How to initialize a static member of a parametrized-template class - c++

Question

I don't think my question is a duplicate of this one.
what I try to do:
template<const char* szFunctionName>
class CReentranceLock
{
public:
CReentranceLock(){}
~CReentranceLock(){}
bool isLocked(){return s_bLock;}
void setLocked(bool b)
{
const bool Result=(bool)InterlockedCompareExchange(
(unsigned long *)&s_bLock, b, !b);
}
private:
static bool s_bLock;
};
template<const char* szFunctionName>
bool CReentranceLock<const char*szFunctionName>::s_bLock=false;
// error C2146: syntax error : missing ',' before identifier 'szFunctionName'
implying that all instances of CReentranceLock would have their own static, relying on the const char address of the function name passed as a parameter of the template.
and that could be used like this:
void CMyObject::InAnyFunction()
{
const char* szFunctionName = __FUNCTION__;
CReentranceLock<szFunctionName> lock; // Edit: <- this doesn't work
if(lock.isLocked()) return;
lock.setLocked(true);
/// business code
lock.setLocked(false);
}
well that's only the theory...
and unfortunately this doesn't compile under visual 2010, at the line where I try to initialize the statics.
error C2146: syntax error : missing ',' before identifier 'szFunctionName'
what am I doing or thinking wrong ?
PS: and I am not dealing with the fact that reentrance is smelling like an awful design (in MFC), I know, I am lost in the middle of it ;-)
Edit: though the answer below is good, and the definition compiles... my use in CMyObject::InAnyFunction() with a const char * as a template-parameter available at compile time seems to be wrong. :-(

Answer 1

bool CReentranceLock<const char*szFunctionName>::s_bLock=false;
This should be:
bool CReentranceLock<szFunctionName>::s_bLock=false;

Answer 2

Just change the line to
bool CReentranceLock<szFunctionName>::s_bLock=false;