Applescript send variable parameters to xslt file (updatedx2) - xslt

Question

I have an applescript that is using xmltransform to transform a xml using and external xlst file. I would like to add a variable in applescript to be picked up by the xslt file.
The satimage dictionary talks about the use of xsl params as part of xmltransform but i cannot find any examples.
Using the template XMLTransform xmlFile with xsltFile in outputpath
how would i define the variables both in the applescript and in the following
xsl file example.
<xsl:stylesheet version="1.0">
<xsl:param name="vb1" value="'unknown'"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xmeml/list/name">
<xsl:value-of select="{$vb1}"/>
</xsl:template>
</xsl:stylesheet>
Applescript snippet
set vb1 to "Hello" as string
XMLTransform xmlFile with xsltFile1 in outputpathtemp xsl params vb1
The current applescript returns "cannot make vb1 into record".
I am now looking at using the following but it is returning NULL in the XML
set vb1 to {s:"'hello'"}
XMLTransform xmlFile with xsltFile1 in outputpathtemp xsl string params vb1
the input is
<xmeml>
<list>
<name>IMaName</name>
<!-- other nodes -->
</list>
</xmeml>
the current output is
<xmeml>
<list>
<name/>
<!-- other nodes -->
</list>
</xmeml>
Can anyone Help please?
many thanks.

Answer 1

When you are calling a XSLT with parameters, the parameters internally appear very similar to variables within the XSLT (and like parameters sent to a function), so if you pass a parameter in as a name:
<xsl:stylesheet version="1.0">
<xsl:parameter name="paramname" value="'unknown'"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xmeml/list/name">
<xsl:value-of select="{$paramname}"/>
</xsl:template>
</xsl:stylesheet>
when passing the parameter in this instance you would use the name 'paramname' (although maybe something else would be better!), and the value is there in case you don't pass anything. If you do, it would be replaced.

Answer 2

xsl params need a record or list
raw string parameter must be quoted
set vb1 to "'Hello'" -- added simple quote
XMLTransform xmlFile with xsltFile1 in outputpathtemp xsl params {vb1} -- {} = list

Answer 3

Here is the Answer:
applescript
XMLTransform xmlFile with xsltFile1 in outputpathtemp xsl params {"vb1", "'hello'"}
XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="vb1" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/xmeml/list/name">
<xsl:element name="name">
<xsl:value-of select="$vb1"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Thanks.