Why the example code below can run fine on Visual Studio. In Eclipse, NetBean or CodeBlock the code can run but can't show the Result? Thanks All.
Ex: input one string.
a/ Uppercase first letter.
b/ Remove spaces inside the string.
#include "iostream"
#include "string.h"
using namespace std;
#define MAX 255
//uppercase first letter
char* Upper(char* input)
{
char* output = new char[MAX];
bool isSpace = false;
for (int i = 0; i < strlen(input); i++)
{
output[i] = input[i];
if (isSpace)
{
output[i] = toupper(output[i]);
isSpace = false;
}
if (output[i] == ' ') isSpace = true;
}
output[strlen(input)] = '\0'; // end of the string
output[0] = toupper(output[0]); // first character to upper
return output;
}
//remove space inside the string
char* RemoveSpaceInside(char* input)
{
char* output = new char[MAX];
strcpy(output, input);
int countWhiteSpace = 0;
for (int i = 0; i < strlen(output); i++)
{
if (output[i] == ' ')
{
for (int j = i; j < strlen(output) - 1; j++) // move before
{
output[j] = output[j + 1];
}
countWhiteSpace++;
}
}
output[strlen(output) - countWhiteSpace] = '\0'; // end of the string
return output;
}
int main()
{
char* name = new char[MAX];
cout << "Enter name: "; cin.getline(name, strlen(name));
cout << "Your name: " << name << endl;
cout << "\n******* Q.A *******\n";
char* qa = Format2VN(name);
cout << qa << endl;
cout << "\n******* Q.B *******\n";
char* qb = RemoveSpaceInside(name);
cout << qb << endl;
return 0;
}
char* name = new char[MAX];
cout << "Enter name: ";
cin.getline(name, strlen(name));
Calling strlen(name) will invoke undefined behavior, because you haven't initialized the array. Poor strlen will try to find the NUL character in an uninitialized byte mess. Definitely not a good idea.
What you probably want is:
cin.getline(name, MAX); // not sure if MAX or MAX-1 or whatever
In general, do yourself a favor and replace char* with std::string. Also, get a good C++ book.
Here is how your example would look like in actual C++:
#include <algorithm>
#include <cctype>
#include <iostream>
#include <string>
std::string upper_first_letter(std::string s)
{
if (!s.empty()) s[0] = toupper(s[0]);
return s;
}
std::string remove_spaces(std::string s)
{
s.erase(std::remove_if(s.begin(), s.end(), isspace), s.end());
return s;
}
int main()
{
std::string name;
std::cout << "Enter name: ";
std::getline(std::cin, name);
std::cout << name << '\n';
std::cout << upper_first_letter(name) << '\n';
std::cout << remove_spaces(name) << '\n';
}
Related
So I have an array of symbols which has another array of symbols in it (if i'm not wrong). What I need to do is to change third element (words[2]). This third element will definitely be a number. I have to increase this number by 15 percent. Therefore, I need to convert words[2] to int?
Function:
void create(char* str) {
char** words = new char* [strlen(str)];
int count = 0;
for (char* part = strtok(str, " "); part != NULL; part = strtok(NULL, " ")) {
words[count] = _strdup(part);
count++;
}
cout << "\nNew sentence with edited values:" << endl;
words[2] = words[2] + ((int)words[2] / 100) * 15; //the main problem as I guess
for (int i = 0; i < count; i++) {
printf("%s ", words[i]);
}
cout << endl;
delete[] words;
}
Full code:
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <iomanip>
#include <conio.h>
#include <string.h>
using namespace std;
void create(char*);
void main() {
const int maxLength = 100;
char* str = new char[maxLength];
cout << "Enter sentence:\n";
cin.getline(str, maxLength);
create(str);
delete[] str;
}
void create(char* str) {
char** words = new char* [strlen(str)];
int count = 0;
for (char* part = strtok(str, " "); part != NULL; part = strtok(NULL, " ")) {
words[count] = _strdup(part);
count++;
}
cout << "\nNew sentence with edited values:" << endl;
words[2] = words[2] + ((int)words[2] / 100) * 15;
for (int i = 0; i < count; i++) {
printf("%s ", words[i]);
}
cout << endl;
delete[] words;
}
What it needs to look like (3rd element increased by 15 percent):
Cannot do this using string. Actually, it is my homework from a university and not using string is the condition
you need to convert a char* to int like below. (int) casting won't work
int a = atoi(words[2]); // make sure words[2] is null terminated
Create a program titled str_compress.cpp. This program will take a sentence input and remove all spaces from the sentence. (A good first step in encryption programs) Make sure that both the input and output strings are all stored in a single variable each. Do not use numbers or symbols. Include both upper-case and lower-case letters. Account for cases with multiple spaces anywhere.
This is what I have so far:
#include <iostream>
#include <string>
using namespace std;
int main()
{
int i = 0, j = 0, len;
string str;
cout << "Enter string: ";
getline(cin, str);
len = str.length();
for (i = 0; i < len; i++)
{
if (str[i] == ' ')
{
for (j = i; j < len; j++)
{
str[j] = str[j + 1];
}
len--;
}
}
cout << str << endl;
system("pause");
return 0;
}
I can eliminate spaces, but only one at a time. If I copy and paste the for loop, I can remove all spaces for how many loops there are. I'm thinking that I can loop the for loop over and over until all spaces are gone, but I'm not sure how to do that. Also, I can't use anything like remove_all() or erase().
This is a strong clue for how the authors of your exercise want you to write your code:
Make sure that both the input and output strings are all stored in a single variable each
You should make a new string:
string new_str;
Use your loop over the input string. For each char in the string, check whether it is a space. If yes, do nothing. If no, append it to the output string:
for (i = ...)
{
char c = str[i];
if (c != ' ')
new_str.push_back(c);
}
Your loop's logic when removing a space is wrong. For instance, after removing a space, you then skip the next char in the string, which may be another space. Also, although you are decrementing the len, you don't resize the string to the new len before printing the new str value.
It should look more like this:
#include <iostream>
#include <string>
using namespace std;
int main()
{
size_t i, j, len;
string str;
cout << "Enter string: ";
getline(cin, str);
len = str.length();
i = 0;
while (i < len)
{
if (str[i] == ' ')
{
for (j = i + 1; j < len; ++j)
{
str[j - 1] = str[j];
}
--len;
}
else
++i;
}
str.resize(len);
cout << str << endl;
/* or, if you are not allowed to use resize():
cout.write(str.c_str(), len);
cout << endl;
*/
/* or, if you are not allowed to use write():
if (len < str.length())
str[len] = '\0';
cout << str.c_str() << endl;
*/
system("pause");
return 0;
}
Live Demo
However, your instructions do say to "Make sure that both the input and output strings are all stored in a single variable each", which implies that separate std::string variables should be used for input and output, eg:
#include <iostream>
#include <string>
using namespace std;
int main()
{
size_t i, j, len;
string str, str2;
cout << "Enter string: ";
getline(cin, str);
str2 = str;
len = str2.length();
i = 0;
while (i < len)
{
if (str2[i] == ' ')
{
for (j = i + 1; j < len; ++j)
{
str2[j - 1] = str2[j];
}
--len;
}
else
++i;
}
str2.resize(len);
cout << str2 << endl;
/* or:
cout.write(str2.c_str(), len);
cout << endl;
*/
/* or:
if (len < str2.length())
str2[len] = '\0';
cout << str2.c_str() << endl;
*/
system("pause");
return 0;
}
Live Demo
Alternatively:
#include <iostream>
#include <string>
using namespace std;
int main()
{
size_t i, j, len;
string str, str2;
cout << "Enter string: ";
getline(cin, str);
len = str.length();
str2.reserve(len);
for(i = 0; i < len; ++i)
{
char ch = str[i];
if (ch != ' ')
str2 += ch;
}
cout << str2 << endl;
system("pause");
return 0;
}
Live Demo
This is what worked for me. Thank you everyone for the help!!
int main()
{
int i, j, len;
string str, str2;
cout << "Enter string: ";
getline(cin, str);
len = str.length();
for (i = 0; i < len; ++i)
{
char ch = str[i];
if (ch != ' ')
str2 += ch;
}
cout << str2 << endl;
system("pause");
return 0;
}
I have a string that contains X words (between each word there is a space) I have to move the words in a circular motion to the left according to the number that the user inserts. For example:
"hi my name is aviv and",
the user entered 2. "name is aviv and hi my" I'm looking for legality that repeats itself but I can not find.
Thanks for the guidance. Most importantly, I can not use built-in libraries
Update:
I see there are examples with libraries, I can not use any library.
So what I've done so far.
I wrote a function that gets a string and a number from the user, to move left.
Before sending the string to the function I try to calculate the number of characters I need to move.
My output is - "name is avivhi my"
Regarding the function:
When it gets a string without spaces it works great.
This is my code:
int main()
{
char str[] = "hi my name is aviv";
char str2[] = "hi my name is aviv";
int CountSpace = 0, CountWord = 0;
int Size = 18, flag = 0;
int MoveLeft, Index = 0;
for (int i = 0; str[i] != '\0'; i++)
{
if (str[i] == ' ')
{
CountSpace++;
}
}
CountWord = CountSpace + 1;//Understand how many words there are in a string.
cin >> MoveLeft;
if (MoveLeft >= CountWord)//
{
MoveLeft = (MoveLeft - ((MoveLeft / CountWord) * CountWord));//the size of movment;//To reduce the amount of moves if there is such a possibility
}
for (int i = Size - 1; i >= 0; i--)
{
if (str[i] == ' ')
{
flag++;
}
if (flag == MoveLeft)
{
Index = Size - 1 - (i + 1);//That's the amount of characters I have to move
break;
}
}
MoveLeft = Index;
//This code belongs to the function that accepts a string and the amount to move the characters
for (int i = 0; i < Size; i++)
{
if (i + MoveLeft < Size)
{
str[i] = str2[i + MoveLeft];
}
else
{
str[i] = str2[(i + MoveLeft) - Size];
}
}
cout << "Move Left: " << MoveLeft << endl << str << endl << str2 << endl;
return 0;
}
Here's a hint:
vector<string> words = Your_Code_To_Split_Input_Into_Words();
int count = words.size();
int shift = Your_Code_To_Read_Users_Input();
// print the sentence with the rotation specified by shift
for (int i = 0; i < count; i++)
{
int shifted_index = (i + shift) % count; // modulo math implements circular rotation
string spacing = (i == 0) ? "" : " "; // add a space before each word, except first word
cout << spacing << words[shifted_index];
}
cout << endl;
One possible answer, i highly recommend using vectors instead of regular arrays, it's easy and more dynamic, but i didn't use it because you said you can't use built-in libraries.
#include <iostream>
#include<string>
using namespace std;
int main() {
string a[10000];
int counter = 0;
string b = "hi my name is aviv and";
string temp = "";
int userNum = 2;
for(int i=0;i<b.length() ; i++){
if(b[i]!=' '){
temp+=b[i];
}
else if(b[i]==' ' && temp.length()){
a[counter]= temp;
temp = "";
counter++;
}
}
if(temp.length()){
a[counter] = temp;
}
for(int i=userNum;i<=counter+userNum;i++){
cout<<a[i%(counter+1)]<<endl;
}
}
If you can make use of std::rotate() from <algorithm>, this is much easy to do with that. Parse the words using std::stringstream and store to std::vector. Then apply the shif directly to the vector.
Sample Output: https://www.ideone.com/rSPhPR
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <sstream>
int main()
{
std::vector<std::string> vec;
std::string str = "hi my name is aviv and";
std::string word;
std::stringstream sstr(str);
while(std::getline(sstr, word,' '))
vec.emplace_back(word);
int shift;
std::cout << "Enter the Shift: ";
std::cin >> shift;
std::rotate(vec.begin(), vec.begin() + shift, vec.end());
for(const auto& it: vec)
std::cout << it << " ";
return 0;
}
Here's a snippet :
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
#define MaxWords 10
int main()
{
stringstream ss;
ss.str("hi my name is aviv and");
string str[MaxWords];
int i;
for (i =0; std::getline(ss, str[i],' ');i++ )
{
cout << str[i] << " ";
}
int n;
cout << "\nEnter pos to split : ";
cin >> n;
for (int j = n; j <= i; j++)
{
cout << str[j] << " ";
}
for (int j = 0; j < n; j++)
{
cout << str[j] << " ";
}
cout << endl;
return 0;
}
Output:
I wrote code to check the input, I set the HavePunct flag always false. However when I input hello,world!! it returns the wrong results to me. Please let me know if you see any problems with my code:
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
int main() {
string s,result_s;
char ch;
bool HavePunct = false;
int sLen = s.size();
cout << "Enter a string:" << endl;
getline(cin, s);
//检测字符串是否有符号
for (string::size_type i = 0;i != sLen; ++i) {
ch = s[i];
if (ispunct(ch)) {
HavePunct = true;
}
else
result_s += ch;
}
if (HavePunct) {
cout << "Result:" << result_s;
}
else {
cerr << "No punction in enter string!" << endl;
system("pause");
return -1;
}
system("pause");
return 0;
}
You are computing the length of the line before you enter any input. Hence, sLen is always zero. Move that line so it is after the line where you read the input.
cout << "Enter a string:" << endl;
getline(cin, s);
int sLen = s.size();
I cannot be sure, however it would seem because your iterator's upper bound is determined by the variable sLen, which you assign to be s.size() before you receive a string, therefore effectively making your upper bound 0 and causing your for loop never to execute.
Try this and let me know:
getline(cin, s);
int sLen = s.size();
for (string::size_type i = 0;i != sLen; ++i) {
ch = s[i];
if (ispunct(ch)) {
HavePunct = true;
}
else
result_s += ch;
}
I've tried so many times in different way to concatenate two strings, one way gives me segment fail,and the other way don't give me error but not it's making the correct function of concatenate. I need result is like this aa, what am I doing wrong?
#include <iostream>
using namespace std;
char str1[20], str2[20], str3[20];
void stringConcat(char[], char[], char[]);
void stringConcat(char str1[], char str2[], char str3[])
{
int i = 0, j = 0;
if (str1[i] != '\0') {
str3[i] = str1[i];
i++;
}
if (str2[j] != '\0') {
str3[i + j] = str2[j];
j++;
}
str3[i] = '\0';
}
int main()
{
int compare;
cout << "First string" << endl;
cin >> str1;
cout << "Second string" << endl;
cin >> str2;
stringConcat(str1, str2, str3);
cout << "result: " << str3 << endl;
return 0;
}