The problem I am facing is that if I have this string:
STARTGAME grindurr 9 51 19 3 7 1 2 2 0
...I want to extract name grindurr from the middle. I tried this regex:
STARTGAME\t.*\t[^\d]
...but it didn't work. :( Can anyone tell me what I'm doing wrong?
STARTGAME\s+(.*?)\s+\d
might work. The result is then in the first capturing group. You can remove the need for the capturing group by using lookaround, but I don't know the exact capabilities by that regex engine, so above is probably the safest way.
You can use...
STARTGAME\s+(.*?)\s+\d+
That should have the word between STARTGAME and the first number.
Related
I have a filename like this:
0296005_PH3843C5_SEQ_6210_QTY_BILLING_D_DEV_0000000000000183.PS.
I needed to break down the name into groups which are separated by a underscore. Which I did like this:
(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)(\d{16})(.*)
So far so go.
Now I need to extract characters from one of the group for example in group 2 I need the first 3 and 8 decimal ( keep mind they could be characters too ).
So I had try something like this :
(.*?)_([38]{2})(.*?) _(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)(\d{16})(.*)
It didn’t work but if I do this:
(.*?)_([PH]{2})(.*?) _(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)(\d{16})(.*)
It will pull the PH into a group but not the 38 ? So I’m lost at this point.
Any help would be great
Try the below Regex to match any first 3 char/decimal and one decimal
(.?)_([A-Z0-9]{3}[0-9]{1})(.?)(.*?)(.?)_(.?)(.*?)(.?)_(.?)
Try the below Regex to match any first 3 char/decimal and one decimal/char
(.?)_([A-Z0-9]{3}[A-Z0-9]{1})(.?)(.*?)(.?)_(.?)(.*?)(.?)_(.?)
It will match any 3 letters/digits followed by 1 letter/digit.
If your first two letter is a constant like "PH" then try the below
(.?)_([PH]+[0-9A-Z]{2})(.?)(.*?)(.?)_(.?)(.*?)(.?)_(.?)
I am assuming that you are trying to match group2 starting with numbers. If that is the case then you have change the source string such as
0296005_383843C5_SEQ_6210_QTY_BILLING_D_DEV_0000000000000183.PS.
It works, check it out at https://regex101.com/r/zem3vt/1
Using [^_]* performs much better in your case than .*? since it doesn't backtrack. So changing your original regex from:
(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)_(.*?)(\d{16})(.*)
to:
([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_(.*?)(\d{16})(.*)
reduces the number of steps from 114 to 42 for your given string.
The best method might be to actually split your string on _ and then test the second element to see if it contains 38. Since you haven't specified a language, I can't help to show how in your language, but most languages employ a contains or indexOf method that can be used to determine whether or not a substring exists in a string.
Using regex alone, however, this can be accomplished using the following regular expression.
See regex in use here
Ensuring 38 exists in the second part:
([^_]*)_([^_]*38[^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_(.*?)(\d{16})(.*)
Capturing the 38 in the second part:
([^_]*)_([^_]*)(38)([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_([^_]*)_(.*?)(\d{16})(.*)
I have a set of data, like below;
1
2
3
4
5
6
7
8
9
10
1,1
1,2
1,3
2,12
11,13,15
7,8,12
And so on... I am trying to use Regex in to target a certain set of ages between 1-7, but I am getting matches on any double digit which contains any of these characters too. My regex is currently as below;
/^(1)|(2)|(3)|(4)|(5)|(6)|(7)|$/g
My current matches include 1,2,3,4,5,6,7 - perfect. However, it matches the line with 11,13,15 and 7,8,12 - not what I wanted.
Any advice would be appreciated on how to resolve? Thanks in advance, I am continuing to try to correct.
You can use word boundaries:
\b[1-7]\b
See a demo on regex101.com.
As pointed out by #Quantic, this matches numbers from 1-7 regardless where they are.
If you only want to have lines where there is a number between 1-7, you'll need to use anchors:
^[0-7]$
Or if you want to capture the number:
^([0-7])$
With this, you'll need the multiline flag, see a demo on regex101.com as well.
(?<!\d)[1-7](?!\d)
This looks for any digit 1-7 that does not have another digit on either side of it. (using negative lookbehind/lookahead)
regex101 test
I have a string of data...
"123456712J456","D","TEST1~TEST2~TEST3~TEST4~TEST5"
I want to take the following string and make 5 strings.
"123456712J456","D","TEST1"
"123456712J456","D","TEST2"
"123456712J456","D","TEST3"
"123456712J456","D","TEST4"
"123456712J456","D","TEST5"
I currently have the following regex...
//In a program like Textpad
<FIND> "\(.\{13\}\)","D","\([^~]*\)~\(.*\)
<REPLACE> "\1","D","\2"\n"\1","D","\3
//On the regex101 site
"(.{13})","D","([^~]*)~(.*)
Now if I run this 5 times it would work fine. The problem is there is an unknown number of lines to be made. For example...
"123456712J456","D","TEST1~TEST2~TEST3~TEST4~TEST5"
"123456712J457","D","TEST1~TEST2~TEST3"
"123456712J458","D","TEST1~TEST2"
"123456712J459","D","TEST1~TEST2~TEST3~TEST4"
I was hoping to be able to use a MULTI capture group to make this work. I found this PAGE talking about the common mistake between repeating a capturing group and capturing a repeated group. I need to capture a repeated group. For some reason I just could not make mine work right though. Anyone else have an idea?
RESOURCES:
http://www.regular-expressions.info/captureall.html
http://regex101.com/
Try this.See demo.Just club match1 and rest of the matches.
http://regex101.com/r/yR3mM3/17
RegEx:
(.*,)|([^"~]+)
Example:
"1234567123456","T","TEST1~TEST2~TEST3~TEST4~TEST5"
Results:
MATCH 1
1. [0-20] `"1234567123456","T",`
MATCH 2
2. [21-26] `TEST1`
MATCH 3
2. [27-32] `TEST2`
MATCH 4
2. [33-38] `TEST3`
MATCH 5
2. [39-44] `TEST4`
MATCH 6
2. [45-50] `TEST5`
I am trying to match a group of numbers in regex that consist of one of the following:
1,2,3,4,5,6,7,8,9,10,11
But I am having trouble figuring out the regex.
For single digits this pattern worked fine "0|1|2|3|4|5|6|7|8|9" but it fails on double digit numbers. For example 12 passes as ok due to the regex finding the 1 in 12.
You can use begin and end anchors to force the whole string to be matched:
^(0|1|2|3|4|5|6|7|8|9|10|11)$
Which can be shortened to:
^(\d|10|11)$
This will work if you want to check if just one number is between 0 and 11.
^[0-9]$|^1?[0-1]$
If you want to match a string like:
1,2,3,12,32,5,1,6,8, 11
and match 0-11 then you can use the following:
(?<=,|^)([0-9]|1?[0-1])(?=,|$)
use this regex ^(0|1|2|3|4|5|6|7|8|9|(10)|(11))$
I am beginner and have some problems with regexp.
Input text is : something idUser=123654; nick="Tom" something
I need extract value of idUser -> 123456
I try this:
//idUser is already 8 digits number
MatchCollection matchsID = Regex.Matches(pk.html, #"\bidUser=(\w{8})\b");
Text = matchsID[1].Value;
but on output i get idUser=123654, I need only number
The second problem is with nick="Tom", how can I get only text Tom from this expresion.
you don't show your output code, where you get the group from your match collection.
Hint: you will need group 1 and not group 0 if you want to have only what is in the parentheses.
.*?idUser=([0-9]+).*?
That regex should work for you :o)
Here's a pattern that should work:
\bidUser=(\d{3,8})\b|\bnick="(\w+)"
Given the input string:
something idUser=123654; nick="Tom" something
This yields 2 matches (as seen on rubular.com):
First match is User=123654, group 1 captures 123654
Second match is nick="Tom", group 2 captures Tom
Some variations:
In .NET regex, you can also use named groups for better readability.
If nick always appears after idUser, you can match the two at once instead of using alternation as above.
I've used {3,8} repetition to show how to match at least 3 and at most 8 digits.
API links
Match.Groups property
This is how you get what individual groups captured in a match
Use look-around
(?<=idUser=)\d{1,8}(?=(;|$))
To fix length of digits to 6, use (?<=idUser=)\d{6}(?=($|;))