When is it more appropriate to use a pthread barrier instead of a condition wait and broadcast? - c++

Question

I am coding a telemetry system in C++ and have been having some difficulty syncing certain threads with the standard pthread_cond_timedwait and pthread_cond_broadcast.
The problem was that I needed some way for the function that was doing the broadcasting to know if another thread acted on the broadcast.
After some hearty searching I decided I might try using a barrier for the two threads instead. However, I still wanted the timeout functionality of the pthread_cond_timedwait.
Here is basically what I came up with: (However it feels excessive)
Listen Function: Checks for a period of milliseconds to see if an event is currently being triggered.
bool listen(uint8_t eventID, int timeout)
{
int waitCount = 0;
while(waitCount <= timeout)
{
globalEventID = eventID;
if(getUpdateFlag(eventID) == true)
{
pthread_barrier_wait(&barEvent);
return true;
}
threadSleep(); //blocks for 1 millisecond
++waitCount;
}
return false;
}
Trigger Function: Triggers an event for a period of milliseconds by setting an update flag for the triggering period
bool trigger(uint8_t eventID, int timeout)
int waitCount = 0;
while(waitCount <= timeout)
{
setUpdateFlag(eventID, true); //Sets the update flag to true
if(globalEventID == eventID)
{
pthread_barrier_wait(&barEvent);
return true;
}
threadSleep(); //blocks for 1 millisecond
++waitCount;
}
setUpdateFlag(eventID, false);
return false;
}
My questions: Is another way to share information with the broadcaster, or are barriers really the only efficient way? Also, is there another way of getting timeout functionality with barriers?

Answer 1

Based on your described problem:
Specifically, I am trying to let thread1 know that the message it is
waiting for has been parsed and stored in a global list by thread2,
and that thread2 can continue parsing and storing because thread1 will
now copy that message from the list ensuring that thread2 can
overwrite that message with a new version and not disrupt the
operations of thread1.
It sounds like your problem can be solved by having both threads alternately wait on the condition variable. Eg. in thread 1:
pthread_mutex_lock(&mutex);
while (!message_present)
pthread_cond_wait(&cond, &mutex);
copy_message();
message_present = 0;
pthread_cond_broadcast(&cond);
pthread_mutex_unlock(&mutex);
process_message();
and in thread 2:
parse_message();
pthread_mutex_lock(&mutex);
while (message_present)
pthread_cond_wait(&cond, &mutex);
store_message();
message_present = 1;
pthread_cond_broadcast(&cond);
pthread_mutex_unlock(&mutex);