lines):
1\t2\t3\t$
4\t5\t6\t$
Output(one line):
1\t2\t\3\t\t4\t5\t6\t\t
In Editplus, the find regex is '\t\n' and the replace is '\t\t'. Then all lines ending with '\t\n' will become one line, and each '\n' is replaced by one additional '\t'.
p.s.
my file is read like this (cat -A myfile.txt)
You may use this perl command to join lines if previous line has a single tab:
perl -i -0777 -pe 's/(\S\t)\n(?!\z)/$1\t/g' excel.log
(?!\z) is a negative lookahead to fail this match for last line of the file.
You need to escape the backslashes.
sed -i -E 's/\\t\\n/\\t\\t/g' myfile.txt
I've found an answer to my question here: "sed" command to remove a line that match an exact string on first word
...but only partially because that solution only works if I query pretty much exactly like the answer person answered.
They answered:
sed -i "/^maria\b/Id" file.txt
...to chop out only a line starting with the word "maria" in it and not maria if it's not the first word for example.
I want to chop out a specific url in a file, example: "cnn.com" - but, I also have a bunch of local host addressses, 0.0.0.0 and both have some with a single space in front. I also don't want to chop out sub domains like ads.cnn.com so that code "should" work but doesn't when I string in more commands with the -e option. My code below seems to clean things up well except that I can't get it to whack out the cnn.com! My file is called raw.txt
sed -r -e 's/^127.0.0.1//' -e 's/^ 127.0.0.1//' -e 's/^0.0.0.0//' -e 's/^ 0.0.0.0//' -e '/#/d' -e '/^cnn.com\b/d' -e '/::/d' raw.txt | sort | tr -d "[:blank:]" | awk '!seen[$0]++' | grep cnn.com
When I grep for cnn.com I see all the cnn's INCLUDING the one I don't want which is actually "cnn.com".
ads.cnn.com
cl.cnn.com
cnn.com <-- the one I don't want
cnn.dyn.cnn.com
customad.cnn.com
gdyn.cnn.com
jfcnn.com
kermit.macnn.com
metrics.cnn.com
projectcnn.com
smetrics.cnn.com
tiads.sportsillustrated.cnn.com
trumpincnn.com
victory.cnn.com
xcnn.com
If I just use that one piece of code with the cnn.com chop out it seems to work.
sed -r '/^cnn.com\b/d' raw.txt | grep cnn.com
* I'm not using the "-e" option
Result:
ads.cnn.com
cl.cnn.com
cnn.dyn.cnn.com
customad.cnn.com
gdyn.cnn.com
jfcnn.com
kermit.macnn.com
metrics.cnn.com
projectcnn.com
smetrics.cnn.com
tiads.sportsillustrated.cnn.com
trumpincnn.com
victory.cnn.com
xcnn.com
Nothing I do seems to work when I string commands together with the "-e" option. I need some help on getting my multiple option command kicking with SED.
Any advice?
Ubuntu 12 LTS & 16 LTS.
sed (GNU sed) 4.2.2
The . is metacharacter in regex which means "Match any one character". So you accidentally created a regex that will also catch cnnPcom or cnn com or cnn\com. While it probably works for your needs, it would be better to be more explicit:
sed -r '/^cnn\.com\b/d' raw.txt
The difference here is the \ backslash before the . period. That escapes the period metacharacter so it's treated as a literal period.
As for your lines that start with a space, you can catch those in a single regex (Again escaping the period metacharacter):
sed -r '/(^[ ]*|^)127\.0\.0\.1\b/d' raw.txt
This (^[ ]*|^) says a line that starts with any number of repeating spaces ^[ ]* OR | starts with ^ which is then followed by your match for 127.0.0.1.
And then for stringing these together you can use the | OR operator inside of parantheses to catch all of your matches:
sed -r '/(^[ ]*|^)(127\.0\.0\.1|cnn\.com|0\.0\.0\.0)\b/d' raw.txt
Alternatively you can use a ; semicolon to separate out the different regexes:
sed -r '/(^[ ]*|^)127\.0\.0\.1\b/d; /(^[ ]*|^)cnn\.com\b/d; /(^[ ]*|^)0\.0\.0\.0\b/d;' raw.txt
sed doesn't understand matching on strings, only regular expressions, and it's ridiculously difficult to try to get sed to act as if it does, see Is it possible to escape regex metacharacters reliably with sed. To remove a line whose first space-separated word is "foo" is just:
awk '$1 != "foo"' file
To remove lines that start with any of "foo" or "bar" is just:
awk '($1 != "foo") && ($1 != "bar")' file
If you have more than just a couple of words then the approach is to list them all and create a hash table indexed by them then test for the first word of your line being an index of the hash table:
awk 'BEGIN{split("foo bar other word",badWords)} !($1 in badWords)' file
If that's not what you want then edit your question to clarify your requirements and include concise, testable sample input and the expected output given that input.
I'm trying to remove everything but 3 separate lines with specific matching pattern and leave just the 3 lines I want
Here is my code;
sed -n '/matching pattern/matching pattern/matching pattern/p' > file.txt
If you have multiple commands on the same line, you need to separate the commands by a ;:
sed -n '/matching pattern/p;/matching pattern2/p;/matching pattern3/p' file
Alternatively you can put them onto separate lines:
sed -n '/matching pattern/p
/matching pattern2/p
/matching pattern3/p' file
Beside that, you can also use regex alternation:
sed -rn '/(pattern|pattern2|pattern3)/p' file
or (better) use grep:
grep -E '(pattern|pattern2|pattern3)' file
However, this might get messy if the patterns getting longer and more complicated.
awk to the rescue!
awk '/pattern1/ || /pattern2/ || /pattern3/' filename
I think it's cleaner than alternatives.
Sed with Deletion
There's always more than one way to do this sort of thing, but one useful sed programming pattern is using alternation with deletion. For example:
# BSD sed
sed -E '/root|daemon|nobody/!d' /etc/passwd
# GNU sed
sed -r '/root|daemon|nobody/!d' /etc/passwd
This makes it possible to express ideas like "delete everything except for the listed terms." Even when expressions are functionally equivalent, it can be helpful to use a construct that most closely matches the idea you're trying to convey.
This might work for you (GNU sed):
sed '/pattern1/b;/pattern2/b;/pattern3/b;d' file
The normal flow of sed is to print what remains in the pattern space after processing. Therefore if the required pattern is in the pattern space let sed do its thing otherwise delete the line.
N.B. the b command is like a goto and if it has no following identifier, it means break out of any further sed commands and print (or not print if the -n option is in action) the contents of the pattern space.
If I understood you correctly:
sed -n '/\(pattern1\|pattern2\|pattern3\)/p' file > newfile
I am learning using sed in unix.
I have a file with many lines and I wanna delete all lines except lines containing strings(e.g) alex, eva and tom.
I think I can use
sed '/alex|eva|tom/!d' filename
However I find it doesn't work, it cannot match the line. It just match "alex|eva|tom"...
Only
sed '/alex/!d' filename
works.
Anyone know how to select lines containing more than 1 words using sed?
plus, with parenthesis like "sed '/(alex)|(eva)|(tom)/!d' file" doesn't work, and I wanna the line containing all three words.
sed is an excellent tool for simple substitutions on a single line, for anything else just use awk:
awk '/alex/ && /eva/ && /tom/' file
delete all lines except lines containing strings(e.g) alex, eva and tom
As worded you're asking to preserve lines containing all those words but your samples preserve lines containing any. Just in case "all" wasn't a misspeak: Regular expressions can't express any-order searches, fortunately sed lets you run multiple matches:
sed -n '/alex/{/eva/{/tom/p}}'
or you could just delete them serially:
sed '/alex/!d; /eva/!d; /tom/!d'
The above works on GNU/anything systems, with BSD-based userlands you'll have to insert a bunch of newlines or pass them as separate expressions:
sed -n '/alex/ {
/eva/ {
/tom/ p
}
}'
or
sed -e '/alex/!d' -e '/eva/!d' -e '/tom/!d'
You can use:
sed -r '/alex|eva|tom/!d' filename
OR on Mac:
sed -E '/alex|eva|tom/!d' filename
Use -i.bak for inline editing so:
sed -i.bak -r '/alex|eva|tom/!d' filename
You should be using \| instead of |.
Edit: Looks like this is true for some variants of sed but not others.
This might work for you (GNU sed):
sed -nr '/alex/G;/eva/G;/tom/G;s/\n{3}//p' file
This method would allow a range of values to be present i.e. you wanted 2 or more of the list then use:
sed -nr '/alex/G;/eva/G;/tom/G;s/\n{2,3}//p' file
I need help with my sed script. I have a XML-file where I have to remove everything except the text enclosed in these tags:
<TEXT>......</TEXT>
<HEADLINE>......</HEADLINE>
How do I write the sed code ? I know how to remove everything except the text enlosed in ONE tag.
s/.*<TEXT>\(.*\)<\/TEXT>.*/\1/
But how do i write the sed code for many tags ?
You can pass multiple commands to sed:
$ echo '<TEXT>Hello</TEXT>
<HEADLINE>there</HEADLINE>' | sed -n 's/.*<TEXT>\(.*\)<\/TEXT>.*/\1/gp; s/.*<HEADLINE>\(.*\)<\/HEADLINE>.*/\1/gp'
Hello
there
But you really should be careful when applying regex to XML-like files.
Assuming that you have valid XML:
sed '/.*<\(TEXT\|HEADLINE\)>\(.*\)<\/\(TEXT\|HEADLINE\)>.*/!d;s//\2/' yourfile.xml
If you want to use a sed script add this line:
/.*<\(TEXT\|HEADLINE\)>\(.*\)<\/\(TEXT\|HEADLINE\)>.*/!d;s//\2/
Then run:
sed -f yourscript.sed < yourfile.xml
This might work for you (GNU sed):
sed -r '/<(text|headline)>/I!d;s//&\n/;s/^[^\n]*\n//;:a;/<\//!{$!{N;ba}};s/\n/ /g;s/<\//\n&/;P;D' file
This removes all text accept that which is between TEXT and HEADLINE tags and on multi-line values replaces newlines with spaces.