Django how to test if message is sent - django

I want to test if message is sent to user after submit. I'm using django.contrib.messages. Everything seems to be working during manual testing (runserver), but in unit test I don't get messages.
Code that stores message:
messages.success(request, _('Internationalized evil message.'))
Code that should test message:
from django.contrib.messages.api import get_messages
...
def test_message_should_sent_to_user(self):
"""After successful phone number submit, message should be displayed."""
response = self.client.post(
reverse('evil.views.evil_data_submit'), self.valid_data)
messages = get_messages(response.request)
self.assertNotEqual(len(messages), 0)
It looks like that no middleware is called during test client post method call.
Update after #Tisho answer
Messages should be found in response.context, even my guts say that it should work, but it doesn't. I've placed import pdb; pdb.set_trace() in django/contrib/messages/context_processors.py to see if its called during test client.post, its not.
I've double checked TEMPLATE_CONTEXT_PROCESSORS, MIDDLEWARE_CLASSES and INSTALLED_APPS - probably tomorrow I'll discover that I missed something.
Important detail
Forgot to mention that in case of successful submit view returns HttpResponseRedirect therefore response.context is empty.
Solution
View returns redirect (which has no context data), to solve that we can pass follow=True to client.post method (method suggested by #Tisho).

During unit tests, the message could be found in
response = self.client.post(
reverse('evil.views.evil_data_submit'), self.valid_data)
messages = response.context['messages']
If your view returns a redirect, response.context will be empty unless you pass follow=True, like so:
response = self.client.post(
reverse('evil.views.evil_data_submit'),
self.valid_data,
follow=True)

The best way I found is by using mock
http://www.voidspace.org.uk/python/mock/patch.html#patch-methods-start-and-stop
class SimpleCommentTestDirect(TestCase):
def setUp(self):
self._patcher1 = patch('django.contrib.messages.error')
self.mock_error = self._patcher1.start()
def tearDown(self):
self._patcher1.stop()
def test_error_message(self):
self.client.get('/vote/direct/unknownapp/comment/1/up/')
self.assertEqual(self.mock_error.call_args[0][1], 'Wrong request. Model.')
BTW: There are also should be a way to get request by using mock. And by using request object get message from django.contrib.messages.get_messages

Related

django test client doesnt call POST, but GET

I try to test view calling by POST. I use follow=True. But test client uses GET method and my POST data are not passed.
here is my view:
def aaa(request):
n = request.method
d = request.POST
template = 'shop/test.html'
return render(request, template, d)
Here is my test:
from django.utils import unittest
from django.test.client import Client
def test_add_to_cart_page(self):
response = self.client.post('/aaa/', {'product': 11}, follow=True)
self.assertEqual(response.status_code, 200)
When the view is called. It is not POST, but GET used and my POST params are empty of course. Can somebody say why its happened?
EDIT:
I made a clean venv with fresh Django. And it works as expected(calls POST) Looks like there is something rotten in the state of Denmark.
follow=True
means that the client follows the redirection.
response = self.client.post('/aaa/', {'product': 11}, follow=True)
means that the response contains the followed response content. There is nothing wrong with your test; it must be doing a POST.
What's weird is that your view doesn't redirect to anything so I don't understand why you use follow=True. Also I don't see why you assume that post isn't working. What's the result of your test?
After investigation I realize that using PREPEND_WWW breaks the test client post requests.

Django Testing - check messages for a view that redirects

I have been writing tests for one of my django applications and have been looking to get around this problem for quite some time now. I have a view that sends messages using django.contrib.messages for different cases. The view looks something like the following.
from django.contrib import messages
from django.shortcuts import redirect
import custom_messages
def some_view(request):
""" This is a sample view for testing purposes.
"""
some_condition = models.SomeModel.objects.get_or_none(
condition=some_condition)
if some_condition:
messages.success(request, custom_message.SUCCESS)
else:
messages.error(request, custom_message.ERROR)
redirect(some_other_view)
Now, while testing this view client.get's response does not contain the context dictionary that contains the messages as this view uses a redirect. For views that render templates we can get access to the messages list using messages = response.context.get('messages'). How can we get access messages for a view that redirects?
Use the follow=True option in the client.get() call, and the client will follow the redirect. You can then test that the message is in the context of the view you redirected to.
def test_some_view(self):
# use follow=True to follow redirect
response = self.client.get('/some-url/', follow=True)
# don't really need to check status code because assertRedirects will check it
self.assertEqual(response.status_code, 200)
self.assertRedirects(response, '/some-other-url/')
# get message from context and check that expected text is there
message = list(response.context.get('messages'))[0]
self.assertEqual(message.tags, "success")
self.assertTrue("success text" in message.message)
You can use get_messages() with response.wsgi_request like this (tested in Django 1.10):
from django.contrib.messages import get_messages
...
def test_view(self):
response = self.client.get('/some-url/') # you don't need follow=True
self.assertRedirects(response, '/some-other-url/')
# each element is an instance of django.contrib.messages.storage.base.Message
all_messages = [msg for msg in get_messages(response.wsgi_request)]
# here's how you test the first message
self.assertEqual(all_messages[0].tags, "success")
self.assertEqual(all_messages[0].message, "you have done well")
If your views are redirecting and you use follow=true in your request to the test client the above doesn't work. I ended up writing a helper function to get the first (and in my case, only) message sent with the response.
#classmethod
def getmessage(cls, response):
"""Helper method to return message from response """
for c in response.context:
message = [m for m in c.get('messages')][0]
if message:
return message
You include this within your test class and use it like this:
message = self.getmessage(response)
Where response is what you get back from a get or post to a Client.
This is a little fragile but hopefully it saves someone else some time.
I had the same problem when using a 3rd party app.
If you want to get the messages from a view that returns an HttpResponseRedict (from which you can't access the context) from within another view, you can use get_messages(request)
from django.contrib.messages import get_messages
storage = get_messages(request)
for message in storage:
do_something_with_the_message(message)
This clears the message storage though, so if you want to access the messages from a template later on, add:
storage.used = False
Alternative method mocking messages (doesn't need to follow redirect):
from mock import ANY, patch
from django.contrib import messages
#patch('myapp.views.messages.add_message')
def test_some_view(self, mock_add_message):
r = self.client.get('/some-url/')
mock_add_message.assert_called_once_with(ANY, messages.ERROR, 'Expected message.') # or assert_called_with, assert_has_calls...

Can i access the response context of a view tested without the test client?

I have a function which i call from a unittest. From setting some debug traces i know the function worked like a charm and has all the values correctly prepared for return.
This is what my testcode looks like (see where my ipdb.set_trace() is ):
#override_settings(REGISTRATION_OPEN=True)
def test_confirm_account(self):
""" view that let's a user confirm account creation and username
when loggin in with social_auth """
request = self.factory.get('')
request.user = AnonymousUser()
request.session={}
request.session.update({self.pipename:{'backend':'facebook',
'kwargs':{'username':'Chuck Norris','response':{'id':1}}}})
# this is the function of which i need the context:
response = confirm_account(request)
self.assertEqual(response.context['keytotest'],'valuetotest')
From what i know from this part of the Django docs, i would be able to access response.context when i have used the testing client. But when i try to access response.context like i did it, i get this:
AttributeError: 'HttpResponse' object has no attribute 'context'
Is there a way to get the special HttpResponse object of the client, without using the client?
The RequestFactory does not touch the Django middleware, and as such, you will not generate a context (i.e. no ContextManager middleware).
If you want to test the context, you should use the test client. You can still manipulate the construction of the request in the test client either using mock or simply saving your session ahead of time in the test, such as:
from django.test import Client
c = Client()
session = c.session
session['backend'] = 'facebook'
session['kwargs'] = {'username':'Chuck Norris','response':{'id':1}}
session.save()
Now when you load the view with the test client, you'll be using the session as you set it, and when you use response = c.get('/yourURL/'), you can then reference the response context using response.context as desired.
The "response.context" is incorrect for new django versions but you can use response.context_data to get the same context that passed to TemplateResponse.
Though this is an old post, I suppose this tip can be of help. You can look into using TemplateResponse (or SimpleTemplateResponse) which can be substituted for render or render_to_response.
The Django docs has more on this
Yes, you can. You have to patch render.
I'm using pytest-django
class Test:
def context(self, call_args):
args, kwargs = call_args
request_mock, template, context = args
return context
#patch('myapplication.views.render')
def test_(self, mock_render, rf):
request = rf.get('fake-url')
view(request)
context = self.context(mock_render.call_args)
keytotest = 'crch'
assert keytotest == context['keytotest']
context (sic!) can be found in Response class. As you see it says it's HTTPResponse you get back from the view function. This happened because you've called it directly. Call this function via test client and it will be okay.
response = client.get('/fobarbaz/')
response.context

django test client gets 404 for all urls

I am doing my first experiments with django testing and I am having the problem that I always get the 404 template regardless which url (even /) I am using.
If I throw the very same code into the django shell it's working as expected and always presents me the contents of the requested url.
class SimpleTest(TestCase):
def setUp(self):
self.user = User.objects.create_user('test', 'test', 'test')
self.user.is_staff = True
self.user.save()
self.client = Client()
def test_something(self):
self.assertTrue(self.client.login(username='test', password= 'test'))
self.client.get("/")
The login returns True, but the get() fails. Any hints what I am doing wrong here?
Keep in mind that most views use something like get_object_or_404, get_list_or_404, or simply raise Http404 when there's a problem accessing some object or another. You'll need to make sure that your test database is populated with sufficient objects to fulfill all these requirements to make the view not return a 404.
Remember, when running tests, the database is rolled back after each test (using transactions), so each test method must stand on its own or the setUp method must populate the database with any required dependencies.

Execute code in Django after response has been sent to the client

In my Django application I want to keep track of whether a response has been sent to the client successfully. I am well aware that there is no "watertight" way in a connectionless protocol like HTTP to ensure the client has received (and displayed) a response, so this will not be mission-critical functionality, but still I want to do this at the latest possible time. The response will not be HTML so any callbacks from the client (using Javascript or IMG tags etc.) are not possible.
The "latest" hook I can find would be adding a custom middleware implementing process_response at the first position of the middleware list, but to my understanding this is executed before the actual response is constructed and sent to the client. Are there any hooks/events in Django to execute code after the response has been sent successfully?
The method I am going for at the moment uses a subclass of HttpResponse:
from django.template import loader
from django.http import HttpResponse
# use custom response class to override HttpResponse.close()
class LogSuccessResponse(HttpResponse):
def close(self):
super(LogSuccessResponse, self).close()
# do whatever you want, this is the last codepoint in request handling
if self.status_code == 200:
print('HttpResponse successful: %s' % self.status_code)
# this would be the view definition
def logging_view(request):
response = LogSuccessResponse('Hello World', mimetype='text/plain')
return response
By reading the Django code I am very much convinced that HttpResponse.close() is the latest point to inject code into the request handling. I am not sure if there really are error cases that are handled better by this method compared to the ones mentioned above, so I am leaving the question open for now.
The reasons I prefer this approach to the others mentioned in lazerscience's answer are that it can be set up in the view alone and does not require middleware to be installed. Using the request_finished signal, on the other hand, wouldn't allow me to access the response object.
If you need to do this a lot, a useful trick is to have a special response class like:
class ResponseThen(Response):
def __init__(self, data, then_callback, **kwargs):
super().__init__(data, **kwargs)
self.then_callback = then_callback
def close(self):
super().close()
self.then_callback()
def some_view(request):
# ...code to run before response is returned to client
def do_after():
# ...code to run *after* response is returned to client
return ResponseThen(some_data, do_after, status=status.HTTP_200_OK)
...helps if you want a quick/hacky "fire and forget" solution without bothering to integrate a proper task queue or split off a separate microservice from your app.
I suppose when talking about middleware you are thinking about the middleware's process_request method, but there's also a process_response method that is called when the HttpResponse object is returned. I guess that will be the latest moment where you can find a hook that you can use.
Furthermore there's also a request_finished signal being fired.
I modified Florian Ledermann's idea a little bit... So someone can just use the httpresponse function normally, but allows for them to define a function and bind it to that specific httpresponse.
old_response_close = HttpResponse.close
HttpResponse.func = None
def new_response_close(self):
old_response_close(self)
if self.func is not None:
self.func()
HttpResponse.close = new_response_close
It can be used via:
def myview():
def myfunc():
print("stuff to do")
resp = HttpResponse(status=200)
resp.func = myfunc
return resp
I was looking for a way to send a response, then execute some time consuming code after... but if I can get a background (most likely a celery) task to run, then it will have rendered this useless to me. I will just kick off the background task before the return statement. It should be asynchronous, so the response will be returned before the code is finished executing.
---EDIT---
I finally got celery to work with aws sqs. I basically posted a "how to". Check out my answer on this post:
Cannot start Celery Worker (Kombu.asynchronous.timer)
I found a filthy trick to do this by accessing a protected member in HttpResponse.
def some_view(request):
# ...code to run before response is returned to client
def do_after():
# ...code to run *after* response is returned to client
response = HttpResponse()
response._resource_closers.append(do_after)
return response
It works in Django 3.0.6 , check the "close" function in the prototype of HttpResponse.
def close(self):
for closer in self._resource_closers:
try:
closer()
except Exception:
pass
# Free resources that were still referenced.
self._resource_closers.clear()
self.closed = True
signals.request_finished.send(sender=self._handler_class)