How to add inner attribute to spring REST webservice response?
Sample xml returned by my webservice:
<books>
<bookId>5</bookId>
<bookName>testBook</bookName>
</books>
I want to use book id as xml attribute for bookName:
<books>
<bookName id="5">testBook</bookName>
</books>
Any suggestion?
Based on how your java types are defined you can either annotate your classes with #XmlAttribute or may need to write your custom XmlAdapter
Related
An API I am communicating with is Soap based and requires XML with inner XML (CDATA) in the request.
For the service connector action test I have hard-coded the inner xml with this format:
<![CDATA[
<Application xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" ApplicationCrossReferenceId="123">
...
...
</Application> ]]>
where the dots indicate the data contained.
When running the test the request payload has been transformed to the html entity for < which is $lt; - as seen below :
Is there a way to avoid this?
This is a bug in Informatica. the other characters are decoded back to their original correctly, as described in KB 512858, > and < however are not decoded.
A bug report has been raised 29.05.2020.
Edit: Further investigation revealed that using CDATA was not necessary in my case, instead I was able to use the following input for the body binding:
<Application xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" ApplicationCrossReferenceId="123">
...
...
</Application>
I want to address an xml value in the Xpath field within the enrich mediator in order to customize an API response. My xml input is as follow:
<member>
<name>ABC</name>
</value>1</value>
</member>
I tried to access the 'ABC' value by using this code:
$body//member[#name='ABC']
but it does not work for me.
First of all your XML input is not valid. There is no opening value tag but two closing.
Can you try //member/name/text(),this worked für me.If its not working,then maybe you need to add the namespaces.
Hope that helps.
I have xml that part of structure looks like this:
<IDList>
<ValuesList ID="1">
<Value>1</Value>
<Value>2</Value>
<Value>3</Value>
</ValuesList>
<ValuesList ID="2">
<Value>1</Value>
<Value>2</Value>
<Value>3</Value>
</ValuesList>
</IDList>
What should be model classes for xmlserializer, so I could deserialize it properly?
On the level of IDList it's quite easy:
[XmlArray("IDList")]
[XmlArrayItem("ValuesList")]
public List<CValuesList> idList = new List<CValuesList>();
but how can I do it when the array element has extra xml attribute?
I tried to do ot in the way shown here:
http://www.codemeit.com/xml/c-xmlserializer-add-an-attribute-to-an-array-element.html
but it didn't worked for me. The elements of the array haven't been deserialized.
There is no simple way to do that.
A good solution would be to create an object that contains a list and your properties and inherit/implements IXmlSerializable.
I've seen some kind of quick and dirty way on this site: http://funcakes.posterous.com/adding-elements-to-lists-in-the-xmlserializer. Since the object doesn't inherit from ISerializable, it won't be serialized as a list by the serializer.
I have have two xml docs:
XML1:
<Books>
<Book id="11">
.......
<AuthorName/>
</Book>
......
</Books>
XML2:
<Authors>
<Author>
<BookId>11</BookId>
<AuthorName>Smith</AuthorName>
</Author>
</Authors>
I'm trying to do the following:
Get the value of XML2/Author/AuthorName where XML1/Book/#id equals XML2/Author/BookId.
XML2/Author/AuthorName[../BookId = XML1/Book/#id]
An XPath 1.0 expression cannot refer to more than one XML document, unless the references to the additional documents have been set up in the context of the XPath engine by the hosting language. For example, if XSLT is the hosting language, then it makes its document() function available to the XPath engine it is hosting.
document($xml2Uri)/Authors/Author[BookId = $mainDoc/Books/Book/#id]
Do note, that even the main XML document needs to be referenced via another <xsl:variable>, named here $mainDoc.
The document() function is available only if Xpath is hosted by XSLT! This is not mentioned in the answer of Doc Brown and is misleading the readers.
An XPath 2.x expression may refer to any additional XML document using the XPath 2.0 doc() function.
for $doc in /,
$doc2 in doc(someUri)
return
$doc2/Authors/Author[BookId = $doc/Books/Book/#id]
The document function is your friend, here is a short tutorial how to combine multiple input files.
EDIT: Of course, that works only if your are using Xpath in an Xslt script.
I have a custom definition for a document library and I am trying to rename documents within the library using only the out of the box web services. Having defined a view with the "Name" field supplied and trying the "LinkFilename", my calls to rename a file are respectively returning a failure or ignoring the new value.
How do I rename a file using the SharePoint web services?
Use the Lists.UpdateListItems web method. The XML request should look like:
<Batch OnError="Continue" PreCalc="TRUE" ListVersion="0">
<Method ID="1" Cmd="Update">
<!-- List item ID of document -->
<Field Name="ID">2</Field>
<!-- Full URL to document -->
<Field Name="FileRef">http://Server/FullUrl/File.doc</Field>
<!-- New filename -->
<Field Name="BaseName">NewName</Field>
</Method>
</Batch>
You should be able to use UpdateListItems. Here's an example.
Per comment: So the actual question is "how do I call a web service?" Take a look a this example. Some more good walkthroughs here.