Redirection + 403 error - django

Question

I am searching for a way to have something like that :
return HttpResponseForbiddenRedirect(reverse("view_name"))
an HttpResponse which redirect to a view (with its name) but still throw a 403 error
I tried to do something like that :
class HttpResponseForbiddenRedirect(HttpResponse):
def __init__(self, redirect_to):
super(HttpResponseForbiddenRedirect, self).__init__()
self['Location'] = iri_to_uri(redirect_to)
self.status_code = 403
But it didn't work. For some reason I don't understand, I don't get any content

Answer 1

It doesn't work because you can't have a 403 response that is also acted upon as if it is a 302 response.
The HTTP spec tells browsers how to handle certain status codes, and so a browser getting a 403 won't bother to look to see if there's a Location header in the way that it would do with a 302.
If you want to redirect someone from X to Y because they're not allowed to see X, then just issue a standard 302, and do something like setting a message (using django.contrib.messages) to inform the user of why they've been redirected, or redirect them to a page that explains what is going on.

Answer 2

You're missing the idea behind HTTP status codes. Redirect is being made with HTTP code 301/302. So you cannot make redirect and return 403 at the same time. It is simply not a redirect, if there is no 301/302 code returned.
I don't get it why you need this, but you can always make a view like:
def my403view(request): # e.g. /403.html
return HttpResponseForbidden()
and to do your redirect with:
return HttpResponseRedirect(reverse("403.html"))
This will redirect(with code 302) to "my403view", and it will return 403.

Answer 3

I found a solution to this :
from app_name.views import my_view
....
retour = my_views(request)
return HttpResponseForbidden(retour)
It is in fact quite simple
And so I get the 403 error + the page I wanna load